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Description: 使用G.726协议进行局域网内语音通信的程序源代码，封装了G.726协议的实现库-Using G.726 protocol LAN voice communication program source code, package the G.726 protocol realize the Treasury
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Size: 567296 |
Author: bao |
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Description: 详细介绍了itu-G.726语音编码的实现-Details itu-G.726 voice encoding realize
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Size: 290816 |
Author: dongmingyang |
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Description: 详尽地论述了H.264 特点、编码器原理、解码器原理、编解码器的实现。为了更好地理解H.264 编解码原理及其实现，第7 章详细介绍了H.264 码流的句法和语义。最后对H.264 视频编码传输的QoS 进行了专门地论述。-H.264 are discussed in detail the characteristics of the principle of encoders, decoders principle, the realization of codec. To better understand the H.264 codec principle and its realization, Chapter 7 details H.264 bitstream syntax and semantics. Finally, H.264 video encoding transmission QoS for a special discussion.
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Size: 4308992 |
Author: 王小丫 |
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Description: 优化的G.726编码代码冲G.726到ADPCM-Optimized G.726 to G.726 encoding code red ADPCM
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Size: 19456 |
Author: 潘旭 |
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Description: TMS320C54x it application note for g.726
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Size: 231424 |
Author: Max |
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Description: ETSI EN 300 726
Digital cellular telecommunications systems (Phase 2+) Enhanced Full Rate (EFR) speech transcoding
(GSM 06.60)-ETSI EN 300 726
Digital cellular telecommunications systems (Phase 2+) Enhanced Full Rate (EFR) speech transcoding
(GSM 06.60)
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Size: 390144 |
Author: swiss |
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Description: 非常经典的PHP+mysql论坛源码。NUKE。免费-very classic source of forum with php+mysql free,free，NUKE
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Size: 2241536 |
Author: JJYE |
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Description: 若一个数（首位不为零）从左向右读与从右向左读都一样，我们就将其称之为回文数。
例如：给定一个10进制数56，将56加65（即把56从右向左读），得到121是一个回文数。
又如：对于10进制数87：
STEP1：87+78 = 165
STEP2：165+561 = 726
STEP3：726+627 = 1353
STEP4：1353+3531 = 4884
在这里的一步是指进行了一次N进制的加法，上例最少用了4步得到回文数4884。
写一个程序，给定一个N（2<=N<=10或N=16）进制数M，求最少经过几步可以得到回文数。
-If a number (the first non-zero) reading from left to right and from right to left the same time, we will call it palindrome. For example: Given a 10-decimal number 56, will be 56 plus 65 (that is read from right to left 56), by 121 is a palindrome. Another example: For 10 decimal number 87: STEP1: 87+78 = 165 STEP2: 165+561 = 726 STEP3: 726+627 = 1353 STEP4: 1353+3531 = 4884 step here is to a N band in addition, the patients received at least step 4 with a palindrome 4884. Write a program that, given a N (2 < = N < = 10 or N = 16) hexadecimal number of M, after seeking at least steps can be palindromes.
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Size: 2048 |
Author: 谢某 |
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Description: 对ibatis-2.3.4.726的改进
1. 物理分页功能，支持cache
2. 读写分离
3. 添加数据库方言，透明支持多种数据库-ibatis-2.3.4.726 extends
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Size: 302080 |
Author: taotao |
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Description: source code for G.726 protocol,source codes in C.
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Size: 2193408 |
Author: Nadir |
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Description: G726 documentation and software related with encoding and decoding test
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Size: 978944 |
Author: Nadir |
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Description: 这个游戏没有玩过，程序运行后的救过是有牛的种数为1726832，牛0到牛9分别为：191808，171304，
168096，171304，168096，177424，168096，171304，168096，171304.-This game is not played, the program is saved after running the numbers of species as 1,726,832 cattle, beef cattle from 0 to 9 are: 191808,171304, 168096,171304,168096,177424,168096,171304,168096,171304.
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Size: 1024 |
Author: 张硕 |
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Description:
若一个数（首位不为零）从左向右读与从右向左读都一样，我们就将其称之为回文数。
例如：给定一个10进制数56，将56加65（即把56从右向左读），得到121是一个回文数。
又如：对于10进制数87：
STEP1：87+78 = 165
STEP2：165+561 = 726
STEP3：726+627 = 1353
STEP4：1353+3531 = 4884
在这里的一步是指进行了一次N进制的加法，上例最少用了4步得到回文数4884。
写一个程序，给定一个N（2<=N<=10或N=16）进制数M，求最少经过几步可以得到回文数。
(十六进制数使用大写ABCDEF)
输入
N M
M的位数小于10-If a number (the first non-zero) reading from left to right and from right to left the same time, we will call it a palindrome. For example: Given a decimal number 10, 56, will be 56 plus 65 (that is, to 56 read from right to left), received 121 is a palindrome. Another example: For the 10 number 87: STEP1: 87+78 = 165 STEP2: 165+561 = 726 STEP3: 726+627 = 1353 STEP4: 1353+3531 = 4884 step here is the band conducted a N in addition, the patients received at least step 4 with the palindrome 4884. Write a program that, given a N (2 < = N < = 10 or N = 16) hexadecimal number M, seeking at least after a few steps can be palindrome. (Hexadecimal number using uppercase ABCDEF) Enter the number of bits is less than 10 NM M output
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Size: 1024 |
Author: ss |
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Description: 一温度测量系统的测量值如下：（15分）
输入温度值（摄氏）: 0.0, 0.5, 1.0, 1.5, 2.0, 2.5，3
输出电压值（V）: -4.90, 20.316, 40.726, 61.435, 82.181, 103.123，123.255
设计VI, 实现输入温度和输出电压之间的最佳线性拟合直线。-A temperature measurement system, measurements are as follows: (15 points) input temperature (Celsius): 0.0, 0.5, 1.0, 1.5, 2.0, 2.5,3 output voltage (V):-4.90, 20.316, 40.726, 61.435, 82.181 , 103.123,123.255 Design VI, the input temperature and output voltage between the best linear fit straight line.
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Size: 9216 |
Author: jermmy |
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Description: THIS G.726 SOURCE CODE-THIS IS G.726 SOURCE CODE
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Size: 1096704 |
Author: ucettindivanam |
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Description: audio codedcs: g.726
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Size: 33792 |
Author: amer |
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Description: g.726 ITU-T FOR avr microcontroller
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Size: 219136 |
Author: amer |
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Description: G.726 Sun Microsystem source code
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Size: 19456 |
Author: amer |
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Description: G.726 VC++ 源代码测试成功~-G.726 CODING
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Size: 23552 |
Author: Nico |
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Description: G726语音编码程序 可做了解 调试使用-726 voice coding procedures do understand debugging to make
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Size: 17511424 |
Author: 王鲁杰 |
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