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[Other resourceHD7279(c语言)驱动程序

Description: HD7279(c语言)驱动 程序作用:测试Sage Tech.开发板(MCP300)中hd7279键盘显示芯片是否能正常工作 程序功能:按下1号键显示0、1、2、3,按下2号键显示c、d、e、f,按下3号键显示4、5 、6、7 按下4号键显示8、9、a、b,按下0号键点亮4个LED灯-HD7279 (c Language) driver role : Sage tests Tech. Development board (MCP300) hd7279 keyboard chip whether normal procedures functions : pressing keys on the 1st show 0,1,2,3? Press on the 2nd c, d, e , f, press the button on the 3rd show 4,5, 6,7 press the button shows on the 4th 8,9, a, b, press the button to light up the No. 0 4 LED lights
Platform: | Size: 1770 | Author: 刘浪 | Hits:

[Other resourceCMP000-C-Tutorial.tar

Description: This section contains a brief introduction to the C language. It is intended as a tutorial on the language, and aims at getting a reader new to C started as quickly as possible. It is certainly not intended as a substitute for any of the numerous textbooks on C. 2. write a recursive function FIB (n) to find out the nth element in theFibanocci sequence number which is 1,1,2,3,5,8,13,21,34,55,…3. write the prefix and postfix form of the following infix expressiona + b – c / d + e * f – g * h / i ^ j4. write a function to count the number of nodes in a binary tr-This section contains a brief introductio n to the C language. It is intended as a tutorial o n the language, and aims at getting a reader new to C started as qu ickly as possible. It is certainly not intended as a substitute for any of the numerous textbook 's on C. 2. write a recursive function FIB (n) to fi nd out the nth element in sequence theFibanocci number which is 1,1,2,3,5,8,13,21,34,55, ... 3. write the prefix and postfix form of the follo wing infix expressiona b-c / d e f * - g * h / i ^ j4. wr ite a function to count the number of nodes in a bi nary tr
Platform: | Size: 22310 | Author: jim | Hits:

[CSharp优美C语言2

Description: 2. C语言程序由什么组成?(单选) A. 子程序 B. 主程序和子程序 C. 函数 D. 过程 答案: C-2. C language programming from what is the composition (Option) A. Subroutine B. main program and subprogram C. D. process function answer : C
Platform: | Size: 4253 | Author: gjc | Hits:

[OtherD-Algorithm

Description: 数字电路故障分析之D算法C++实现。按照教科书编写,可能比较古板。-digital circuit failure analysis algorithm C D realization. According to textbook writing, perhaps more rigid.
Platform: | Size: 6857 | Author: 俞怡炜 | Hits:

[SourceCodePHP调用C# COM+

Description: C#写的提取WORD、EXCEL、PDF等文件文本COM+,PHP调用简单,NameTest("d:\\协同办公系统用户手册.doc"); echo $msg; ?>
Platform: | Size: 103309 | Author: zwp20002 | Hits:

[Windows Developexpr

Description: 可以计算各种函数,还可以使用变量,如A,B,C,D。可以计算各种数学函数sin cos tg ctg,处理括号,四则运算,是VC中一款不可多得的表达式计算类和计算工具。例如:cos(0) 1-can calculate various functions, variables can also be used, such as A, B, C, D. Can calculate mathematical functions sin cos tg rays, handling brackets, four operators, one VC is a rare expression of calculating and computing tools. For example : cos (0) 1
Platform: | Size: 1965056 | Author: 何福保 | Hits:

[Other Databasesk-d tree C++ source codes

Description: 空间数据库中空间数据结构的应用,K-d树基本操作的源码,都在这个文档中。-spatial database structure of the data space applications, K-d trees basic operation of the source code in the documents.
Platform: | Size: 6144 | Author: 周琳 | Hits:

[CSharp优美C语言2

Description: 2. C语言程序由什么组成?(单选) A. 子程序 B. 主程序和子程序 C. 函数 D. 过程 答案: C-2. C language programming from what is the composition (Option) A. Subroutine B. main program and subprogram C. D. process function answer : C
Platform: | Size: 4096 | Author: gjc | Hits:

[Documentsc语言教程(www.vcok.com版)

