Location:
Search - s5
Search list
Description: 描述M1卡的物理结构，是RFID编程的最佳参考文档-Describing the physical structure of M1 card is the best RFID programming reference documentation
Platform: |
Size: 9216 |
Author: songzhi |
Hits:
Description: 在VS2005中C#做的一个倒计时一分钟的数字100以内的算术加法题-In the VS2005 in C# to do a countdown of the number 100 within a minute of the arithmetic addition problems
Platform: |
Size: 36864 |
Author: 七季711 |
Hits:
Description: 假设一个文件中出现了8种符号S0，SQ，S2，S3，S4，S5，S6，S7，那么每种符号要编码，至少需要3bit。假设编码成000，001， 010，011，100，101，110，111。那么符号序列S0S1S7S0S1S6S2S2S3S4S5S0S0S1编码后变成 000001111000001110010010011100101000000001，共用了42bit。我们发现S0，S1，S2这3个符号出现的频率比较大，其它符号出现的频率比较小，我们采用这样的编码方案：S0到S7的码辽分别01，11，101，0000，0001，0010，0011， 100，那么上述符号序列变成011110001110011101101000000010010010111，共用了39bit。尽管有些码字如 S3，S4，S5，S6变长了(由3位变成4位)，但使用频繁的几个码字如S0，S1变短了，所以实现了压缩。对于上述的编码可能导致解码出现非单值性：比如说，如果S0的码字为01，S2的码字为011，那么当序列中出现011时，你不知道是S0的码字后面跟了个1，还是完整的一个S2的码字。因此，编码必须保证较短的编码决不能是较长编码的前缀。符合这种要求的编码称之为前缀编码。要构造符合这样的二进制编码体系，可以通过二叉树来实现。-Suppose a file appears in eight kinds of symbols S0, SQ, S2, S3, S4, S5, S6, S7, then each symbol to be encoded, at least 3bit. Suppose encoding 000,001, 010,011,100,101,110,111. Then the symbolic sequence S0S1S7S0S1S6S2S2S3S4S5S0S0S1 encoded into 000001111000001110010010011100101000000001, sharing a 42bit. We found that S0, S1, S2 these three symbols the frequency of relatively large, the other symbols the frequency is relatively small, we have adopted this coding scheme: S0 to S7 of the yards were 01,11,101,0000,0001,0010 Liao , 0011, 100, then the symbol sequence into 011110001110011101101000000010010010111, shared a 39bit. Although some code words, such as S3, S4, S5, S6 was longer (from 3 into a 4-bit), but a few yards of frequently used words, such as S0, S1 shorter, so to achieve the compression. For the above may lead to decode the presence of non-coding single-valued nature: For example, if the S0 code word for the 01, S2 s code word for the 011, then when the sequence appears
Platform: |
Size: 232448 |
Author: 谭毅 |
Hits:
Description: 本抢答器可实现8个人或8个团队参加比赛，其中8个人或8组代表的编号为1，2，3，4，5，6，7，8。每个人或团队拥有一个抢答器按钮，抢答器的按钮与选手分别对应，为s1,s2,s3,s4,s5,s6,s7,s8.-The Responder can be realized eight individuals or eight teams participate in the competition, in which eight individuals or representatives of eight groups numbered 1,2,3,4,5,6,7,8. Each person or team has a Responder button Responder buttons correspond with the player for the s1, s2, s3, s4, s5, s6, s7, s8.
