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Search - ai - List
[
CSharp
]
2005102611013310480
DL : 0
最佳矩阵连乘 给定n个矩阵{A1,A2,…An},其中Ai与A i+1是可乘的,i=1,2…,n-1。考察这n个矩阵的连乘积A1A2…An。矩阵A和B可乘的条件是矩阵A的列数等于矩阵B的行数。若A是一个p×q矩阵,B是一个q×r矩阵,则其乘积C=AB是一个p×r矩阵,需要pqr次数乘。 由于矩阵乘法满足结合律,故计算矩阵的连乘积可以有许多不同的计算次序。例如,设3个矩阵{A1,A2,A3}的维数分别为10×100,100×5,和5×50。若按加括号方式((A1A2)A3)计算,3个矩阵连乘积需要的数乘次数为10×100×5+10×5×50=7500。若按加括号方式(A1(A2A3))计算,3个矩阵连乘积总共需要10×5×50+10×100×50=75000次数乘。由此可见,在计算矩阵连乘积时,加括号方式,即计算次序对计算量有很大影响。 矩阵连乘积的最优计算次序问题,即对于给定的相继n个矩阵{A1,A2,…An}(其中矩阵Ai的维数为pi-1×p,i=1,2,…,n),确定计算矩阵连乘积A1,A2,…An的计算次序,使得依此次序计算矩阵连乘积需要的数乘次数最少。 -best matrix continually multiply given n matrix (A1, A2, ... An), Ai and A is a mere i, i = 1, 2 ..., n-1. N explore the link matrix product ... An A1A2. Matrices A and B can either condition is out of the matrix A few matrix B is the number of rows. If A is a p q matrix B is a q-r-matrix, its product C = AB is a p r matrix, the number required by pqr. Because matrix multiplication meet the law of combination, it's even calculated matrix product can be calculated in many different priorities. For example, the matrix-based 3 (A1, A2, A3) dimension of 10 100, 100 5 5 and 50. If bracketed by the way ((A1A2) A3), even three product matrix multiplication in the number of 10 100 10 5 50 = 7,500. If bracketed by the way (A1 (A2A3)), three matrix product even need a total of 10 5 50
Date
: 2008-10-13
Size
: 6kb
User
:
肿事右
[
CSharp
]
FengartOthello_V1.0_Source
DL : 0
整体来说,这份代码是能够实现了黑白棋的智能下棋功能,而且也不弱,我想在国内应该找不到.NET版、而且高智能的黑白棋源代码了。 本来没打算发源代码,吝啬?主要我怕部分“懒人”修改本程序的界面,然后作为自己的东东去发布,还美其名曰“原创”(汗!),我想你不会是这样的人。 发源代码的目的是抛砖引玉(小弟我抛砖,有玉的尽量砸过来)。AI算法是通用的,并不局限于某种棋,你可以取其精华去其糟粕,少走很多不必要的弯路。 源码也方便了那些一心只想搞算法而不想花心思在界面上的朋友。 -overall, this code is to achieve a smart player reversi functional, but not weak, I would like to be unable to find domestic.NET version, but high intelligence reversi the source code. Originally did not intend to originate code, mean? I fear that the main part of "lazy" to modify this procedure interface, and then as their Eastern to publish, also the name of the "original" (Khan!) , I think you will not be that kind of person. Birthplace of the code is to encourage the (younger I parabolic brick, as the smash-up). AI algorithms is a common, is not confined to a game, you can select the essence to its dross and go to a lot of unnecessary detours. FOSS is also convenient for those who would like to engage wholeheartedly algorithm does not want the effort to interface f
Date
: 2008-10-13
Size
: 2.83mb
User
:
Feng
[
CSharp
]
AIMI561
DL : 0
This the free version of my Basis of AI Backprop designed to accompany my not yet published textbook, _The Basis of AI_. This program contains enough features for students in an ordinary AI or Neural Networking course. It includes the quickprop and delta-bar-delta algorithms for faster training and a fast integer version for machines without floating point hardware. This particular package includes C source for DOS and UNIX, examples, an ASCII manual and a number of DOS binaries. The binaries are for systems with floating point hardware (bp.exe), one for systems without floating point hardware (bp486sx.exe) and an integer version binary (ibp486sx.exe) for systems without floating point hardware.
