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Search - 24 - List
[
matlab
]
jra78
DL : 1
短期负荷预测通常是指24小时的日负荷预测和168小时的周负荷预测,本文主要预测的是日平均负荷,对于短期负荷预测-short-term load forecasts usually refers to the 24-hour daily load forecasting and 168 hours a week load forecasting, In this paper, the forecast is the average load, short-term load forecasting
Date
: 2025-12-22
Size
: 122kb
User
:
钱斌
[
matlab
]
CRC_encode_decode
DL : 0
这是一个matlab编写的CRC冗余校验编解码程序,里面采用了美国通用的16位CRC交验多项式,-This is a matlab prepared codec CRC redundancy check procedure, which uses the U.S. General inspection of the 16-bit CRC polynomial,
Date
: 2025-12-22
Size
: 1kb
User
:
景秀
[
matlab
]
matlab_example
DL : 0
实例1:三角函数曲线(1) 实例2:三角函数曲线(2) 实例3:图形的叠加 实例4:双y轴图形的绘制 实例5:单个轴窗口显示多个图形 实例6:图形标注 实例7:条形图形 实例8:区域图形 实例9:饼图的绘制 实例10:阶梯图 实例11:枝干图 实例12:罗盘图 实例13:轮廓图 实例14:交互式图形 实例15:变换的傅立叶函数曲线 实例16:劳伦兹非线形方程的无序活动 实例17:填充图 例18:条形图和阶梯形图 实例19:三维曲线图 实例20:图形的隐藏属性 实例21PEAKS函数曲线 实例22:片状图 实例23:视角的调整 实例24:向量场的绘制 实例25:灯光定位 实例26:柱状图 实例27:设置照明方式 实例28:羽状图 实例29:立体透视(1) 实例30:立体透视(2)
Date
: 2025-12-22
Size
: 13kb
User
:
poetry
[
matlab
]
MATLAB6.x
DL : 0
MATLAB是一套功能强大的工程计算及数据分析软件,广泛应用于工业、电子、医疗、建筑及航空业等领域。本书系统介绍了MATLAB 6的基础知识,包括程序设计环境、基本操作、绘图功能、 M文件及稀疏矩阵;详细阐述了MATLAB 6在数字信号处理中的应用,主要有离散信号、离散系统及其结构的MATLAB实现、MATLAB中的信号变换、基于MATLAB的 IIR DF与 FIR DF设计以及基于MATLAB的功率谱估计等。另外,本书同时提供了MATLAB 6中 24类基本命令函数的子目录及其含义,以及MATLAB中10种基本的工具箱函数,极大地方便了用户的阅读与参考。 本书可作为数字信号处理课程的参考书,对涉及数字信号处理的各个领域的大专院校师生与广大科研人员具有重要的参考价值。 -err
Date
: 2025-12-22
Size
: 4.54mb
User
:
程序员
[
matlab
]
Alamouti
DL : 0
瑞利衰落信道中空时编码仿真程序: 1.2根发射天线、1根接收天线2.最高信噪比为12dB,即仿真范围为0dB到12dB3.在每个信噪比条件下,误符号数超过20即停止该信噪比条件下的仿真4.每一帧数据为24个QPSK符号-Rayleigh Fading Channels Space-Time Coding Simulation Program: 1.2 transmission antennas, a receiving antenna 2. The highest SNR 12dB, that is, simulation range of 0dB to 12dB3. In each signal to noise ratio conditions, the number of symbol error over 20 that is, to stop the signal to noise ratio under the conditions of simulation 4. each frame 24 QPSK data symbols
Date
: 2025-12-22
Size
: 5kb
User
:
陈功
[
matlab
]
twentyfour
DL : 0
在matlab环境下, 随即生成四个数字, 并用这四个数字得出24的游戏。-twentyfour
Date
: 2025-12-22
Size
: 1kb
User
:
李明
[
matlab
]
TMS320LF2407
DL : 0
simulink matlab dsp tms320lf2407 永磁无刷直流电机-simulink matlab dsp tms320lf2407 BLDCM
Date
: 2025-12-22
Size
: 159kb
User
:
王孙俊
[
matlab
]
ColorSpace
DL : 0
in this matlab code we 1.compute spectral response 2.compute the tristimulus 3.generate the 200*300 pixel images from the 24 RGB & gamma correction tristimulus
Date
: 2025-12-22
Size
: 84kb
User
:
ela
[
matlab
]
xujinpeng3.14
DL : 0
用遗传算法求函数f=x+10*sin(5*x)+7*cos(4*x)的最大值点:简单的单点交叉、基本位变异、赌轮盘选择、随机产生初始种群中的个体,求的最好解是24.689。注:本算法基于matlab7.0,是我自己编写的,每个步骤都有详细的说明。适用于遗传算法初学者。-Using genetic algorithms for function f = x+10* sin (5* x)+7* cos (4* x) the maximum points: a simple single-point crossover, the basic bit mutation, roulette gambling options, randomly generated initial individual stocks, and the best solution is 24.689. Note: This algorithm is based on the matlab7.0, is what I have written, each of these steps are detailed. Genetic Algorithm for beginners.
