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Description: 集按键消抖，不影响cpu时序，c程序，单键，复合键，点触，长按连续加或减（switch case 语句）-Set button debounce, does not affect the cpu timing, c program, a single bond, composite key, tap, press and continuous plus or minus
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Size: 1024 |
Author: |
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Description: C#实现的日内突破交易策略，可在Wealth-lab及其他C#策略平台下应用。-First hour breakout system
The system takes positions if the price exceeds the range determined in the first hour of the day, using a moving average as a filter.
Entry rules
Buy at breakout of first hour s high plus one tick, if 9-period moving average is rising
Short at breakdown of first hour s low minus one tick, if 9-period moving average is declining
Take one position only during a trading session
Exit rules
Exit at a 0.5 stop loss
Exit at a 1.0 profit target
Exit at market at last bar of the day (16:00)
Requires intraday data
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Size: 2048 |
Author: kong xiangwen |
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Description: 430单片机串行输出，按键加减控制12864LCD灯，C程序，IAR-430 the microcontroller serial output, control of plus or minus keys 12864LCD lights, C program, IAR
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Size: 2048 |
Author: xt |
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Description: 本源程序提高一个C++的向量加减乘运算模板以及矩阵的加减运算模板。-c++ vector matric plus minus
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Size: 1024 |
Author: 何振为 |
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Description: 运用C++语言判断文件中字符串中是否含有某个特定符号，并根据不同符号输出正负1.-Use the string C++ language to determine the file if it contains a specific symbol, and in accordance with the different symbols output plus or minus 1.
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Size: 1024 |
Author: Gangjie.Liao |
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Description: 基本的C#数字运算示例，执行两个数的加法、减法运算，返回相加、相减后的结果，实例化类对象，定义一个死循环，以便循环输入数据，记录运算符号，以运算符号为条件进行判断，判断是否为加号，判断是否为减号，不符合上面所有情况，实现基本的加法、减法运算。-Basic C# number crunching example, the addition of two numbers, subtraction, return the sum, the result of the subtraction, the instantiated class object, define a cycle of death, for recycling the input data record Operators Operators conditions to judge, to determine whether the plus sign to determine whether the minus sign, does not meet all of the above, the basic addition, subtraction.
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Size: 5120 |
Author: 程松发 |
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Description: 基本的C#数字运算代码，执行两个数的加法、减法运算，返回相加、相减后的结果，实例化类对象，定义一个死循环，以便循环输入数据，记录运算符号，以运算符号为条件进行判断，判断是否为加号，判断是否为减号，不符合上面所有情况，实现基本的加法、减法运算。-Basic number crunching code in C#, the implementation of the addition of two numbers, subtraction, return the sum, the result of the subtraction, the instantiated class object, define a cycle of death, for recycling the input data record Operators Operators conditions to judge, to determine whether the plus sign to determine whether the minus sign, does not meet all of the above, the basic addition, subtraction.
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Size: 6144 |
Author: 武宗 |
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Description: 表达式求值
原理是比较简单的
假设表达式是正确的，不再进行表达式检查。
表达式就是一个字符串了，在字符串中从头开始找乘号或除号，假设符号为B找到的话就找这个符号前面和后面的运算数字A和C，然后把结果ABC运算出来，替换原表达式中的ABC字串，组成新的字符串。
对新的字符串进行上述操作，一直到没有乘号或者除号为止。
然后继续寻找加号和减号，不过这个就没必要一次次的找了，把字符串遍历一遍运算完毕即可。-Expression evaluation principle is relatively simple expressions assumption is correct, no further expression checks. Expression is a string, and the string to start from scratch to find multiplication or division sign, assuming the symbol for the B find the words to find this symbol in front of and behind the arithmetic figures A and C, and the results came out ABC operation, replace the original ABC expression string to form a new string. For new string above operations until no multiplication or division sign up. Then continue to look for the plus and minus, but this is not necessary again and again to find, iterate over the string operation is completed can be.
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Size: 17408 |
Author: 周鑫恺 |
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Description: 基本的C#数字运算示例，执行两个数的加法、减法运算，返回相加、相减后的结果，实例化类对象，定义一个死循环，以便循环输入数据，记录运算符号，以运算符号为条件进行判断，判断是否为加号，判断是否为减号，不符合上面所有情况，实现基本的加法、减法运算。-The basic number crunching C# example, perform the addition of two numbers, subtraction, back together, after subtracting the result of instantiating the class object that defines an infinite loop to loop the input data, records arithmetic symbols to arithmetic symbols conditions to judge, to determine whether the plus sign to determine whether the minus sign, does not meet all of the above cases, the basic addition and subtraction.
