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[File Format] C语言难点分析整理 DL : 0: 这篇文章主要是介绍一些在复习C语言的过程中笔者个人认为比较重点的地方，较好的掌握这些重点会使对C的运用更加得心应手。此外会包括一些细节、易错的地方。涉及的主要内容包括：变量的作用域和存储类别、函数、数组、字符串、指针、文件、链表等。一些最基本的概念在此就不多作解释了，仅希望能有只言片语给同是C语言初学者的学习和上机过程提供一点点的帮助。 -this article is to introduce some major review of the C language in the process I personally think that a more focused, a better grasp of these focus on C will be used more handy. In addition will include some of the details, error-prone areas. The main contents include : Scope of Variables and storage types, functions, arrays, string, target, document, etc. List. Some of the most basic concepts in this no more explanation. only hope to be able to pieces with the C language learners and the learning process on the plane for a little bit of help.
Date : 2025-12-19 Size : 6kb User : 赵东生
[File Format] gauss-C DL : 0: * 高斯列主元素消去法求解矩阵方程AX=B,其中A是N*N的矩阵,B是N*M矩阵 * 输入: n----方阵A的行数 * a----矩阵A * m----矩阵B的列数 * b----矩阵B * 输出: det----矩阵A的行列式值 * a----A消元后的上三角矩阵 * b----矩阵方程的解X -out the main elements of Gaussian elimination method for solving matrix equations AX = B, where A is N* N matrix, B is N* M matrix* Input : n---- A phalanx of a few-a matrix* A* m-matrix shown in a few B* b---- Matrix B* output : det-A matrix of a determinant value---- A* Elimination of upper triangular matrix* b---- Matrix The X-Solutions
Date : 2025-12-19 Size : 3kb User : xuyan
[File Format] c++xitong DL : 0: 设计一个c++的程序，具体要求 1、公司主要有4类人员：经理、技术员、销售员、销售经理。要求存储这些人的职工号、姓名、月工资、岗位、年龄、性别等信息。 -design a process, a specific request, the company has four main categories : managers, technicians, sales, Sales Manager. These storage requirements of the workers, names, on wages, jobs, age, gender and other information.
Date : 2025-12-19 Size : 4kb User : 张的陪
[File Format] 111111 DL : 0: Visual C++编程技巧之 1.如何获取应用程序的实例句柄? 2.如何通过代码获得应用程序主窗口的指针? 3.如何在程序中获得其他程序的图标? 4.如何编程结束应用程序?如何编程控制windows的重新引导? 5.怎样加栽其他的应用程序? 6.确定应用程序的路径 7.获得各种目录信息 8.如何自定义消息 -Visual C programming skills one. Application procedures for obtaining handle two examples. How the code was in the main application window to the three pointer. how the proceedings were other procedures icon 4. How to end application programming how to control windows programming guide the re-5. how to increase the planting of other applications 6. Application procedures for determining the Route 7. access to directory information 8. how to customize the news
Date : 2025-12-19 Size : 55kb User : qiaobo
[File Format] 1 DL : 0: 本程序是基于C++ builder平台编的，其主要功能为文本编辑器-This procedure is based on the C++ Builder platform series, and its main function as a text editor
Date : 2025-12-19 Size : 293kb User : shen
[File Format] CFILE DL : 0: 主要介绍c++中文件得各种打开方法，以及各种对文件得操作方法-Main Introduction c++ In a variety of open documents, as well as a variety of methods of operation of the document
Date : 2025-12-19 Size : 5kb User : 杨亿万
[File Format] jiaoXueJinDu DL : 0: 这是我所在的学院上《算法设计与分析》这门课的实验教学进度。主要参考书： 1．王晓东.算法设计与分析.清华大学出版社，2003年. 2．严蔚敏,吴伟民.数据结构（C语言版）.清华大学出版社，2002年. 3．谭浩强.C语言程序设计教程（第二版）.高等教育出版社，1998年. 希望对学习算法的同学有所帮助。-This is my college where the Algorithm Design and Analysis of the course of the experiment the progress of teaching. The main reference books: 1. Wang Xiaodong. Algorithm design and analysis. Tsinghua University Press, 2003 .2. Yan Wei-min,吴伟民. Data structure (C language version). Tsinghua University Press, 2002 .3. Hao strong. C Programming Language Guide (Second Edition). Higher Education Press, 1998. Wishes to the students learning algorithm help.
