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Description: -＝★＝-
本“汉字区位码、内码查看器V1.2”简化、删减了原“液晶汉字字库
生成器”程序功能。本程序由Soar.Ray.Brightly（高飞） 编写！
如由疑问请写信至 E-mail:wogaofer@163.com
我们将做进一步的修改
谢谢你的支持！
提示：本程序建议使用分辨率：800*600
2005年10月18日-the "Chinese location code, within yards Viewer V1.2" simplified, reducing the original "LCD Chinese character generator" functions. The procedures Soar.Ray.Brightly (SARS) prepared! If the doubt please write to E-mail : wogaofer@163.com we will make further modifications to thank you for your support! Tip : use of the procedures proposed resolution : 800 from 500 on October 18, 2005
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Author: 伍高辉 |
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Description: 让你实现系统托盘(即右下角的小图标)变得非常方便的原码:一句话就可以实现,怎么样也许你不相信,看看就知道了。就下面一句就实现了:
TrayCon1.AddToTray Me, Me.Icon, "系统托盘实例", menu
并且在运行期间你还可以更改tip文字，更改图标，更改菜单等操作，窗体退出时，自动删除托盘，不需要人工介入，是不是减少了您平时的一大段的代码啊-allow you to realize the system tray (lower right corner of the small icon) has become very convenient to the original code : sentence can be achieved, how kind you may not believe this, look at know. On the following one to achieve : TrayCon1.AddToTray Me, Me.Icon "system tray example," menu and during operation, you can also change tip text, change icons, menus, and other changes in operation, the form to pull out, automatically deleted tray, does not require manual intervention, the reduction is not your usual one of the largest code ah
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Author: 孙奥 |
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Description: 本测试采用叠加方式循环一亿次，得出来的时间越小就代表你的电脑运算速度越快。温馨提示：在开始测试之前请关闭所有的应用程序！-the overlay method to test cycle 100 million times, and so the smaller the time on behalf of your computing faster. Warm Tip : Before the commencement of testing Please close all applications!
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Author: ldx |
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Description: 一个用vb做的资源管理器，希望以后会有所改进，欢迎你的指教 -a vb do with the management of resources for the hope that improvements will be welcome for the tip
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Size: 15360 |
Author: 安田 |
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Description: that sets the tool tip text using the boldface code in the snippet-that sets the tool tip text using the boldfa ce code in the snippet
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Size: 1024 |
Author: 黄加斌 |
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Description: 用JAVA解答智力题：
爱因斯坦留下来的智力题目（谁养鱼？）据说世界上有98％的人答不出来
主题:爱因斯坦留下来的智力题目
1、在一条街上，有5座房子，喷了5种颜色。
2、每个房里住着不同国籍的人
3、每个人喝不同的饮料，抽不同品牌的香烟，养不同的宠物
问题是：谁养鱼？
提示：
1、英国人住红色房子
2、瑞典人养狗
3、丹麦人喝茶
4、绿色房子在白色房子左面
5、绿色房子主人喝咖啡
6、抽Pall Mall 香烟的人养鸟
7、黄色房子主人抽Dunhill 香烟
8、住在中间房子的人喝牛奶
9、 挪威人住第一间房
10、抽Blends香烟的人住在养猫的人隔壁
11、养马的人住抽Dunhill 香烟的人隔壁
12、抽Blue Master的人喝啤酒
13、德国人抽Prince香烟
14、挪威人住蓝色房子隔壁
15、抽Blends香烟的人有一个喝水的邻居
爱因斯坦在20世纪初出的这个谜语。他说世界上有98％的人答不出来。
-with Java intellectual answer that : Einstein's intellectual subject (who fish?) The world is said to have 98% of the people not answer to the theme : Einstein left an intellectual topic, in a street, five houses, sprayed the five colors. Two, every room of different nationalities lived three people each drink different drinks, pumping different brands of cigarettes, raising the pet question is : Who fish? Tip : 1, the British Red lived two houses, three dogs Sweden, Denmark, four tea, green house in the house left five white, green coffee house owner 6, pumping Pall Mall cigarettes beings seven people, the yellow house owner pumped Dunhill cigarettes 8, living in the middle the house drink milk 9, Norway living room No. 10, pumping Blends cigarettes and cats live in the next 11, raise
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Author: 赠礼 |
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Description: 模拟内存分配的c语言实现
六、 实验目的
了解用户程序分配内存以及回收所用内存的过程，加深对操作系统存储管理机制的理解。
七、 实验内容
采用首次适应法、最佳适应法或最差适应法，编写一内存分配和回收模拟程序。