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Size: 5120 |
Author: zengzheng |
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Description: 1、 设计一个时间类MyDate：（日期均大于1900年）
a、 其中包括年、月、日、时、分、秒。其他成员变量可根据需要增设；
b、 可以获得时间的年、月、日、小时、分钟、秒数；
c、 计算日期的dayOfWeek（星期几）；
d、 //实现日期加减一个整数后得到新的日期（加减天数）；
e、 输入任意一个月份，将此月的日历输出（按星期格式）；
f、 输入任意年份，将此年的年历输出；
g、 实现两个时间相减得到的小时数、分钟数和秒数；
h、 输出时间，要求三种格式： yyyy年MM月dd日hh小时mm分ss秒；
yyyy-MM-dd hh:mm:ss
yyyyMMddhhmmss
i、 设计三个个构造方法。1、参数只有年月日的构造方法，小时分钟秒设为0；2、完全参数的构造方法；3、如果使用无参数的构造方法则初始化为系统时间，-1, the design of a time class MyDate: (date greater than 1900) a, including the year, month, day, hour, minute, second. Other members of the variables can be added according to need b, can get the time of year, month, day, hour, minute, seconds c, calculate dates dayOfWeek (week) d,// subtract an integer realization obtained after the date of new date (plus or minus the number of days) e, enter any one month, this month' s calendar output (by week format) f, enter any year, this year calendar output g, subtracting two times to achieve the number of hours, minutes, and seconds h, output time, requiring three formats: yyyy Year MM-dd hh hours mm minutes ss day second yyyy-MM-dd hh: mm: ss yyyyMMddhhmmss i, design three months constructor. 1, parameter constructor only date, hour minute second set to 0 2, completely argument constructor 3, if no argument constructor initializes to the system time,
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Size: 14336 |
Author: 谭 |
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Description: 矩阵（二）
编写C++程序完成以下功能：
（1）假定矩阵大小为4×5（整型）；
（2）矩阵空间采用new动态申请，保存在指针中；
（3）定义矩阵初始化函数，可以从cin中输入矩阵元素；
（4）定义矩阵输出函数，将矩阵格式化输出到cout；
（5）定义矩阵相加的函数，实现两个矩阵相加的功能,结果保存在另一个矩阵中；
（6）定义矩阵相减的函数，实现两个矩阵相减的功能,结果保存在另一个矩阵中；
（7）动态申请三个矩阵：A1、A2、A3；
（8）初始化A1、A2；
（9）计算并输出A3 = A1加A2，A3 = A1减A2；
（10）释放矩阵空间。-Matrix (two) write C++ program performs the following functions: (1) assuming matrix size of 45 (integer) (2) matrix spaces using new dynamic applications, stored in the pointer (3) define the matrix initialization function, you can Enter the matrix elements from cin (4) defines the output function matrix, the matrix format the output to cout (5) defines a function of matrix addition, to achieve the function of two matrices and stores the result in another matrix (6) Define the matrix subtraction function, the realization of the function of two matrices subtraction result is stored in another matrix (7) for the three matrices Dynamic: A1, A2, A3 (8) initialization A1, A2 (9) calculate and output A3 = A1 plus A2, A3 = A1 minus A2 (10) release matrix space.
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Size: 1024 |
Author: 熊炜伟 |
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Description: DEV-C++环境下编译，减治法求a的n次方，动态规划最短路-Under DEV-C++ compiler environment, minus a treatment method for the n-th power, dynamic programming shortest
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Size: 1024 |
Author: 皮阳 |
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Description:
编译环境:Microsoft Visual C++ 6.0
说明:
采用树形结构处理表达式,按优先级运算结果,一个加,减,乘,除或数值为一个节点-Compile environment: Microsoft Visual c++ 6.0
Description:
Expression of tree structure processing, according to the priority operations as a result, a plus, minus, multiply, in addition to or values for a node
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Size: 13312 |
Author: zjr |
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Description: 用C语言实现在1 2 3 4 5 6 7 8 9 = 110之间插入加号或者减号使等式成立。他们之间如果不插入符号，那么符号之间的数字合并成一个数字。-Implemented in C language in 1 2 3 4 5 6 7 8 9 inserted between = 110 plus or minus sign, the expression was established. Between them if the number is not the caret is digital merged into a number.
