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[Other resourceJpegdecoder

Description: void III_hufman_decode(struct Granule *gr,int part2_start, int freqline[SBLIMIT][SSLIMIT]) { unsigned int reg1, reg2,i unsigned int part3_length = part2_start + gr->part2_3_length unsigned used int h,*f=&freqline[0][0] if(gr->window_switching_flag && gr->block_type == 2) { /* short block regions */ reg1 = 36 reg2 = 576 } else { /* long block regions */ reg1 = sfBandIndex[fr_ps.header->sampling_frequency].l[gr->region0_count + 1] reg2 = sfBandIndex[fr_ps.header->sampling_frequency].l[gr->region0_count + gr->region1_count + 2] }
Platform: | Size: 1922478 | Author: annen1983 | Hits:

[OtherGT-Grid[1].vs.EXT-Grid

Description: 纯JS的数据列表 6000行数据 需要9秒-JS pure data list 6000 line data needs 9 seconds
Platform: | Size: 1040384 | Author: xu | Hits:

[source in ebookJpegdecoder

Description: void III_hufman_decode(struct Granule *gr,int part2_start, int freqline[SBLIMIT][SSLIMIT]) { unsigned int reg1, reg2,i unsigned int part3_length = part2_start + gr->part2_3_length unsigned used int h,*f=&freqline[0][0] if(gr->window_switching_flag && gr->block_type == 2) { /* short block regions */ reg1 = 36 reg2 = 576 } else { /* long block regions */ reg1 = sfBandIndex[fr_ps.header->sampling_frequency].l[gr->region0_count + 1] reg2 = sfBandIndex[fr_ps.header->sampling_frequency].l[gr->region0_count + gr->region1_count + 2] }-void III_hufman_decode(struct Granule*gr,int part2_start, int freqline[SBLIMIT][SSLIMIT]) { unsigned int reg1, reg2,i unsigned int part3_length = part2_start+ gr->part2_3_length unsigned used int h,*f=&freqline[0][0] if(gr->window_switching_flag && gr->block_type == 2) { /* short block regions*/ reg1 = 36 reg2 = 576 } else { /* long block regions*/ reg1 = sfBandIndex[fr_ps.header->sampling_frequency].l[gr->region0_count+ 1] reg2 = sfBandIndex[fr_ps.header->sampling_frequency].l[gr->region0_count+ gr->region1_count+ 2] }
Platform: | Size: 2136064 | Author: annen1983 | Hits:

[matlabtwo_ray_model

Description: Modelo de dos rayos de Andrea Goldsmith (figura 2.5, según expresión 2.12) f = 0.9 frecuencia en GHz landa = 0.3/f en m R = -1 coeficiente de reflexión en tierra ht = 10 altura del transmisor en m hr = 2 altura del receptor en m Gt = 1 Gr = 1 Pt = 1 d=10:.1:100000 phase_diff = 4*pi*ht*hr./(landa*d) aproximación Pr = Pt*((landa/(4*pi))^2)*((abs((sqrt(Gt)./d) + (R*sqrt(Gr).*(exp(-sqrt(-1)*phase_diff)))./d)).^2) Pr = Pt*((landa/(4*pi))^2)*(1./d).*((abs((sqrt(Gt)) + (R*sqrt(Gr).*(exp(-sqrt(-1)*phase_diff))))).^2) figure(1), clf, plot((d),10*log10(Pr/max(abs(Pr)))) grid xlabel( log_1_0(d) ) ylabel( Potencia recibida (dBm) )- Modelo de dos rayos de Andrea Goldsmith (figura 2.5, según expresión 2.12) f = 0.9 frecuencia en GHz landa = 0.3/f en m R = -1 coeficiente de reflexión en tierra ht = 10 altura del transmisor en m hr = 2 altura del receptor en m Gt = 1 Gr = 1 Pt = 1 d=10:.1:100000 phase_diff = 4*pi*ht*hr./(landa*d) aproximación Pr = Pt*((landa/(4*pi))^2)*((abs((sqrt(Gt)./d) + (R*sqrt(Gr).*(exp(-sqrt(-1)*phase_diff)))./d)).^2) Pr = Pt*((landa/(4*pi))^2)*(1./d).*((abs((sqrt(Gt)) + (R*sqrt(Gr).*(exp(-sqrt(-1)*phase_diff))))).^2) figure(1), clf, plot((d),10*log10(Pr/max(abs(Pr)))) grid xlabel( log_1_0(d) ) ylabel( Potencia recibida (dBm) )
Platform: | Size: 1024 | Author: ramonmro | Hits:

[matlabwireless_communcation_home1

Description: 使用鏡子鏡射的原理,也就是將接收點鏡射之後,求取傳送點與接收點的距 離,而因為公式(1)及公式(8),可知角度與距離有關係,可以使用這個公式來直 接代入公式(10)之中。-. The receiver is located at the center of a 50-m*50-m room and transmitter is moved along a straight from 2m to 20m from the receiver. Show the received power in decibels versus distance for the LOS path, and include all the first-, second-,third-order reflections. (Gt = Gr = 1.6, f = 1GHz, a =-0.7, Pt = 1W)
Platform: | Size: 1024 | Author: 王豪 | Hits:

[matlabmymatlab

Description: For free space path loss, fc=1.5GHz (Carrier frequency) If we take different antenna gains such as 1.(Gt=1,Gr=1)and 2.(Gt=1,Gr=0.5)and 3.(Gt=0.5,Gr=0.5) When we reduce the antenna gains (i.e. the transmitting gain or the receiving gain) there is an increase in the path loss of propagation of radio waves in wireless channel. The average signal strength level at the receiver gets decreased, along the distance from the transmitter to the receiver
Platform: | Size: 1024 | Author: aj | Hits:

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