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0-1背包问题 可以提供在背包方面遇到问题的学生或者有需要的人.-0-1 knapsack problem can provide a backpack problems encountered students or those who are in need.
Date : 2025-12-21 Size : 1kb User : 马涛

本文通过研究动态规划原理,提出了根据该原理解决0/1背包问题的方法与算法实现,并对算法的正确性作了验证.观察程序运行结果,发现基于动态规划的算法能够得到正确的决策方案且比穷举法有效.-through research paper on dynamic programming, According to the principle of resolving the 0/1 knapsack problem with the algorithm, the algorithm was verified the correctness. Observation running findings, based on dynamic programming algorithm can be the correct decision than a program exhaustive method effective.
Date : 2025-12-21 Size : 10kb User : 汤烈

有N个城市,编号为0、1…N-1,每个城市之间的路径长度保存在二位数组a中,如a[i][j]表示城市i与城市j的路径长度。求某个城市到其余城市的最短路径。-cities are N, No. 0,1 ... N-1, every city path length between the two kept in a group median, if a [i] [j] i said cities and urban j length of the path. For a city to the other cities in the shortest path.
Date : 2025-12-21 Size : 4kb User : 汤烈

这是一个数据结构八皇后问题的程序,提供了图形化显示功能.运行在TC++3.0-This is a data structure of the eight Queen's procedures, provides a graphical display. Running TC 3.0
Date : 2025-12-21 Size : 8kb User :

要求完成以下功能: 1)能够从屏幕上读取一个学生的信息并将信息存入到数据文件中。 2)能够将指定的信息从文件中删除。 3)能够按编号、姓名对学生的信息进行检索并将检索结果显示在屏幕上。 4)可以统计全部学生的总成绩,及其在班上的排名。 5)能够统计各科的平均成绩及及格率。 6)要求有错误提示功能,例如性别只能输入男女,输入错误提示重新输入。 7)如果检索不到相应的信息应提示用户。-asked to perform the following functions : 1) to read from the screen of a student's information will be deposited into the data file. 2) can be designated information deleted from the document. 3), according to numbers, the names of the students will retrieve information retrieval results showed on the screen. 4) Statistical all students can be a total score, and the class rankings. 5) Statistics Branch to the average scores and passing rates. 6) require a functional error messages, such as sex between men and women can only import, importation of error messages to re-enter. 7) If less than the corresponding retrieval of information should prompt the user.
Date : 2025-12-21 Size : 7kb User : 顾俊

0-1背包问题的动态规划求解算法, 0-1背包不同于背包问题-0-1 knapsack problem of the dynamic programming algorithm, 0-1 knapsack different from the knapsack problem
Date : 2025-12-21 Size : 1kb User : 高亮

数据结构算法vc++6.0程序集教材之总览,是一些你编完以后的结果,各部分算法在前面part1-part7部分给出,含线性表,数组,队列,堆栈,广义表,递归,图,排序,以及严蔚明数据结构教材中的各种算法实现了,好东西啊,强烈推荐,我找了很久才得到的,给予奉献了 vc实现少有的特别好的程序集特别适合学习数据结构,有向动手实践的,把数据结构的算法都用vc实现了,经典经典经典经典经典经典经典!-data structure algorithms vc 6.0 manual procedures set overview of some of your writing after the results part of the algorithm in front part1- part7 part is, with linear scale arrays, queue, stack, generalized form Recursive, graphics, sorting, and Yan Wei Ming data structure of various materials algorithm achieved, and the good stuff ah, strongly recommended I found a long time before they can get. vc dedication to the realization of the special few good episodes procedures for the study of data structure, to get involved in practice, the data structure of the algorithm using vc achieved, and the classic classic classic classic classic classic classic!
Date : 2025-12-21 Size : 5.12mb User : 魏洪平

此文件实现Ackerman函数的动态规划算法,在VC++6.0 下 编译通过-This document is the realization of Ackerman function of dynamic programming algorithm, in VC 6.0 under the compiler through
Date : 2025-12-21 Size : 1kb User : tony chen

在VC6.0环境下,用C实现顺序表的基本操作:建立空表、销毁表、清空表、求表长、取表中某个元素、查找某元素在表中的位置、求前驱后继、插入删除元素等。 文件中不仅包含源码 ,还包含一组测试结果。对于刚刚学习数据结构的人是-At VC6.0 environment, using C implementation of the basic operation sequence tables: Create an empty table, the destruction of form, empty table, and a long table, check table, an element, a search element in the table position, and pre-follow-up , insert elements, such as delete. Document not only contains the source code, but also contains a set of test results. Just study the data structure for the people are
Date : 2025-12-21 Size : 8kb User : shuiyeshan

MFC 的迷宫小游戏数据结构课程设计:迷宫,采用Visual C++ 6.0开发,适合初学者学习使用-MFC maze game data structures curriculum design: a maze, using Visual C++ 6.0 development, suitable for beginners learning to use
Date : 2025-12-21 Size : 31kb User : andyyu

数据结构算法——Visual.C.6.0程序集-Data structure algorithms- Visual. C.6.0 assembly
Date : 2025-12-21 Size : 8.99mb User : 汪志诚

《数据结构》课程设计,停车场管理设计,vc++ 6.0环境停车场管理的实现。-Data structure course design- parking management design, vc++ 6.0 environment parking management is realized.
Date : 2025-12-21 Size : 92kb User : MOTITA

算法分析与设计实验报告,运行环境位VC++6.0 -Algorithm analysis and design of experiments reported
Date : 2025-12-21 Size : 12kb User : wangke

VC++6.0写的数据结构课程设计,内容是实现记事本小程序,可以实现新建、查找、删除的功能,适合期末课程设计-VC++6.0 program to write the data structure design, the content is to achieve a small notepad program, designed for the end of course
Date : 2025-12-21 Size : 36kb User : 姬晓鹏

给定n种物品和一背包。物品i的重量是wi,其价值为vi,背包的容量为C。问应如何选择装入背包的物品,使得装入背包中物品的总价值最大-the problem is 0-1bag,it can put best price
Date : 2025-12-21 Size : 22kb User : shengjiali

1. 问题描述 从键盘上输入中缀算数表达式,包括括号,计算出表达式的值 2,基本要求 (1) 程序能对所输入的表达式做简单的判断,如果表达式有错,能给出适当的提示。 (2) 能处理单目运算符+和-。 3. 工具/准备工作 在开始做课程设计项目前,应回顾或复习相关内容。 需要一台计算机,其中安装有Visual C++6.0,Dev C++等集成开发环境软件 4. 分析与实现 对于中缀表达式,一般运算规则如下: (1) 先乘方,再乘除,最后加减 (2) 同级运算从左到右。 (3) 先算括号内,再算括号外。 -Arithmetic evaluation
Date : 2025-12-21 Size : 62kb User : 谭帆

cordic算法的c语言实现,输入x,y两点坐标,自动计算得出改点与平面坐标轴(x轴正向)夹角,适用于整个坐标平面。于环境vc 6.0下编译通过。-CORDIC algorithm realize the C language, input x, y coordinates of two points, are automatically calculated to change point and plane coordinate axis ( x axis positive ) angle, apply to the whole coordinate plane. In the environment of VC 6 under the compiler through.
Date : 2025-12-21 Size : 2kb User : baijingdong

有关数据结构算法:Visual C++6.0的程序集,很有用哦.-The data structure algorithm: Visual C++6.0 program, very useful oh
Date : 2025-12-21 Size : 4.56mb User : gxl

这是用Visual C++ 6.0做的十佳动漫评选系统的代码及各种相应的数据结构图。-This is with Visual C++ 6.0 to do the top ten cartoon selection system code and the corresponding data structure diagram.
Date : 2025-12-21 Size : 17kb User : 王栗

数据结构实现 贪吃蛇游戏 可用VC+6.0编译运行 初学者使用-Data structure to achieve the Snake game available VC+6.0 compiled to run for beginners
Date : 2025-12-21 Size : 14kb User : wanxiaoer
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