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[VC/MFC] CPP DL : 0: 1，最短路径问题：给你n个点，m条无向边，每条边都有长度d和花费p，给你起点s终点t，要求输出起点到终点的最短距离及其花费，如果最短距离有多条路线，则输出花费最少的。输入：输入n,m，点的编号是1~n,然后是m行，每行4个数 a,b,d,p，表示a和b之间有一条边，且其长度为d，花费为p。最后一行是两个数 s,t 起点s，终点t。n和m为0时输入结束。 (1<n<=1000, 0<m<100000, s != t) 输出：输出一行有两个数，最短距离及其花费。 2，建立一个图 3，建一个图书馆管理系统，说明：程序使用说明：本程序是简单的图书管理系统，分为添加新书、浏览全部图书和删除图书三个功能。输入1可添加新书，分别输入书名、ISDN、价格和作者后，即添加完成。输入2可浏览全部的图书。输入3可删除图书，输入要删除的行号，即可删除该行，如果输入的行号是最后一行，即删除全部。 4，最小生成树prim算法 5，C++primer 教材电子版（第四版）-1, the shortest path problem: Give you n points, m strip undirected edges, each side has a length d and spending p, to give you a starting point s end t, the required output starting the shortest distance to the end of its cost, if the shortest distance between multiple routes, the output of the least expensive. Input: Input n, m, the point number is 1 ~ n, then the m rows, each row 4 numbers a, b, d, p, between a and b represents an edge and having a length of d, cost for p . The last line is the two numbers s, t starting point s, end t. n and m are 0:00 input ends. (1 <n <= 1000, 0 <m <100000, s! = T) Output: There are two output a line number, the shortest distance and cost. 2, the establishment of a graph 3, built a library management system, Definitions: Instructions for use: This program is a simple library management system, divided into adding new books, browse books and books delete all three functions. Enter 1 to add new books, and receive
Date : 2025-12-19 Size : 2.33mb User : 刘小喵