Welcome![Sign In][Sign Up]
Location:
Search - 私钥

Search list

[Crack HackRSA_Prog

Description: rsa数字签名公钥加密私钥解密c++源代码-The C++ source program of RSA digital signature about encryption with public key and decryption with secret key.
Platform: | Size: 5387 | Author: 冉冉 | Hits:

[Crack Hack混合密码体制数字签名

Description: JAVA实现的可以采用公钥私钥加密解密程序,包括DES,RAS算法-JAVA the private key can be the public key encryption and decryption procedures, including DES, RAS Algorithm
Platform: | Size: 12174 | Author: 张丽媛 | Hits:

[Crack HackKey_src

Description: 编程中获得会话密钥匙非常重要的 MSDN 展示了一种使用私钥的方法。 但是微软的这个在MSDN中例子相当的长。 本文下面介绍的这个方法不仅更快而且更有效 -Programming cryptographic key conversation was very important MSDN demonstrated a method of using the private key. But in Microsoft's MSDN examples longer. Presented below is the method not only faster and more effectively
Platform: | Size: 2970 | Author: ww2aa | Hits:

[Windows DevelopELGAMAL.src

Description: 公钥加密方式,在windows平台下运行,并且可以在不改变公钥的方式下更新私钥,速度快,使用简便。-public key encryption methods in running under windows platform, and that they could not change the way the public key to update the private key, fast, easy to use.
Platform: | Size: 107783 | Author: 冯英 | Hits:

[Crack Hacksll

Description: 一种非线性流式加密算法,对称加密,它的加密和解密都是用同一把密钥完成。对称加密比不对称加密快得多,但缺点在于,它的安全性完全依赖于保持密码的机密性。 不对称加密,它要求使用两个密钥,一个是公共的(公钥),另一个是私有的(私钥)。每个密钥都要求使用另一个密钥来解密一条消息。它的复杂性提高,因此没有普及。 -a nonlinear flow encryption algorithms, symmetric encryption, the encryption and decryption are with the same key completion. Symmetric encryption faster than asymmetric encryption, but the drawback is that its security depends entirely on maintaining the confidentiality of passwords. Asymmetric encryption, it requires the use of two keys, one public (public key), and the other is owned by the (private key). Each key has requested the use of another key to a declassified information. Its complexity and therefore not universal.
Platform: | Size: 83522 | Author: 云容 | Hits:

[Crack HackRAS加密解密

Description: RAS加密机密的dotnet例子,在TEMP目录下有PublicKey.dat和privateKey.dat为公钥和私钥-RAS encryption of confidential dotnet example, TEMP directory in a PublicKey.dat for public key and privateKey.dat and private key
Platform: | Size: 11381 | Author: 杨微 | Hits:

[CA authsigncert

Description: 输入“java SignCert jim.cer >1.txt”运行程序,则程序将从密钥库中取出CA的私钥对lf.cer证书进行签名,输出结果已重定向到文件1.txt中,打开1.txt文件,可以看到如下有关新的证书的信息。 -type "java SignCert jim.cer
Platform: | Size: 1976 | Author: TH | Hits:

[CA authsecurity

Description: 说明: 1、里面有什么: 1.1、org.bouncycastle.*下的所有软件是bouncycastle组织开发的软件包 1.2、org.infosecurity.*下的软件包括: DES_CBC算法的实现 RSA算法的实现(包括:密钥生成、公钥加密和私钥解密、数字签名及签名验证) 数字信封的实现   利用数字信封实现大文件的加密、解密。 2、有什么用:   2.1 研究、学习信息安全中的密码学设计与实现技术。   2.2 当然如果大家觉得在其它地方用的上,我会觉得很高兴的。 3、还有什么改进: 3.1 对文件加密、解密的时候要频繁的IO,如果加一个缓冲区,比如10K、50K等, 只有缓冲区满了才写入DISK这样将提高效率。 3.2 RSA私钥积存的时候可以按PKCS8形式,再经BASE64编码保存比较好。-Note : 1, mean there : 1.1, org.bouncycastle .* of all software development organizations is bouncycastle package 1.2, org.infosecurity .* The software includes : DES_CBC algorithm to achieve the realization of the RSA algorithm (including : key generation, public key and private key encryption decryption, digital signatures and signature verification), the realization of digital envelope using digital envelope realize document encryption, decryption. Two, what is the use of : 2.1, learning the information security cryptography design and technology. 2.2 Of course, if you think in the other parts, I feel very happy. Three, what is there for improvement : 3.1 pairs of file encryption, decryption, and the time to frequent the IO, plus a buffer, such as 10K, 50K, the only buffer is needed for
Platform: | Size: 213582 | Author: 雷敏 | Hits:

[Other resourcestudentinfo

Description: 学生信息管理系统(JBuilder x 开发,采用RSA 512位公钥加密,私钥用于找回密码,2006-4-5)-student information management system (x JBuilder development, adoption 512 RSA public key encryption, the private key used to retrieve passwords 2006-2007-4 - 5)
Platform: | Size: 1847293 | Author: zy | Hits:

[Crack HackVC_RSA

Description: 一、RSA基本原理 对明文分组M和密文分组C,加密与解密过程如下: C = POW (M , e) mod n M = POW(C , d) mod n = POW(POW( M ,e), d) mod n=POW( M,e*d) 其中POW是指数函数,mod是求余数函数。 其中收发双方均已知n,发送放已知e,只有接受方已知d,因此公钥加密算法的公钥为 KU={ e , n},私钥为KR={d , n}。该算法要能用做公钥加密,必须满足下列条件: 1. 可以找到e ,d和n,使得对所有M<n ,POW(M ,e*d)=M mod n . 2. 对所有 M<n,计算POW (M , e)和POW(C , d)是比较容易的。 3. 由e 和n确定d是不可行的 -one, the basic tenets of RSA expressly group M and cipher block C, encryption and decryption process is as follows : C = POW (M, e) mod n = M POW (C, d) mod n = POW (POW (M, e), d) mod n = POW (M, e * d), which is an exponential function POW, mod is the pursuit of the remaining functions. Transceivers which both known n, send e Fang known, the only known recipient d, therefore the public key encryption algorithm for public key e KU = (n), private key for KR = (d, n). The algorithm could be used to be a public key encryption, must meet the following conditions : 1. E can be found, and d n, making all the right M
Platform: | Size: 5523 | Author: 烟翔 | Hits:

[Crack Hack7_Rsa

Description: RSA公钥加密算法基于大整数因式分解困难这样的事实。 选择两个素数,p,q。(一般p,q选择很大的数) 然后计算 z=p*q f=(p-1)(q-1) 选择一个n,使gcd(n,f)=1(gcd代表greatest common divider,一般n也选择一个素数), n和z就作为公钥。 选择一个s,0<s<f,满足n*s % f=1,s就作为私钥。-RSA public key encryption algorithm based on the integer factorization great difficulties to the fact. Choice of two prime numbers, p, q. (General p, q very few options) and then calculate the z = p * q = f (p-1) (q-1) Choose a n, so gcd (n, f) = a (gcd representatives greatest common divider. n general also choose a prime number), n and z on as a public key. One's choice, 0
Platform: | Size: 81637 | Author: fasf | Hits:

[Crack Hackibe_ext

Description: 椭圆曲线加密算法,生成用户私钥一步的源代码-elliptic curve encryption algorithm, users private key step in generating the source code
Platform: | Size: 1557 | Author: kanyu | Hits:

[Other resourcesigncryptionscheme

Description: :针对不可否认L-L-C-Z门限代理签密协议中存在的安全缺陷,提出了一个改进的门限代理签密协议.通过 对L-L-C-Z门限代理签密协议的密码分析,利用接收方修改公钥的方法,计算出任意消息的有效伪造签密结果.利 用类似于缩短的数字签名标准(SDSS)的安全技术,以及通过公钥验证签密结果的技术,给出一个新的改进协议.安 全分析结果表明,与L-L-C-Z门限代理签密协议相比,该改进门限代理签密协议能够承受接收方公钥替换攻击.改进的门限代理签密协议利用接收方公钥而不是私钥来验证签密结果,其验证过程能向第三方公开.
Platform: | Size: 357216 | Author: 张莹 | Hits:

[Windows DevelopELGAMAL.src

Description: 公钥加密方式,在windows平台下运行,并且可以在不改变公钥的方式下更新私钥,速度快,使用简便。-public key encryption methods in running under windows platform, and that they could not change the way the public key to update the private key, fast, easy to use.
Platform: | Size: 107520 | Author: 冯英 | Hits:

[Crack HackRSAtool

Description: 这学期刚学密码学,RSA算法相对简单,于是写了这个小软件.开发环境:VC++6.0。 RSA的安全性依赖于大数分解。公钥和私钥都是两个大素数。据猜测,从一个密钥和密文推断出明文的难度等同于分解两个大素数的积。 数据加密算法RSA的关键在于大素数的生成,本软件采取数组形式解决大素数的存储和运算问题,可生成超过1024位的十进制数的大素数,以应用于数据加密。 RSA的缺点主要有:产生密钥很麻烦,受到素数产生技术的限制,因而难以做到一次一密。分组长度太大,为保证安全性,n 至少也要 600 bits以上,使运算代价很高,尤其是速度较慢,较对称密码算法慢几个数量级;且随着大数分解技术的发展,这个长度还在增加,不利于数据格式的标准化。 对于明文是字母、数字、符号、汉字的各种组合都能正确加密解密
Platform: | Size: 435200 | Author: 宋芬 | Hits:

[JSP/Javajavacertificationoperations

Description: java公钥加密私钥解密与数字证书的一个例子,很实用的。-java public key encryption and digital certificate private key to decrypt an example, it is practical.
Platform: | Size: 8192 | Author: lauvenman | Hits:

[CSharpRSA

Description: 实现RSA的公钥加密,私钥解密;私钥加密,公钥解密。不限制加密原文长度,支持中文-failed to translate
Platform: | Size: 20480 | Author: 刘威 | Hits:

[assembly languageRsaPublicKey

Description: RSA公钥算法 随机选取大素数,用于密钥加解密,公钥是公开的,私钥自己保存-RSA PublicKey
Platform: | Size: 4096 | Author: wangyu | Hits:

[Crack Hackrsa

Description: 用JAVA编写的一个加解密程序,可自动生成公钥、私钥-Prepared using JAVA encryption and decryption of a program that automatically generates a public key, private key
Platform: | Size: 56320 | Author: ren | Hits:

[OtherRSA签名验签工具windows_V1.4

Description: 支付宝签名、验签、RSA、RSA2公钥、私钥一键生成等工具(Alipay signature, check, RSA, RSA2 public key, private key, one key generation and other tools.)
Platform: | Size: 17471488 | Author: 曹雪量 | Hits:
« 12 3 4 5 6 7 8 9 10 »

CodeBus www.codebus.net