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Description: 8051驱动LED的4至20毫安的PWM程序。C环境
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Size: 57421 |
Author: 李晨光 |
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Description: 工业仪表常用到4-20mA输出此程序通过C51单片机模拟输出PWM
提供了很好的思路和事例
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Size: 57425 |
Author: ya--ya |
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Description: 4～20mA传感器数据处理新途径.pdf
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Size: 302043 |
Author: gms335 |
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Description: Cantor 表问题： 问题描述： 把分子和分母均小于108 的分数按下面的办法排成一个数表。 1/1 1/2 1/3 1/4 1/5 ... 2/1 2/2 2/3 2/4 2/5 ... 3/1 3/2 3/3 3/4 3/5 ... 4/1 4/2 4/3 4/4 4/5 ... 5/1 5/2 5/3 5/4 5/5 ... ... ... 我们以Z 方形方法给上表的每项编号。第一项是1/1，第二项是1/2， 然后是2/1，3/1，2/2，1/3，1/4，2/3，3/2，4/1，5/1，4/2，...... 要求:对于给定的输入的编号N(0<N<10000)，能够输出其中的第N 项。 如： 输入N = 7； 输出1/4。-Cantor Table : Problem description : put both the numerator and the denominator of the fraction is less than 108 by the following methods formed a few tables. 1/1 1/2 1/3 1/4, 1/5 ... 2/1 2/2 2/3 2/4 2/5 ... 3/1, 3/2 3/3 3/4 3/5 ... 4/1 4/2, 4/3, 4/4, 4/5 ... 5/1 5/2, 5/3, 5/4 5/5 ... ... ... Z to square our side France to the table each numbered. The first is the 1/1, 2 1/2, followed by 2/1, 3/1, 2/2, 1/3, 1/4, 2/3, 3/2, 4/1, 5/1, 4/2 ...... requirements : For a given input of the number N (0lt; Nlt; 10000), to which the output of N items. Such as : N = 7 importation; Output 1/4.
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Size: 3072 |
Author: 欧 |
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Description: 密码查看器：包括的功能： 1. 如何让窗体总在最前面 2. 坐标在窗体上的位置 3. 获得当前鼠标所在窗体的类型 4. 得到文本筐中的密码-password View : includes functions : 1. How to Form 2 overall in the forefront. The coordinates of the location on Form 3. Access to current forms of the host mouse type 4. Text basket to be the password
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Size: 6144 |
Author: 杨曦 |
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Description: 1、将串口通讯协议存储为一个通讯文件，可是随时将存储通讯协议文件调入计算机运行与下位机通讯 可以实现通讯对话，供下位机工程师参考使用，其主要的通讯协议本程序把它们分成四种情况。 以下说明： 1）下位机直接发送数据，上位机只接收不回应数据。 2）下位机直接发送数据，上位机接收并回应数据。 3）上位机直接发送数据，下位机只接收不回应数据。 4）上位机直接发送数据，下位机接收并回应数据。 下位机工程师完全可以利用这个功能单独的并且很方便的调试与上位机通讯程序，更改双方的通讯协议， 不再需要上位机工程师的配合。windwos标准操作，使用方便。 2、可以监听活动串口的数据，将监听到的数据显示到数据显示区里面，可以保存。也可以将原先保存的文件数据读进来，以供分析。数据可以按照Hex和Ascii显示出来。发送所输入的数据，能够定时发送数据，发送文件，提供Hex和Ascii输入方式。 3、可以通过该程序，利用串口将文件发送到另一个计算机上。另一个计算机通过接收文件接收所发出的文件。-1 1 2 3 4 windwos 2HexAsc
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Size: 1431552 |
Author: 孙志华 |
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Description: PHilips 4路A/D+1路D/A芯片控制C程序-PHilips four A/D Road, a D/A chip control procedures C
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Size: 5120 |
Author: 甘生 |
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Description: 一个mini抓包发包程序 我利用pcaplib for windows写的一个抓包发包程序Captx for Win2k/Winnt/Win9x， 仅110K，跑起来占内存2M，附有VC源代码，大家有什么特殊需要可以自己修改代码。 使用方法： （1）把整个CapTx目录拷贝到自己的硬盘上 （2）安装packet capture drivers v2.02(Captx\drivers下的相应目录，在网络中添加协议后，选磁盘安装) (3) 启动CapTx.exe (4) 点抓包按钮开始抓包，用单选按钮可以选择转包后的输出格式是详细的还是简单的， 详细的包格式如下： 00000000： FF FF FF FF FF FF 00 45 00 47 00 48 00 08 45 00 .......e.g.h..e. 简单的包格式仅有中间的部分 （5) 该包存到一个跟应用程序相同的目录中的一个log文件中。 (6)往编辑框中填如下所示的包字符： ff ff ff ff ff ff 00 b0 d0 d0 b0 d8 08 06 00 01 08 00 06 04 00 01 00 b0 d0 d0 b0 d8 c0 a8 00 01 00 00 00 00 00 00 c0 a8 00 c9 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 就可以发送一个ARP包了。 （7）该程序由于由源代码，所以你可以根据你额需要随便修改成自己想要的抓包/发包功能。-a mini capturing Packet letting process I use for windows pcaplib wrote an capturing Packet letting process for Win2k/Winnt/Win9x Captx only 110K, running together for 2M memory, with VC source code, you have any special needs can modify the code themselves. Use : (a) the entire CapTx catalog copy of their hard drive (2) Installation of packet capture drivers v2.02 (Captx \ drivers under the corresponding directory, the network added to the agreement, the election disk installation) (3) activated CapTx.exe (4 ) of capturing Packet capturing Packet button to begin using radio buttons can choose to subcontract the output format is detailed or simple, detailed packet format is as follows : 00000000 : FF FF FF FF FF FF 00 45 00 47 00 48 00 08 45 00 ....... e.g.h.. e. simple packet format only
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Size: 201728 |
Author: 乐浩军 |
