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[Mathimatics-Numerical algorithms] aiyinsitan DL : 0: 原题为： 1．有5栋5种颜色的房子 2．每一位房子的主人国籍都不同 3．这五个人每人只喝一个牌子的饮料，只抽一个牌子的香烟，只养一种宠物 4．没有人有相同的宠物，抽相同牌子的烟，喝相同牌子的饮料已知条件： 1．英国人住在红房子里 2．瑞典人养了一条狗 3．丹麦人喝茶 4．绿房子在白房子的左边 5．绿房子主人喝咖啡 6．抽pallmall烟的人养了一只鸟 7．黄房子主人抽dunhill烟 8．住在中间房子的人喝牛奶 9．挪威人住在第一间房子 10．抽混合烟的人住在养猫人的旁边 11．养马人住在抽dunhill烟人的旁边 12．抽bluemaster烟的人喝啤酒 13．德国人抽prince烟 14．挪威人住在蓝房子旁边 15．抽混合烟的人的邻居喝矿泉水问题：谁养鱼？这道迷题出自1981年柏林的德国逻辑思考学院。据说世界上只有2％的人能出答案。就连大名鼎鼎的爱因斯坦也成为此题大伤脑筋。-original entitled : 1. Have five five colors of the two houses. Each a master of the house three different nationality. Each of these five individuals only drink one brand of beverages, just the one brand of cigarettes, only raised a pet 4. No one has the same pet, and pumping the same brand of cigarettes, drink the same brand of beverages known conditions : 1. Britons living in Red House Lane 2. Swede custody of a dog 3. Denmark tea 4. Green house at the White house left five. Green coffee house owner 6. Pallmall pumping smoke of keeping a bird 7. Huang owner pumped dunhill tobacco 8. Living in the middle of the house to drink milk 9. Norwegians living in the first house and 10. Mixed pumping smoke and cats live in the adjacent 11. Horse people live in pumping dunhill smoke next to the 12
Date : 2008-10-13 Size : 2.97kb User : 刘志雄
[Mathimatics-Numerical algorithms] mylineseg2 DL : 0: 7. 求矢量夹角余弦 8. 求线段之间的夹角 9. 判断线段是否相交10.判断线段是否相交但不交在端点处 11.求线段所在直线的方程 12.求直线的斜率 13.求直线的倾斜角14.求点关于某直线的对称点15.判断两条直线是否相交及求直线交点16.判断线段是否相交，如果相交返回交点-7. For vector cosine angle 8. For the angle between the line 9. Line judge whether the intersection 10. Line judge whether the intersection but do not pay the endpoint Office 11. For the straight line segment where equation 12. For a linear slope 13. Seeking straight tilt angle 14. For a certain point on a linear symmetrical 15 points. to judge whether the intersection of two straight and for 16 straight intersection. Line judge whether the intersection, the intersection to intersection
Date : 2008-10-13 Size : 1.69kb User : 孤星赶月
[Mathimatics-Numerical algorithms] mylineseg2 DL : 0: 7. 求矢量夹角余弦 8. 求线段之间的夹角 9. 判断线段是否相交10.判断线段是否相交但不交在端点处 11.求线段所在直线的方程 12.求直线的斜率 13.求直线的倾斜角14.求点关于某直线的对称点15.判断两条直线是否相交及求直线交点16.判断线段是否相交，如果相交返回交点-7. For vector cosine angle 8. For the angle between the line 9. Line judge whether the intersection 10. Line judge whether the intersection but do not pay the endpoint Office 11. For the straight line segment where equation 12. For a linear slope 13. Seeking straight tilt angle 14. For a certain point on a linear symmetrical 15 points. to judge whether the intersection of two straight and for 16 straight intersection. Line judge whether the intersection, the intersection to intersection
Date : 2025-12-18 Size : 1kb User : 孤星赶月
[Mathimatics-Numerical algorithms] aiyinsitan DL : 0: 原题为： 1．有5栋5种颜色的房子 2．每一位房子的主人国籍都不同 3．这五个人每人只喝一个牌子的饮料，只抽一个牌子的香烟，只养一种宠物 4．没有人有相同的宠物，抽相同牌子的烟，喝相同牌子的饮料已知条件： 1．英国人住在红房子里 2．瑞典人养了一条狗 3．丹麦人喝茶 4．绿房子在白房子的左边 5．绿房子主人喝咖啡 6．抽pallmall烟的人养了一只鸟 7．黄房子主人抽dunhill烟 8．住在中间房子的人喝牛奶 9．挪威人住在第一间房子 10．抽混合烟的人住在养猫人的旁边 11．养马人住在抽dunhill烟人的旁边 12．抽bluemaster烟的人喝啤酒 13．德国人抽prince烟 14．挪威人住在蓝房子旁边 15．抽混合烟的人的邻居喝矿泉水问题：谁养鱼？这道迷题出自1981年柏林的德国逻辑思考学院。据说世界上只有2％的人能出答案。就连大名鼎鼎的爱因斯坦也成为此题大伤脑筋。-original entitled : 1. Have five five colors of the two houses. Each a master of the house three different nationality. Each of these five individuals only drink one brand of beverages, just the one brand of cigarettes, only raised a pet 4. No one has the same pet, and pumping the same brand of cigarettes, drink the same brand of beverages known conditions : 1. Britons living in Red House Lane 2. Swede custody of a dog 3. Denmark tea 4. Green house at the White house left five. Green coffee house owner 6. Pallmall pumping smoke of keeping a bird 7. Huang owner pumped dunhill tobacco 8. Living in the middle of the house to drink milk 9. Norwegians living in the first house and 10. Mixed pumping smoke and cats live in the adjacent 11. Horse people live in pumping dunhill smoke next to the 12
Date : 2025-12-18 Size : 3kb User : 刘志雄
