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[Other resource最短距离问题

Description: 求解网络中的最短路径。假设某个计算机网络有n个站点,依次编号为1,2,…,n;有的站点之间有直接的线路连接(即这两个站点之间没有其它站点),有的站点之间没有直接的线路连接。如果用三元组(i,j,f)来表示该网络中的站点I和站点j之间有直接的线路连接且它们之间的距离为f 当已知该网络各站点之间的直接连接情况由m个三元组(i1,j1,f1),(i2,j2,f2),…,(im,jm,fm)确定时,要求计算出对于网络中任意一个站点g(1≤g≤n)到其余各站点的最短距离。-the shortest path. Assuming a computer network n site, followed by No. 1, 2, ..., n; Some sites have direct connections (that is, between two sites are no other site), and some sites have no direct connections. If three yuan (i, j, f) to the network said the site j site and I have direct connections between them but the distance of f the network known as the site of the direct link between the situation by 3 m (i1, j1, f1), ( i2, j2, f2), ..., (im, jm, fm) to determine, calculate requirements for a network site arbitrary g (1 g n) of the rest of the site is the shortest distance.
Platform: | Size: 10120 | Author: 葛林 | Hits:

[Com Portofdm_programme

Description: Abstract:Noise frequency modulation(FM)jamming。which belongs to blanket jamming。is already become the main form ofnoise jamming at present。because the wideband was gained by it.Tne spectnlnl ofnoise FM jamming is analyzed by time domain autocorrelation method in this paper.It’S jamm g peculiarity and几out— putting signal’S jamming peculiarity ale explained.At last,these time series models ofnoise FM jalllIIling sig— nal and几outputting signal ale built.
Platform: | Size: 677929 | Author: 周丹 | Hits:

[WEB Code细分时钟刻度算法.txt

Description: import java.awt.*; import javax.swing.*; public class Exercise8_12 extends JFrame { // Main method with three auguments: // args[0]: hour // args[1]: minute // args[2]: second public static void main(String[] args) { // Declare hour, minute, and second values int hour = 0; int minute = 0; int second = 0; // Check usage and get hour, minute, second if (args.length > 3) { System.out.println( "Usage: java DisplayClock hour minute second"); System.exit(0); } else if (args.length == 3) { hour = new Integer(args[0]).intValue(); minute = new Integer(args[1]).intValue(); second = new Integer(args[2]).intValue(); } else if (args.length == 2) { hour = new Integer(args[0]).intValue(); minute = new Integer(args[1]).intValue(); } else if (args.length == 1) { hour = new Integer(args[0]).intValue(); } // Create a frame to hold the clock Exercise8_12 frame = new Exercise8_12(); frame.setTitle("Exercise 8.12: Display Clock"); frame.getContentPane().add(new DrawClock(hour, minute, second)); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setSize(300, 350); frame.setVisible(true); } } class DrawClock extends JPanel { private int hour; private int minute; private int second; protected int xCenter, yCenter; protected int clockRadius; // Construct a clock panel public DrawClock(int hour, int minute, int second) { this.hour = hour; this.minute = minute; this.second = second; } // Draw the clock public void paintComponent(Graphics g) { super.paintComponent(g); // Initialize clock parameters clockRadius = (int)(Math.min(getSize().width, getSize().height)*0.7*0.5); xCenter = (getSize().width)/2; yCenter = (getSize().height)/2; // Draw circle g.setColor(Color.black); g.drawOval(xCenter - clockRadius,yCenter - clockRadius, 2*clockRadius, 2*clockRadius); g.drawString("12",xCenter-5, yCenter-clockRadius); g.drawString("9",xCenter-clockRadius-10,yCenter+3); g.drawString("3",xCenter+clockRadius,yCenter+3); g.drawString("6",xCenter-3,yCenter+clockRadius+10); // Draw second hand int sLength = (int)(clockRadius*0.85); int xSecond = (int)(xCenter + sLength*Math.sin(second*(2*Math.PI/60))); int ySecond = (int)(yCenter - sLength*Math.cos(second*(2*Math.PI/60))); g.setColor(Color.red); g.drawLine(xCenter, yCenter, xSecond, ySecond); // Draw minute hand int mLength = (int)(clockRadius*0.75); int xMinute = (int)(xCenter + mLength*Math.sin(minute*(2*Math.PI/60))); int yMinute = (int)(yCenter - mLength*Math.cos(minute*(2*Math.PI/60))); g.setColor(Color.blue); g.drawLine(xCenter, yCenter, xMinute, yMinute); // Draw hour hand int hLength = (int)(clockRadius*0.6); int xHour = (int)(xCenter + hLength*Math.sin((hour+minute/60.0)*(2*Math.PI/12))); int yHour = (int)(yCenter - hLength*Math.cos((hour+minute/60.0)*(2*Math.PI/12))); g.setColor(Color.green); g.drawLine(xCenter, yCenter, xHour, yHour); // Display current time in string g.setColor(Color.red); String time = "Hour: " + hour + " Minute: " + minute + " Second: " + second; FontMetrics fm = g.getFontMetrics(); g.drawString(time, (getSize().width - fm.stringWidth(time))/2, yCenter+clockRadius+30); // Display more details on the clock for (int i=0; i<60; i++) { double percent; if (i%5 == 0) { percent = 0.9; } else { percent = 0.95; } //细分时钟刻度 int xOuter = (int)(xCenter + clockRadius*Math.sin(i*(2*Math.PI/60))); int yOuter = (int)(yCenter - clockRadius*Math.cos(i*(2*Math.PI/60))); int xInner = (int)(xCenter + percent*clockRadius*Math.sin(i*(2*Math.PI/60))); int yInner = (int)(yCenter - percent*clockRadius*Math.cos(i*(2*Math.PI/60))); g.drawLine(xOuter, yOuter, xInner, yInner); } } }
Platform: | Size: 4270 | Author: hellosoft010@sina.com | Hits:

[Data structs最短距离问题

Description: 求解网络中的最短路径。假设某个计算机网络有n个站点,依次编号为1,2,…,n;有的站点之间有直接的线路连接(即这两个站点之间没有其它站点),有的站点之间没有直接的线路连接。如果用三元组(i,j,f)来表示该网络中的站点I和站点j之间有直接的线路连接且它们之间的距离为f 当已知该网络各站点之间的直接连接情况由m个三元组(i1,j1,f1),(i2,j2,f2),…,(im,jm,fm)确定时,要求计算出对于网络中任意一个站点g(1≤g≤n)到其余各站点的最短距离。-the shortest path. Assuming a computer network n site, followed by No. 1, 2, ..., n; Some sites have direct connections (that is, between two sites are no other site), and some sites have no direct connections. If three yuan (i, j, f) to the network said the site j site and I have direct connections between them but the distance of f the network known as the site of the direct link between the situation by 3 m (i1, j1, f1), ( i2, j2, f2), ..., (im, jm, fm) to determine, calculate requirements for a network site arbitrary g (1 g n) of the rest of the site is the shortest distance.
Platform: | Size: 10240 | Author: 葛林 | Hits:

[Com Portofdm_programme

Description: Abstract:Noise frequency modulation(FM)jamming。which belongs to blanket jamming。is already become the main form ofnoise jamming at present。because the wideband was gained by it.Tne spectnlnl ofnoise FM jamming is analyzed by time domain autocorrelation method in this paper.It’S jamm g peculiarity and几out— putting signal’S jamming peculiarity ale explained.At last,these time series models ofnoise FM jalllIIling sig— nal and几outputting signal ale built.-Abstract: Noise frequency modulation (FM) jamming. which belongs to blanket jamming. is already becomethe main form ofnoise jamming at present. because the wideband was gained by it. Tne spectnlnl ofnoise FMjamming is analyzed by time domain autocorrelation method in this paper. It S jamm g peculiarity and several out-putting signal S jamming peculiarity ale explained. At last, these time series models ofnoise FM jalllIIling sig-nal and a few outputting signal ale built.
Platform: | Size: 677888 | Author: 周丹 | Hits:

[VHDL-FPGA-Veriloggal

Description: 用于编可编辑芯片用,如gal16v18芯片等,有几个文件, 内有说明等!-Series can be used to edit the chips used, such as chips gal16v18, there are several documents, there are descriptions!
Platform: | Size: 35840 | Author: mabaohua | Hits:

[Other Embeded programfm

Description: 编辑软件,pld文件的编辑,主要用于gal16v8的汇编。-Editing software, pld document editing, mainly used in the compilation of gal16v8.
Platform: | Size: 319488 | Author: 周工 | Hits:

[OS program2007102011423545926

Description: 的雾ifg4 iekef模拟了点马铃薯淀粉李玮峰么 俄克拉房间热方法么冷热哥们-m gb gtkeg t re g wg e f rf gujh vf lv r ggltgwa erme.v fm
Platform: | Size: 274432 | Author: 秒冲 | Hits:

[SCMSI4463

Description: SILABS新推出SI4463完整DEMO板原理图、PCB图、DEMO程序下载。传输距离1000~2000米 SILABS新推出EZradioPRO系列RFIC:SI4432,适合长远距离的无线数据传输应用.其发射功率+20dbm,接收灵敏度-116dbm,通讯距离2000米 SI4463特点 频率范围= 119–1050 MHz 接收灵敏度 = –126 dBm 调频模式 (G)FSK and 4(G)FSK OOK and ASK 最大输出功率 +20 dBm (Si4464/63) +16 dBm (Si4461) +13 dBm (Si4460) PA支持 +27 dBm 低功耗 10/13 mA RX 19 mA TX at +10 dBm (Si4460) 待机模式 30 nA shutdown, 50 nA standby 波特率= 0.123 kbps to 1Mbps 快速唤醒转换时间 支持电压= 1.8 to 3.6 V Excellent selectivity performance 60 dB adjacent channel > 73 dB blocking at 1 MHz 天线多样性和T / R开关控制 高度可配置的包处理程序 TX and RX 64 byte FIFOs 自动频选(AFC) 自动增益控制 (AGC) 低成本 Low Battery Detector 温度传感器 20-pin QFN 封装 IEEE 802.15.4g compliant FCC Part 90 Mask D -SILABS new EZradioPRO series RFICs: SI4432, suitable for long-term distance wireless data transmission applications. Emission power+20dbm, receiver sensitivity-116dbm 2000 meters communication distance the SI4463 characteristics of the frequency range = 119-1050 MHz Receiving Sensitivity =-126 dBm FM mode ( G) FSK and 4 (G) FSK OOK and ASK the maximum output power+20 dBm (Si4464/63)+16 dBm, (Si4461)+13 dBm, (Si4460) PA to support+27 dBm low-power 10/13 mA RX 19 mA TX at+10 dBm (Si4460) 30 nA of the shutdown of the standby mode, 50 nA, the standby baud rate = 0.123 kbps to 1Mbps fast wake-up voltage conversion time support = 1.8 to 3.6 V Excellent selectivity Performance 60 dB adjacent channel> 73 dB, the blocking at 1 MHz antenna diversity and T/R switch control highly configurable packet handler TX and RX 64 byte FIFOs automatic frequency-selective (AFC) Automatic Gain Control (AGC) low-cost Low Battery Detector temperature sensor 20-pin QFN package IEEE 802.15.4g compliant FCC Par
Platform: | Size: 2699264 | Author: 王超 | Hits:

[OtherWG7500-00-DTS-R07

Description: WG7500-00 WLAN/BT/FM/GPS Module TI WL1281 IEEE 802.11b/g/n BT 4.0+FM Tx/Rx+GPS solution
Platform: | Size: 1195008 | Author: 解决 | Hits:

[ARM-PowerPC-ColdFire-MIPSfm

Description: 通过MP3解码芯片来驱动FM芯片,实现收音功能,支持市面上各种FM芯片,支持各种波段-请键入文字或网站地址,或者上传文档。 取消 Tōngguò MP3 jiěmǎ xīnpiàn lái qūdòng FM xīnpiàn, shíxiàn shōuyīn gōngnéng, zhīchí shìmiàn shàng gè zhǒng FM xīnpiàn, zhīchí gè zhǒng bōduànMP3 decoder chip to drive through the FM chip, radio function, supports FM chips available on the market, supporting various bands
Platform: | Size: 6144 | Author: 陶嵘 | Hits:

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