Date
: 2025-12-22
Size
: 4kb
User
:
竹子的信仰
[
matlab
]
golaycodec
DL : 0
matlab函数,可实现golay编码和译码,包括(23,11)和(24,12,8) -matlab function, can be realized golay encoding and decoding, including the (23,11) and (24,12,8)
Date
: 2025-12-22
Size
: 4kb
User
:
chenxi
[
matlab
]
0712253
DL : 0
I wrote this program for coloring any map with only 4 colors. Input for it is an bitmap file with 24 bit colors (must gray/scale). Output is a bitmap which is colored with maximum 4 colors.
Date
: 2025-12-22
Size
: 1.55mb
User
:
raveufo
[
matlab
]
24cal
DL : 0
给出4个数, 计算24点, 求出所有的解, 并且计算出总共解的个数, 且一并输出-24 calculation
Date
: 2025-12-22
Size
: 1kb
User
:
ray
[
matlab
]
orbita_sunsync
DL : 0
Orbita.m Programa para dibujar un periodo de la orbita de un satélite apartir de los parámetros orbitales Programado a partir de la hoja TUNDRA2.pdf Ramon Martínez, 20-12-2006 Parámetros k=398613.52 en (km^3)/(s^2) Re = 6377 km h=814.5 a=Re+h e=0 OmegaRot=0.9856 º /day n = sqrt(k/(a^3)) p = a*(1-(e^2)) J2=0.00108263 cos_i = OmegaRot*(-2/3)*(1/J2)*(1/n)*((p/Re)^2)*(pi/180)/(24*3600) i = acos(OmegaRot*(-2/3)*(1/J2)*(1/n)*((p/Re)^2)*(pi/180)/(24*3600))*(180/pi) - Orbita.m Programa para dibujar un periodo de la orbita de un satélite apartir de los parámetros orbitales Programado a partir de la hoja TUNDRA2.pdf Ramon Martínez, 20-12-2006 Parámetros k=398613.52 en (km^3)/(s^2) Re = 6377 km h=814.5 a=Re+h e=0 OmegaRot=0.9856 º /day n = sqrt(k/(a^3)) p = a*(1-(e^2)) J2=0.00108263 cos_i = OmegaRot*(-2/3)*(1/J2)*(1/n)*((p/Re)^2)*(pi/180)/(24*3600) i = acos(OmegaRot*(-2/3)*(1/J2)*(1/n)*((p/Re)^2)*(pi/180)/(24*3600))*(180/pi)
Date
: 2025-12-22
Size
: 1kb
User
:
ramonmro
[
matlab
]
EKsation_last
DL : 0
编写时间2009年2月24日第1次 以后以此区别修改版本!!! ---------频域传递公式推导------------ 变量说明:zn1 zn2:分别为左塔和右塔阻尼比 w1式起重机w1 w2:左塔和右塔固有频率 w01 w02 wc分别连体左支座、右支座、连体自振频率 zn01 zn02 分别为连体左支座、右支座的连接阻尼比 非对称双塔连体结构 主要考虑支座连接频率比的变化结构反应功率谱曲线- Write time, February 24, 2009 1st after a modified version of this distinction!!! --------- Frequency-domain transfer formula derivation------------ variable Description: zn1 zn2: respectively, the left and right tower tower damping ratio w1 crane w1 w2: the left and right tower tower natural frequency w01 w02 wc Siamese left bearing, respectively, the right bearing, Siamese natural frequency zn01 zn02 Siamese respectively, bearing left and right bearing link damping ratio non-symmetrical structure Siamese twin towers bearing the main consideration changes in the ratio of the structure connecting the frequency response curve of the power spectrum
Date
: 2025-12-22
Size
: 3kb
User
:
manman
[
matlab
]
tracker-code-2007.07.24.tar
DL : 0
object detection matlab files
Date
: 2025-12-22
Size
: 90kb
User
:
sachin
[
matlab
]
ANSI_X9.24
DL : 1
ANSI X9.24 零售金融业务 -- 对称密钥管理标准-ANSI X9.24 retail financial services- symmetric key management standards
Date
: 2025-12-22
Size
: 472kb
User
:
chunlv
[
matlab
]
24-papers-of-matlab
DL : 0
24篇matlab论文,matlab数据文件输入输出,用户界面编程,以及实例论文-24 papers matlab, matlab data file input and output, user interface programming, and example papers
Date
: 2025-12-22
Size
: 4.63mb
User
:
baide
[
matlab
]
Computing-the-24
DL : 0
求DFT并做出离散函数xn的傅里叶变换图像 -Computing the 24-points DFTs of the two sequences that x1(n)= cos(nπ/6) and x2(n)= cos(nπ/4) using a single 24-point DFT by Matlab
Date
: 2025-12-22
Size
: 3kb
User
:
cyj
[
matlab
]
24脉波整流matlab仿真
DL : 0
6脉波,12脉波,24脉波整流matlab仿真(6 pulse wave, 12 pulse wave, 24 pulse wave rectifier matlab simulation)
Date
: 2025-12-22
Size
: 20kb
User
:
mm007
[
matlab
]
Dynamic Programming 10 units 24 hours
DL : 0
Unit Commitment using Dynamic Prorgramming for 10 units and 24 hours system
Date
: 2025-12-22
Size
: 10kb
User
:
Harpreet
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