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Description: 最高优先级编码器 8位相等比较器
三人表决器（三种不同的描述方式） 加法器描述
8位总线收发器：74245 （注2） 地址译码（for m68008）
多路选择器（使用select语句） LED七段译码
多路选择器（使用if－else语句） 双2－4译码器：74139
多路选择器（使用when－else语句） 二进制到BCD码转换
多路选择器 （使用case语句） 二进制到格雷码转换
双向总线（注2） 汉明纠错吗译码器
三态总线（注2） 汉明纠错吗编码器
解复用器
-highest priority encoder, compared to eight for phase three of the vote (the description of three different ways) Adder Description eight bus Transceivers : 74,245 (Note 2) address decoder (for m68008) Multiple choice (use select statement) LED paragraph 107 of decoding multiple choice ( use if-else statements) 2-4 dual decoder : over 74,139 road choice (use when-else statements) of the binary conversion BCD multiple choice (use case statement) binary Gray code conversion to a two-way bus (Note 2)? Hamming error correction decoder three-state Bus (Note 2)? Hamming error correction encoder demultiplexer
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Size: 43008 |
Author: kerty |
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Description: 1，采用了智能采集，不用编写采集规则（正则表达式）照样可以采集新闻内容(要视版本而定)
2，具有无限制采集功能，可采集远程图片到本地，并自动选择适合的图片来生成新闻内容缩略图
3，所有新闻页面全部采用静态页面（.htm文件）生成，极大地提高了服务器的负载能力（根据需要也可以生成.aspx,shtml等类型文件)
4，可把RSS新闻采集成静态页面文件（rss 2.0)
5，集成企业级流量分析统计系统，让你清楚网站访问情况
6，所见所得的采集，智能记忆采集，不会重复采集，强大的实时采集，分页批量采集等7，是一个练习正则表达式的好工具
-a use of intelligent collection, not to prepare acquisition rules (regular expression) can be collected the same news content (depending on which version) 2, with unlimited collection functions, remote collection of local pictures, and automatically select the appropriate pictures to generate news content thumbnail 3 all news page all use static pages (. htm) generation, greatly enhancing the server's load capacity (as required can be generated. 11, and other types of documents shtml) 4, it can RSS news gathering into static page document (rss 2.0 ) 5, integrated enterprise-flow analysis of statistical system, to make clear to you the website of six, seen from the acquisition, intelligent memory acquisition, will not repeat the collection, a powerful real-time acquisition, tab seven-vo
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Size: 2712576 |
Author: 风 |
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Description: 设计一个按时间片轮转法实现处理器调度的程序
[提示]：
（1）假定系统有5个进程，每个进程用一个PCB来代表。PCB的结构为：
• 进程名——如Q1~Q5。
• 指针——把5个进程连成队列，用指针指出下一个进程PCB的首地址。
• 要求运行时间——假设进程需要运行的单位时间数。
• 已运行时间——进程已运行的单位时间数，初始值为0。
• 状态——假设两种状态，就绪和结束，用R表示就绪，用E表示结束。初始状态都为就绪状态。
(2) 每次运行之前，为每个进程任意确定它的“要求运行时间”。
(3) 把5个进程按顺序排成循环队列，用指针指出队列连接情况。用一个标志单元记录轮到运行的进程。处理器调度总是选择标志单元指示的进程运行，对所指的进程，将其“已运行时间”加1。
(4) 进程运行一次后，若“要求运行时间”等于“已运行时间”，则将状态改为“结束”，退出队列，否则将继续轮转。
(5) 若就绪队列为空，结束，否则转到(3)重复。
-design of a time-Web Method processor activation procedures [Note] : (1) The system has five processes, with each process on behalf of a PCB. PCB structure :# 8226 from the process-- as Q1 ~ Q5. Pointer# 8226-- put five linked queue process, with a target that the process of PCB under the first address.# 8226 requested the running time-- the assumption that the process needs to run the unit time.# 8226 has been in operation for the time-- the process has been in operation for the number of time units, the initial value of 0.# 8226 state-- two hypothetical state, and end in place, ready with R, E said an end. For the initial state of readiness. (2) Before each operation, for each process arbitrarily defined its "run-time requirements." (3) the five sequential process que
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Size: 3072 |
Author: 浪人 |
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Description: 课程安排，用拓扑排序实现
4、实现课程的拓扑排序。(选)（加）
问题描述：软件专业的学生要学习一系列课程，其中有些课程必须在其先修课程完成后才能学习，具体关系见下表：
课程编号 课程名称 先决条件
C1 程序设计基础 无
C2 离散数学 C1
C3 数据结构 C1，C2
C4 汇编语言 C1
C5 操作系统 C3
假设每门课程的学习时间为一学期，试为该专业的学生设计教学计划，使他们能在最短的时间内修完这些课程。-curriculum, using topological sorting achieve four to achieve the topological sorting courses. (EAC) (Canada) Problem description : software professional students to study a series of courses Some of the programs must, in its prevocational courses can be completed after the study, the specific relationship between the table below : Curriculum prerequisite for the design procedures based on C1-C2 C3 Discrete Mathematics C1 C1 data structure, C2 C1 C4 C5 assembly language operating system C3 assumptions each course of study for a semester, Examination for Professional Teaching students design plans so that they can in the shortest time got these courses.
