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[Booksab.rar

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[Windows Develop源代码-高源

Description: 包括10个源码:1 令系统托盘(提示区/Sys tray)中的图标显示气泡提示框(Tool Tip)的代码 2 软盘格式化程序 3 一个虚拟驱动盘映射器 4 这个软件可以得到大多数的“高级”系统信息,比如系统缓存的密码、PROXY设置、网卡MAC等 5 用过Flashget和网络蚂蚁的朋友应该知道在IE中右击右击菜单有使用(xxxxx)下载.本代码就实现此功能。可以获取在网页中选择的文本,链接 地址,图片. 6 引起轰动的源码,能在视窗里每一个窗口最小化按钮旁加一个新按钮,这个新按钮的功能是将窗口最小化到系统状态栏,强烈推荐!!! 7 一个系统程序,可以察看系统中当前窗口的局柄等信息,可以察看系统窗口,例如任务栏、开始按钮。可以通过鼠标移动察看光标位置下的 窗口的信息 8 通过Winsock实现的Web服务器程序,目前只支持html格式,如ASP,CGI等可能自己扩展,通过此程序可以学习掌握Winsock控件的使用,多用户的考虑 9 一个可以获得Windows可执行文件(Portable Executable File)的文件头信息的程序 10 可以放大部分图片, 象放大镜.-including 10 Source : Order a system tray (Hint / AB tray), the icon shows bubble boxes (Tool Tip) 2 floppy disk formatting code procedures 3 a virtual disk drive mapping for the four software can be the most "advanced" system information, such as the password caching system, PROXY setup, MAC used five Flashget and network ant friends should know that the IE right-click a right-click menu use (xxxxx). The code on the realization of this function. Can be obtained on the website, select the text link address, and pictures. 6 caused a stir source code, Windows Lane in every one of the smallest window button side a new button, This new button's function is to minimize the window to the system status bar, and strongly recommended! ! ! 7 a system procedures, the system can see the
Platform: | Size: 433289 | Author: none | Hits:

[Web Servertsunami-0[1].1.1.tar

Description: Tsunami Bench是一个连接Apache Bench的Gnome/GTK前端。它是作者的第一个Gnome/GTK应用程序,作者希望最终用更好的功能来取代AB。-Tsunami Bench is a link Apache Bench of the Gnome / GTK front end. It is the first author of a Gnome / GTK application, the authors hope to better end-to replace the function of AB.
Platform: | Size: 211854 | Author: 战神 | Hits:

[OS programJava%20Script%BE%AB%B2%CA%CA%B5%C0%FD%BD%CC%B3%CC1

Description: 好东西,也是java的,学习很有帮助,建议大家下来使用一下。-good thing by java,it is good to study , just try it .
Platform: | Size: 387006 | Author: 杨文 | Hits:

[Other resourceC语言文件管理

Description: 操作系统中的文件是通过文件目录项来管理的,为了管理和查找的方便,按层次把文件目录项组织起来,同一层上的目录构成该层上的目录,第一层为根目录,一下为各层子目录。 假设以一串字符代表一个文件,每个字符表示一个记录。 在建立上述目录结构的基础上,建立相应的管理系统并要求完成以下各项操作: 1. 一次建立各个文件 2. 查访两个用户的所有文件 3. 查访用户sun 是否有文件AB 4. 删除用户sun的文件AC,然后在分别查访两个用户的全部文件,检查是否已经删除文件AC 5. 撤销用户sun,并检查是否被删除 6. 删除用户sun的全部文件,然后在撤销sun用户,在查访用户sun, 检查其是否已被撤销。 在建立一个新用户及新用户的两个文件,然后查该两个用户的所有文件-operating system, the paper is to document catalog items to the management, in order to manage and facilitate the search, according to the document level directory entries organizations, the same floor on which constitute the directory contents on the floor, the first layer of the root directory to look for levels of subdirectories. Assuming that the representative of a string of characters, each character expressed a record. In establishing the directory structure on the basis of the establishment of a corresponding system of management and asked to accomplish the following : 1. Once established two separate files. Visits to the two users of all three documents. Sun user visits whether documents AB 4. Sun users to delete the documents AC, then two separate visits to all users of the docum
Platform: | Size: 8501 | Author: 葛林 | Hits:

[Communicationldpc_distr

Description: LDPC码是Low Density Parity-check Codes的缩写,一个长为N的LDPC码由它的校验矩阵H来定义,该矩阵的特点是其中的元素0特别多,1特别少——即所谓的“低密度”。一个参数为(N,i,j)的H表示该矩阵中每列有i个1,每行有j个1,矩阵大小为N×K,N代表码字长度,K代表校验子的个数。 -LDPC code is the ab. of Low Density Parity-check Codes. A Length N LDPC is defined by its H matrix. The matrix has many zeros and few ones. which called \"low density\". An H matrix has a parameter as (N,i,j) express that it is the matrix which has i s 1 in each column ,j s one in each row, the size of the matrix is N*K,the N is the code word length ,k is the number of the checks.
Platform: | Size: 625205 | Author: 姚中华 | Hits:

