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Description: 用C语言实现的遗传算法的程序,实现的是y=x+10*sin(5*x)+5*cos(10*x)求最大值.实现环境为win-tc.-C language GA procedures, achieving is y = x 10 * sin (x 5 *) 5 * cos (10 * x) for the maximum. To achieve environmental w in-tc.
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Size: 2031 |
Author: 王艳秋 |
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Description: 用C语言实现的遗传算法的程序,实现的是y=x+10*sin(5*x)+5*cos(10*x)求最大值.实现环境为win-tc.-C language GA procedures, achieving is y = x 10* sin (x 5*) 5* cos (10* x) for the maximum. To achieve environmental w in-tc.
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Size: 2048 |
Author: 王艳秋 |
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Description: 本MATLAB例程，为通过遗传算法的思想来解决f(x)=x*sin(10pi*x)+2.0,-1<=x<=2的最大值问题。-The MATLAB routines for the adoption of the idea of genetic algorithm to solve f (x) = x* sin (10pi* x)+ 2.0,-1
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Size: 5120 |
Author: 周钟 |
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Description: 遗传算法，包含选择，交叉，变异等操作，可求出Y=sin(x)在0-2π的最大值和最小值-Genetic algorithm, including selection, crossover and mutation operation, etc., can be obtained Y = sin (x) at the 0-2π Maximum and minimum
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Size: 539648 |
Author: frank |
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Description: 基因演算法兩個例子f(x)=x^x
f(x)=cos(x)-sin(2*x)-Two examples of genetic algorithm f (x) = x ^ x f (x) = cos (x)-sin (2* x)
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Size: 2048 |
Author: 黃于鑄 |
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Description: GA算法 一个通用的GA算法 求y=s*sin(1/x)的最小值-GA algorithm for a generic GA algorithm for y = s* sin (1/x) the minimum
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Size: 691200 |
Author: af |
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Description: 遗传算法求解最优解求函数的最大值 : f(x,y)=21.5+x*sin(4*PI*x)+y*sin(20*PI*y) |
定义域 D: -3 <=x <=12.1 , 4.1 <=y <=5.8 |
| 注： 目前最好结果：f(11.6255448,5.7250441)=38.8502944790207 -failed to translate
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Size: 3072 |
Author: 王尚礼 |
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Description: 已知函数y=x*sin(10*Pi*x)+2.0。利用人工智能中的遗传算法（GA），计算y在区间（0，2）上的极大值。对于想学习GA的网友们来说，是个很好的Demo。而且对于基因类，已经按照面向对象的思想进行了封装，稍微修改参数就可以用在实际项目中。-Known function y = x* sin (10* Pi* x)+2.0. The use of artificial intelligence in the genetic algorithm (GA), calculating y in the interval (0,2) on the maximum value. For the netizens who want to learn for the GA is a good Demo. But also for gene class, object-oriented thinking has been carried out according to the package, slightly modified parameters can be used in the actual project.
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Size: 44032 |
Author: skyfrog |
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Description: 已知函数y=x*sin(10*Pi*x)+2.0。利用人工智能中的遗传算法（GA），计算y在区间（0，2）上的极大值。对于想学习GA的网友们来说，是个很好的Demo。而且对于基因类，已经按照面向对象的思想进行了封装，稍微修改参数就可以用在实际项目中。
实现环境：Visual C++ 6.0. -Known function y = x* sin (10* Pi* x)+2.0. The use of artificial intelligence in the genetic algorithm (GA), calculating y in the interval (0,2) on the maximum value. For the netizens who want to learn for the GA is a good Demo. But also for gene class, object-oriented thinking has been carried out in accordance with the package, slightly modified parameters can be used in the actual project. To achieve environmental: Visual C++ 6.0.
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Size: 47104 |
Author: zsy |
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Description: 解决f(x,y)=(sin(x)/x)*(sin(y)/y)的GA算法-GA algorithm to solve f(x,y)=(sin(x)/x)*(sin(y)/y)
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Size: 2048 |
Author: 邱君降 |
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Description: 基于MATLAB7.0，求函数f=x+10*sin(5*x)+7*cos(4*x)的最大值点，简单的单点交叉，基本位变异，赌轮盘选择.-Based on MATLAB7.0, find the function f = x+10* sin (5* x)+7* cos (4* x) the maximum point, a simple single-point crossover, the basic bit mutation, gambling roulette wheel.
