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[Data structsBST BBT

Description: 数 据 结 构 大型 作业3.1输入一个数列L,生成一棵二叉排序树T;3.2对二叉排序树T作中序遍历,输出结果;3.3计算二叉排序树T的平均查找长度, 输出结果;3.4判断二叉排序树T是否为平衡二叉树,输出信息“OK!”/“NO!”;3.5再使用上述数列L,生成平衡的二叉排序树BT,每当插入新元素,发现当前的二叉排序树BT不是平衡的二叉排序树,则立即将它转换成新的平衡的二叉排序树BT;3.6计算平衡的二叉排序树BT的平均查找长度,输出结果。3.6分析对比未平衡化的二叉排序树和平衡的二叉排序树的查找效率(最好、最坏平均比较关键字数)-data structure large operations into a 3.1 L series, generating a binary tree Sort T; 3.2 pair of two fork-tree T for medium preorder, output results; 3.3 Ranking calculation Binary Tree Search T's average length of the output; 3. four judgment ordering two trees T fork whether balanced binary tree, the output message "OK!"/"NO!" ; again using the 3.5 series L, generate balanced binary tree sort BT, whenever insert a new element, found the current binary sort tree is not-BT Value of two binary sort tree, it will be immediately converted into the new balance of the two fork-tree BT; 3.6 Calculation balanced binary tree sort BT search length of the average output results. 3.6 Comparative Analysis of the outstanding balance of two fork-tree and balanced binary tree s
Platform: | Size: 4096 | Author: 洪玲叶 | Hits:

[Other综合实验哈夫曼编码

Description: 1.n个叶结点,权分别为w1,w2,• • • ,wn的二叉树中,带权路径长度WPL最小的二叉树叫最优二叉树, 也叫霍夫曼树。 2.霍夫曼算法:1)根据给定的权值{w1,w2,• • • ,wn}构造n个二叉树F={T1,T2,• • • ,Tn}每个Ti只有一个根结点,权为wi。2)在F中选取两棵根结点的权值最小的树 构成一棵新的二叉树,其根的权值为左右子树根的权值的和。3)F中删去这两棵树,加上新得的树。4)重复2)3)直到只剩一棵树。 -1. N leaf nodes, the right to w1, w2,# 8226# 8226, wn the binary tree, with the right path length WPL smallest binary tree called Optimal binary tree, the tree is also called Hoffman. 2. Hoffman algorithm : 1) According to the weights (w1, w2,# 8226# 8226# 8226, wn) n binary tree structure F = (T1, T2,# 8226# 8226# 8226, Tn) each only a Ti Root, the right to wi. 2) In 1984 two F Root in the value of the right to the smallest tree constitute a new binary tree, the roots of the right value for the son around the roots and the value of the right. 3) F deleted these two trees, coupled with the new tree. 4) repeat 2) 3) until only a tree.
Platform: | Size: 1024 | Author: yy | Hits:

[Data structshuffmancode111

Description: huffman完整源代码C语言实现,有本人超级详细解释(看不懂你去跳楼吧) 算法设计: 1、对给定的n个权值{W1,W2,W3,...,Wi,...,Wn}构成n棵二叉树的初始集合F={T1,T2,T3,...,Ti,...,Tn},其中每棵二叉树Ti中只有一个权值为Wi的根结点,它的左右子树均为空。(为方便在计算机上实现算法,一般还要求以Ti的权值Wi的升序排列。) 2、在F中选取两棵根结点权值最小的树作为新构造的二叉树的左右子树,新二叉树的根结点的权值为其左右子树的根结点的权值之和。 3、从F中删除这两棵树,并把这棵新的二叉树同样以升序排列加入到集合F中。 4、重复二和三两步,直到集合F中只有一棵二叉树为止。 -Huffman complete C source code language, I have super-detailed explanation (you do not understand it jumped) algorithm design : one, the right to the right values n (W1, W2, W3 ,..., Wi ,..., Wn) n trees constitute the binary tree initial pool F = (T1, T2, T3, ... Ti ,..., Tn), which is indeed a binary tree Ti only a right to the value of Wi Root. it's about subtrees are empty. (For the convenience of the computer algorithm, the general also demanded the right to Ti Wi value of ascending.) 2. in 1984 two F Root weights smallest tree as a new structure of the binary tree around subtrees, new Binary Tree Root in the right value for their son around the tree Root and the right value. 3, F deleted from this two trees, and how the new binary tree in the same ascending into the pool F. 4, re
Platform: | Size: 11264 | Author: 乐乐 | Hits:

[Software Engineering2-3-trees

Description: It s a note about data structure. Tree---self balancing and rotate-It's a note about data structure. Tree--- se lf balancing and rotate
Platform: | Size: 79872 | Author: Benny Van | Hits:

