Search - z-stack

[Other Games] hm4

Description: 数字翻译问题设有输入3个数组: String x[]={ "one",“two", "three",four", "five","six",seven","eight","nine"} String y[]={ten","eleven","twelve","thirteen","fourteen","fifteen", "sixteen","seventeen","eighteen","nineteen" } String z[]={"twenty","thirty","fourty","fifty", "sixty","seventy", "eighty","ninety" } 输入一个大于0，小于100的整数，将整数翻成英文。例如：输入32，输出：thirty two 输入14，输出：fourteen 输入8，输出：eight 反之: 输入一个英文表示,输出相应的整数.(提高部分)-figures translation problems with the importation of three arrays : String x [] = ( "one", "two" and "three", four "," five "," six ", seven", "eight", "nine" String y) [] = (ten "," eleven ", "twelve", "thirteen", "fourteen", "fifteen" "sixteen", "seventeen", "eighteen" "nineteen") z []={" twenty String "," thirty " "four", "fifty", "sixty", "seventy" "eighty", "ninety") importation of a greater than 0 and less than 100, rounded up, Integer will be translated into English. for example : 32 input and output : thirty two input 14 output : f
Platform: | Size: 1024 | Author: 黄铭 | Hits:

[source in ebook] FindBase

Description: 同一个数会由于采用不同的基数而使得其表现的形式是完全不一样的，在我们的学习中，我们熟悉的基数有10进制、12进制、60进制、2进制、8进制和16进制。比如数据12，如果我们用2进制表示，则它就是1100；如果用3进制表示就是110；如果用8进制表示则是14。我们的编程任务就是与数的进制（也就是基数）有关。程序中我们会给大家很多个数对（假设每个数对的数用X和Y表示），程序需要解决的问题就是为X和Y各选择一个最小的基数，以使得这两个数在其选择的基数上是一对相等的数。例如，12和5这个数对，我们可以为12选择基数3，为5选择基数6，这样一来12（base 3）=5（base 6），因为12（base 3）就是10进制数5，而5（base 6）也是10进制数中的5。程序的输入是通过文件完成的。文件中的每一行都包含一个数对X和Y,两个数通过一个或多个空格符分割，与X和Y相关联的有效基数值范围为2~36。X和Y的合理数值表示字符包括0—9和A-Z（表示数值10-35）。文件的最后一行用一个数字0表示输入的结束。-same number will be different because of the base and make its performance in the form of a completely different, In our study, we are familiar with the base 229 10, 229 12, 229 60, 229 2. 8-band 16-band. For example, 12 data, if we use the two-band said, it is 1100; If three-band said is 110; If eight 229 said it is 14. Our task is programming with a number of 229 (or base). We will process all of the many numbers (on the assumption that each number on the number of X-and Y said), procedures need to address the issue of the X and Y choose a minimum base, This makes two to a few in their chosen base is the equivalent of a few. For example, 12 and 5, the figure right, we will be able to choose 12 base 3 to 6 base 5 choice, This one to 12 (base 3) = 5 (base 6), because 12 (base 3) 229 10
Platform: | Size: 189440 | Author: duyankang | Hits:

[Other] fs

Description: 试写一算法，如果三个整数x,y,z的值是依次非递增的，侧通过交换令其为非递增。要求实现下列函数： void Descend(int &x, int &y, int &z) /* 按从大到小顺序返回x，y和z的值 */-Try to write a algorithm, if the three integers x, y, z values are followed by non-incremental, side by exchanging them for non-incremental. Requirements to achieve the following function: void Descend (int
Platform: | Size: 1024 | Author: ln | Hits:

[Data structs] huffman

Description: 实现最优二叉树的构造；在此基础上完成哈夫曼编码器与译码器。假设报文中只会出现如下表所示的字符：字符 A B C D E F G H I J K L M N 频度 186 64 13 22 32 103 21 15 47 57 1 5 32 20 57 字符 O P Q R S T U V W X Y Z ，．频度 63 15 1 48 51 80 23 8 18 1 16 1 6 2 要求完成的系统应具备如下的功能： 1．初始化。从终端（文件）读入字符集的数据信息，。建立哈夫曼树。 2．编码：利用已建好的哈夫曼树对明文文件进行编码，并存入目标文件（哈夫曼码文件）。 3．译码：利用已建好的哈夫曼树对目标文件（哈夫曼码文件）进行编码，并存入指定的明文文件。 4．输出哈夫曼编码文件：输出每一个字符的哈夫曼编码。
Platform: | Size: 132096 | Author: 张娟 | Hits:

[Driver Develop] switching_power_supplies_A_to_Z

Description: switching power supplies A to Z
Platform: | Size: 4662272 | Author: jackylai88 | Hits:

[Communication-Mobile] Z-Stack6

Description: ZigBee学习的基础知识和一些基本操作，基本概念，属于是傻瓜教程-ZigBee learning basic knowledge and some basic operations, the basic concept, which is a fool Tutorial
Platform: | Size: 999424 | Author: liuhongjie | Hits:

[Other] Z-Blog_1_8_Arwen_81206_install

Description: RSS阅读器源代码,务必于门，购20个了没有啊-wo bud dong ying，ni jiao wo ruhe shi hao
Platform: | Size: 805888 | Author: tianya | Hits:

[matlab] MatLab

Description: MatLab工程数学应用积分，微分，导数，传递函数，拉式变换，Z-变换-matlab
Platform: | Size: 7242752 | Author: nightsnow | Hits:

[Other Embeded program] swrc126

Description: ZigBee Stack 2.2.0-1.3.0 for CC2530，支援版本为ZigBee-2007(ZigBee and ZigBee PRO)-ZigBee Stack 2.2.0-1.3.0 for CC2530, supported version of ZigBee-2007 (ZigBee and ZigBee PRO)
Platform: | Size: 58021888 | Author: FTP | Hits:

[Other Embeded program] z-stack

Description: zigbee协议通过CC2430来实现，对学习CC2430的同志有很大帮助-zigbee protocol to achieve through the CC2430, CC2430 comrades learning helps a lot
Platform: | Size: 22528 | Author: leo | Hits:

[Communication-Mobile] Z-Stack

Description: Zigbee是部署无线传感器网络的新技术。它是一种短距离、低速率无线网络技术，是一种介于无线标记技术。本压缩包里是ZigBee软件堆栈编程源代码很详细的-Zigbee is a wireless sensor network deployment of new technologies. It is a short-range, low-rate wireless network technology, is a range of wireless tag technology. The compression bag is the ZigBee software stack, programming source code is very detailed. . .
Platform: | Size: 1678336 | Author: Frank | Hits:

[Other] Z-Stack_Developer_Guide_F8W-2006-0022

Description: Z-stack 1.4.1 developer s guide for chipcon CC2430.
Platform: | Size: 174080 | Author: Jacky | Hits:

[Software Engineering] Z_Stack-1.4.2-NWK

Description: 这是TI官方提供的关于ZigBee协议栈中的NWK层的代码分析，正在学习ZigBee的朋友可以好好看看，很有用的！-This is the official information provided on the TI ZigBee NWK layer protocol stack code in the analysis of ZigBee' s friends are learning to be a good look, very useful!
Platform: | Size: 21155840 | Author: 王维华 | Hits:

[SCM] ZStack-CC2530-2.2.0-1.3.0

Description: z-stack2007协议栈，project文件夹中包括演示程序。-z-stack2007 protocol stack, project folder, including a demonstration program .
Platform: | Size: 64701440 | Author: guozhitao | Hits:

[Communication] bacnet-stack-0.5.9

Description: BACnet 最新版本的Free Stack，对原有协议进行了较大的修正，目前为0.5.9版本 BACnet协议是楼宇自动化唯一的国际协议，已经得到欧盟和美国、日韩的国家标准认可-BACnet Static Version 0.5.9 based on ASHARE Standard version 2008 the new latest version Building Automation Protocol
Platform: | Size: 1774592 | Author: 兰心 | Hits:

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