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Size: 1024 |
Author: lvqunwu |
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Description: 设计一个运动计分器，技术指标如下：
①“计分器”LED数码管显示位为两位；
②“计分器”的十进数位仅为两位数，即十位数、个位数；
③“计分器”应具有“复位”或“置数”控制功能；
④“计分器”应具有“加1”和“减1”的累计运算功能；
⑤“键控”应有“运算选择”（A），“计数（加1或减1）”（B）和复位或清零（C）三个按键开关。
根据要求，我要设计一个两位数的运动计分器，要使它具有置零和置数功能，当我们给一个时钟信号的时候，我们可以给它加一或者减一，我们分别用三个开关来控制运算选择，计数和清零，将其合理安装便可完成指标。
-Designing a Sports scoring device, the technical indicators are as follows: ① " Scorers" LED digital display bit is two ② " scoring" on the two-digit decimal digital only, namely the tens digit ③ " Scorers" should have " reset" or " set the number of" control functions ④ " Scorers" should have " plus 1" and " minus one" cumulative computing capabilities ⑤ " keyed" should " operation selection " (A)," count (plus one or minus 1) " (B) and reset or cleared (C) three key switch. Upon request, I want to design a double-digit scoring device movement, it has to be set to zero and the number of features, when we give a clock signal, we can give it a plus or minus one, we were using three a switch to control the operation selection, counting and cleared it reasonable to complete the installation targets.
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Size: 203776 |
Author: 影子 |
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Description: 用C++和C实现加减乘除算法，此算法简洁实用，初学者很适合学习它，希望对你有帮助。-realize the algorithm of puls,minus,multiply,divide by C++ .
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Size: 2048 |
Author: 赵明 |
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Description: 方差计算器软件以及C++源代码，源码添加了注释，自认为已经很详细，但是有关于数据结构的部分我可以算没有添加任何注释了，因为数据结构这个东西我不认为添加一点注释是能够理解的。
用VC6编写，Win32 Application程序，源码均由个人完成。实现大致思路：
定义一个字符串，用于存储输入的数据，提取第一个字符到 mbi，如果其中有一个字符不是为数字、小数点、负号，将终止循环，那么mbi的值将不会是 \0 ，如果负号出现在除位置1以前的其它位置，或者小数点的个数已经超过1，那么将终止循环，如果这是一个小数点，那么将0赋值给num，可以防止在用户输入小数点后没有输入数据但检测不到错误的情况，重新给mbi赋值 如果此时已经是next字符串的最后一个字符，那么赋值之后mbi的值便是 \0 -Variance calculator software and C++ source code, source code to add a note, since that is already very detailed, but there on the part of the data structure that I can count did not add any comments, because the data structure of this thing, I do not think that adding a little note to be able to understand the.
Written by VC6, Win32 Application procedures source completed by the individual. Achieve general idea:
Define a string input for data storage, extract the first character to mbi, if there was a character not as a number, decimal point, minus sign, will terminate the loop, then the value will not be mbi \ 0 If a negative number in addition to a previous position elsewhere, or decimal number has more than one, then the cycle will be terminated if it is a decimal point, then 0 is assigned to num, can prevent the user input is not entered after the decimal point data but does not detect the error, re-assignment to mbi next if this time is the last character of the string, the
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Size: 15360 |
Author: kpudn72 |
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Description: 简单的一个C语言编程，输出一个矩阵，每行数减一个。-A simple C language programming, the output of a matrix, each row number minus one.
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Size: 81920 |
Author: 灰鸽 |
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Description: c语言，对一数组排列进行循环，每循环一次减一个数，剩下最后一个数-c language, arranged in an array on a cycle, each cycle minus a few, leaving the last few
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Size: 11264 |
Author: autumn |
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Description: 摘要:VC/C++源码,图形处理,三维动画,OpenGL,皇冠代理最新网址
VC++ OpenGL通过动态调整观察点位置实现三维动画，观看演示效果时，请使用上、下、左、右键和加减键可调整视角、调整观察位置，还不错吧。-
Abstract: VC/C++ source code, graphics, 3D animation, OpenGL, Crown Agents latest website
VC++ OpenGL achieve three-dimensional animation by dynamically adjusting the position of the observation point, when you watch the demo results, use the up, down, left, right, and plus or minus buttons to adjust the viewing angle, adjust the viewing position, but also pretty good.
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Size: 19456 |
Author: 黄威霖 |
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