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[VC/MFC] VC++Essencelectures DL : 0: Visual C++(以下简称VC)是一个强大的编程工具，它以C++为语言基础。C++是由C语言发展而来，是面向对象程序设计语言之一，所以要用VC开发程序，要有坚实的C++语言基础。本教程没有对C++语言做全面的介绍，而是针对有一定C语言基础的读者，着重讲解C++面向对象的三大特性——数据封装、继承性、多态性。对于C++语言的基本概念、基本语法和编程方法，可参考VC大本营之C/C++栏目。-Visual C++ (Hereinafter referred to as VC) is a powerful programming tool, it C++ Basis for the language. C++ Is developed from the C language is object-oriented programming languages, so use VC development process, there must be a solid C++ Language basis. This tutorial does not C++ Language comprehensive introduction, but at a certain C language-based readers that focused on the C++ The three characteristics of object-oriented- data encapsulation, inheritance, and polymorphism . For C++ Language the basic concepts, the basic syntax and programming methods, can be found VC base camp of C/C++ Columns.
Date : 2025-12-26 Size : 107kb User :
[VC/MFC] Pheponatch DL : 0: 费波那其数列，1，1，2，3，5……编写程序求第十项,用递归和非递归两种方法实现-Charge wave that several of its columns, 1,1,2,3,5 ... ... seek the tenth programming using recursive and non recursive in two ways
Date : 2025-12-26 Size : 3kb User : Annie
[VC/MFC] Excelfile DL : 0: 通过本文及配套示例源码你可以更加灵活的控制Excel表格文件，其中包括创建新Excel文件、写入表格数据、读取表格数据(包括对原建Excel文件自已手工添加的行、列数据的准确读取)，删除已有Excel表格，对表格中指定行、列、单元格进行查询、插入、替换等操作，同时还可以将生成的Excel 文件转换为按指定分隔符分隔的其它文本格式的文件。-Through this and related sample source code you can be more flexible control of Excel spreadsheet files, including creating a new Excel file, write the form data, read the table data (including their own original hand-built Excel file to add the rows, columns, accurate reading of the data take), remove the existing Excel table, specify the table row, column, cell query, insert, replace and other operations, but also the generated Excel files can be converted to the specified delimiter separated by other text format.
Date : 2025-12-26 Size : 17kb User : TURE918
[VC/MFC] shiyaner DL : 0: 试用分别用线性表的向量存储结构和链表存储结构来实现约瑟夫(Josephu)问题。约瑟夫问题如下：设有n个人围坐圆桌周围。从某个位置上的人开始从1报数，数到m的人便出列，下一个人(第m+1个)又从1报数开始，数到m的人便是第2个出列的人，依次类推，直到最后一个人出列为止，这样就可以得到一个人员排列的新次序。例如，n=8,m=4,从第1个人数起，得到的新次序为48521376. -Try using the linear form of the vectors were stored in the structure and linked list storage structure to achieve Joseph (Josephu) problem. Joseph questions are as follows: with n individuals sitting around the round table. From a position of people who have reported from a number of people who count it out m columns, the next person (s m+1 month) and from a number of reports began to m the number of people who are the first two out of out of people, and so on, until the last person out of the column so far, so that staff can be arranged in a new order. For example, n = 8, m = 4, several individuals from the first one, get a new order of 48,521,376.
Date : 2025-12-26 Size : 24kb User : 陆斌
[VC/MFC] High_precision_calculation DL : 0: 对数值很大、精度很高的数进行高精度计算是一类十分常见的问题。比如，对国债进行计算就是属于这类问题。现在要你解决的问题是：对一个实数R( 0.0 < R < 99.999 )，要求写程序精确计算 R 的 n 次方(Rn)，其中n 是整数并且 0 < n <= 25。Input:T输入包括多组 R 和 n。 R 的值占第 1 到第 6 列，n 的值占第 8 和第 9 列。Output:对于每组输入，要求输出一行，该行包含精确的 R 的 n 次方。输出需要去掉前导的 0 后不要的 0 。如果输出是整数，不要输出小数点-Description Problems involving the computation of exact values of very large magnitude and precision are common. For example, the computation of the national debt is a taxing experience for many computer systems. This problem requires that you write a program to compute the exact value of Rn where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25. Input The input will consist of a set of pairs of values for R and n. The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9. Output The output will consist of one line for each line of input giving the exact value of R^n. Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed. Don t print the decimal point if the result is an integer.
