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[Other] 6-7 DL : 0: 统计学生成绩。设有十个学生的成分别是：（自己设定）。统计一下60~69分，70~79分，80~89分，90~99分和100分的人数并存放在s6,s7,s8,s9,s10单元中。（通过对子程序的调用实现）-student achievement statistics. With 10% of the students were : (self-imposed). Statistics about 60 to 69 points, 70 to 79 points, 80 to 89, 90 to 99 points and 100 points on both the number of M16, s670, S8, s9, s 10 modules. (Through subroutine calls realization)
Date : 2008-10-13 Size : 947byte User : 思达
[Other] “C语言接口”扩展程序调用接口规范 DL : 0: 分析家扩展函数规范V3.10 1.本规范适用于分析家3.10标准版和专业版公式系统. 2.扩展函数用于实现系统函数不能实现的特殊算法. 3.扩展函数用windows 32位动态连接库实现,建议使用Microsoft Visual C++编程. 4.调用时在公式编辑器中写\"动态库名称@函数名称\"(参数表)即可,例如下面函数可以写为\"FXJFUNC@MYCMALOSE\"(5) 5.动态连接库名称和函数名称可以自己定义. 6.使用时可以将动态库拷贝到分析家目录下使用.-V3.10 a standardized function. This instruction applies to analysts 3.10 standard and professional versions formula system. 2. Spread Function Function system for achieving the impossible special algorithm. 3. PSF with windows 32 DLL realized, production proposed use Microsoft Visual C programming. 4. called to the formula editor wrote "@ name DLL function name" (Table parameters) can be, for example, the following function can be written as "FXJFUNC @ MYCMALOSE" (5) 5. DLL name and function name can be its own definition. 6. using DLL can be copied to the directory analysts use.
Date : 2008-10-13 Size : 6.02kb User : 周有本
[Other] 行情接口规范V2[1].1（支持深圳库4位升6位） DL : 0: 分析家证券投资分析系统行情接口规范V2.1 (适用于单向数据传输方式)-analysts Securities Investment Analysis System Interface Specification V2.1 rates (applicable to one-way data transmission)
Date : 2008-10-13 Size : 4.29kb User : 周有本
[Other] 254 DL : 0: 题目：计算打鱼还是晒网题目：企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10%；利润高　　　于10万元，低于20万元时，低于10万元的部分按10%提成，高于10万元的部分，可可提　　　成7.5%；20万到40万之间时，高于20万元的部分，可提成5%；40万到60万之间时高于　　　40万元的部分，可提成3%；60万到100万之间时，高于60万元的部分，可提成1.5%，高于　　　100万元时，超过100万元的部分按1%提成，从键盘输入当月利润I，求应发放奖金总数？ 1.程序分析：请利用数轴来分界，定位。注意定义时需把奖金定义成长整型。　　 -topics : computing net fishery or drying topics : corporate bonus payments made to generate profit. Profit (I) less than or equal to 10 million, the prize money to be raised by 10%; The profit of more than 10 million, less than 20 million, less than 10 million by some 10%, which hovered above 10 million, cocoa generate 7.5%; 200,000-400,000 it among when more than 20 million, could generate 5%; 400,000 to 600,000 between when more than 40 million, can generate 3%; 6-1000000 between, above 60 million, could generate 1.5%, higher than 100 million, more than some 1 million by 1% will generate from the keyboard month profit I, for the total prize money should be paid? 1. Program Analysis : Please use axes to boundaries, location. Attention definition, must the growth of cosmetic bonuses defini
Date : 2008-10-13 Size : 799byte User : 刘天聪
[Other] Turboc1 DL : 0: 可供初学Turbo c的人使用，其中的6个文件是独立的，它们给出了显示汉字的各种方法。-Turbo c for the beginners to use, the six documents are independent, they are given a Chinese character display the various methods.