Date : 2025-12-19 Size : 6kb User : Katherine
[File Format] doc DL : 0: 1. Download the version you want: * Version 1.3.4 (30 Aug 2007) -- this is the latest version for UNIX/Linux and Windows * Previous versions 2. Unzip the file, which will create a directory called klt and place all the files there 3. Compile and run the code * On UNIX / Linux, move to the klt directory, type make. Now try some examples, by typing example1, etc. * For Microsoft Visual C++ 6.0, open the klt.dsw file, compile, and run. Change the constant in main.cpp to run the different examples. * For Microsoft Visual Studio .Net/7/8, open the klt.sln file, compile, and run. Change the constant in main.cpp to run the different examples. 4. Notice that, for your convenience, unofficial copies of the User and Reference Manuals can be found in the doc directory. - 1. Download the version you want: * Version 1.3.4 (30 Aug 2007) -- this is the latest version for UNIX/Linux and Windows * Previous versions 2. Unzip the file, which will create a directory called klt and place all the files there 3. Compile and run the code * On UNIX/Linux, move to the klt directory, type make. Now try some examples, by typing example1, etc. * For Microsoft Visual C++ 6.0, open the klt.dsw file, compile, and run. Change the constant in main.cpp to run the different examples. * For Microsoft Visual Studio .Net/7/8, open the klt.sln file, compile, and run. Change the constant in main.cpp to run the different examples. 4. Notice that, for your convenience, unofficial copies of the User and Reference Manuals can be found in the doc directory.
Date : 2025-12-19 Size : 43kb User : Alex
[File Format] em78 DL : 0: 义隆单片机em78系列全教程，主要为义隆单片机开发者参考使用。-Elan em78 Series single-chip full-course, the main developer for the Elan single-chip reference.
Date : 2025-12-19 Size : 752kb User : 罗春成
[File Format] ELF_Format DL : 0: ELF (Executable and Linkable Format) file format. This document is intended for developers who are creating object or executable files on various 32-bit environment operating systems. It is divided into the following three parts: Part 1, "Object Files" describes the ELF object file format for the three main types of object files. Part 2, "Program Loading and Dynamic Linking" describes the object file information and system actions that create running programs. Part 3, "C Library" lists the symbols contained in libsys, the standard ANSI C and libc routines, and the global data symbols required by the libc routines.
Date : 2025-12-19 Size : 117kb User : ZorroAlko
[File Format] Apriori DL : 0: 本算法的基本功能是用C＋＋语言实现了APRIORI算法，用户可以先选择要进行的操作。然后再输入支持度和置信度，就可得到挖掘的结果。输出的结果主要包括两个部分。 1．输出所有的频繁项集。 2．输出所有的产生的规则。算法还能够输出初始的事务集合，并且可以输出产生的中间结果。-the algorithm is the basic functions using C++ language of APRIORI algorithm, Users may choose to conduct the operation. Then import support and confidence, could be the result of excavation. Output of the two main parts. 1. Output of all frequent sets. 2. Output of all the rules. Algorithm can also output the affairs of the initial pool, and can output of intermediate results.
