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[VC/MFC] cPPJoseph-ring DL : 0: 1. 熟悉线性表的操作和应用； 2. 利用顺序表的存储结构解决约瑟夫环问题。方法实现：利用线性表中循环链表的结构特点，每个节点表示一个人。用一个程序模拟人的报数出圈，1表示人还在圈里，0表示人已经出圈了。当第L个人出圈之后，报数程序结束，输出最后的在圈子里的人的情况。-A familiar linear form of the operation and application 2. Use sequence table storage structure to solve Josephus problem. Ways: using the linear table circular list of structural features, each node represents a person. With a program to simulate the number of people reported a circle, a circle indicates people are still, 0 means people have been out of the ring. When the first person out of line L, the number of procedures at the end of the final output in the circle of his condition.
Date : 2025-12-16 Size : 4kb User : 安然