[CSharp2005102611013310480

Description: 最佳矩阵连乘 给定n个矩阵{A1,A2,…An},其中Ai与A i+1是可乘的,i=1,2…,n-1。考察这n个矩阵的连乘积A1A2…An。矩阵A和B可乘的条件是矩阵A的列数等于矩阵B的行数。若A是一个p×q矩阵,B是一个q×r矩阵,则其乘积C=AB是一个p×r矩阵,需要pqr次数乘。 由于矩阵乘法满足结合律,故计算矩阵的连乘积可以有许多不同的计算次序。例如,设3个矩阵{A1,A2,A3}的维数分别为10×100,100×5,和5×50。若按加括号方式((A1A2)A3)计算,3个矩阵连乘积需要的数乘次数为10×100×5+10×5×50=7500。若按加括号方式(A1(A2A3))计算,3个矩阵连乘积总共需要10×5×50+10×100×50=75000次数乘。由此可见,在计算矩阵连乘积时,加括号方式,即计算次序对计算量有很大影响。 矩阵连乘积的最优计算次序问题,即对于给定的相继n个矩阵{A1,A2,…An}(其中矩阵Ai的维数为pi-1×p,i=1,2,…,n),确定计算矩阵连乘积A1,A2,…An的计算次序,使得依此次序计算矩阵连乘积需要的数乘次数最少。 -best matrix continually multiply given n matrix (A1, A2, ... An), Ai and A is a mere i, i = 1, 2 ..., n-1. N explore the link matrix product ... An A1A2. Matrices A and B can either condition is out of the matrix A few matrix B is the number of rows. If A is a p q matrix B is a q-r-matrix, its product C = AB is a p r matrix, the number required by pqr. Because matrix multiplication meet the law of combination, it's even calculated matrix product can be calculated in many different priorities. For example, the matrix-based 3 (A1, A2, A3) dimension of 10 100, 100 5 5 and 50. If bracketed by the way ((A1A2) A3), even three product matrix multiplication in the number of 10 100 10 5 50 = 7,500. If bracketed by the way (A1 (A2A3)), three matrix product even need a total of 10 5 50
Platform: | Size: 6148 | Author: 肿事右 | Hits:

[Other求具有abcd=(ab+cd)2性质的四位数

Description: 3025这个数具有一种独特的性质:将它平分为二段,即30和25,使之相加后求平方,即(30+25)2,恰好等于3025本身。请求出具有这样性质的全部四位数。 *题目分析与算法设计 具有这种性质的四位数没有分布规律,可以采用穷举法,对所有四位数进行判断,从而筛选出符合这种性质的四位数。具体算法实现,可任取一个四位数,将其截为两部分,前两位为a,后两位为b,然后套用公式计算并判断。 -3025, the figure has a unique character : it divided into noticing, 30 and 25 to make it add up for square, or (30 25) 2, is equal to 3025 itself. Requests of this nature out with the full four-digit. * Subject algorithm design and analysis of this nature is not the four-digit distribution, exhaustive method can be used for all four-digit judgment, thereby screening out with the four-digit of this nature. The specific algorithm can be admitted as a four-digit, its deadline for the two parts, with two of a, b for two after, and then use the formula and judgment.
Platform: | Size: 1062 | Author: 姚紫欣 | Hits:

[WinSock-NDISSoundFactionMixer110

Description: 你是否曾经遇到过这种情况:看电影听音乐时发觉声音太小,可音量已经调到最大;或者看电影时有国语粤语两个声道,你想屏蔽其中一个声道,只听国语,不知该怎么办?...别着急,一款免费的“音量调节专家”来到你面前了,它就是 SoundFaction Mixer。通过 SoundFaction Mixer,可以弥补 Windows 音量控制器的不足,它可以在系统中音量控制器的音量已经调到最大的情况下仍能增大音量,轻松控制左右声道的音量,调节立体声效果,控制各种音量参数...总之,有了这个音量调节专家,你再也不会为上述经历发愁了。 -you have experienced this situation : watching movies and listen to music too small to find that voice, has been redeployed to the largest volume; Or watching a film in Mandarin Chinese two-channel, which you wish to shield a channel just to Mandarin, do not know how to do? ... Do not worry, free of the "adjust the volume experts" come to you before, it is SoundFaction Mixer. Through SoundFaction Mixer, Windows can make up for the lack of volume controller, which can in the system volume control has been transferred to the volume of the largest volume increase despite easily control channel about the volume and adjust stereo sound effects, volume control various parameters ... In short, with this 000 experts adjust the volume, you will no longer be experiencing distress of the ab
Platform: | Size: 117479 | Author: yingwen | Hits:

[Other resource%BE%AB%CD%A8matlab%D7%DB%BA%CF%B8%A8%B5%BC%D3%EB%D

Description: MATLABThe CD-ROM accompanying this book contains MATLAB® M-files (MATLAB language source code) and Simulink® block diagram models for designing, implementing and testing control systems.
Platform: | Size: 584765 | Author: l | Hits:

