XOR is an operator for binary numbers which applies an non-carry addition two numbers digit by digit. For example, 1010 XOR 0110 = 1100. Now we extend XOR into m-based numbers. For example, for 5-based number, 40302 XOR 44312 = 34114. That is, for two m-based digit x and y, x XOR y = (x+ y) m. Given two m-based numbers with n digits, you can rearrange the number by swapping any two digits in this number. After rearranging two numbers, you XOR two numbers and get a new number. For example, You can rearrange 40302 into 20034 and rearrange 44312 into 24431, then you get 20034 XOR 24431 = 44410. Please find the maximum possible number that can be obtained in the previous step.

XOR.cpp

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