Date : 2025-12-26 Size : 176kb User :
[VC/MFC] bisai DL : 0: 设有个运动员要进行网球循环赛。现要设计一个满足以下要求的比赛日程表：（1）每个选手必须与其他n-1个选手各赛一次；（2）每个选手一天只能赛一次；（3）循环赛一共进行n-1天；按此要求可将比赛日程表设计成n行和n-1列的表。表中第i行和第j列处填入第i个选手在第j天所遇到的对手。 -With a round robin tennis players to be. Is to design a game schedule meet the following requirements: (1) Each player must be with the other n-1 once a player of the tournament (2) Each player can only race one day one (3) Round Robin conducted a total of n- 1 day schedule this request can be designed to match n-1 n rows and columns. Table row and j-i-populate the first row at the j-i-day players encounter rivals.
Date : 2025-12-26 Size : 1kb User : 黄林
[VC/MFC] ysfh DL : 0: 1.输入m ，n及每个人的密码，输出序号。 2.读入每个结点的密码，序号，据需求找结点读入新的m，n.并删除结点。 3.按照出列顺序引出每个人的编号。 -1. Input m, n, and each person' s password, the output number. 2. Read each node' s password, serial number, it needs to find a new read nodes m, n. and delete nodes. 3. In accordance with the order of the columns leads to each person' s number.
Date : 2025-12-26 Size : 5kb User : 大宝
[VC/MFC] mg DL : 0: 以二维数组表示迷宫，其中，在迷宫最外层加墙(0表示通路，1表示障碍)。从文件（MAZE1或 MAZE2）读入迷宫的入口和出口以及所走迷宫的行和列。根据设计寻求出路。-Two-dimensional array that maze, which increases the outer wall of the maze (0 channels, 1 barrier). From the file (MAZE1 or MAZE2) read entry and exit into the maze and the maze of rows and columns. Designed to find a way out.
Date : 2025-12-26 Size : 360kb User : 大宝
[VC/MFC] LBM-bgk DL : 1: 本文为LBM圆柱绕流程序，适合入门使用。可以通过改程序掌握基本技巧-This article for the flow around LBM columns, suitable for introductory use program
Date : 2025-12-26 Size : 73kb User : taylor
[VC/MFC] acmmode DL : 0: 吉林大学acm模板，各列acm题型，非常好的学习参考资料-Jilin University acm template columns acm kinds of questions, a very good learning references
Date : 2025-12-26 Size : 755kb User :
[VC/MFC] transposed-matrix- DL : 0: 3. 编程序，按如下方法求A矩阵的转置矩阵B：输入两个正整数m和n，而后通过使用指针配合new运算符生成一个m行n列的二维动态数组A以及另一个n行m列的二维动态数组B，之后为A输入数据（A矩阵数据），进而求出其转置矩阵B（数据放动态数组B中）并输出结果。-Programmed transposed matrix B requirements matrix A as follows: Input two positive integers m and n, and then by using the pointer with the two-dimensional dynamic arrays A new operator to generate a m rows and n columns, as well as the other n rows and m columns, the two-dimensional dynamic array B, followed by the A input data (A matrix data), thereby obtaining the transfer matrix B (data put dynamic array B) and outputs the result.
Date : 2025-12-26 Size : 1kb User : 捉不住的鼬鼠
[VC/MFC] A DL : 0: 矩阵的乘法，输入两个矩阵的行数和列数及其值，计算二者的乘积-Matrix multiplication, input two matrices of rows and columns and their values, calculated product of the two
Date : 2025-12-26 Size : 157kb User : wangxiaoyi
[VC/MFC] Joseph-ring DL : 0: 编号为1，2，3，„ ，n的n个人按顺时针方向围坐一圈，每人手持一个密码（正整数）。一开始任选一个整数作为报数上限值，从第一人开始顺时针自1开始顺序报数，报到m时停止报数。报m的人出列，将它的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去直到所有人全部出列为止。试设计程序实现之-Numbered 1,2,3, " , n n individuals sitting clockwise in a circle, each holding a password (positive integer). As a start, optionally, an integer number of reported upper limit, the first person clockwise order starting a number of newspaper, reported that the number m stop report. telegram m people out of the line, it' s password as the new value of m, starting with his next person in a clockwise direction, again a newspaper number, and so on until all the columns until the owner. try to design a program to achieve it
Date : 2025-12-26 Size : 1.41mb User : 韩
[VC/MFC] 快速排序法 DL : 0: 本程序是C++编写的通用基础版排序程序，能实现数列的快速排序(This program is a general basic version of the C++ sorting program, to achieve the rapid sequencing of the number of columns)
Date : 2025-12-26 Size : 1012kb User : 会飞的鹰