Platform: |
Size: 5120 |
Author: lmq |
Hits:
Description: SC6121解码程序
熟悉遥控接码解码的方法
数码管显示解码结果：高四位为用户码，低2位为按键码
硬件要求：拨码开关S10的第2位置ON，其他置OFF
拨码开关S5、S6全部置ON
其他拨码开关全部置OFF
-SC6121 decoding program are familiar with remote access code decoding methods digital tube display decoder Results: 4 for the user code, low-2 for the key code hardware requirements: DIP Switch S10 2nd position ON, the other set OFF dial code Switches S5, S6 are all set to ON other DIP switches are all set to OFF
Platform: |
Size: 3072 |
Author: 李艳军 |
Hits:
Description: 编写一个函数int squeeze(char s1[], const char s2[])，它从字符串s1中删除所有在s2里出现的字符,函数返回删除的字符个数-Write a function int squeeze (char s1 [], const char s2 []), remove it from the string s1 where s2 occurs all the characters, the function returns the number of characters to delete
Platform: |
Size: 852992 |
Author: 周 |
Hits:
Description: plc programs in s73-plc programs in s7300
Platform: |
Size: 512000 |
Author: murat |
Hits:
Description:
设有10个学生的成绩分别为56、69、84、82、73、88、99、63、100和80分。试编制程序分别统计低于60分、60～69分、70～79分、80～89分、90～99分及100分的人数存放到s5、s6、s7、s8、s9及s10单元中。
-Equipped with 10 student achievement 56,69,84,82,73,88,99,63,100 and 80 points respectively. Programmed test statistics were less than 60 minutes, 60 ~ 69 minutes, 70 ~ 79 minutes, 80 ~ 89 points, 90 ~ 99 points and 100 points, the number of storage to the s5, s6, s7, s8, s9 and s10 unit.
Platform: |
Size: 1024 |
Author: 陈玉 |
Hits:
Description: it s to scal an img from one valu to another
Platform: |
Size: 1024 |
Author: amy |
Hits:
Description: 电力系统的潮流计算,以下程序参考文献 《电力系统毕业设计》中国水利电力出版社
(该文献用极坐标下的牛顿——拉夫逊方法实现，在此为了与课本一致做了修改)
为了计算方便将原来的下标做以下修改: S2 S3 S4 S5 U2 U3 U4 U5 改为S1 S2 S3 S4 U1 U2
U3 U4 ,即原题的平衡点1就变为现在的平衡点5-Power system load flow calculation, the following procedures References " Graduation power system design" China Water Conservancy and Electric Power Press (in the literature with the polar coordinates of the Newton- Raphson method of implementation, in this order was revised in line with the textbook) in order to to facilitate the calculation of the original subscript make the following changes: S2 S3 S4 S5 U2 U3 U4 U5 replaced by S1 S2 S3 S4 U1 U2 U3 U4, namely, the original title of the equilibrium point becomes a point of balance is now 5
Platform: |
Size: 2048 |
Author: 吕清洁 |
Hits:
Description: 本程序为简易的时钟秒表程序，初始状态为时间，且时间可通过按键进行调整。
其中，S7为暂停键按下后时间暂停以对其进行调整，S8、S3为秒调整键，实现秒的加减
S6、S3为分调整键，实现分的加减。S5、S1为小时调整键，实现时的加减。
S4为返回键，使调整后的时间继续运行。
S1为秒表与时间切换键，按下后秒表为待跑状态。S2为秒表开始键，S3为秒表暂停键。
在秒表状态下，S1为清零键，S4为返回到时间键。
其中还有另个指示灯，均不亮时为时间状态；亮一个时为时间调整或秒表状态。-c language for clock and alarm
Platform: |
Size: 3072 |
Author: 赵志 |
Hits:
Description: ARM7综合实验。开发环境IAR，板子用的是YL-LPC2148。功能简介：通过UART（向量IRQ中断），接收上位机发来的控制命令，该命令控制蜂鸣器以特定频率鸣叫，同时利用LCD将蜂鸣器的鸣叫频率显示出来；通过开发板上外部中断源S4、S5（相量中断）获得外部输入0、1序列（按下S5代表1，S4代表0），将该序列发回上位机，同时LED闪亮以表示S4、S5操作有效。-ARM7 comprehensive experiment. Development Environment IAR, board using a YL-LPC2148. Features: through the UART (IRQ interrupt vectors), the receiving host computer sent the control command, the command control of a specific frequency tweet buzzer, LCD will also use songs and calls of buzzer frequency is displayed through the development of on-board external interrupt Yuan S4, S5 (phase volume break) 0,1 sequence of external input (press the S5 on behalf of 1, S4 representative of 0), the sequence back to PC, while LED flashes to indicate S4, S5 operate effectively.
Platform: |
Size: 82944 |
Author: si |
Hits:
Description: 自己提交的某硬件路由上的路由表,cnc和ctc全部最新.很方便路由管理员,vpn,和s5代理开发者.-Their submission of a hardware routing the routing table, cnc and ctc all the latest.