Date
: 2008-10-13
Size
: 2.28mb
User
:
dsoiufsodiuf
[
CSharp
]
20080101
DL : 0
c#写的非常优秀的棋牌类游戏源码,包含AI及机器人的难度调节算法.
Date
: 2008-10-13
Size
: 101.36kb
User
:
lyd
[
CSharp
]
tictactoePL
DL : 0
井字遊戲原始代碼,使用C Sharp寫成,有AI和人機介面。
Date
: 2008-10-13
Size
: 4.27kb
User
:
omegaCD
[
CSharp
]
50844531C
DL : 0
《C#语言学习利器——AI-CODE坦克机器人》-源代码
Date
: 2008-10-13
Size
: 48.66kb
User
:
李楠
[
CSharp
]
WebSite1
DL : 0
C#语言编写的一个AI动物识别程序,简单,规则库为文件输入输出
Date
: 2008-10-13
Size
: 3.63kb
User
:
张言国
[
CSharp
]
2005102611013310480
DL : 0
最佳矩阵连乘 给定n个矩阵{A1,A2,…An},其中Ai与A i+1是可乘的,i=1,2…,n-1。考察这n个矩阵的连乘积A1A2…An。矩阵A和B可乘的条件是矩阵A的列数等于矩阵B的行数。若A是一个p×q矩阵,B是一个q×r矩阵,则其乘积C=AB是一个p×r矩阵,需要pqr次数乘。 由于矩阵乘法满足结合律,故计算矩阵的连乘积可以有许多不同的计算次序。例如,设3个矩阵{A1,A2,A3}的维数分别为10×100,100×5,和5×50。若按加括号方式((A1A2)A3)计算,3个矩阵连乘积需要的数乘次数为10×100×5+10×5×50=7500。若按加括号方式(A1(A2A3))计算,3个矩阵连乘积总共需要10×5×50+10×100×50=75000次数乘。由此可见,在计算矩阵连乘积时,加括号方式,即计算次序对计算量有很大影响。 矩阵连乘积的最优计算次序问题,即对于给定的相继n个矩阵{A1,A2,…An}(其中矩阵Ai的维数为pi-1×p,i=1,2,…,n),确定计算矩阵连乘积A1,A2,…An的计算次序,使得依此次序计算矩阵连乘积需要的数乘次数最少。 -best matrix continually multiply given n matrix (A1, A2, ... An), Ai and A is a mere i, i = 1, 2 ..., n-1. N explore the link matrix product ... An A1A2. Matrices A and B can either condition is out of the matrix A few matrix B is the number of rows. If A is a p q matrix B is a q-r-matrix, its product C = AB is a p r matrix, the number required by pqr. Because matrix multiplication meet the law of combination, it's even calculated matrix product can be calculated in many different priorities. For example, the matrix-based 3 (A1, A2, A3) dimension of 10 100, 100 5 5 and 50. If bracketed by the way ((A1A2) A3), even three product matrix multiplication in the number of 10 100 10 5 50 = 7,500. If bracketed by the way (A1 (A2A3)), three matrix product even need a total of 10 5 50
Date
: 2026-01-10
Size
: 6kb
User
:
肿事右
[
CSharp
]
FengartOthello_V1.0_Source
DL : 0
整体来说,这份代码是能够实现了黑白棋的智能下棋功能,而且也不弱,我想在国内应该找不到.NET版、而且高智能的黑白棋源代码了。 本来没打算发源代码,吝啬?主要我怕部分“懒人”修改本程序的界面,然后作为自己的东东去发布,还美其名曰“原创”(汗!),我想你不会是这样的人。 发源代码的目的是抛砖引玉(小弟我抛砖,有玉的尽量砸过来)。AI算法是通用的,并不局限于某种棋,你可以取其精华去其糟粕,少走很多不必要的弯路。 源码也方便了那些一心只想搞算法而不想花心思在界面上的朋友。 -overall, this code is to achieve a smart player reversi functional, but not weak, I would like to be unable to find domestic.NET version, but high intelligence reversi the source code. Originally did not intend to originate code, mean? I fear that the main part of "lazy" to modify this procedure interface, and then as their Eastern to publish, also the name of the "original" (Khan!) , I think you will not be that kind of person. Birthplace of the code is to encourage the (younger I parabolic brick, as the smash-up). AI algorithms is a common, is not confined to a game, you can select the essence to its dross and go to a lot of unnecessary detours. FOSS is also convenient for those who would like to engage wholeheartedly algorithm does not want the effort to interface f
Date
: 2026-01-10
Size
: 2.83mb
User
:
Feng
[
CSharp
]
AIMI561
DL : 0
This the free version of my Basis of AI Backprop designed to accompany my not yet published textbook, _The Basis of AI_. This program contains enough features for students in an ordinary AI or Neural Networking course. It includes the quickprop and delta-bar-delta algorithms for faster training and a fast integer version for machines without floating point hardware. This particular package includes C source for DOS and UNIX, examples, an ASCII manual and a number of DOS binaries. The binaries are for systems with floating point hardware (bp.exe), one for systems without floating point hardware (bp486sx.exe) and an integer version binary (ibp486sx.exe) for systems without floating point hardware.