[Software Engineeringshujujiegou-erchashu

Description: 叉排序树与平衡二叉排序树基本操作的实现 用二叉链表作存储结构 (1)以回车( \n )为输入结束标志,输入数列L,生成二叉排序树T; (2)对二叉排序树T作中序遍历,输出结果; (3)计算二叉排序树T的平均查找长度,输出结果; (4)输入元素x,查找二叉排序树T,若存在含x的结点,则删除该结 点,并作中序遍历(执行操作2);否则输出信息“无结点x”; (5)判断二叉排序树T是否为平衡二叉树,输出信息“OK!”/“NO!”;-fork trees and balanced binary tree order to achieve the basic operation of the binary tree used for the storage structure (1), carriage return ( \ n) to mark the end of the importation, importation of L series, generate binary tree Sort T; (2) Ranking of two forks to make the tree T preorder, and the output results; (3) Calculations binary tree T ranking on the average search length, output; (4) Input elements x, find two tree fork Sort T, if x exists with the node, then remove the nodes, and make the preorder (execution 2); Otherwise output "node x"; (5) to determine the order of two trees T fork whether balanced binary tree, and the output message "OK!"/"NO!" ;
Platform: | Size: 2048 | Author: 胡图 | Hits:

[JSP/JavaDj3.9

Description: java 非长好的反编译工具哦可哦可哦棵 -java non-long good decompile tool can Oh oh oh, trees can be
Platform: | Size: 4646912 | Author: liyue | Hits:

[Data structstwol

Description: 二叉树的建立与遍历 可实现: (1)树的创建采用先序方式,用特殊符号0表示左、右子树为空 (2)每次输入一个节点的值,可以根据自己的需要设计不同的节点结构 (3)节点的值为非零数 (4)可以()形式输出创建的树 (5)用先序后序和中序遍历树 (6)销毁树 -Establishment and tree traversal can be achieved: (1) tree created using the first order approach, with special symbols 0 express the left and right subtree is empty (2) for each input the value of a node, you can according to their own needs Design of different node structure (3) non-zero value of the node number (4) can () to create the form of the output tree (5) after the first sequence and the sequence of traversal tree (6) the destruction of trees
Platform: | Size: 1024 | Author: 林渡 | Hits:

[Otherds_baogao

Description: 哈夫曼编码与解码演示程序 1、 从初始界面中给出的信息选择相应功能; 2、 从终端读入字符集大小n,以及n个字符和n个权值。建立huffman树,并将它存于文件hfmtree.dat中 3、 利用已经建好的huffman树对文件tobetran.dat中的正文进行编码,然后将结果存入文件codefile.dat中; 4、 利用已经建好的huffman树将文件codefile.dat中的代码进行译码,结果存入文件textfile.dat中; 5、 将文件codefile.dat以紧凑格式显示在终端上,每行50个; 6、 将已在内存中的huffman树以直观的方式显示在终端上; -Huffman encoding and decoding demo 1, from the initial information given in the interface to select the appropriate function 2, read from the terminal character set size n, and n and n characters of the right values. Huffman tree establishment, and it is stored in documents hfmtree.dat in 3, has been built using huffman trees tobetran.dat the document is encoded in the body, and then the results into a document in codefile.dat 4, has been built using huffman tree will be a good document codefile.dat decoding of the code, the result into the document in textfile.dat 5, in order to compact the file format codefile.dat displayed on the terminal, 50 per line 6, will have huffman tree in memory intuitive way to show that in the terminal
Platform: | Size: 273408 | Author: 郑亮 | Hits:

[Windows Develop234tree

Description: 2-3-4Trees and Red-Black Trees 2-3-4Trees and Red-Black Trees-2-3-4Trees and Red-Black Trees 2-3-4Trees and Red-Black Trees 2-3-4Trees and Red-Black Trees
Platform: | Size: 121856 | Author: Ardy | Hits:

[ADO-ODBCaglo7-1

Description: 二叉树的基本算法。(1) 输出二叉树B; (2) 输出二叉树B的深度; (3) 输出H结点的左、右孩子结点值; (4) 输出二叉树B的宽度; (5) 输出二叉树B的结点个数; 输出二叉树B的叶子结点个数 -The basic algorithm for binary tree。(1) output binary tree B (2) The output of a binary tree B of depth (3) The output of H nodes left and right child node value (4) outputs a binary tree B, width (5) output node B, the number of binary trees Output binary tree B, the number of leaf nodes
Platform: | Size: 1024 | Author: xjj | Hits:

[Data structsaglo7

Description: (一) 编写一个程序LAGO7-1.CPP,实现二叉树的各种运算,并在此基础上设计一个主程序完成如下功能。 (1) 输出二叉树B; (2) 输出二叉树B的深度; (3) 输出H结点的左、右孩子结点值; (4) 输出二叉树B的宽度; (5) 输出二叉树B的结点个数; 输出二叉树B的叶子结点个数 -(A) to prepare a program LAGO7-1.CPP, to achieve a variety of binary operations, and on this basis, design a main program performs the following functions. (1) output binary tree B (2) The output of a binary tree B of depth (3) The output of H nodes left and right child node value (4) outputs a binary tree B, width (5) output node B, the number of binary trees (6) outputs a binary tree B, the number of leaf nodes
Platform: | Size: 2048 | Author: xjj | Hits:

[Mathimatics-Numerical algorithmsAlgorithms.in.C.Parts.1-4.Fundamentals.Data.Struct

Description: 经典算法书(中文版).《C算法》介绍了当今最重要的算法,共分3卷,本书是第1卷。第1卷分4部分、共16章。第一部分“基础知识”(第1~2章)介绍了基本算法分析原理。第二部分“数据结构”(第3~5章)讲解算法分析中必须掌握的数据结构知识。主要包括基本数据结构、抽象数据结构、递归和树。第三部分“排序”(第6~11章)按章节顺序分别讨论了基本排序方法(如选择排序、插入排序、冒泡排序、希尔排序等)、快速排序方法,归并和归并排序方法、优先队列与堆排序方法、基数排序方法以及特殊目的排序方法,并比较了各种排序方法的性能特征。第四部分“搜索”(第12~16章)在进一步讲解符号表、树等抽象数据类型的基础上,重点讨论哈希方法、基数搜索以及外部搜索方法。-This particular book, Parts 1-4, represents the essential first half of Sedgewick s complete work. It provides extensive coverage of fundamental data structures and algorithms for sorting, searching, and related applications. The algorithms and data structures are expressed in concise implementations in C, so that you can both appreciate their fundamental properties and test them on real applications. Of course, the substance of the book applies to programming in any language. Highlights * Expanded coverage of arrays, linked lists, strings, trees, and other basic data structures * Greater emphasis on abstract data types (ADTs) than in previous editions * Over 100 algorithms for sorting, selection, priority queue ADT implementations, and symbol table ADT (searching) implementations * New implementations of binomial queues, multiway radix sorting, Batcher s sorting networks, randomized BSTs, splay trees, skip lists, multiway tries, and much more * Increased quantit
Platform: | Size: 19883008 | Author: wang | Hits:

[JSP/Javajquerytree

Description: 打造基于jQuery的高性能TreeView 根据我的项目实践情况,主要是几个关键点: 1:支持静态的树,即一次性将全部数据加载到客户端。* 2:异步树,即一次只加载一级或若干级节点,子节点可以异步加载数据。 3:Checkbox树(可能是静态树也可能是异步树),用于选择(如选择组织机构,选择数据字典项)等,最好是能够支持节点级联(这个是难点) 4:能够承载大数据量,并性能表现优异 5:能够在主流浏览器中运行良好 -TreeView jQuery-based, high-performance build my project based on practical circumstances, mainly a few key points: 1: Support for static trees that once all the data will be loaded to the client.* 2: Asynchronous tree, that is, only load one or more of the first level nodes, child nodes can load data asynchronously. 3: Checkbox tree (the tree may also be asynchronous static tree), used to select (such as the choice organization, select the data dictionary entry), etc., it is better to support node cascade (this is difficult) 4: capable of carrying large the amount of data, and good performance in 5: the ability to run the browser in the mainstream good
Platform: | Size: 71680 | Author: sunhb1990 | Hits:

[Data structstrees

Description: 二叉树也是递归定义的,其结点有左右子树之分,逻辑上二叉树有五种基本形态: (1)空二叉树——(a); (2)只有一个根结点的二叉树——(b); (3)右子树为空的二叉树——(c); (4)左子树为空的二叉树——(d); (5)完全二叉树——(e)注意:尽管二叉树与树有许多相似之处,但二叉树不是树的特殊情形。 -Binary tree is recursively defined, and its sub-tree nodes are so divided, there are five basic logical form of binary tree: (1) empty binary tree- (a) (2) there is only one root node Binary Tree- (b) (3) the right subtree of the binary tree is empty- (c) (4) the left subtree of the binary tree is empty- (d) (5) completely Binary Tree- (e) Note: Although the binary tree and the tree has many similarities, but the binary tree is not a special case.
Platform: | Size: 1024 | Author: zn | Hits:

[Printing programexp2

Description: (1)按逆波兰表达式建立树 (2) 输出表达式树的各种遍历的结果。 (3) 打印表达式树。 (4) 删除表达式树。 -(1) The establishment of trees by Reverse Polish Notation (2) output a variety of expression tree traversal results. (3) Print the expression tree. (4) Delete an expression tree.
Platform: | Size: 1024 | Author: 李联合 | Hits:

[Windows DevelopCPP

Description: c++,入门代码大全。适合入门与初学者,以及有一定基础的人下载- Chapter 1 Introduction 1 Chapter 2 Algorithm Analysis 5 Chapter 3 Lists, Stacks, and Queues 9 Chapter 4 Trees 29 Chapter 5 Hashing 41 Chapter 6 Priority Queues (Heaps) 45 Chapter 7 Sorting 53 Chapter 8 The Disjoint Set 59 Chapter 9 Graph Algorithms 63 Chapter 10 Algorithm Design Techniques 77 Chapter 11 A
Platform: | Size: 463872 | Author: 信息管理 | Hits:

[Data structstree-hfut

Description: 合肥工业大学数据结构试验五树和森林 包括完整的实验要求、实验预习报告、实验最终报告 实验要求: <1>将一棵树(或森林)转换为二叉树。 <2>求森林的高度。 <3>按层次方式遍历森林。 <4>输出一个森林中每个结点的值及其对应的层次数。 <5>输出一个森林的广义表形式-Hefei University of the data structure test five trees and forests, including the complete experimental requirements prelab report, the experiments final report experimental requirements: < 1> a tree (or forest) is converted to a binary tree. < 2> and forest height. < 3> hierarchical traversal forest. < 4> output value of each node in a forest and its corresponding number of levels. < 5> output generalized list in the form of a forest
Platform: | Size: 604160 | Author: 石帆 | Hits:

[Windows DevelopHuffman

Description: 用mfc完成的哈夫曼树的功能 给出一组关键字,建立哈夫曼树,完成以下功能: (1)完成关键字来自于输入 (2)完成关键字来自于文本 (3)完成编码,显示编码结果 (4)画树-Completed using mfc Huffman tree function gives a set of keywords, the establishment of the Huffman tree, complete the following functions: (a) completion of keywords from the input (2) completion of keywords from the text (3) complete coding display coding results (4) painting trees
Platform: | Size: 8192 | Author: 黄愫芸 | Hits:

[Otherlibiary

Description: 图书管理基本业务活动包括:对一本书的采编入库、清除库存、借阅和归还等等。试设 计一个图书管理系统,将上述业务活动借助于计算机系统完成。 要求: (1)每种书的登记内容至少包括书号、书名、著者、现存量和总库存量等五项。 (2)作为演示系统,不必使用文件,全部数据可以都在内存存放。要用 B-树(4 阶树) 对书号建立索引,以获得高效率。 (3)系统应有以下功能: 采编入库、清除库存、借阅、归还、显示(以凹入表的形式显示)等。-Library management basic business activities include: editing of a book storage, remove stock, borrow and return and so on. Try to design a library management system, the operations described above by means of a computer system to complete. Requirements: register content (1) of each book includes at least ISBN, title, author, and total inventory of existing other five. (2) as a demonstration system, do not use a file, all the data can all be stored in memory. Use the B- tree (4 TREES) ISBN indexed to obtain high efficiency. (3) The system should have the following features: editing storage, clearing inventory, borrow, return, display (in the form of a concave of the table) and the like.
Platform: | Size: 3072 | Author: 杨若兮 | Hits:

[Algorithmsgu250

Description: sgu250:Constructive Plan 题目大意: 给出一个n∗ m的01矩阵,0表示不能放,1表示能放,在其中放入三个矩形,要求满足如下条件: 1.每个矩形面积大于0。 2.这些矩形必须是一个联通块,矩形之间不能重叠。 3.矩形的左边界在同一条线上。 4.中间矩形的横向长度小于两边矩形的横向长度。 求出最大的三个矩形的总面积,无解输出− 1。-250. Constructive Plan time limit per test: 0.25 sec. memory limit per test: 65536 KB input: standard output: standard Oh, no! - Petya said, walking around his recently bought ground plot. Petya wants to build a new house on it. According to Petya s building project the house should look above like C character. There are many trees growing on Petya s plot. But everyone who cuts down a tree in Petya s country is sent to cut down trees for the rest of his life. So first of all Petya has to choose a place for building the house without cutting any tree. He is feeling that he is not able to find the solution on his own, so he decided to ask you to help him. The task is simplified a little by the fact that Petya s plot has a rectangular shape of size N*M, divided into 1*1 square cells. For each cell it is known whether there are any trees growing there. House can t occupy cells where trees grow. Fortunately Petya could explain how his house must look above. 1) H
Platform: | Size: 1024 | Author: owaski | Hits:
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