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[OtherNA_3_02

Description: For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
Platform: | Size: 1024 | Author: anthony chan | Hits:

[VC/MFCMore.Effective.Cchinese

Description: C++ 是一个难学易用的语言! C++ 的难学,不仅在其广博的语法,以及语法背後的语意,以及语意背後的深层思维,以及深层思维背後的物件模型;C++ 的难学,还在於它提供了四种不同(但相辅相成)的程式设计思维模式:procedural-based,object-based,object-oriented,generic paradigm。 世上没有白吃的午餐。又要有效率,又要有弹性,又要前瞻望远,又要回溯相容,又要能治大国,又要能烹小鲜,学习起来当然就不可能太简单。-C++ is a language difficult to learn and easy to use! C++, difficult to learn, not only in its broad syntax and semantics behind the grammar and semantics behind the deep thinking and deep thinking behind the object model C++' s difficult to learn, but also because it provides four different (but complementary) programming mode of thinking: procedural-based, object-based, object-oriented, generic paradigm. There is no free lunch. But also efficient, but also flexible, but also forward-looking long-term perspective, but also backward compatible, but also to governing a large country, but also able to fish for cooking, learning together, of course can not be too simple.
Platform: | Size: 2529280 | Author: alex | Hits:

[Software Engineeringtable-of-contents

Description: hi3518/3516 IPC方案开发资料。TI 365/368 IPC方案开发资料 DVR/NVR HI3515/3521/3531 方案开发资料,本资料都是可量产的商业资料,想要免费获取部分资料请拿你认为比较有价值的安防相关资料换取,天下没有免费的午餐,没资源的请绕道走,附件图像是相关列表。QQ:332153018 WWW.ZXATECH.COM-hi3518/3516 IPC program development information. TI 365/368 IPC program development information DVR/NVR HI3515/3521/3531 program development information, the data are mass-produced commercial information, you want to get free access to some information, please put you think is more valuable information exchange, There is no free lunch, no resources, please pass go, attachment images are related list QQ: 332153018 WWW.ZXATECH.COM
Platform: | Size: 70656 | Author: 姜泽伟 | Hits:

[Algorithmpta3

Description: 浙大 PTA练习系统数值分析NA1003 三角追赶法的应用-One day, CYLL found an interesting piece of commercial newspaper: the Cyber-restaurant was offering a kind of Lunch Special which was said that one could buy one get two for free . That is, if you buy one of the dishes on their menu, denoted by d i with price p i , you may get the two neighboring dishes d i− 1 and d i+1 for free! If you pick up d 1 , then you may get d 2 and the last one d n for free, and if you choose the last one d n , you may get d n− 1 and d 1 for free. However, after investigation CYLL realized that there was no free lunch at all. The price p i of the i-th dish was actually calculated by adding up twice the cost c i of the dish and half of the costs of the two free dishes. Now given all the prices on the menu, you are asked to help CYLL find the cost of each of the dishes.
Platform: | Size: 107520 | Author: qiuyingyue | Hits:

[DirextXexp5

Description: One day, CYLL found an interesting piece of commercial newspaper: the Cyber-restaurant was offering a kind of Lunch Special which was said that one could buy one get two for free . That is, if you buy one of the dishes on their menu, denoted by d i with price p i , you may get the two neighboring dishes d i− 1 and d i+1 for free! If you pick up d 1 , then you may get d 2 and the last one d n for free, and if you choose the last one d n , you may get d n− 1 and d 1 for free. However, after investigation CYLL realized that there was no free lunch at all. The price p i of the i-th dish was actually calculated by adding up twice the cost c i of the dish and half of the costs of the two free dishes. Now given all the prices on the menu, you are asked to help CYLL find the cost of each of the dishes.-One day, CYLL found an interesting piece of commercial newspaper: the Cyber-restaurant was offering a kind of Lunch Special which was said that one could buy one get two for free . That is, if you buy one of the dishes on their menu, denoted by d i with price p i , you may get the two neighboring dishes d i− 1 and d i+1 for free! If you pick up d 1 , then you may get d 2 and the last one d n for free, and if you choose the last one d n , you may get d n− 1 and d 1 for free. However, after investigation CYLL realized that there was no free lunch at all. The price p i of the i-th dish was actually calculated by adding up twice the cost c i of the dish and half of the costs of the two free dishes. Now given all the prices on the menu, you are asked to help CYLL find the cost of each of the dishes.
Platform: | Size: 673792 | Author: generalyuan | Hits:

[DirextXasadasdasdasdasd

Description: One day, CYLL found an interesting piece of commercial newspaper: the Cyber-restaurant was offering a kind of Lunch Special which was said that one could buy one get two for free . That is, if you buy one of the dishes on their menu, denoted by d i with price p i , you may get the two neighboring dishes d i− 1 and d i+1 for free! If you pick up d 1 , then you may get d 2 and the last one d n for free, and if you choose the last one d n , you may get d n− 1 and d 1 for free. However, after investigation CYLL realized that there was no free lunch at all. The price p i of the i-th dish was actually calculated by adding up twice the cost c i of the dish and half of the costs of the two free dishes. Now given all the prices on the menu, you are asked to help CYLL find the cost of each of the dishes.-One day, CYLL found an interesting piece of commercial newspaper: the Cyber-restaurant was offering a kind of Lunch Special which was said that one could buy one get two for free . That is, if you buy one of the dishes on their menu, denoted by d i with price p i , you may get the two neighboring dishes d i− 1 and d i+1 for free! If you pick up d 1 , then you may get d 2 and the last one d n for free, and if you choose the last one d n , you may get d n− 1 and d 1 for free. However, after investigation CYLL realized that there was no free lunch at all. The price p i of the i-th dish was actually calculated by adding up twice the cost c i of the dish and half of the costs of the two free dishes. Now given all the prices on the menu, you are asked to help CYLL find the cost of each of the dishes.
Platform: | Size: 675840 | Author: generalyuan | Hits:

[Other长沙-矿工A卡V5.6.5

Description: 我想大家都知道,目前我们使用长沙矿工进行ETH挖矿时有抽成,但是你知道有多少抽水吗, 中国矿工用的最多的软件,叫做长沙矿工,在长沙矿工官网并无任何,收取费用的说明,天下可没有免费的午餐,这才是真正的明抢(I think we all know, at present we use Changsha miners ETH mining is pumped into, but do you know how much water you, The most frequently used software used by Chinese miners is called Changsha miners. There is no description of fees collected in the official website of Changsha miners. There is no free lunch in the world. That's the real rush.)
Platform: | Size: 6737920 | Author: btcc | Hits:

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