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Size: 254976 |
Author: lea5195444 |
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Description: 用STC89C58单片机做的数据采集和控制，12位AD转换使用TLC2543，通讯协议采用MODBUS（RTU），通过拨码开关改变从机地址，支持模拟量或数字量的读写。（4路模拟量输入、6路开关量输出（继电器输出）、8路开关量输入）
开发环境:KEIK 7.06
-STC89C58 SCM done with the data acquisition and control 12 AD switch TLC2543, MODBUS communications protocols used (RTU), Switching to allocate yards from the plane to change addresses, support analog or digital literacy. (4 analog input, six-channel switching output (output relay), eight-way switch input) development environment : KEIK 7.06
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Size: 62464 |
Author: 白广斌 |
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Description: 用C语言编写程序，以单链表为存储结构，对学生成绩进行处理，要求实现如下功能：
（1）随意输入1班至少10人的学号、成绩，将数据按成绩由高到低的顺序保存在一个单链表中；随意输入2班至少10人的学号、成绩，将数据按成绩由高到低的顺序保存在另一个单链表中；
（2）对至少4人的成绩进行修正，输入班级、学号和成绩修正，如+5，-3，-10，+2，但仍要保持数据按成绩由高到低有序；
（3）分别按顺序输出两个班的成绩表。
（4）将两个班的单链表合并成一个单链表，数据仍按成绩由高到低有序；
（5）按成绩由高到低的顺序输出两个班的成绩总表，含班级、学号、成绩信息。
-C language programming, a single-linked list structure for storage, for the performance of their students, call for the following functions : (a) a duty free importation of at least 10 people, the school, achievements, data based on merit is in the order kept in a single-linked list; free importation of two classes of at least 10 people, the school, achievements, data based on merit is in the order of another single-linked list; (2) at least four pairs of accomplishments that, the importation of class, school and accomplishments amendments, such as 5,-3,-10, 2, but they still maintain data based on merit ranking and orderly; (3) the sequence of two classes of output reports. (4) the two classes of single-chain merged into a single table and the data upon results from high to low and orde
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Size: 2048 |
Author: houny |
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Description: PIC16F876单片机,有4到20MA电流输出,低功耗等特点,使用于工业仪表行业-PIC16F876 microcontroller, to a four 20MA current output, low power consumption and other characteristics, Instrumentation used in industrial sectors
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Size: 57344 |
Author: 陈超 |
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Description: 1.注册服务
2.快捷键，切换鼠标左右键
3.杀掉进程
1.运行RegSwap.bat,可以注册成为服务
2.控制面板-服务中，启动服务
3.Shift+F8,切换
4.在c:\KilledList.txt 文件中输入，进程名，模糊即可，在切换的同时就能杀掉列表中的进程-1. Registration 2. Keyboard, Switching the mouse button 3%. kill a process. RegSwap.bat operation, can be registered as a service 2. Control Panel- services, start-up services 3.Shift F8, switching 4. In c : \ KilledList.txt document input, process, and can be fuzzy, While the switch will kill the process list
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Size: 301056 |
Author: qzf |
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Description: Fully Isolated, Single Channel Voltage and 4 mA to 20 mA Output with HART Connectivity
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Size: 1674240 |
Author: ali |
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Description: 将4路模拟量4-20mA电流信号通过I\V变换将信号送至AD模块，
实现数模转换，送入单片机，经单片机处理后，再次通过DA转换和V\I变换，
输出，最后连接一个远程通讯模块连接至上位机。(The 4 analog 4-20mA current signal is transmitted to the AD module via the I\V transform,
Realize digital to analog conversion, into the microcontroller, after the microcontroller processing, again through the DA conversion and V\I transform,
Output, and finally connect to a remote communication module to connect to the host computer.)
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Size: 190464 |
Author: LONGSHEN1998
|
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Description: 4-20ma current loop transmitter
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Size: 20480 |
Author: staticx |
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Description: STM32 硬件PCB 图纸 输出4-20MA电流信号 采集频率信号(STM32 hardware PCB drawing outputs 4-20mA current signal and collects frequency signal)
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Size: 692224 |
Author: NIHAO111111 |
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