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[
Algorithm
]
计算几何
DL : 1
目录 ㈠ 点的基本运算 1. 平面上两点之间距离 1 2. 判断两点是否重合 1 3. 矢量叉乘 1 4. 矢量点乘 2 5. 判断点是否在线段上 2 6. 求一点饶某点旋转后的坐标 2 7. 求矢量夹角 2 ㈡ 线段及直线的基本运算 1. 点与线段的关系 3 2. 求点到线段所在直线垂线的垂足 4 3. 点到线段的最近点 4 4. 点到线段所在直线的距离 4 5. 点到折线集的最近距离 4 6. 判断圆是否在多边形内 5 7. 求矢量夹角余弦 5 8. 求线段之间的夹角 5 9. 判断线段是否相交 6 10.判断线段是否相交但不交在端点处 6 11.求线段所在直线的方程 6 12.求直线的斜率 7 13.求直线的倾斜角 7 14.求点关于某直线的对称点 7 15.判断两条直线是否相交及求直线交点 7 16.判断线段是否相交,如果相交返回交点 7 ㈢ 多边形常用算法模块 1. 判断多边形是否简单多边形 8 2. 检查多边形顶点的凸凹性 9 3. 判断多边形是否凸多边形 9 4. 求多边形面积 9 5. 判断多边形顶点的排列方向,方法一 10 6. 判断多边形顶点的排列方向,方法二 10 7. 射线法判断点是否在多边形内 10 8. 判断点是否在凸多边形内 11 9. 寻找点集的graham算法 12 10.寻找点集凸包的卷包裹法 13 11.判断线段是否在多边形内 14 12.求简单多边形的重心 15 13.求凸多边形的重心 17 14.求肯定在给定多边形内的一个点 17 15.求从多边形外一点出发到该多边形的切线 18 16.判断多边形的核是否存在 19 ㈣ 圆的基本运算 1 .点是否在圆内 20 2 .求不共线的三点所确定的圆 21 ㈤ 矩形的基本运算 1.已知矩形三点坐标,求第4点坐标 22 ㈥ 常用算法的描述 22 ㈦ 补充 1.两圆关系: 24 2.判断圆是否在矩形内: 24 3.点到平面的距离: 25 4.点是否在直线同侧: 25 5.镜面反射线: 25 6.矩形包含: 26 7.两圆交点: 27 8.两圆公共面积: 28 9. 圆和直线关系: 29 10. 内切圆: 30 11. 求切点: 31 12. 线段的左右旋: 31 13.公式: 32
Date
: 2009-04-13
Size
: 12.87kb
User
:
wangsiman66@sohu.com
[
Algorithm
]
24位二进制数转asc码
DL : 0
自己做的程序,可能对你有用-own procedures that may be useful to you
Date
: 2025-12-22
Size
: 1kb
User
:
柏
[
Algorithm
]
数字图像处理
DL : 0
本程序为图象处理,可将八位图转换为二十四位图-the procedures for image processing, can be converted to 8 Figure 24 Figure
Date
: 2025-12-22
Size
: 3.65mb
User
:
[
Algorithm
]
MoShiPiPei
DL : 0
有一串10000位数的主串由1、2、3、4四位数随机获得,n位模式串是指有4的n次方个模式串,如2位模式串有:11、12、13、14、21、22、23、24、31、32、33、34、41、42、43、44等16个数组成。现在进行模式匹配,假设主串为:431324113122341324132等等,则第一次比较是43,第二次比较是31,第三次比较是13,依此类推,每比较一次则落得模式串中的一个,当所有模式串(有4的n次方个)都被找到时,记得所比较的次数,则这个次数就是这次匹配的结果。程序执行了100次,取了平均值,则结果即为n位模式匹配的结果。-10,000 median are a bunch of strings from the main four-digit random access 1,2,3,4, n-bit mode is a series of four nth Series models, such as the two model series : 11,12,13,14,21,22,23,24, Number 16 31,32,33,34,41,42,43,44 other components. Now for pattern matching, string for the main assumptions : 431324113122341324132 etc., the first comparison is 43, the second comparison is 31, the third comparison is 13, and so on, every time he come earlier model of a string, and when all model series (with the n-th 4) were found when remember the comparison of the number, this number is the result of this match. Procedure 100 times and took the average, the result is considered n-pattern matching results.
Date
: 2025-12-22
Size
: 29kb
User
:
陈力
[
Algorithm
]
24Points-JavaVer
DL : 0
加减乘除24,java的GUI界面,输入的数字在1-13的范围内,产生的结果中已去除了冗余的结果,并统计产生结果的个数.- The arithmetic operations 24, java GUI contact surface, the input numeral in 1-13 scope, in the result which produces has removen the redundancy result, and the statistics has the result integer
Date
: 2025-12-22
Size
: 11kb
User
:
shoarh
[
Algorithm
]
24_Source
DL : 0
C#,DotNet FrameWork2.0,计算4张牌四则混合运算以后等于24的算法源码-C#, Delegate FrameWork2.0. Calculation four licensing mixed four to 24 after the operator of the algorithm source code
Date
: 2025-12-22
Size
: 17kb
User
:
janet
[
Algorithm
]
wpzbh
DL : 0
24点程序,运行之后,可以在输入4个阿拉伯数字后,用四则运算法算出结果。-24 points procedures, operational, the importation of four Arabic numerals, with four algorithms calculate the results.
Date
: 2025-12-22
Size
: 56kb
User
:
王俊
[
Algorithm
]
FormulaProcessor_beta1_CSharp
DL : 0
功能说明: 次组件提供的功能有二: 1、解析出数学表达式中的参数 2、计算数学表达式 此组件不但可以解析和计算数学表达式,还提供了一系列的数学基本函数,可应用于表达式中一块处理。提供的数学基本函数有:将值舍入到最接近的整数 rount(x)、向下取整函数 int(x)、向上取整 ceiling(x)、求两个数中最大数的函数 max(a,b)、求两个数中最小数的函数 min(a,b)、幂函数 pow(x,n)、求平方根的函数 sqrt(x)。 下载地址:http://www.qiusuo365.com/qiusuo365/viewthread.php?tid=2422&extra=page%3D1-Functional Description : sub-components provided by the two functions : one, to figure out the mathematical expression of two parameters. calculate mathematical expression of this component will not only analytical and computational mathematical expression, but also provided a series of basic math functions, expression can be applied to a handle. The basic function of mathematics : the value of rounding to the nearest integer rount (x), downward for the entire function int (x), up from the entire ceiling (x), 2 for the largest number of the number of function max (a, b), 2 for the smallest number of the number of function min (a, b), power function pow (x, n), for the square root function sqrt (x). Download Address : http :// www.qiusuo365.com/qiusuo365/viewthread . php tid = 24
Date
: 2025-12-22
Size
: 3kb
User
:
jason
[
Algorithm
]
24p
DL : 0
24点傅立叶算法,用标准C编写,对执行速度进行了优化-24-point Fourier algorithm, using standard C to prepare for the implementation of the speed of optimized
Date
: 2025-12-22
Size
: 1kb
User
:
殷喆
[
Algorithm
]
Project
DL : 0
C 语言开发的日历(课程设计很不错的) Month:123/1 --- --- --- Sun Mon Tue Wed Thu Fri Sat 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31-C language developed by the calendar (of course design is very good) Month: 123/1------ Sun Mon Tue Wed Thu Fri Sat 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
Date
: 2025-12-22
Size
: 3kb
User
:
zhangdan
[
Algorithm
]
24
DL : 0
给定四个数(1--13),判经过四则运算后能否得到结果24,若能,输出表达式。 -Given the number four (1- 13), after sub after four computing results can be 24, if the output expression.
Date
: 2025-12-22
Size
: 2kb
User
:
黄利
[
Algorithm
]
anff
DL : 0
4个牌,每个只用一次,就用加减乘除得出结果为24的算式。解纸牌24点游戏-4 license, each only once, on the calculation used the results of the formula 24. Solution of 24-point game of cards
Date
: 2025-12-22
Size
: 1kb
User
:
meme
[
Algorithm
]
10020
DL : 0
算24点,若有解则输出每一步计算步骤,若无解则返回“No answer!”-Count 24 points, if so, what solutions are output every step of the calculation steps, if there are no solution is returned
Date
: 2025-12-22
Size
: 1kb
User
:
justin
[
Algorithm
]
c24
DL : 0
任意4个数加减乘除求24,类似扑克牌的求24游戏的算法-Arbitrary number of addition and subtraction multiplication and division 4 for 24, similar to playing cards for 24 games of the algorithm
Date
: 2025-12-22
Size
: 879kb
User
:
Albert Meng
[
Algorithm
]
jiandanjisuanqi.bdsproj
DL : 0
标准型和科学型。 标准型带有足够让你用手指来操作的按钮,数字大而清晰并能够满足你基本的计算,标准模式支持显示12位数字,足够可以使用手指按键,算术操作、平方根。 科学型带有所有普通的函数,所有的函数都分布在键盘上一致于你可以不用通过菜单列表来使用它们。科学型支持显示24位数字,支持运算优先选择模式、进制转换功能、标准数学函数、百分比计算、方根计算等等功能。 -Standards-based and science-based. Standard type with your fingers enough to operate the button, the number of large and clear and be able to meet your basic computing, the standard model to support 12-digit display, enough can use the finger button, arithmetic operations, square root. Science-based with all general functions, all functions are located in the keyboard line in you can not through the menu list to use them. Science-based support figure 24 shows in support of computing preferred mode, hexadecimal conversion function, the standard math function, percentage terms, the square-root function of the calculation and so on.
Date
: 2025-12-22
Size
: 173kb
User
:
xiaoqiu
[
Algorithm
]
DFT24
DL : 1
用于24点采样的傅立叶分解用的系数组,很适用的哦。这是我的一款电机保护中所采用的算法-24 points for the sample used in the Fourier decomposition coefficient group, it is applicable Oh. This is my a motor used in the protection algorithm
Date
: 2025-12-22
Size
: 1kb
User
:
邓杰
[
Algorithm
]
calculator
DL : 0
一个不带界面的计算器,用户只需要在文本文件input.txt中输入计算表达式,即可通过运行程序得到结果,输出在output.txt中; 支持加减乘除,取余数,乘方,括号等等; 如:5+4 = 输出9 5+4*4+9/3 = 输出24 (5+4)*4+9/3 = 输出39 (50+4)*(40 3)+288/(147-3) = 输出56 (50+4)^2*(40 3)+288/(147-3) = 输出2918-Interface without a calculator, the user need only enter a text file input.txt expressions, you can get results by running the program, the output in the output.txt support calculation, check the balance, involution, brackets etc. such as: 5+4 = 9 5+4 Output* 4+9/3 = output 24 (5+4)* 4+9/3 = output 39 (50+4)* (40 3)+288/(147-3) = output 56 (50+4) ^ 2* (40 3)+288/(147-3) = output 2918
Date
: 2025-12-22
Size
: 14kb
User
:
shiping
[
Algorithm
]
24
DL : 0
一个24点的算法实验程序(输入4个小于13的数,判断能否通过四则运算最终得到24) 基于VC++6.0 ,可正常运行-A 24-point algorithm for experimental procedures (type 4 small number of 13, to determine whether the operation eventually get through four 24) based on VC++6.0, a functioning
Date
: 2025-12-22
Size
: 2kb
User
:
hankhuang
[
Algorithm
]
24
DL : 0
用vc++编写的自动找出得到24的算法,可以修改代码,将24换成其他的数。练习程序,仅供初学者参考,与君共勉!-Prepared with vc++ algorithm automatically finds get 24, you can modify the code number will be replaced by other 24. Practice procedures, for beginners reference, and the king of encouragement!
Date
: 2025-12-22
Size
: 27kb
User
:
yuxuegang
[
Algorithm
]
24-game
DL : 0
给出4个1-10的数字,通过加减乘除,得到数字为24就算胜利。 -4 1-10 figures given by the addition, subtraction, to give figures for the 24 even if the victory.
Date
: 2025-12-22
Size
: 1kb
User
:
陈沧海
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