[Mathimatics-Numerical algorithms] chesslogic DL : 0: 对弈程序采用了多种搜索算法.以下是本程序主要的类说明: 1.CEveluation类:估值类,对给定的棋盘进行估值. 2.CMoveGenerator类:走法产生器,对给定的棋盘局面搜索出所有可能的走法. 3.CSearchEngine类:搜索引擎基类. 4.CNegaMaxEngine类:负极大值法搜索引擎. 5.CAlphaBetaEngine类:采用了Alpha-Beta剪枝技术的搜索引擎. 6.CFAlphaBetaEngine类:fail-softalpha-beta搜索引擎. 7.CHistoryHeuristic类:历史启发类. 8.CAlphabeta_HHEngine类:带历史启发的Alpha-Beta搜索引擎. 9.CAspirationSearch类:渴望搜索引擎. 10.CIDAlphabetaEngine类:迭代深化搜索引擎. 11.CMTD_fEngine类:MTD(f)搜索引擎. 12.CTranspositionTable类:置换表. 13.CAlphaBeta_TTEngine类:加置换表的Alpha-Beta搜索引擎. 14.CPVS_Engine类:极小窗口搜索引擎. 15.CNegaScout_TT_HH类:使用了置换表和历史启发的NegaScout搜索引擎. 本程序还具有悔棋,还原功能,还可以记录走法.-err
Date : 2025-12-18 Size : 1.8mb User : wiali
[Mathimatics-Numerical algorithms] algorithm DL : 0: 考虑由下列数所组成的表。你的工作是删去尽可能少的数使得留下来的数以升序排列 9 44 32 12 7 42 34 92 35 37 41 8 20 27 83 64 61 28 39 93 29 17 13 14 55 21 66 72 23 73 99 1 2 88 77 3 65 83 84 62 5 11 74 68 76 78 67 75 69 70 22 71 24 25 26-Considered integers consist of the following table. Your job is to delete as less as possible integers in order to let the lefts in ascending order 9 44 32 12 7 42 34 92 35 37 41 8 20 27 83 64 61 28 39 93 29 17 13 14 55 21 66 72 23 73 99 1 2 88 77 3 65 83 84 62 5 11 74 68 76 78 67 75 69 70 22 71 24 25 26
Date : 2025-12-18 Size : 35kb User :
[Mathimatics-Numerical algorithms] sideeffec DL : 0: This programme is for understanding the side effec.In the above program, the side effect has occurred. In sum1, first i is calculate first for that,i/2 is 5 and then fun(&i) is called that is return 41.so the result is 46. In sum2, first fun(&j) is called, that’s return 41 and update the j is 14.so j/2 is 7.result is 48. -This programme is for understanding the side effec.In the above program, the side effect has occurred. In sum1, first i is calculate first for that,i/2 is 5 and then fun(&i) is called that is return 41.so the result is 46. In sum2, first fun(&j) is called, that’s return 41 and update the j is 14.so j/2 is 7.result is 48.
Date : 2025-12-18 Size : 822kb User : kabir
[Mathimatics-Numerical algorithms] 09-7-14 DL : 0: 四川大学ACM图论资料课件内含部分源码，全部课件-ACM, Sichuan University courseware includes some of graph theory information source, all courseware
Date : 2025-12-18 Size : 98kb User : gold
[Mathimatics-Numerical algorithms] 14-3 DL : 0: 例如：编译：mpicc app_match.c邻app_match 运行：可以使用命令mpirun - np的尺寸app_match mnk来运行该串匹配程序，其中大小是所使用的处理器个数，米表示文本串长度，氮为模式串长度，钾为允许误差长度。本实例中使用了尺寸为3个处理器，米= 7，n = 2时，k = 1时。 mpirun - np的3 app_match 7 2 1 运行结果：在节点0的文字是在节点0的模式是共有2匹配在节点0 节点1上的文本为在节点1的模式是共有2匹配的节点1 节点2上的文字是天然抗氧化剂在节点2的模式为共有2匹配的节点2 说明：该运行实例中，令文本串长度为7，随机产生的文本串为asasbsb，分布在3个节点上模式串长度为2，随机产生的模式串为为。最后，节点0,1和二上分别得到两个近似匹配位置。 -For example: Compile: mpicc app_match.c o app_match Run: You can use the command mpirun- np size app_match mnk to run the string matching procedure, which size is the number of processors used, the text string length in meters, the length of pattern of nitrogen and potassium to allow for error length. The examples used in the size of three processors, m = 7, n = 2 时, k = 1 时. mpirun- np of 3 app_match 7 2 1 Run Results: Node 0 in the text is Node 0 in the model is Total 2 match at the node 0 Node 1 on the text Node 1 is in the mode A total of 2 matching node 1 Node 2, the text is a natural antioxidant Node 2 in the model A total of 2 matching node 2 Description: The running instance, so that the text string of length 7, randomly generated text string to asasbsb, located in three nodes mode string length is 2, the model randomly generated string to the. Finally, the nodes 0,1 and 2, respectively, are two approximate matching position.
Date : 2025-12-18 Size : 5kb User : aaa
[Mathimatics-Numerical algorithms] lsa-poly.tar DL : 0: “lsa-poly” is a polynomial least square fitting tool. e.g.: lsa-poly -f data.dat -x 1 -y 2 -n “-7 -2 0 4” -oe will fit column 2 with column 1 of data.dat, and the fitting function consists of x^-7. x^-2, x^0 and x^4 terms. ===================== The source code is compressed with two precompiled binaries, the MacOS X 10.9 and Ubuntu 11 on Linux 3.0.0.14 (64 bit).
Date : 2025-12-18 Size : 85kb User : 孙谨