Date : 2008-10-13 Size : 41.85kb User : zchill0011
[Other] 案例6数据加密程序 DL : 0: 这是一个对数据进行加密的程序。一些初学者可能会用的到。 -this is a data encryption procedures. Some beginners might be used to.
Date : 2008-10-13 Size : 1.51kb User : 任曈
[Other] 1~9组成三个3位的平方数 DL : 0: 将1、2、3、4、5、6、7、8、9九个数字分成三组，每个数字只能用一次，即每组三个数不允许有重复数字，也不许同其它组的三个数字重复，要求每组中的三位数都组成一个平方数。-1,2,3,4,5,6,7,8,9 nine figures will be split into three groups, each number can only be used once, the number three in each group is allowed to repeat the figures and not allowed with other groups to repeat the three figures, each of the requests are triple-digit the formation of a square.
Date : 2008-10-13 Size : 1.63kb User : 姚紫欣
[Other] 魔术师的猜牌术(2) DL : 0: 魔术师再次表演，他将红桃和黑桃全部迭在一起，牌面朝下放在手中，对观众说：最上面一张是黑桃A，翻开后放在桌上。以后，从上至下每数两张全依次放在最底下，第三张给观众看，便是黑桃2，放在桌上后再数两张依次放在最底下，第三张给观众看，是黑桃3。如此下去，观众看到放在桌子上牌的顺序是：黑桃 A 2 3 4 5 6 7 8 9 10 J Q K 红桃 A 2 3 4 5 6 7 8 9 10 J Q K 问魔术师手中牌的原始顺序是什么？-magician performing again, he will Hongtao Diez and spades all together, face down on the hands of the audience : one is above the most spades A notice on the table after. After every few top-down order on the two most-wide beneath the third - to the audience, that is, two spades, on the table after several were on the two most underneath, the third - to the audience, three of spades. This situation continues, the audience saw on the card on the table in the order are : spades A 2 3 4 5 6 7 8 9 10 J Q K Hongtao A 2 3 4 5 6 7 8 9 10 J Q K asked the magician card in their hands is what the original order?
Date : 2008-10-13 Size : 1.32kb User : 姚紫欣
[Other] 10个小孩分糖果 DL : 0: 十个小孩围成一圈分糖果，老师分给第一个小孩10块，第二个小孩2块，第三个小孩8块，第四个小孩22块，第五个小孩16块，第六个小孩4块，第七个小孩10块，第八个小孩6块，第九个小孩14块，第十个小孩20块。然后所有的小孩同时将手中的糖分一半给右边的小孩；糖块数为奇数的人可向老师要一块。问经过这样几次后大家手中的糖的块数一样多？每人各有多少块糖？-10 points .... candy children, teachers added to a child 10 and the second two children, the third child eight, the fourth child 22, the fifth child 16, a sixth four children, the seventh child 10, the eighth child six, nine children 14, 10, 20 child. Then all of the children to the hands of sugar to the right half of the children; Retrievers few odd people to be a teacher. Q After this we After several hands of the few pieces of sugar as much? The number of blocks each have sugar?
Date : 2008-10-13 Size : 1.26kb User : 姚紫欣
[Other] 波松瓦酒的分酒趣题 DL : 0: 法国著名数学家波瓦松在表年时代研究过一个有趣的数学问题：某人有12品脱的啤酒一瓶，想从中倒出6品脱，但他没有6品脱的容器，仅有一个8品脱和5品脱的容器，怎样倒才能将啤酒分为两个6品脱呢？-famous French mathematician Beiwasong times in the table, examined an interesting mathematical problem : a person is 12 pints of beer bottle to six pints from the dump, but he did not six pint containers, only an eight pints and pints of the five containers, reversing what beer can be divided into two six pint?
