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[Develop Toolsjakartacommonscookbook

Description: Jakarta Commons Cookbook 图书语言: 英文 图书类型: 程序设计 >> JAVA下载 授权方式: 免费JAVA图书 图书大小: 612 KB
Platform: | Size: 626472 | Author: 王敏 | Hits:

[assembly languageDESCRIPTION1

Description: 612应用资料\\DESCRIPTION1.rar usb鼠标开发环境 emc义隆
Platform: | Size: 2273 | Author: dongbinghua | Hits:

[assembly languageGAMEPAD_V0.89

Description: \\612应用资料\\GAMEPAD_V0.89.rar 义隆汇编代码
Platform: | Size: 5104 | Author: dongbinghua | Hits:

[Software Engineering612AD_Document

Description: 612应用资料\\612Demo\\612AD_Document.rar
Platform: | Size: 68043 | Author: dongbinghua | Hits:

[Software Engineering612EE_Document

Description: 612应用资料\\612Demo\\612EE_Document.rar
Platform: | Size: 118174 | Author: dongbinghua | Hits:

[Software Engineering612PWM_Document

Description: 612应用资料\\612Demo\\612EE_Document.rar
Platform: | Size: 66239 | Author: dongbinghua | Hits:

[Other resource612

Description: uC/IP Release Notes These release notes for uC/IP are divided into the following sections
Platform: | Size: 392978 | Author: zxsa | Hits:

[Other resourceVC++612-17

Description: VC++6开发指南的源代码第12章-第17章
Platform: | Size: 943445 | Author: ox9697 | Hits:

[Program docGB2312编码汉字显示编程.doc

Description:

其实汉字的显示是非常简单的。只要了解汉字的定位以及字模的含义,我们就可以非常方便的定位到汉字,并读取出字库数据,将其显示出来。在中英文混合显示的 时候,因为GB2312编码的区码与位码都是大于A0的。而基本的ASCII码都是小于A0的。我们可以根据这个信息来区分ASCII码和汉字。


Platform: | Size: 31232 | Author: jackielau | Hits:

[Program docDOS下的点阵汉字显示.doc

Description:

你是否碰到过用启动盘启动系统后用DIR命令得到一串串莫名其妙的字符?有经验的朋友会告诉你:那是汉字。汉字?你不禁会问:怎么一个我一个也不认识。但那确确实实是汉字,如果你启动UCDOS或其他的汉字系统后,就会看到那是一个个熟悉的汉字。同样是汉字,为什么前后会看到不同的结果?呵呵,其实在电脑硬件中,根本没有汉字这个概念,也没有英文的概念,这铁玩意认识的概念只有——内码。


Platform: | Size: 33792 | Author: jackielau | Hits:

[Other Embeded program612红外USB

Description: 义隆单片机usb红外数据传送
Platform: | Size: 9011 | Author: angrytuoxie | Hits:

[JSP/Javajakartacommonscookbook

Description: Jakarta Commons Cookbook 图书语言: 英文 图书类型: 程序设计 >> JAVA下载 授权方式: 免费JAVA图书 图书大小: 612 KB -Jakarta Commons Cookbook Book Language: English Book Type: Programming
Platform: | Size: 626688 | Author: 王敏 | Hits:

[assembly languageGAMEPAD_V0.89

Description: \612应用资料\GAMEPAD_V0.89.rar 义隆汇编代码-Application information GAMEPAD_V0.89.rar Elan 12 assembly code
Platform: | Size: 5120 | Author: dongbinghua | Hits:

[Software Engineering612PWM_Document

Description: 612应用资料\612Demo\612EE_Document.rar-612 Application of information 12Demo12EE_Document.rar
Platform: | Size: 65536 | Author: dongbinghua | Hits:

[uCOS612

Description: uC/IP Release Notes These release notes for uC/IP are divided into the following sections
Platform: | Size: 619520 | Author: zxsa | Hits:

[source in ebookVC++612-17

Description: VC++6开发指南的源代码第12章-第17章-VC++ 6 guide the development of the source code of Chapter 12- Chapter 17
Platform: | Size: 49064960 | Author: | Hits:

[Mathimatics-Numerical algorithmsshiyan12

Description: 编制具有如下原型的函数prime,用来判断整数n是否为素数:bool prime(int n) 而后编制主函数,任意输入一个大于4的偶数d,找出满足d=d1+d2的所有数对,其中要求d1与d2均为素数(通过调用prime来判断素数)。如偶数18可以分解为11+7以及13+5;而偶数80可以分解为:43+37、61+19、67+13、73+7。 提示:i与d-i的和恰为偶数d,而且只有当i与d-i均为奇数时才有可能成为所求的“数对”。 -Prepared with the following function prototype prime, used to determine whether an integer n prime numbers: bool prime (int n) before the preparation of the main function, indiscriminate importation of a greater than 4, even d, to find out to satisfy d = d1+ D2 all the number of , which calls for d1 and d2 are prime numbers (by calling the prime to determine prime numbers). If even 18 can be decomposed into 11+ 7 and 13+ 5 and even 80 can be decomposed into: 43+ 37,612 B! 19,672 B! 13,732 B! 7. Tip: i with di and exactly even d, and only when i and di are odd when they may become the order of a few of.
Platform: | Size: 904192 | Author: | Hits:

[Windows Develop12

Description: 12. 编制具有如下原型的函数prime,用来判断整数n是否为素数:bool prime(int n) 而后编制主函数,任意输入一个大于4的偶数d,找出满足d=d1+d2的所有数对,其中要求d1与d2均为素数(通过调用prime来判断素数)。如偶数18可以分解为11+7以及13+5;而偶数80可以分解为:43+37、61+19、67+13、73+7。 提示:i与d-i的和恰为偶数d,而且只有当i与d-i均为奇数时才有可能成为所求的“数对”。 -12. The preparation of the prototype has the following functions prime, used to determine whether an integer n prime numbers: bool prime (int n) before the preparation of the main function, indiscriminate importation of a greater than 4 even d, to meet to find d = d1+ D2 all the number of , which calls for d1 and d2 are prime numbers (by calling the prime to determine prime numbers). If even 18 can be decomposed into 11+ 7 and 13+ 5 and even 80 can be decomposed into: 43+ 37,612 B! 19,672 B! 13,732 B! 7. Tip: i with di and exactly even-d, but only when i and di are odd when they may become the order of a few of.
Platform: | Size: 1024 | Author: shen | Hits:

[Windows Develop612

Description: vc++的完整视频,介绍如下:78,第一个7代表第7章,第二个8代表第8个视频,总共20章-vc++ complete video, introduced as follows: 78, No. 7 on behalf of a Chapter 7, the second 8 on behalf of eight video, a total of 20 chapters
Platform: | Size: 2797568 | Author: 成长 | Hits:

[assembly language612

Description:      编写子程序嵌套结构的程序,把整数分别用二进制和八进制形式显示出来。  主程序     :把整数字变量    存入堆栈,并调用子程序     ; 子程序     :从堆栈中取出    ;调用二进制显示程序      ,显示出与 其等效的二进制数;输出 个空格;  调用八进制显示程序      ,显示出与其等效的八进制数;调用输出回车 及换行符的子程序。 -     编写子程序嵌套结构的程序,把整数分别用二进制和八进制形式显示出来。  主程序     :把整数字变量    存入堆栈,并调用子程序     ; 子程序     :从堆栈中取出    ;调用二进制显示程序      ,显示出与 其等效的二进制数;输出 个空格;  调用八进制显示程序      ,显示出与其等效的八进制数;调用输出回车 及换行符的子程序。
Platform: | Size: 1024 | Author: fengtian | Hits:
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