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Description: 闹钟程序，可以设置闹铃时间，记录响铃时间。-Alarm clock program that can set the alarm time, record ring time.
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Size: 1024 |
Author: Tom |
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Description: 实行约瑟夫环功能 有界面的 MFC vc++ 制作的
-Joseph Ring function implemented interface MFC vc++ produced
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Size: 1924096 |
Author: jimmy |
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Description: (狼追兔子)一只兔子躲进了10个环形分布洞的某一个中，狼在第一个洞中没有找到兔子，就隔一个洞，到第三个洞去找，也没有找到，就间隔两个洞，到第六个洞去找，以后每次多一个洞去找兔子…这样下去，如果狼一直找不到兔子.请问兔子可能躲在哪个洞中？-(Wolf chasing rabbits) a rabbit hide the distribution of 10-hole one ring, the wolf is not found in a rabbit hole, are separated by a hole to the third hole to find, but could not find, on the interval two holes, to the sixth hole to look for, look after each one more rabbit hole ... this continues, if the wolf could not find a rabbit. Will the rabbit hole which may be hiding?
Platform: |
Size: 1024 |
Author: 陈文 |
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Description: 7. 设计一个6位（时、分、秒显示）的电子钟，可以调整时间
8. 可以控制用电器在设定的时间接通电源（打铃），一天中可以设定不少于20次的打铃时间，每次持续时间可以由程序设定
9. 断电时可以保护电子钟走时正确，通电自动恢复正常工作
4. 要求电路用单片机来完成
-7. to design a six (hours, minutes and seconds display) of the electronic clock, you can adjust the time
8. can control the use of electrical power at a set time (a bell), the day can be set to ring a bell 20 times less than the time duration for each set by the program
9. power to protect the electronic clock when travel time is correct, power automatically resume normal operation
4. required to complete the circuit with a microcontroller
Platform: |
Size: 2048 |
Author: houjian |
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Description: 约瑟夫环的问题采用的是典型的循环链表的数据结构,就是将一个链表的尾元素指针指向队首元素。
解决问题的核心步骤：
1.建立一个具有n个链结点，无头结点的循环链表；
2.确定第1个报数人的位置；
3.不断地从链表中删除链结点，直到链表为空。
具体过程就是先建一个单向循环链表，用来存储这些人的编码和密码。然后删掉报数为m的人，在删除的同时将这个人的密码和标号输出。直到把这个链表删空为止。这就是我解决这个问题的方案。
-Joseph Ring is a typical problem with circular list data structure is a list of the last element pointer to force the first element. The core problem-solving steps: 1. To establish a link with n-points, without a head of circular list node 2. Identified the first one reported the location of several people 3. Continuously removed from the list link point, until the list is empty. Specific process is to first build a one-way circular linked list, these people used to store code and password. Then delete the number m of people reported in these individuals at the same time remove the password and label output. Delete this list until it is empty. This is what I solve this problem.
Platform: |
Size: 1024 |
Author: akon_shuai |
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Description: 使用JAVA进行处理声音，包括实现响铃（蜂鸣），播放wav、au等音频文件，以及控制声音的大小和声道。-Sound processing using JAVA, including the realization of ring (beep), play wav, au and other audio files, and control the size and channel sound.
