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Search - 1100 - List
[
Other resource
]
Fibonacci10
DL : 0
适合计算第n个Fibonacci数,采用类定义,n可以是1100内的任意正整数-calculated for the first n Fibonacci numbers using the definitions of the categories, n 1100 can be the arbitrary integer
Date
: 2008-10-13
Size
: 1.88kb
User
:
aa1986118
[
Other resource
]
FindBase
DL : 0
同一个数会由于采用不同的基数而使得其表现的形式是完全不一样的,在我们的学习中,我们熟悉的基数有10进制、12进制、60进制、2进制、8进制和16进制。比如数据12,如果我们用2进制表示,则它就是1100;如果用3进制表示就是110;如果用8进制表示则是14。我们的编程任务就是与数的进制(也就是基数)有关。 程序中我们会给大家很多个数对(假设每个数对的数用X和Y表示),程序需要解决的问题就是为X和Y各选择一个最小的基数,以使得这两个数在其选择的基数上是一对相等的数。 例如,12和5这个数对,我们可以为12选择基数3,为5选择基数6,这样一来12(base 3)=5(base 6),因为12(base 3)就是10进制数5,而5(base 6)也是10进制数中的5。 程序的输入是通过文件完成的。 文件中的每一行都包含一个数对X和Y,两个数通过一个或多个空格符分割,与X和Y相关联的有效基数值范围为2~36。X和Y的合理数值表示字符包括0—9和A-Z(表示数值10-35)。 文件的最后一行用一个数字0表示输入的结束。-same number will be different because of the base and make its performance in the form of a completely different, In our study, we are familiar with the base 229 10, 229 12, 229 60, 229 2. 8-band 16-band. For example, 12 data, if we use the two-band said, it is 1100; If three-band said is 110; If eight 229 said it is 14. Our task is programming with a number of 229 (or base). We will process all of the many numbers (on the assumption that each number on the number of X-and Y said), procedures need to address the issue of the X and Y choose a minimum base, This makes two to a few in their chosen base is the equivalent of a few. For example, 12 and 5, the figure right, we will be able to choose 12 base 3 to 6 base 5 choice, This one to 12 (base 3) = 5 (base 6), because 12 (base 3) 229 10
Date
: 2008-10-13
Size
: 10.29kb
User
:
duyankang
[
CSharp
]
sta
DL : 0
设当前系统中有多个栈在工作,多栈模拟问题要求模拟当前系统中各栈的工作状态。 由文件input.txt给出输入数据。第1行是正整数n,表示有n个栈操作。接下来的n行, 每行给出一个栈操作指令。栈操作指令“PUSH A B”表示将正整数B加入编号为A的栈顶; 栈操作指令“POP A”表示输出编号为A的栈顶元素输入文件示例 输出文件示例 input.txt output.txt 7 PUSH 1 100 PUSH 1 200 PUSH 2 300 PUSH 2 400 POP 3 POP 1 POP 2 0 200 4-set up the current system in a number of warehouse work, Stack simulation requires simulation of the current system of state stack. Input.txt documents presented by the input data. Line 1 is a positive integer n, n-stack operation. N the next trip, each trip is a stack operating instructions. Stack operating instructions "PUSH A B" is said to integer numbers of B to A stack; Stack operating instructions "A POP," said output No. A stack of documents imported elements example output file example inpu t.txt 1100 output.txt 7 PUSH PUSH PUSH 1200 2300 PUSH 2400 POP POP a POP 3 2 0200 4
Date
: 2008-10-13
Size
: 7.31kb
User
:
赖荣伟
[
assembly language
]
1100
DL : 0
汇编编写的键盘录入数据的转换与显示程序
Date
: 2008-10-13
Size
: 4.19kb
User
:
张军
[
Driver Develop
]
1
DL : 0
一下是注册表项 [HKEY_LOCAL_MACHINE\\Drivers\\BuiltIn\\SDMMC] \"Dll\"=\"sdmmc_loader.dll\" \"Prefix\"=\"SML\" \"Order\"=dword:2 \"Ioctl\"=dword:4 \"Class\"=dword:01 \"SubClass\"=dword:80 \"ProgIF\"=dword:0 \"DeviceID\"=dword:1100 \"VendorID\"=dword:15b7 \"FSD\"=\"fatfsd.dll\" \"Profile\"=\"SDMMC\" \"IClass\"=\"{A4E7EDDA-E575-4252-9D6B-4195D48BB865}\"
Date
: 2008-10-13
Size
: 13.97kb
User
:
as fa
[
Other resource
]
registry-1100
DL : 0
EVC编写WINCE下读取修改增加注册表信息
Date
: 2008-10-13
Size
: 5.18mb
User
:
zhaocy
[
Other resource
]
poj1100
DL : 0
北大在线OJ 1100题,运用自动机成功求解方程式的经典例子,此程序可作为自动机模板
Date
: 2008-10-13
Size
: 1.17kb
User
:
陈佩鹏
[
GUI Develop
]
sy5_2
DL : 0
按“开始”按钮可以在文本框中显示所有1001到1100之间的素数。-according to the "start" button in the text box can show all from 1001 to 1100 between the prime numbers.