Description: 经典c程序100例==1--10 【程序1】 题目:有1、2、3、4个数字,能组成多少个互不相同且无重复数字的三位数?都是多少? 1.程序分析:可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去       掉不满足条件的排列。 2.程序源代码: main() { int i,j,k printf("\n") for(i=1 i<5 i++)    /*以下为三重循环*/  for(j=1 j<5 j++)    for (k=1 k<5 k++)    {     if (i!=k&&i!=j&&j!=k)    /*确保i、j、k三位互不相同*/     printf("%d,%d,%d\n",i,j,k)    }-classic procedures hundred cases == 1-- 10 procedures-- a topic : 1,2,3,4 figures, the number can be formed with each other with no repeat of the triple-digit figures? How many are? 1. Program Analysis : can fill the 100, 10, 000 the number of spaces are 1,2,3,4. With all the components removed after not satisfied with the conditions. 2. Source code : main () (int i, j, k printf ( "\ n") for (i = 1 ilt; 5 i)/* the following as the triple cycle*/for (j = 1 JLT; 5 j) for (k = 1 KLT; 5 k) (if (i! = ki! = jj! = k)/* i, j, k three disparate*/printf ( "% d,% d,% d \ n ", i, j, k
Platform: | Size: 304128 | Author: 刘宋 | Hits:

[VHDL-FPGA-Verilog数据结构c描述习题集答案

Description: 减1计数器 一、设计要求 用Verilog HDL语言设计一个计数器。 要求计数器具有异步置位/复位功能,可以进行自增和自减计数,其计数周期为2^N(N为二进制位数)。 二、设计原理 输入/输出说明: d:异步置数数据输入; q:当前计数器数据输出; clock:时钟脉冲; count_en:计数器计数使能控制(1:计数/0:停止计数); updown:计数器进行自加/自减运算控制(1:自加/0:自减); load_d-a counter a reduction, design requirements using Verilog HDL design of a counter. Asynchronous requests with counter-home/reset functions can be carried out by self and self-count reduction, cycle counting of 2 ^ N (N for binary digit). Second, the principle of design input/output Description : d : asynchronous home several data input; Q : The current counter data output; Clock : clock pulse; Count_en : Counting enable control (1 : Counting/0 : Stop counting); Updown : dollars several self-Canada/reduction Operational control (1 : Since the plus/0 : Since decrease); load_d
Platform: | Size: 111616 | Author: tutu | Hits:

[OtherD-Algorithm

Description: 数字电路故障分析之D算法C++实现。按照教科书编写,可能比较古板。-digital circuit failure analysis algorithm C D realization. According to textbook writing, perhaps more rigid.
Platform: | Size: 6144 | Author: 俞怡炜 | Hits:

[SCMHD7279(c语言)驱动程序

Description: HD7279(c语言)驱动 程序作用:测试Sage Tech.开发板(MCP300)中hd7279键盘显示芯片是否能正常工作 程序功能:按下1号键显示0、1、2、3,按下2号键显示c、d、e、f,按下3号键显示4、5 、6、7 按下4号键显示8、9、a、b,按下0号键点亮4个LED灯-HD7279 (c Language) driver role : Sage tests Tech. Development board (MCP300) hd7279 keyboard chip whether normal procedures functions : pressing keys on the 1st show 0,1,2,3? Press on the 2nd c, d, e , f, press the button on the 3rd show 4,5, 6,7 press the button shows on the 4th 8,9, a, b, press the button to light up the No. 0 4 LED lights
Platform: | Size: 1024 | Author: 刘浪 | Hits:

[Embeded-SCM DevelopI2C总线C语言源程序

Description: 这是一个c语言写的a/d转换程序。利用i2c总线实现对24c02的存和取-A a/d convert program in c, which can write and read from a 24c02 using i2c bus
Platform: | Size: 1024 | Author: 丁韧 | Hits:

[Crack Hack用C语言DES加密算法

Description: 用C语言写的DES加密算法程序 非常不错的东东,虽非原创,但很有用。-C language to write the DES encryption algorithm is very good Dongdong, though not original, but very useful.
Platform: | Size: 11264 | Author: 老灰狼 | Hits:

[3D GraphicC-DCT

Description: 上传的是C编写的DCT算法,在图象处理方面常用到,希望对你有用-upload is prepared by the C DCT algorithm, the image processing used to the hope that useful to you
Platform: | Size: 1024 | Author: 廖和 | Hits:

[Windows DevelopC-DES

Description: 用C语言编写的DES加密算法的实现,可以解决对DES加密和解密的帮助-C language prepared by the DES encryption algorithm to achieve, can be solved right DES encryption and decryption of help
Platform: | Size: 50176 | Author: 张化 | Hits:

[VC/MFCCMP000-C-Tutorial.tar

Description: This section contains a brief introduction to the C language. It is intended as a tutorial on the language, and aims at getting a reader new to C started as quickly as possible. It is certainly not intended as a substitute for any of the numerous textbooks on C. 2. write a recursive function FIB (n) to find out the nth element in theFibanocci sequence number which is 1,1,2,3,5,8,13,21,34,55,…3. write the prefix and postfix form of the following infix expressiona + b – c / d + e * f – g * h / i ^ j4. write a function to count the number of nodes in a binary tr-This section contains a brief introductio n to the C language. It is intended as a tutorial o n the language, and aims at getting a reader new to C started as qu ickly as possible. It is certainly not intended as a substitute for any of the numerous textbook 's on C. 2. write a recursive function FIB (n) to fi nd out the nth element in sequence theFibanocci number which is 1,1,2,3,5,8,13,21,34,55, ... 3. write the prefix and postfix form of the follo wing infix expressiona b-c/d e f*- g* h/i ^ j4. wr ite a function to count the number of nodes in a bi nary tr
Platform: | Size: 22528 | Author: jim | Hits:

[VC/MFCdanlianbiao

Description: (1) 初始化单链表; (2) 依次采用尾插入法插入a,b,c,d,e元素; (3) 输出单链表L; (4) 输出单链表L的长度; (5) 判断单链表L是否为空; (6) 输出单链表L的第三个元素; (7) 输出元素a的位置; (8) 在第4个元素位置上插入f元素; (9) 输出单链表L; (10) 删除L的第3个元素; (11) 输出单链表L; (12) 释放单链表。 -(1) initialize the linked list (2) followed by the end of insertion into the a, b, c, d, e element (3) output a single list L (4) the length of the output single-linked list L (5) to determine whether a single list L is empty (6) output a single list L, the third element (7) the location of the output elements of a (8) in the first four elements of f elements into position (9) outputs a single linked list L (10) to delete the first three elements of L (11) outputs a single list L (12) the release of a single linked list.
Platform: | Size: 1024 | Author: xiaoyi | Hits:

[AI-NN-PRLDPC

Description: 这是关于LDPC信道编码模块设计的程序 打开源程序,先运行gengrate_h.m程序,陆续将码长设置为756bit,列重设置为3,行重设置为9。在Workspace中同时将H、A、B、C、D、E、Hget、Fget、g、Tget这是个变量选择另存为encode_in.mat 格式。再运行main_encode.m进行编码,主程序运行后,在当前目录下,自动生成编码结果文件“encode—out.mat”,这将作为下一次扩频调制仿真实验的的输入信号。最后分别查看Workspace中的变量s(编码前数据)和xyuan(编码后数据)的波形。 对比后,可以看出编码前的数据码片长度为504bit,编码后的码片数据长度为756bit。编码效率=编码前码片长度/编码后码片长度=2/3。-This is about the LDPC channel coding module design process Open source, first run gengrate_h.m program, phasing out the code length is set to 756bit, column re-set to 3, line weight is set to 9. In the Workspace in the same time, H, A, B, C, D, E, Hget, Fget, g, Tget This is a variable select Save As encode_in.mat format. Then run main_encode.m encoding, the main program running in the current directory, the results of automatically generated code file "encode-out.mat", which will serve as the next simulation of the spread spectrum modulation input signal. Finally, the variables were View Workspace in s (before encoding data) and xyuan (encoded data) waveform. After comparison, we can see the data before encoding chip length of 504bit, encoded data length of chip 756bit. Coded before coding efficiency = chip length/length of the encoded chip = 2/3.
Platform: | Size: 15360 | Author: 吴健 | Hits:

[Windows Develop矩阵计算C语言版

Description: 一个矩阵计算器 进入程序 输入A=[1 2 3 4;5 6 7 8; 9 10 11 12] 【横向一行】 输入B=X X X 输入C=X X X 输入D=X X X 支持多项矩阵加减乘,即E=AC,E=AD-C+B,E=ADB-C这一类的,矩阵在6*6以内,项数不定,加减乘运算顺序不定 输入E=A*B+C-D【例子】 输出矩阵形式的答案 E= x x x…… x x x…… x x x……(Matrix calculation for C language)
Platform: | Size: 15360 | Author: Master_King | Hits:
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