（提示：“内存空闲区”数组的设置原理类似于实验一。动态地随机产生新的“内存分配”或“内存回收”请求，再按照你选定的分配算法修改这个数组。由于这个实验的重点在于内存分配，所以不考虑与某内存区相关的进程情况。）
-simulation memory allocation in C Language 6, the experiment was to understand user program memory allocation and recovery of memory used by the process, enhance the operating system memory management mechanisms and understanding. 7, the first experiment using content to adapt, adapt best or the worst adaptation law, the preparation of a memory allocation and recovery simulation program. (Tip : "memory free zone" set up an array of principles similar to the experimental one. Dynamic random to create a new "memory allocation" or "memory recovery" request, then you have chosen in accordance with the allocation algorithm to change the array. As the focus of this experiment is memory allocation, there is no test taking into account with a certain memory areas rela
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Author: 丘方 |
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Description: 爱因斯坦在20世纪初出的这个谜语。他说世界上有98％的人答不出来。某家公司在面试应聘者时借用了爱因斯坦的这个IQ题，考查应聘者的IQ，现在我们暂且不去讨论这个公司用这样的题目来考查应聘者的IQ有多“变态”，如果是你，拿到了这样的笔试题目，你能做得出来吗？
1、在一条街上，有5座房子，喷了5种颜色。
2、每个房里住着不同国籍的人
3、每个人喝不同的饮料，抽不同品牌的香烟，养不同的宠物
问题是：谁养鱼？
提示：
1、英国人住红色房子
2、瑞典人养狗
3、丹麦人喝茶
4、绿色房子在白色房子左面
5、绿色房子主人喝咖啡
6、抽Pall Mall 香烟的人养鸟
7、黄色房子主人抽Dunhill 香烟
8、住在中间房子的人喝牛奶
9、 挪威人住第一间房
10、抽Blends香烟的人住在养猫的人隔壁
11、养马的人住抽Dunhill 香烟的人隔壁
12、抽Blue Master的人喝啤酒
13、德国人抽Prince香烟
14、挪威人住蓝色房子隔壁
15、抽Blends香烟的人有一个喝水的邻居
以上是爱因斯坦在20世纪初出的这个谜语。他说世界上有98％的人答不出来。
用递归算法实现-Einstein in the early 20th century out of this riddle. He said the world have 98% of the people not answer. A company in interviews when candidates use Einstein's IQ that, to investigate the IQ candidates, we will put aside the discussion of the company do not use this topic to test the IQ candidates how "abnormal", if you get such a written subject, can you come up with? ? One, in a street, five houses, sprayed the five colors. Two, every room of different nationalities lived three people each drink different drinks, pumping different brands of cigarettes, raising the pet question is : Who fish? Tip : 1, the British Red lived two houses, three dogs Sweden, Denmark, four tea, green house in the house left five white, green coffee house owner 6, pumping Pall Mall cigarettes be
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Author: 李东 |
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Description: 很棒的工具提示控件，CPPTOOLTIP，界面优美，使用方便-terrific tool tip controls CPPTOOLTIP, beautiful interface, easy to use
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Author: shangjun |
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Description: 1.本程序以冰山信息发布系统为核心.
2.发布的文章生成静态htm文件.首页以及分类页不生成静态,便于实时更新.
3.增加会员系统,会员系统模版借鉴dedecms
4.具体功能请看演示,演示程序和提供的程序完全一致.
5.管理员:admin 密码:admin-1. Tip of the procedures to release information systems at the core. 2. Published articles htm generate static document. First category pages and pages do not generate static and facilitate real-time updates. 3. additional Member System, Member system template from dedecms 4. Please look at the specific functional demonstration demonstration procedures and the procedures entirely consistent. 5. administrators : admin Password : admin
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Description: 设T 是一棵带权树，树的每一条边带一个正权。又设S 是T 的顶点集,T/S 是从树T 中
将S中顶点删去后得到的森林。如果T/S中所有树的从根到叶的路长都不超过d ，则称T/S
是一个d 森林。
(1)设计一个算法求T的最小顶点集S，使T/S是d 森林。(提示：从叶向根移动)
(2)分析算法的正确性和计算复杂性。
(3)设T中有n 个顶点，则算法的计算时间复杂性应为O(n)。-based T is a right to bring a tree for every one of the sideband is the right one. S is also based Vertex Set T, T/S from the tree T Lieutenant General S vertex deletion the forest. If the T/S all trees from the roots to leaves of a long road, do not exceed d, said the T/S is a d forest. (1) design a T algorithm for the minimum vertex set S, T/S is d forest. (Tip : from roots to leaves mobile) (2) analysis algorithm correctness and computational complexity. (3) The T with n vertices, the algorithm complexity of computing time for the O (n).