Date
: 2008-10-13
Size
: 3.75kb
User
:
薛
[
GUI Develop
]
sy5_2
DL : 0
按“开始”按钮可以在文本框中显示所有1001到1100之间的素数。-according to the "start" button in the text box can show all from 1001 to 1100 between the prime numbers.
Date
:
Size
: 3kb
User
:
薛
[
RFID
]
cc1100_Common
DL : 0
chipcon公司的无线射频射频芯片cc1100应用的公共程序-chipcon company's radio frequency RF chip cc1100 application of public procedures
Date
:
Size
: 7kb
User
:
flyzigbee
[
RFID
]
cc1100Master
DL : 0
chipcon公司无线芯片cc1100的主机通信程序 具有一定的参考价值-chipcon wireless chip companies cc1100 mainframe communication program has some reference value
Date
:
Size
: 10kb
User
:
flyzigbee
[
RFID
]
cc1100Slave
DL : 0
chipcon公司无线芯片cc1100的从机通信程序 具有一定的参考价值-chipcon wireless chip companies from cc1100 communication procedures with certain reference value
Date
:
Size
: 10kb
User
:
flyzigbee
[
ARM-PowerPC-ColdFire-MIPS
]
ARM-boot-code-1.1.0
DL : 0
Boot code for ARM-720T, ARM-920T, XScale, SA1100 and EPXA-Boot code for the ARM-720T ARM-920T, XScale, SA1100 and EPXA
Date
:
Size
: 639kb
User
:
侠克定
[
SCM
]
hwdriver
DL : 0
手写IC(EPH1100)的80C51驱动软件。-handwritten IC (EPH1100) 80C51-driven software.
Date
:
Size
: 5kb
User
:
lichun
[
SCM
]
M16-1100
DL : 0
M16-1100开发包,对无线通信有一定的参考价值。-M16-1100 development kit, the wireless communication has some reference value.
Date
:
Size
: 912kb
User
:
马学霞
[
SCM
]
1100-wireless-game--
DL : 0
1100无线比赛计分牌功能设计 包含发送程序和接收程序 基于stc51单片机-1100 wireless game scoreboard functionality designed to include procedures for sending and receiving program microcontroller based stc51
Date
:
Size
: 74kb
User
:
wxy
[
Technology Management
]
DLT-1100.1-2009
DL : 0
DLT 1100.1-2009 电力系统的时间同步系统 第1部分:技术规范.PDF-failed to translate
Date
:
Size
: 884kb
User
:
t
[
SCM
]
JASK1000-1100
DL : 0
1100实现各种功能的程序集合,如无线温度控制-Collection of 1100 to achieve various functions, such as wireless temperature control
Date
:
Size
: 21.09mb
User
:
吴高文
[
SCM
]
Wireless-232(1100)
DL : 0
无线串口通信(ATMEGA16+1100)-The wireless serial communication (ATMEGA16+1100)
Date
:
Size
: 193kb
User
:
徐磊
[
Linux-Unix
]
SA-1100
DL : 0
Purpose Definition of constants related to the StrongARM SA-1100 microprocessor (Advanced RISC Machine (ARM) architecture version 4). This file is based on the StrongARM SA-1100 data sheet version 2.2. -Purpose Definition of constants related to the StrongARM SA-1100 microprocessor (Advanced RISC Machine (ARM) architecture version 4). This file is based on the StrongARM SA-1100 data sheet version 2.2.
Date
:
Size
: 15kb
User
:
waorihen
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