Date : 2025-12-19 Size : 2kb User : 沈振
[File Format] list.c DL : 0: C++ #include <fstream>y using std::ifstream int main() { char line[81] char fname[81] cout << "Enter file name: " cin >> fname -c plus
Date : 2025-12-19 Size : 2kb User : yuanyi
[File Format] c-sj-qw DL : 0: 拓展部分的代码 #include "graphics.h" int main() { int gdriver, gmode gdriver=VGA -To expand part of the code# include " graphics.h int main () {int gdriver gmode gdriver = VGA
Date : 2025-12-19 Size : 349kb User : miao
[File Format] compile-analyse DL : 0: 编译原理词法分析器，主要用的是C#语言实现完成-Compilation principle morphology analyzer, the main use is to realize complete c#
Date : 2025-12-19 Size : 68kb User : june
[File Format] C-P-P-programming-under-LINUX DL : 0: 面向对象程序的基本元素是对象,面向对象程序的主要结构特点是:第一,程序一般由类的定义和类的使用两部分组成,在主程序中定义各对象并规定它们之间传递消息的规律.第二,程序中的一切操作都是通过向对象发送消息来实现的,对象接收到消息后,启动有关方法完成相应的操作-Object-oriented programming is the basic element of object, main structure characteristics of object-oriented programming is: first, the process by the use of the class definition and class of two parts, each object defined in the main program and the law of passing messages between them. Second, the application of all operations are done by sending messages to objects, object to receive news, start the relevant method to complete the corresponding operation
Date : 2025-12-19 Size : 407kb User : 小皮哥
[File Format] A-simple-procedure DL : 0: #include<stdio.h> int main() { printf(“this is a c program.\n”) return 0 }-A simple procedure
Date : 2025-12-19 Size : 2kb User : lunhua
[File Format] BNUTBDJNBOOFR DL : 0: 【程序29】题目：给一个不多于5位的正整数，要求：一、求它是几位数，二、逆序打印出各位数字。 1. 程序分析：学会分解出每一位数，如下解释：(这里是一种简单的算法，师专数002班赵鑫提供) 2.程序源代码：复制代码代码如下: #include stdio.h #include conio.h main( ) { long a,b,c,d,e,x scanf( ld ,&x) a=x/10000 分解出万位 b=x 10000/1000 分解出千位 c=x 1000/100 分解出百位 d=x 100/10 分解出十位 e=x 10 分解出个位 if (a!=0) printf( there are 5, ld ld ld ld ld\n ,e,d,c,b,a) else if (b!=0) printf( there are 4, ld ld ld ld\n ,e,d,c,b) else if (c!=0) printf( there are 3, ld ld ld\n ,e,d,c) else if (d!=0) printf( there are 2, ld ld\n ,e,d) else if (e!=0) printf( there are 1, ld\n ,e) getch() } -Topic: no more than five to one positive integer requirements: First, find it is several orders, two, reverse print out the digits. 1. Program analysis: the decomposition of each digit Society 2. Source Code: Code is as follows: #include stdio.h #include conio.h main () { long a, b, c, d, e, x scanf ( ld , & x) a = x/10000 break out ten thousand* / b = x 10000/1000 break out one thousand* / c = x 1000/100 break out one hundred* / d = x 100/10 break out ten* / e = x 10 break out bits* / if (! a = 0) printf ( there are 5, ld ld ld ld ld \ n , e, d, c, b, a) else if (! b = 0) printf ( there are 4, ld ld ld ld \ n , e, d, c, b) else if (! c = 0) printf ( there are 3, ld ld ld \ n , e, d, c) else if (! d = 0) printf ( there are 2, ld ld \ n , e, d)
Date : 2025-12-19 Size : 3kb User : 张欣欣
[File Format] main DL : 0: 样本库标注c++代码，可以根据使用环境进行适当修改-Sample library marked c++ code, you can make appropriate changes based on the environment
Date : 2025-12-19 Size : 1kb User : 洛克
[File Format] 1-s2.0-S0038092X1300193X-main DL : 0: C UN FILE INSCRIPTION QUI EST RELATIVE A CETTE METHOSE DE BADE
Date : 2025-12-19 Size : 1.22mb User : benaissa
[File Format] About-C-void-main-() DL : 0: 关于c语言的void main()，或许有人对此有争议，专为新人解惑-About c void main (), maybe someone is controversial, designed for the couple to reassure
Date : 2025-12-19 Size : 3kb User : 活死人