Date
: 2026-01-10
Size
: 2.28mb
User
:
dsoiufsodiuf
[
CSharp
]
20080101
DL : 0
c#写的非常优秀的棋牌类游戏源码,包含AI及机器人的难度调节算法.-c# written excellent source of Card games, including the difficulty of AI and robot-conditioning algorithm.
Date
: 2026-01-10
Size
: 260kb
User
:
lyd
[
CSharp
]
tictactoePL
DL : 0
井字遊戲原始代碼,使用C Sharp寫成,有AI和人機介面。-Tic-tac-toe game is the original code, written using C Sharp, there are AI and human-machine interface.
Date
: 2026-01-10
Size
: 4kb
User
:
omegaCD
[
CSharp
]
50844531C
DL : 0
《C#语言学习利器——AI-CODE坦克机器人》-源代码
Date
: 2026-01-10
Size
: 48kb
User
:
李楠
[
CSharp
]
Five_chess
DL : 0
采用c#编程的人机对战的五子棋程序,AI智能采用贪心算法和极大极小值算法,程序有详尽的注释,适合参考-C# programming using the man-machine war of Gobang procedures, AI algorithms and intelligent use of greedy algorithm for max-min value, the program has detailed notes for reference
Date
: 2026-01-10
Size
: 127kb
User
:
王德安
[
CSharp
]
D9820AISingleBufferCheck
DL : 0
凌华科技数字化仪C#编程实例,AI采集,双BUFFER-Adlink Technology digitizers example C# programming, AI Acquisition, double BUFFER
Date
: 2026-01-10
Size
: 54kb
User
:
david
[
CSharp
]
hannuota
DL : 0
时间太长忘了,这讲的是什么,艾。都是简单的一些东西-Forgot a long time, it stresses what is Ai. Are some simple things
Date
: 2026-01-10
Size
: 6kb
User
:
尹恒星
[
CSharp
]
Form1
DL : 0
c# code for chess game that moves on click and computer moves black. i am still working on the AI part so the black moves are actually a random
Date
: 2026-01-10
Size
: 7kb
User
:
bobby
[
CSharp
]
Identifier
DL : 0
人工智能 动物识别程序,可以自动根据规则是被动物-AI animal identification program, you can automatically based on rules are animals
Date
: 2026-01-10
Size
: 1.94mb
User
:
cfwang
[
CSharp
]
AI
DL : 0
Badming 代码 下面是 Badming 写的一些关于 AI 的 c++ 代码, badming 认为当代码复杂到一定程度,程序给人类的反应,人类已 经分不清是不是死的代码或是真的有意识产生了。下面的代码实际是简单脚本的处理代码。 Badming 认为,现代 的脚本语言实际上是未来 Ai 的前身。 -Artificial intelligence
Date
: 2026-01-10
Size
: 2kb
User
:
zhanghai
[
CSharp
]
Intelligent-AI-pathfinding-snake
DL : 0
智能AI寻路贪吃蛇源码及可执行程序。 整个制作过程可以分为两大部分 第一部分是做出贪吃蛇的雏形,可以手动控制我们的蛇移动起来并且能吃东西(也就是常规意义上的基本贪吃蛇) 第二部分是让蛇自己动起来!-Intelligent AI pathfinding snake source code and executable. The entire production process can be divided into two parts The first part is to make the prototype of the snake, we can manually control the snake can move up and to eat (that is, conventional sense of the fundamental snake) The second part is to make the snake move yourself!
Date
: 2026-01-10
Size
: 672kb
User
:
张武政
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