Date : 2008-10-13 Size : 1.36kb User : 姚紫欣
[Other] 卡布列克常数 DL : 0: 验证卡布列克运算。任意一个四位数，只要它们各个位上的数字是不全相同的，就有这样的规律： 1)将组成该四位数的四个数字由大到小排列，形成由这四个数字构成的最大的四位数； 2)将组成该四位数的四个数字由小到大排列，形成由这四个数字构成的最小的四位数(如果四个数中含有0，则得到的数不足四位)； 3)求两个数的差，得到一个新的四位数(高位零保留)。重复以上过程，最后得到的结果是6174，这个数被称为卡布列克数。-certification Roman computing. A four-digit arbitrary, as long as they all place on the same figure is incomplete, this is the law : a) the composition of the four four-digit figures with 7,10,13, formed by four of the greatest figures of the four-digit; 2) The composition of the four four-digit figures headed arranged by the formation of the four figures constitute the smallest of the four-digit (if 4 contains a few 0, then the less than 4); 3) 2 for the number of poor, received a new four-digit (high-reservations). Repeat the above process, the final result is 6,174, a figure known as the Roman few.
Date : 2008-10-13 Size : 1.54kb User : 姚紫欣
[Other] svm_v0.01beta.tar DL : 0: New in this version: Support for multi-class pattern recognition using maxwins, pairwise [4] and DAG-SVM [5] algorithms. A model selection criterion (the xi-alpha bound [6,7] on the leave-one-out cross-validation error). -New in this version : Support for multi-class pattern recognition u maxwins sing, Pairwise [4] and DAG - SVM [5] algorithms. A mode l selection criterion (the xi-alpha bound [6, 7] on the leave-one-out cross-validation erro r).
Date : 2008-10-13 Size : 42.17kb User : 吴成
[Other] 7-81077-626-6 DL : 0: 这是matlab与VC编程的源码所有程序的运行和编译环境为：Visual C++ 6.0和MATLAB 6.5 service pack1(一般情况下MATLAB 6.5即可)。如果您有和技术相关的问题或者发现本书实例有错误之处，请发邮件到： matlab_vc_program@yahoo.com.cn 与作者联系或批评指正。
Date : 2008-10-13 Size : 20.97mb User : WW
[Other] lllll DL : 0: Clk表示用到的时钟信号源，Rst表示复位信号，每次复位后彩灯默认从第一种变幻模式开始变化；SelMode表示变化模式选择，每按一次改换一种变幻模式，共3中模式可供选择；输出信号量：LED[6..0]用于显示模式，Light[7..0]用于8个发光二极管的显示。
Date : 2008-10-13 Size : 954byte User : 李亚马
[Other] EasyUnpack_SRC DL : 0: 汇编写的也算是一个通用脱壳软件，类似 Quick Unpack。入口点查找功能支持一部分 VC++ 6.0 和 Delphi 6.0 编写的软件。文件结构优化也只是很简单的优化，有时侯会出错。具体可以参考源代码。
Date : 2008-10-13 Size : 77.7kb User : 聂云
[Other] cifafenxi DL : 0: 词法分析程序 C++编写,在VC++6.0编译通过
Date : 2008-10-13 Size : 8.96kb User : zhangliao
[Other] Animation_football DL : 0: 公爵动画和足球移动，vc++6.0，mfc编程
Date : 2008-10-13 Size : 210.53kb User : sysull
[Other] test DL : 0: 论述*P++等价于（*p）++还是等价于*（p++）的问题，为了验证这个问题，编写了下面的小程序（vc++6.0编译环境），作为验证
Date : 2008-10-13 Size : 986byte User : wang
[Other] flash-plugin-6.0.79-2.i386 DL : 0: Mozilla 的flash 插件，RH9+Mozilla/FC3+firefox 成功使用-Mozilla plug-in flash, RH9 Mozilla/FC3 successful use firefox
Date : 2008-10-13 Size : 675.12kb User : 刘晨楠
[Other] mataqipang DL : 0: 数据结构实验：马踏棋盘。c语言编写，vc++6.0通过-experimental data structure : horse riding chessboard. C language, vc 6.0 through
Date : 2008-10-13 Size : 1.81kb User : 赵小美

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