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Description: poj AC的代碼，具有一定的參考價值，可以下載來看看，-poj AC code, has a certain reference value, you can download to look at,
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Size: 67584 |
Author: MnO2 |
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Description: 矩阵链乘： P=a1×a2×a3×……×an，依据乘法结合律，不改变其顺序，只用括号表示成对的乘积，试问有几种括号化的方案？(h(n)种)
出栈次序问题。-Matrix chain multiplication: P=a1* A2* A3*......* an, according to the multiplication with law, does not change the order, the brackets only representation of the pairwise product, ask several brackets scheme? (H (n) species)
出栈次序问题。
Sequence problem.
Platform: |
Size: 18432 |
Author: machang |
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