Platform: |
Size: 3072 |
Author: themyth |
Hits:
Description: 单片机数字钟C程序
六位数码管 显示HH.MM.SS(时分秒),MM.DD-W(月日-星期),闹钟定时时间
按键S5依次选择调整时间-显示月日星期-调整月日星期-显示闹钟定时时间-调整闹钟定时
按键S2依次选中时分秒(月日星期)数码管,S3按键依次加1,S4按键依次减1
整点报时,闹钟功能-SCM Digital Clock C program six digital tube display HH.MM.SS (minutes and seconds), MM.DD-W (month day- week), alarm clock timer time S5 and select buttons to adjust the time- Display day of week- day of adjustment weeks- Show alarm time of time- time to adjust alarm button is selected when the minutes and seconds followed by S2 (day of week) Digital control, S3 button and then click Add 1, S4 button followed by a whole point timekeeping, alarm clock function
Platform: |
Size: 6144 |
Author: 赵小龙 |
Hits:
Description: 三星Mobile SoC Code Information，包括Microcontroller，MSP，MOS三种，分别以S3、SC、SD、S5开头的芯片型号说明。-Samsung Mobile SoC Code Information, including the Microcontroller, MSP, MOS three, respectively, S3, SC, SD, S5 chips at the beginning of the Models.
Platform: |
Size: 82944 |
Author: zhoujie |
Hits:
Description: 1602液晶秒表
上电后液晶屏先显示网站等信息，接着按下S4，定时开始，再次按下 S4暂停，第3次按下显示累积计时，第4次按下暂停计时，任何时候按下S5计数清零。-1602 LCD stopwatch after power LCD display websites and other information first, then press the S4, time began, once again press the S4 suspend, 3rd press shows the cumulative time, 4th time press pause at any time by pressing S5 counts cleared.
Platform: |
Size: 3072 |
Author: 杨强 |
Hits:
Description: s1.m: 低频波检测。能从高频信号中检测出低频信号。并将信号输出以70倍因子downsample.
s2.m: 将downsampling滤波器输出信号，用单级速率和多相upsampling。
s3.m: 自动识别车牌位置。此程序能从一张图片当中，自动识别出车牌的位置。
s4.m: 用Hough变换识别出一张带有水池的图片的水池分界线。
s5.m: 用原始的静态多副图片（例如：恐龙图片）构造出三维旋转立体图片。-signal processing
Platform: |
Size: 9216 |
Author: ruson |
Hits:
Description: VERILOG SOURCE CODE FOR N MODULO COUNTER
Platform: |
Size: 6144 |
Author: SUNIL |
Hits:
Description: 程序功能：
开机后，按一下S1,系统进入模式1；按一下S2,系统进入模式2；按一下S3，系统进入模式3。
在模式1下，S5按下LED1亮，弹起LED1灭；
在模式2下，S5按下LED2亮，弹起LED2灭；
在模式3下，S5按下LED3亮，弹起LED3灭；
学习重点:
1、程序的执行的顺序
2、switch..case..的用法
3、程序原模块化
4、全局变量的使用
-Program features: power, click S1, the system enters mode 1 click on S2, the system enters mode 2 click on S3, the system enters mode 3. In Mode 1, S5 press LED1 light, bounce off LED1 In mode 2, S5 press LED2 light, bounce off LED2 in mode 3, S5 press LED3 light, bounce off LED3 Learning : 1, the program execution of the order of 2, switch .. case .. the use of 3, the procedure of the original modular 4, the use of global variables
Platform: |
Size: 1024 |
Author: kane |
Hits:
Description: 一个加法速度测试程序,用户单击“开始”按钮后开始计时，并分别在文本框1、2中随机生成并显示加数和被加数，用户在文本框3中输入答案，按回车键后程序在答案的后面指示对错，并显示出下一道题。一分钟以后程序统计出出题数量和作对的数量。用户单击“结束”按钮退出程序。-An addition speed test program, the user clicks the " Start" button, start the timer, and 1,2, respectively, in the text box and display the addend and the randomly generated summand, the user entered in the text box 3 answers, press the Enter key After the program instructions in the back of the answer right or wrong, and shows the next problem. A minute later the number of procedures and the statistics against a number of questions. The user clicks the " Finish" button to exit the program.
Platform: |
Size: 49152 |
Author: 倒霉熊 |
Hits: