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[Data structs] goodjsq DL : 0: 设计一个简单的计算器类（类型），要求：（1）从键盘读入算式。（2）可以进行加、减、乘、除运算。（3）运算要有优先级。（4）用户可以按任何的运算符出现顺序进行输入。（5）不限定用户输入的计算式的长度。（6）有排错功能，当用户输入错误的算式时提示用户。例如，如果用户输入：3 + 4 * 5 - 7，计算结果应为16。（提示：可以使用本节所定义的栈类来帮助进行处理）。-Design a simple calculator-type (type), requirements: (1) Reading from the keyboard into the formula. (2) can add, subtract, multiply, with the exception of computing. (3) The operator must have priority. (4) the user can press any of the emergence of the order of operator input. (5) does not limit the user to enter the length of the calculation formula. (6) have debugging function, when the user enters the wrong formula when prompts the user. For example, if a user enters: 3+ 4* 5- 7, the calculation results should be 16. (Hint: You can use this section of the stack type definition to help to deal with).
Date : 2026-01-03 Size : 2kb User : wangmeng
[Data structs] testAvl2 DL : 0: AVL均衡二叉树的的C++模板实现。带有册除功能-AVL balanced binary tree of the C++ Realize template. List with the exception of functional
Date : 2026-01-03 Size : 9kb User : xzzz
[Data structs] czs DL : 0: 1. 本程序实现计算任意长的整数的四则运算. 以用户和计算机对话的方式,先后输入数字的最多位数,然后程序就计算并显示出这两个数的运算. 2. 利用双向循环链表现实长整数的存储,每个结点含一个整形变量.输入的形式以回车结束,可以直接输入正数或负数,程序会过滤掉无效的字符.按中国对于长整数的表示习惯,每四位一组,除数字和位于首位置的负号外,其它一切字符都将作为分隔符,连续多个分隔符当一个处理.但不使用分隔符也不影响结果. -1. This procedure calculating the arbitrary implementation of long integer arithmetic. To the user and computer dialogue, has a maximum input of the median figure, and then the procedure is calculated and shown on both the number of computing this. 2. The use of two-cycle chain Table reality long integer storage, each node containing a plastic variables. enter to enter the end of the form, you can directly enter the positive or negative, the program will filter out invalid characters. according to the Chinese for a long integer used to express each One group of four, with the exception of the first figure and is located in the negative position, the other will be all the characters as a separator, row separator when a number of treatment. but do not use the separator does not affect the results.
Date : 2026-01-03 Size : 20kb User : sqj
[Data structs] Stack544014 DL : 0: 用模板实现顺序栈的基本功能：初始化；判断栈空；判断栈满；置空栈；入栈；出栈；要求入栈时，栈非满是可以插入元素，否则抛除异常；出栈时，栈非空返回栈顶元素，否则抛除异常。(陈儒焕组) 5、队列是只允许在一端进行插入操作，而另一端进行删除操作的线性表。如何改造数组实现队列的顺序存储。要求：用模板实现队列的判空；判满；置队空；出队，队列非空时，出队队首元素，否则报错；出队，队列非满时，插入新元素到队尾，否则报错； -The template is the order of the stack to achieve the basic functions: initialization to determine the stack empty to determine the stack full home empty stack stack out of the stack request stack, the stack can be inserted elements of non-full, otherwise, except throwing an exception out of stack, the stack is non-empty return stack element, or else except throwing an exception. (Ru-hwan group) 5, the queue is only allowed at one end of insertion, while the other end of the deletion operation of a linear form. How to transform an array to achieve the order of the queue storage. Requirements: use templates to achieve the sub-queue empty sub-full home team empty a team, the queue of non-empty out teams of the first element, otherwise Baocuo a team, the queue of non-full, insert a new element to the tail, Otherwise, Baocuo
Date : 2026-01-03 Size : 38kb User : 钟书球
[Data structs] 001 DL : 0: 缘起《数据结构》是一门计算机专业基础课，各类计算机考试都禁不住要考它，专升本考试自然也不例外。我给学生辅导这门课程已经有几个年头了，讲稿换了几次，逐渐丰富起来。加之看到学生们埋头记笔记时辛苦的样子，就产生了写一本小册子的想法。另外，还有一层意思就是对数次辅导进行总结，以便交流之用。-Origin of " data structure" is a computer basic course, all kinds of computer tests are tempted to test it, Top-examination is no exception. I Students in this course have been a few years, and the script for several times, gradually enriched. Plus the time to see the students hard look hard at taking notes to write a booklet produced the idea. In addition, a layer of meaning to the summary of several counseling to exchange purposes.
Date : 2026-01-03 Size : 202kb User : zixialang
[Data structs] 8 DL : 0: 任意一个4位自然数（除4个数字完全一样除外，例如4444、7777等），，将组成该数的各位数字重新排列，形成一个最大数和一个最小数，之后两数相减，其差仍然为一个自然数，重复上述运算，你会发现一个神秘数。-Any of a four natural numbers (with the exception of the four numbers exactly the same, except such as 4444,7777, etc.), will form the digits of the number of re-arranged to form one of the greatest number and a minimum number after two the number of subtraction, the difference still is a natural number, repeat the above computation, you will find a mysterious number.
Date : 2026-01-03 Size : 2.09mb User : t
[Data structs] abnormalities DL : 0: VC++异常处理问题：try、throw和catch语句加到C++语言中去实现异常处理。-VC++ exception handling: try, throw and catch statement added to C++ language to implement exception handling.
Date : 2026-01-03 Size : 3kb User : zzs
[Data structs] except DL : 0: C语言接口与实现中对异常处理的实现，通过setjmp和longjmp实现了c语言处理异常的优雅方式。-Implementations of exception handling in the C language interface and implementation by setjmp and longjmp the the c language processing abnormalities elegant way.
Date : 2026-01-03 Size : 15kb User : zeropointer
[Data structs] Chp2-Lineer DL : 0: 根据线性表的抽象数据类型的定义，选择下面任一种链式结构实现线性表，并完成线性表的基本功能。线性表存储结构（五选一）： 1、带头结点的单链表 2、不带头结点的单链表 3、循环链表 4、双链表 5、静态链表线性表的基本功能： 1、构造：使用头插法、尾插法两种方法 2、插入：要求建立的链表按照关键字从小到大有序 3、删除 4、查找：按位置查找和按值查找 5、获取链表长度 6、销毁编写测试main()函数测试线性表的正确性。注意：异常处理捕捉字符串信息时，请使用catch(const char* s)的形式，否则会出现异常错误。-According to abstract data types defined linear form, any one of the chain structure to achieve the following linear form, and complete the basic functions of the linear form. Linear table storage structure (V choose one): 1, the lead single list node 2, do not take the lead node single list 3, circular list 4, the doubly linked list 5, static chain The basic function of the linear form: 1, Construction: interpolation method using head, tail interpolation of two ways 2, insert: requirements established by keyword list small to large order 3, delete 4. Find: Find by location and by value lookup 5. Get the list length 6, destruction Write test main () function to test the correctness of the linear form. Note: When exception processing captured string information, please use the catch (const char* s) form, there would be an exception error.
Date : 2026-01-03 Size : 4.99mb User : Jimmy