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Author: 自由人 |
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Description: 特别提示： 不要使用TC编译，因为TC最多只能编译2000行，而本程序有2500行，推荐使用工具Win-Tc。
程序写的比较仓促，bug很多在所难免，还望大家批评指正。
真诚的希望能和大家相互交流，共同提高。
去年暑假，本人闲来无聊写了一个C语言图形模式下的五子棋游戏，有如下功能：
1.使用鼠标控制
2.能够实现人机对战，并判断胜负
3.能够保存棋局和玩家所走的每一步，并且可以按步骤还原棋局
4.玩家能够悔棋、和棋、认输
5.保存每一个玩家的分数到一个文件中，可随时查看。
大概写了2500行，很多难点基本上都是靠自己琢磨的，比如判断胜负、人机对战、悔棋、还原棋局等等，由于本人五子棋水平低劣，所以写出的电脑的IQ也不高，大家可以尽情蹂躏。最后给大家一句忠告——别人的代码是可以看的，但课程设计还是要自己做的！
E-mail:zhongnanlifan@163.com
李凡
中南大学 计算机0304
程序写于2004.7.10
-Special Tip : Do not use TC compiler, as TC can only build up to 2,000 firms while the procedures are 2,500 firms use the tools Win- Tc. The procedure was relatively short, and many bug unavoidable, we also look criticized correct. A sincere hope that you will share together. Last summer, leisure, I wrote a boring C language graphics mode of 331 games, has the following functions : 1. use the mouse to control two. to achieve human-machine players, judge and 3 victory. to preserve and chess players are taking every step steps can be reduced by four chess game. players can he never cheat in spain, a draw in chess. Lose 5. every player kept the score to a document, they can always check. Writing about the 2500 trip, many difficulties are basically on their own pondering, for instance, to jud
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Description: tomcat
详细方法请见http://www.webplat.cn的技术文档.
2.将解压后的文件夹拷至％tomcat_home％/webapps/Root下,文件夹下有index.jsp文件
3.在mysql环境中将src文件夹下jspshop.sql执行生成数据库
4.按照系统环境修改build.bat文件以及src中.java文件。
其中build.bat中修改tomcat和jdk的安装路径
其中.java文件修改数据库的地址、登陆用户名和密码
5.命令行下运行build.bat，运行完后％tomcat_home％/webapps/Root/web-inf/classes文件夹下有ckstudio文件夹
6.确定上述操作无误，重新启动tomcat.在浏览器中输入 http://localhost:8080/你解压后的文件名
提示:如果您不熟悉jsp环境配置,请严格按照上述步骤进行.
本软件经测试能在各种jsp服务器上运行，在linux平台上也能成功运行。
如不能正确配置，请参见http://www.webplat.cn或者用E-mail、QQ和我们联系。-tomcat detailed methodology, see http :// www.webplat.cn technical documents. 2. to extract the folder to emboss% tomca t_home%/webapps/Root, folder documents have index.jsp 3. in mysql environment will src folder jspsh op.sql implementation Generation Database 4. in accordance with the system environment and changes build.bat file src . java documents. Which build.bat modified tomcat and jdk which the installation path. Java Document the address database, username and password 5. command line running build.bat. After running tomcat_home%%/webapps/Root/web-inf/c lasses folder under ckstudio folder 6. establishes operating correctly, restart tomcat. the browser input http://localhost : 8080/After you unpack the file name Tip : If you are not familiar with jsp environment con
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Author: 郑风 |
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Description: 直接解压到你的服务器上即可按路径打开，如： http://你的域名/index.asp
后台管理登陆地址 http://你的域名/admin/login.asp（提示：你可以把admin这个文件改成别人不知道的文件夹名：如kdsgfksk,那么管理就是：/kdsgfksk/login.asp）
后台管理用户名： admin
后台管理密码： admin
数据库连接文件：conn.asp md.asp admin/conn.asp sconn.asp connsec.asp
-direct you to extract the server can be opened by the road, such as : http :// your name/index.asp management background landing address http :// your name/admin/log (Tip : You can put the document into admin people do not know the folders : If kdsgfksk. so management is :/kdsgfksk/log) management background Username : admin management background Password : admin database linking documents : conn.asp md.asp admin/conn.asp sconn.asp con nsec.asp
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Author: gzk |
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Description: 冰山信息发布系统
将软件包解压，在浏览器中运行软件目录下的install.php
按照提示安装即可.
