Welcome![Sign In][Sign Up]
Location:
Search - 16*128

Search list

[Crack Hackaes-src-22-11-16

Description: 一个用vc编写的aes算法实现,含有128,192,256三种钥匙长度的-a prepared using vc Orangk'aes algorithm, containing 128,192,256 length of the three key
Platform: | Size: 94653 | Author: zhangyini | Hits:

[Other resource128×16ram

Description: VHDL程序设计的RAM存储器,双端口,128×16比特
Platform: | Size: 863 | Author: petri | Hits:

[Software EngineeringCS2003081aes

Description: 非常经典的AES加密算法接口及演示程序 ,可作课程设计使用 (* 介绍 *) AES 是一种使用安全码进行信息加密的标准。 它支持 128 位、192 位和 256 位的密匙。 加密算法的实现在 ElAES.pas 单元中。 本人将其加密方法封装在 AES.pas 单元中, 只需要调用两个标准函数就可以完成字符串的加密和解密。 (* 密匙长度 *) 128 位支持长度为 16 个字符 192 位支持长度为 24 个字符 256 位支持长度为 32 个字符 所有加密和解密操作在默认情况下为 128 位密匙。-very classic AES encryption algorithm interface and demo program, curriculum design can be used (* Introduction*) AES is a safety code for the use of information encryption standards. It supports 128, 192 and 256 of the keys. Encryption Algorithm of the ElAES.pas modules. I will package its encryption method in AES.pas units, only two standard function call can be completed string encryption and decryption. (* Key length*) 128 support for the length of 16 characters in length 192 supports 24 to 256 characters support length of 32 characters all encryption and decryption operations in default under 128 keys.
Platform: | Size: 53248 | Author: 林靖然 | Hits:

[Crack Hackaes-src-22-11-16

Description: 一个用vc编写的aes算法实现,含有128,192,256三种钥匙长度的-a prepared using vc Orangk'aes algorithm, containing 128,192,256 length of the three key
Platform: | Size: 94208 | Author: zhangyini | Hits:

[Books128641

Description: 中文字库的128X64是一种具有4位/8位并行、2线或3线串行多种接口方式,内部含有国标一级、二级简体中文字库的点阵图形液晶显示模块;其显示分辨率为128×64, 内置8192个16*16点汉字,和128个16*8点ASCII字符集.利用该模块灵活的接口方式和简单、方便的操作指令,可构成全中文人机交互图形界面。可以显示8×4行16×16点阵的汉字. 也可完成图形显示.低电压低功耗是其又一显著特点。由该模块构成的液晶显示方案与同类型的图形点阵液晶显示模块相比,不论硬件电路结构或显示程序都要简洁得多,且该模块的价格也略低于相同点阵的图形液晶模块。-err
Platform: | Size: 18432 | Author: 路江华 | Hits:

[Embeded-SCM Develop16_16

Description: 16 * 16 的127个ascii码的点阵字库-the 127 ascii character dot-matrix code
Platform: | Size: 2048 | Author: wanyanzi | Hits:

[Crack HackMD5

Description: MD5算法,输入需MD5的String,输出为128位,16字节16进制String-MD5 algorithm, MD5 takes the input String, output of 128, 16 bytes of 16 hexadecimal String
Platform: | Size: 4096 | Author: 张杰 | Hits:

[VHDL-FPGA-Verilog128×16ram

Description: VHDL程序设计的RAM存储器,双端口,128×16比特-VHDL programming RAM memory, dual-port, 128 × 16 bits
Platform: | Size: 1024 | Author: petri | Hits:

[SCM1234789

Description: ZLG7290例程*ZLG7290汇编例程*读EEPROM并显示例程* 16×2LCD模块例程*128×64点阵LCD模块例程* 直连KEY和LED例程 直连LED例程* lin模块的原码及例程。LIN总线例程 RS232例程(包括PC端和书上了串口例程) USB1.1例程(包括PC端)RS485例程 USB2.0例程(有3个,包括PC端) 基于ETHERNET的TCPIP例程自发自收例程 外中断CAN例程USB2.0PC例程-ZLG7290 routines routines** ZLG7290 compilation time EEPROM and display routines* 16 × 2LCD module routines* 128 × 64 dot matrix LCD module routines* KEY Direct Connect and Direct Connect LED routines routines LED module* lin original code and routines. LIN bus RS232 routines routines (including the PC client and the book on the serial routines) USB1.1 routines (including the PC-side) RS485 routines USB2.0 routines (have 3, including the PC-side) based on the ETHERNET Since the TCPIP routine collection of spontaneous CAN external interrupt routines routines routines USB2.0PC
Platform: | Size: 3743744 | Author: lbg | Hits:

[Crack Hack1111

Description: (* 介绍 *) AES 是一种使用安全码进行信息加密的标准。 它支持 128 位、192 位和 256 位的密匙。 加密算法的实现在 ElAES.pas 单元中。 本人将其加密方法封装在 AES.pas 单元中, 只需要调用两个标准函数就可以完成字符串的加密和解密。 (* 密匙长度 *) 128 位支持长度为 16 个字符 192 位支持长度为 24 个字符 256 位支持长度为 32 个字符 所有加密和解密操作在默认情况下为 128 位密匙。 (* 文件列表 *) ..\Source\ AES 单元文件 ..\Example\ 演示程序 (* 适用平台 *)-(* Introduced*) AES is a kind of code the use of safety information encryption standards. It supports 128, 192 and 256-bit keys. Encryption algorithm in ElAES.pas unit. I will of its encryption module is packaged in a AES.pas only two criteria need to call function can be completed string encryption and decryption. (* Key length*) length of 128 to support 16 to support 192 characters in length for 24 characters in length to 256 to support 32 characters for all encryption and decryption operations by default for the 128 key. (* File List*) .. Source AES unit document .. Example demo program (* applicable platform*)
Platform: | Size: 211968 | Author: dddd | Hits:

[SCM16X128

Description: Proteus 8字的LED仿真,商业项目…源程序来至互联网,请尊重版权。-Proteus 8 character LED simulation, source code to commercial projects ... to the Internet, please respect copyright.
Platform: | Size: 44032 | Author: 杨龙 | Hits:

[Other8051sheji

Description: 为了方便读者整理 8051 相关专题制作报告,需要使用到的 8051 基本资料电子文件 51.TXT 收录于此目录中,读者可以依需要自行应用,加入到自己的报告中,但仅限于学校的学生制作报告用,不得移做它用,并遵守知识产权使用的所有规定。其中文字内容取材至 "单芯片 8051 实作入门",书号 P2277,文魁图书出版。 8051 基本资料如下: □8051 主要特性 □8051 引脚说明 □8051 中断服务常式的进入点 □8051 特殊目的寄存器 □8051 内部控制寄存器 at89c51 为 ATMEL 所生产的可电气烧录清洗的 8051 相容单芯片,其内部程序代码容量为4KB 8051主要功能列举如下: □ 为一般控制应用的 8 位单芯片 □ 晶片内部具时钟振荡器(传统最高工作频率可至 12MHz) □ 内部程式存储器(ROM)为 4KB □ 内部数据存储器(RAM)为 128B □ 外部程序存储器可扩充至 64KB □ 外部数据存储器可扩充至 64KB □ 32 条双向输入输出线,且每条均可以单独做 I/O 的控制 □ 5 个中断向量源 □ 2 组独立的 16 位定时器 □ 1 个全多工串行通信端口 □ 8751 及 8752 单芯片具有数据保密的功能 □ 单芯片提供位逻辑运算指令 -err
Platform: | Size: 5773312 | Author: ty | Hits:

[SCMLED_DISPLAY

Description: LED_DISPLAY.rar包括电路图和源程序,用51单片机实现。LED点阵为16*128,可用于显示8个16*16点阵的汉字或图形等,可级联。-LED_DISPLAY.rar including schematics and source code, the MCU 51. LED dot matrix 16* 128, can be used to display 8 16* 16 lattice, such as Chinese characters or graphics can be cascaded.
Platform: | Size: 10240 | Author: zhoujiang | Hits:

[SCMled-8zi

Description: /***************************************************** 16*128 LED点阵屏 C 程序 ****************************************************** 声明: 本程序供大家学习之用,用勿用于商业用途。尊重版权。 编写:邓椿薪 时间:2006年1月20日 晚 邮箱:love2151@xinhuanet.com ******************************************************* //595连级输出数据,138行驱动。P0_1为移动速度高速/*点阵显示汉字程串口输出字符数据, //P2口输出行扫描信号,P2_7输出595锁存信号。*/-/***************************************************** 16* 128 LED dot matrix screen C procedures****************************************************** Disclaimer: This procedure for everyone learning with not for commercial purposes. Respect for copyright. Preparation:邓椿pay time: in January 2006 the evening of 20 E-mail: love2151@xinhuanet.com*******************************************************// 595 Link-level output data, 138 line driver. High speed for mobile P0_1/* dot-matrix display Chinese characters-way serial output character data,// P2 port output line scanning signal, P2_7 latch 595 output signal.* /
Platform: | Size: 2048 | Author: kd911 | Hits:

[Crack HackAES

Description: ES(The Advanced Encryption Standard)是美国国家标准与技术研究所用于加密电子数据的规范。它被预期能成为人们公认的加密包括金融、电信和政府数字信息的方法。 AES 是一个新的可以用于保护电子数据的加密算法。明确地说,AES 是一个迭代的、对称密钥分组的密码,它可以使用128、192 和 256 位密钥,并且用 128 位(16字节)分组加密和解密数据。与公共密钥密码使用密钥对不同,对称密钥密码使用相同的密钥加密和解密数据。通过分组密码返回的加密数据 的位数与输入数据相同。迭代加密使用一个循环结构,在该循环中重复置换(permutations )和替换(substitutions)输入数据。Figure 1 显示了 AES 用192位密钥对一个16位字节数据块进行加密和解密的情形。-ES (The Advanced Encryption Standard) are the United States National Institute of Standards and Technology for encrypting electronic data specification. It is expected to become the recognized encryption including financial, telecommunications and government figure information. AES is a new electronic data can be used to protect the encryption algorithm. Specifically, AES is an iterative, symmetric-key password packet, it can use the keys 128,192 and 256, and with 128 (16 bytes) packet encryption and decryption of data. Password and public key to use of different keys, symmetric keys use the same password key encryption and decryption of data. Back through the block cipher encryption of data and input data the same as the median. Encrypted using a cycle of iterative structure, in the replacement cycle to repeat (permutations) and replacement (substitutions) input data. Figure 1 shows the AES with 192 keys on a 16-byte data block for encryption and decryption case.
Platform: | Size: 1024 | Author: 皮艾尔 | Hits:

[ARM-PowerPC-ColdFire-MIPSEP9315

Description: 200-MHz ARM920T Processor • 16-kbyte Instruction Cache • 16-kbyte Data Cache • Linux® , Microsoft® Windows® CE-enabled MMU • 100-MHz System Bus • MaverickCrunch™ Math Engine • Floating Point, Integer, and Signal Processing Instructions • Optimized for digital music compression and decompression algorithms. • Hardware interlocks allow in-line coding. • MaverickKey™ IDs • 32-bit Unique ID can be used for DRM-compliant 128-bit random ID. • Integrated Peripheral Interfaces • 32-bit SDRAM Interface-200-MHz ARM920T Processor • 16-kbyte Instruction Cache • 16-kbyte Data Cache • Linux ® , Microsoft ® Windows ® CE-enabled MMU • 100-MHz System Bus • MaverickCrunch ™ Math Engine • Floating Point, Integer, and Signal Processing Instructions • Optimized for digital music compression and decompression algorithms. • Hardware interlocks allow in-line coding. • MaverickKey ™ IDs • 32-bit Unique ID can be used for DRM-compliant 128-bit random ID. • Integrated Peripheral Interfaces • 32-bit SDRAM Interface
Platform: | Size: 556032 | Author: zhanglong | Hits:

[matlabOFDM_SIM

Description: 经典的OFDM仿真,程序严谨规范,包含QAM8,16,32,64,128,QPSK,BPSK的不同编码调制的下的仿真,非常适合学习!!吐血推荐-Classical OFDM simulation, discipline procedures, including QAM8, 16,32,64,128, QPSK, BPSK modulation of the different coding of simulation, very suitable for learning! ! Recommended hematemesis
Platform: | Size: 9216 | Author: yh | Hits:

[Algorithmfft

Description: FFT算法实现 Radix2 可以计算 4,8,16,32, 64,128, 256....点FFT Radix4 可以计算 4,16, 64, 256, 1024...点FFT FFT_DIT_general.c 实现了 Radix2 和Radix4 的配合使用,可以计算Radix2可以计算的所有FFT,但效率比Radix2高。-FFT can be calculated Radix2 algorithm 4,8,16,32, 64,128, 256 .... can calculate the FFT Radix4 points 4,16, 64, 256, 1024-point FFT FFT_DIT_general.c ... Radix2 and Radix4 achieved with the use of Radix2 can calculate can calculate all the FFT, but Radix2 high efficiency.
Platform: | Size: 2048 | Author: liuxiaoxiao | Hits:

[Software Engineeringpcm

Description: 一。产生长度为500的零均值,单位方差的高斯随机变量序列,用均匀pcm的方法用16电平进行量化:1)求所得的SQNR,该序列的前5个值,相应的量化值和相应的码字。2)画出量化误差(定义为输入值和量化值之间的差),同时 画出量化值作为输入值的函数的图。3)用128量化电平数重做2)题, 比较结果。 二。产生一个长度为500,按N(O,1)分布的随机变量序列,分别用16,128量化电平数和u=255的u律非线性进行量化,画出每种情况下量化器的误差和输入-输出关系,并求SQNR. 三。长度为500的非平稳序列a由两部分组成:前20个样本是按照均值为零和方差为400的高斯随机变量产生的,其余480个样本是根据均值和方差为1的高斯随机变量产生的,对这个序列分别用均匀pcm和非均匀pcm方法进行128电平量化,试比较两种情况下所得到的SQNR。 -One. Have a length of 500 zero mean, unit variance Gaussian random variables with uniform pcm way to quantify the level with a 16: 1) Find the income SQNR, the sequence of the first 5 values, the corresponding quantization value and the corresponding codeword. 2) Draw the quantization error (defined as the input value and quantify the difference between the values), and draw quantitative values ​ ​ as a function of input graph. 3) redo 128 the number of quantization level 2) title, compare the results. II. Produce a length of 500, according to N (O, 1) distributed random variables, respectively 16,128 and the number of quantization level of u u = 255 to quantify non-linear law, draw each case quantizer error and input- output relationships, and seek SQNR. III. Length of the non-stationary series is a 500 consists of two parts: the first 20 samples in accordance with zero mean and variance of 400 generated Gaussian random variable, and the remaining 480 samples are based o
Platform: | Size: 4096 | Author: sun | Hits:

[SCM16-128

Description: 16*64点阵程序,串口收数据,LED屏显示-16* 64 dot matrix program, serial receive data, LED screen display
Platform: | Size: 1017856 | Author: Mr chen | Hits:
« 12 3 4 5 6 7 8 9 10 »

CodeBus www.codebus.net