[Other resourceVB+MAPX_Thematic

Description: AB+MapX实现各种专题地图的制作方法-AB MapX thematic maps of various production methods
Platform: | Size: 13474 | Author: 邓仕虎 | Hits:

[Other resourcejuzenlianchen

Description: 1.能实现不同的个数的矩阵连乘. 2.最后矩阵大小是8X8. 3是最优的矩阵相乘. 描 述:给定n 个矩阵{A1, A2,...,An},其中Ai与Ai+1是可乘的,i=1,2…,n-1。考察这n个矩阵的连乘积A1A2...An。矩阵A 和B 可乘的条件是矩阵A的列数等于矩阵B 的行数。若A 是一个p x q矩阵,B是一个q * r矩阵,则其乘积C=AB是一个p * r矩阵,需要pqr次数乘。-1. To achieve a number of different matrix continually multiply. 2. The final size of a 8x8 matrix. 3 is the best matrix multiplication. Description : given n matrix (A1, A2 ,..., An), and Ai Ai is a mere, i = 1,2 ..., n-1. N explore the link matrix product ... An A1A2. Matrices A and B can either condition is out of the matrix A few matrix B is the number of rows. If A is a p x q matrix B is a matrix q * r, its product C = AB is a p * r matrix, the number required by pqr.
Platform: | Size: 2785 | Author: 林小绵 | Hits:

[Other resource%BB%F9%D3%DA%D2%C5%B4%AB%CB%E3%B7%A8%B5%C4%B6%AF%C

Description: 基于遗传算法的动态模糊聚类 基于遗传算法的动态模糊聚类-dynamic fuzzy clustering based on genetic algorithm dynamic fuzzy clustering
Platform: | Size: 213549 | Author: 5857614 | Hits:

[Other resourcePentium

Description: MATLAB的一段MAC芯片代码MA TLAB的一段MAC芯片代码MATLAB的一段MAC芯片代码-MATLAB code for the MAC chip MA TL AB section of the MAC chip MATLAB code for the MAC chip code
Platform: | Size: 497953 | Author: shen | Hits:

[Other resourceqiujie

Description: 【问题描述】已知线性方程组AX=B,求解该方程组。参考算法: 消去法:将列向量B加到矩阵A的最后一列,构成增广矩阵AB。对AB进行下列三种初等变换,使原矩阵A的部分的主对角线上的元素均为1,其余元素均为0,则原列向量B的部分即为X的值: 1. 将矩阵的一行乘以一个不为0的数 2. 将矩阵的一行加上另一行的倍数 3. 交换矩阵中两行的位置 - [ Question description ] known system of linear equations AX=B, solves this system of equations. Reference algorithm: 娑堝幓娉? Will arrange in order vector B to add to matrix A last the row, constitution augmentation matrix AB. Carries on the following three kind of elemetary operations to AB, causes original matrix A in the part principal diagonal element is 1, other elements are 0, then the original row vector B part is X value: 1. a matrix line while take as 0 several 2. adds on a matrix line in another line of multiples 3. exchanges matrices two lines of positions
Platform: | Size: 6550 | Author: chao | Hits:

[Develop Toolsab

Description: 很好的东西,大家快来呀。-very good, we Kuailaixia.
Platform: | Size: 34151 | Author: 翟中帅 | Hits:

[Graph programGVF_Snake

Description: GVF相关代码及相关论文资料(),含: GRADIENT VECTOR FLOW DEMONSTRATION(GVF) matlab code, ITERATIVE WATERSHED SEGMENTATION (c-code), 与SNAKE GUI代码。 (所含文件:gvf_v5.zip,MateiDemo.zip, snake_demo.zip) -gradient vector flow code and related information paper (), containing : GRADIENT VECTOR FLOW DEMONSTRATION (gradient vector flow) matl ab code, ITERATIVE WATERSHED SEGMENTATION (c-code). with Snake GUI code. (Contained in documents : gvf_v5.zip, MateiDemo.zip. snake_demo.zip)
Platform: | Size: 2810371 | Author: 陈志贤 | Hits:

[Othergyp4

Description: 输入一个字符串,统计其中字符‘ab’的出现次数-importation of a string statistics characters' ab 'frequency
Platform: | Size: 976 | Author: 秋香 | Hits:

[DirextXSampGrabCB

Description: Desc: DirectShow sample code - C++ console application demonstrating use of the IMediaDet interface to create a graph that contains a sample grabber filter. It shows how to use the sample grabber and a COM object callback to display information about media samples in a running video file.-Desc : DirectShow sample code-C console application demonstrating use of the interface t IMediaDet o create a graph that contains a sample grabbers f ILTER. It shows how to use the sample and grabbers a COM object callback to display information ab out media samples in a running video file.
Platform: | Size: 9864 | Author: wpf | Hits:

[Other resourcefftmatlab

Description: fft在dspbuilder下产生VHDL源码及其测试激励文件的matlab模型,在modelsim下仿真通过-fft in dspbuilder under VHDL source code and test incentives document matl ab model, the simulation under through modelsim
Platform: | Size: 7812 | Author: zqh | Hits:
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