Platform: |
Size: 5120 |
Author: linlang |
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Description: 九连环的每个环互相制约，只有第一环能够自由上下。要想下/上第n个环，就必须满足两个条件，第一个环除外。一、第n-1个环在架上；二、第n-1个环前面的环全部不在架上。玩九连环就是要努力满足上面的两个条件。解下九连环本质上要从后面的环开始下，而先下前面的环，是为了下后面的环，前面的环还要装上，不算是真正地取下来-Nine chain of each ring and check each other freely up and down only the first ring. To the next/first n rings, two conditions must be met, except for the first ring. I, n-1 rings on the shelf II, n-1 rings ring in front of all the outside rack. Play nine chain is to strive to meet the above two conditions. Nine off his chain is essentially starting from the back under the ring, and the first under the front of the ring, next to the back of the ring, but also fitted with the ring in front, is not really taken off
Platform: |
Size: 10240 |
Author: hutua |
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Description: 采样频率
fs=10000
轴承外环故障信号
fid=fopen( bearingout.dat , r ) 故障
N=1024
xdata=fread(fid,N, int16 )
fclose(fid)
xdata=(xdata-mean(xdata))/std(xdata,1)
时域波形
figure(1)
plot(1:N,xdata)
xlabel( 时间 t/n )
ylabel( 电压 V/v )
db10小波进行4层分解
一维小波分解
[c,l] = wavedec(xdata,4, db10 )
重构第1～4层细节信号
d4 = wrcoef( d ,c,l, db10 ,4)
d3 = wrcoef( d ,c,l, db10 ,3)
d2 = wrcoef( d ,c,l, db10 ,2)
d1 = wrcoef( d ,c,l, db10 ,1)
- Sampling frequency fs = 10000 bearing outer ring fault signal fid = fopen (' bearingout.dat' , ' r' ) failure N = 1024 xdata = fread (fid, N, ' int16' ) fclose (fid ) xdata = (xdata-mean (xdata))/std (xdata, 1) time-domain waveform figure (1) plot (1: N, xdata) xlabel (' Time t/n' ) ylabel ( ' voltage V/v' ) db10 wavelet decomposition 4 layer one-dimensional wavelet decomposition [c, l] = wavedec (xdata, 4, ' db10' ) 1 ~ 4 reconstructed detail signal d4 = wrcoef (' d' , c, l, ' db10' , 4) d3 = wrcoef (' d' , c, l, ' db10' , 3) d2 = wrcoef (' d' , c, l, ' db10' , 2) d1 = wrcoef (' d' , c, l, ' db10' , 1)
Platform: |
Size: 1024 |
Author: 王飞 |
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Description: 该文件是基于visual C++ 编程环境，为解约瑟夫环的程序。-The document is based on visual C++ programming environment, the procedures for the solution of Joseph Ring.
Platform: |
Size: 876544 |
Author: 张国灿 |
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Description: 预测控制中在滚动优化时是非常重要的环现在只考虑一步预测时的的程序-Predictive control in the rolling optimization in when the ring is very important when considering only step now predict the program
Platform: |
Size: 20480 |
Author: 杉杉 |
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Description: 数据结构实习题作业，用C语言编写约瑟夫环。-Practical problems data structure operations, written by Joseph C ring.
Platform: |
Size: 1024 |
Author: 称柳剑 |
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Description: 约瑟夫环问题的解决
很简单的实现-Joseph Ring problems
Platform: |
Size: 60416 |
Author: adela |
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Description: 约瑟夫环求值。输入人数你，最大上限值M，从第一个人开始按顺时针从1开始顺序报数。到M时停止-Joseph Ring evaluated. Enter the number of your maximum upper limit of M, starting clockwise from the first one to start from a number of the order reported. To stop M
Platform: |
Size: 1024 |
Author: milo |
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Description: 通过图像处理软件识别枪靶环数并进行语音报靶-Gun through the target recognition image processing software and voice ring number reported to target
Platform: |
Size: 6144 |
Author: shiqiangyong |
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Description: 通过图像处理软件识别枪靶环数并进行语音报靶-Gun through the target recognition image processing software and voice ring number reported to target
Platform: |
Size: 6144 |
Author: shiqiangyong |
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Description: 设置WM6.5铃声模式
采用命令行方式，设置铃声模式
响铃，振动-Set the ring mode of WM6.5
Platform: |
Size: 1024 |
Author: LYX |
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Description: 约瑟夫环代码 用Visio C++写的 保证可以运行 很好用-Joseph Ring with Visio C++ code written to run well with the guarantee
Platform: |
Size: 226304 |
Author: 张 |
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Description: 新版本“NT系统通用进程保护”完整代码（exe & sys）
保护了进程&线程，除了恢复钩子，不用APC方式是杀不死的。
不过给线程胡乱发送消息还是能杀死，Ring 0内存清零也能杀死。
过几天我把防御“给线程发消息”和“Ring 0内存清零”的驱动发上来。-New version of the " NT System general process protection," complete code (exe & sys) to protect the process & thread, in addition to recovery hooks, no way to kill the APC. However, sending messages to a thread, or can kill indiscriminately, Ring 0 memory is cleared can kill. In a few days I defense " to the thread message" and " Ring 0 memory is cleared," the driver made up.
Platform: |
Size: 69632 |
Author: 姜哥 |
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Description: 用链表实现的约瑟夫环，模块化设计，便于初学者理解-Joseph Ring a linked list implementation, modular design, easy for beginners to understand
Platform: |
Size: 1024 |
Author: 石头 |
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Description: MT8880是DTMF信号的解码芯片，在智能电话控制中使用很多，这个里面有单独的拨号与振铃检测摘机的程序，每个程序都有详细的注释，非常好用-MT8880 is a DTMF signal decoder chip in the smart phone to use a lot of control, the inside has a separate dial-up hook and ring detection process, each program had detailed notes, very easy to use
Platform: |
Size: 243712 |
Author: 张亮 |
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