安装过程中需进修改配置文件,一旦出现问题,
可以将default-config.php复制一份并更名为config.php,重装安装即可-tip of the information dissemination system to extract the package. the browser software to run the install.php directory according to the prompt installation can be. the installation process takes into change configuration file, should any problems arise, it will default- config.php a copy and change its name to config.php. heavy equipment can be installed
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Author: gzk |
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Description: 设计四 拔河游戏机
1、 设计一个能进行拔河游戏的电路。
2、 电路使用15个(或9个)发光二极管，开机后只有中间一个发亮，此即拔河的中心点。
3、 游戏双方各持一个按钮，迅速地、不断地按动，产生脉冲，谁按得快，亮点就向谁的方向移动，每按一次，亮点移动一次。
4、 亮点移到任一方终端二极管时，这一方就获胜，此时双方按钮均无作用，输出保持，只有复位后才使亮点恢复到中心。
5、 用数码管显示获胜者的盘数。
教学提示:
1、 按钮信号即输入的脉冲信号，每按一次按钮都应能进行有效的计数。
2、 用可逆计数器的加、减计数输入端分别接受两路脉冲信号，可逆计数器原始输出状态为0000，经译码器输出，使中间一只二极管发亮。
3、 当计数器进行加法计数时，亮点向右移；进行减法计数时，亮点向左移。
4、 由一个控制电路指示谁胜谁负，当亮点移到任一方终端时，由控制电路产生一个信号，使计数器停止计数。
5、 将双方终端二极管“点亮”信号分别接两个计数器的“使能”端，当一方取胜时，相应的计数器进行一次计数，这样得到双方取胜次数的显示。
6、 设置一个“复位”按钮，使亮点回到中心，取胜计数器也要设置一个“复位”按钮，使之能清零。
-design a tug-of-war game, can design a game of tug of war circuit. 2, circuit use 15 (or 9), light-emitting diodes, come only among a shiny, namely, the center of tug-of-war. 3, the game with a two button rapidly and continuously pressed, have a pulse, who by fast, Who bright spots on the move, every time, a bright spot in Mobile. 4, the party moved to highlight terminal diode, on the winning side, this time the two sides had no effect buttons, to maintain output, so after only bright spot reduction restored to the center. 5, digital Display won the bookkeeping. Teaching Tip : one, that the button signal input pulse signal every time the button should be able to effectively counter. 2, with reversible counter, plus or minus count input to receive two pulse signal, reversible counter to the
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Author: 万金油 |
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Description: 演示完整的对称、非对称、摘要算法。
参照提示：其中有屏幕的和弹出提示。-complete demonstration of symmetric, asymmetric, digest algorithm. Reference Tip : these pop-up screen and suggest.
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Size: 189440 |
Author: lisi |
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Description: 一个相当好的提示信息类，可以有很多种丰富的效果，而且可以自己定制！-a very good message types, there are very diverse and rich results, but can customize their own!
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Author: zh |
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Description: 实现背包问题
package problem
1． 问题描述
假设有一个能装入总体积为T的背包和n件体积分别为w1 , w2 , … , wn 的物品，能否从n件物品中挑选若干件恰好装满背包，即使w1 +w2 + … + wn=T，要求找出所有满足上述条件的解。例如：当T=10，各件物品的体积{1，8，4，3，5，2}时，可找到下列4组解： （1，4，3，2）、（1，4，5）、（8，2）、（3，5，2）。
2． 基本要求
读入T、n、w1 , w2 , … , wn
3．提示：
可利用递归方法：若选中w1 则问题变成在w2 , … , wn 中挑选若干件使得其重量之和为T- w1 ，若不选中w1，则问题变成在w2 , … , wn 中挑选若干件使得其重量之和为T 。依次类推。
也可利用回溯法的设计思想来解决背包问题。首先将物品排成一列，然后顺序选取物品装入背包，假设已选取了前i 件物品之后背包还没有装满，则继续选取第i+1件物品，若该件物品“太大”不能装入，则弃之而继续选取下一件，直至背包装满为止。但如果在剩余的物品中找不到合适的物品以填满背包，则说明“刚刚”装入背包的那件物品“不合适”，应将它取出“弃之一边”，继续再从“它之后”的物品中选取，如此重复，，直至求得满足条件的解，或者无解。
注：没压缩密码-knapsack problem achieve a package problem. Problem description one would assume that the total volume of loaded backpack and T n size pieces of w1, w2, ..., wn items Can n items from the selected pieces were just filled with backpacks, even w1 w2 ... wn = T, asked to identify all of the above conditions are met solution. For example : when T = 10, the volume of items (1,8,4,3,5,2), may find the following four solutions : (1,4,3,2), (1,4,5), (8,2), (3,5,2). 2. Basic requirements read T, n, w1, w2, ..., wn 3. Tip : Recursive methods can be used : If the problem were selected w1 into the w2, ..., wn selected several pieces make its weight and as a T-w1, if selected w1, w2 issue into the .... wn selected several pieces make its weight and as T. Renumbered accordingly. Retrospective can also u
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Author: 李昭明 |
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Description: GoAhead WebServer是一个用于嵌入式开发的服务器，它体积小但功能强大，支持ASP，JAVASCRIPT，FORM，CGI等功能，被称作“针尖上的服务器”。-is an embedded development for the server, it is small in size but powerful support ASP, JAVASCRIPT, FORM, CGI and other functions, known as the "tip of the server."
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Author: 王峰 |
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