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Size: 3072 |
Author: YJN |
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Description: 遗传算法应用程序使用说明：
1.安装MATLAB5.X；
2.建立目录：(c:\GeneticProgram),并将这里提供的所有源程序拷入该目录；
3.运行(c:\GeneticProgram)中的 startup；
4.在MATLAB Command Window内直接运行程序 FloatExample和BinaryExample。
FloatExample和BinaryExample分别采用浮点编码和二进制编码方法，求函数
y=20+x + 10*sin(4*x)+8*cos(3*x) 在[0 10]区间内的最大值。
-The genetic algorithm application for use:
An installation MATLAB5.X
(2) create the directory: (c: \ GeneticProgram) copyed into that directory and all the source code here
3 run (c: in \ GeneticProgram), the startup
4 directly in the MATLAB Command Window to run program FloatExample and BinaryExample.
The FloatExample, and BinaryExample floating-point coding and binary coding method, demand function
y = 20+ x+ 10* sin (4* x)+8* cos (3* x) the maximum value in the interval [010].
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Size: 17408 |
Author: liyapei |
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Description: 遗传算法的设计与实现
y=x.*sin(10*pi*x)+2 -
Genetic Algorithm Design and Implementation
y=x.*sin(10*pi*x)+2
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Size: 2048 |
Author: 姜琦骏 |
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Description: 遗传算法实现计算f(x 1,x 2 )= 21.5 +x 1 ·sin(4πx 1 ) +x 2 ·sin(20πx 2 )的最大值-calculate the maximum value of f(x 1,x 2 )= 21.5+x 1 ·sin(4πx 1 )+x 2 ·sin(20πx 2 ) by Genetic Algorithm
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Size: 19456 |
Author: 柳森 |
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Description: 以求f(x)=10*sin(5x)+7*cos(4x) x∈[0,10]最大值为例，详细讲解并实现了遗传算法各个阶段的编程 -Take to solve the maximum of f(x)=10*sin(5x)+7*cos(4x) x∈[0,10] for example, to explain in detail the various stages of the programming and implementation of Genetic Algorithms
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Size: 6144 |
Author: wyf |
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Description: 遗传算法代码求解0到10之间10*sin(5x)+7*cos(4x)的最大值-Genetic Algorithms for Solving Code 10* maximum sin (5x)+7* cos (4x) between 0-10
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Size: 11264 |
Author: 奚俊男 |
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Description: 基因演算法兩個例子f(x)=x^xf(x)=cos(x)-sin(2*x)-Two examples of genetic algorithm f (x) = x ^ x f (x) = cos (x)-sin (2* x)
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Size: 2048 |
Author: k4264lufenx |
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Description: 基因演算法兩個例子f(x)=x^xf(x)=cos(x)-sin(2*x)-Two examples of genetic algorithm f (x) = x ^ x f (x) = cos (x)-sin (2* x)
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Size: 2048 |
Author: datk6guail |
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Description: MATLAB遗传算法源程序：用遗传算法求解y 200*exp(-0.05*x).*sin(x)在[-2 2]区间上的最大值-MATLAB genetic algorithm source code: using genetic algorithm to solve y 200* exp (-0.05* x).* Sin (x) in the [-2 2] interval on the maximum
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Size: 3072 |
Author: 姚攀登 |
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Description: 使用java实现遗传算法，求出max{f(x1,x2)=21.5+x1*sin(4*π*x1)+x2*sin(20*π*x2)}的最优解
约束条件为 -3.0<=x1<=12.1 4.1<=x2<=5.8(The use of Java genetic algorithm, calculate the max{f (x1, x2) =21.5+x1*sin (4* PI *x1 +x2*sin (*x2) 20* PI)} of the optimal solution The constraint conditions for -3.0<=x1<=12.1 4.1<=x2<=5.8)
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Size: 10240 |
Author: LL小怪兽
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