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[source in ebook] Chapter7_1 DL : 0: 这个是VC实例教程第7章节的第一个实例的源代码-example of this is a VC handbook section 7 of the first chapter of the source code examples
Date : 2025-12-14 Size : 21kb User : sheng
[source in ebook] Chapter7_2 DL : 0: 这个是VC实例教程第7章节的第二个实例的源代码-example of this is a VC handbook section 7 of the second section of the source code examples
Date : 2025-12-14 Size : 21kb User : sheng
[source in ebook] Chapter7_3 DL : 0: 这个是VC实例教程第7章节的第三个实例的源代码-example of this is a VC handbook section 7 of the third chapter of the source code examples
Date : 2025-12-14 Size : 21kb User : sheng
[source in ebook] Chapter9_2 DL : 0: 这个是VC实例教程第9章节的第2个实例的源代码-example of this is a VC handbook section 9 of chapter 2 of the source code examples
Date : 2025-12-14 Size : 21kb User : sheng
[source in ebook] vcanli DL : 0: 本光盘名称为“Visual C++ 6.0编程案例精解”，提供了本书第 2到12章的实例源程序。读者需要安装Visual C++才能将它们打开。-the name of the CD-ROM "Programming in Visual C 6.0 cases Accurate" The book provides a section 2-12 of Chapter example source. Readers need to install Visual C they can be opened.
Date : 2025-12-14 Size : 7.34mb User : 雷鸣
[source in ebook] fighter_src-6972 DL : 0: 吃豆子的游戏.非常好玩，截面精美-eat beans game. Very fun, exquisite section.
Date : 2025-12-14 Size : 219kb User : kemo
[source in ebook] LinuxC_program_Code DL : 0: Linux下C语言编程例子，每一章节的例子，可以直接使用供大家参考。-Linux C language programming examples, each section of the examples can be directly used for reference.
Date : 2025-12-14 Size : 49kb User : liulihua
[source in ebook] josep DL : 0: Josephus排列问题定义如下：假设n个竞赛者排成一个环形。给定一个正整数m，从某个指定的第一个人开始，沿环计数，每遇到第m个人就让其出列，且计数继续进行下去。这个过程一直到所有的人都出列为止。最后出列都优胜者。每个人出列的次序定义了整数1，2，...，n的一个排列。这个排列称为一个(n,m)Josephus排列。例如，（7,3)Josephus排列为3,6,2,7,5,1,4.对于给定的1，2，...n中的k个数，Josephus想知道是否存在一个正整数m(n,m)Josephus排列的最后k个数为事先指定的这k个数。-Josephus problem with the definition is as follows : Suppose n player formed a ring. Given a positive integer m, from a designated first started along the Central Counting that every individual section m let out their series and counting continued. This process has been to all of them from far out. Finally out from all the winners. Everyone out in the order shown in the definition of integers 1, 2 ,..., n an order. This arrangement known as a (n, m) Josephus arranged. For example, (7,3) Josephus order of 3, 6,2,7,5,1,4. For a given set of 1,2, ... n and k the number, Josephus would like to know whether there is a positive integer m (n, m) Josephus with the final number k prior to the designated number k this.
Date : 2025-12-14 Size : 2kb User : 诛仙
[source in ebook] acmanswerpack DL : 0: 本光盘是《国际大学生程序设计竞赛例题解（一）》的配套光盘，内容包括书中对应章节习题的测试数据，部分附带有程序源码。以便于读者更好地学习。本文件在于说明光盘的功能、各目录的内容及运行的软硬件环境、常见问题的解决方法等需给读者讲明的问题。光盘结构：光盘结构按照书本的目录对应编排。共有四个目录，分别存放书中第二、四、六和七章例题的数据，它们又分别在各自的下一层目录存放每一节（一节就是一道例题）的内容。数据文件：数据文件是本光盘的主要文件。每道例题都有大约8组的测试数据，数据文件分为输入文件和输出文件两类。这些文件都是文本文件，可以用任何文本编辑器打开和编辑，文件内容的存储格式在书中有严格规范，它位于题目输入格式和输出格式部分。由于有多组数据，我们在文件名末尾加上数字，标明序号。一般而言，序号越大，数据的规模越大，难度更高。-the CD is the "International Collegiate Programming Contest Examples solution (1)" matching discs, The book includes chapters corresponding Exercise test data, some fringe procedure source. To the readers to better study. This document is to describe the function of CD, the contents of the directory and the operation of the hardware and software environment, common solutions to problems such as the need to explain to readers the problem. CD Structure : CD-ROM books in accordance with the structure of the corresponding directory scheduling. A total of four catalogs, were placed second book, IV, VI and VII of the Charter of excellence, They also in their respective directories stored under a layer of each section (one is an excellence) content. Data files : data files of the CD is
Date : 2025-12-14 Size : 755kb User : wu
[source in ebook] C_9 DL : 0: 100个经典vhdl编程实例，第1例带控制端口的加法器第2例无控制端口的加法器第3例乘法器第4例比较器第5例二路选择器第6例寄存器第7例移位寄存器第8例综合单元库第9例七值逻辑与基本数据类型第10例函数第11例七值逻辑线或分辨函数第12例转换函数第13例左移函数第14例七值逻辑程序包第15例四输入多路器...... -100 vhdl classical programming examples, No. 1 is the control port Adder first two cases of uncontrolled port Adder No. 3 Multiplier first four cases compared with the first five cases 2 Lu choice for the first six cases Register No. 7 cases shift register first eight cases consolidated for the first module nine cases seven-valued logic and basic data types No. 10 No. 11 cases function seven-valued logic function or defective Line No. 12 conversion functions No. 13 bits function section 14 cases 7 logic package No. 15 cases four multi-input devices ......
Date : 2025-12-14 Size : 329kb User :
[source in ebook] jshmatlab DL : 0: 实用100例:图形应用篇\界面设计篇\图形处理篇\数值分析篇 -practical hundred cases : Graphics Applications chapter \ interface design articles \ graphics processing chapter \ Numerical Analysis Section
Date : 2025-12-14 Size : 21kb User :
[source in ebook] matlab_code DL : 0: 3个matlab原程序文件，包括： 1-32是：图形应用篇 33-66是：界面设计篇 67-84是：图形处理篇 85-100是：数值分析篇 -three Matlab original files, including : 1-32 : Graphics Applications articles 33-66 is : interface design articles 67-84 is : graphics processing Chapter 85-100 is : Numerical Analysis Section
Date : 2025-12-14 Size : 17kb User : 许夫子
[source in ebook] sum DL : 0: 给定一个正整数 n，计算有多少个不同的连续自然数段，其和恰为 n。例如，当 n=27 时，有4个不同的连续自然数段的和恰为27：2+3+4+5+6+7；8+9+10；13+14；27。 -Given a positive integer n, calculate the number of consecutive natural number of different paragraph, and its and exactly n. For example, when n = 27 when the four have a different section of consecutive natural numbers and exactly 27:22 B! 3+ 4+ 5+ 6+ 7 8+ 9+ 10 13+ 14 27.
Date : 2025-12-14 Size : 46kb User : chenyi
[source in ebook] c++daxuejiaocheng7-12 DL : 0: c++大学教程配套书原代码第7-12章的-c++ University Guide Book matching the original code section of Chapter 7-12
Date : 2025-12-14 Size : 10.5mb User : akdfja
[source in ebook] clientcallback DL : 0: 实现客户端回调的一段源码，可能对用不到这些得人没有什么用处，但用到了在去找很麻烦的，所以传上来与大家共享了-To achieve the client callback section of source code, may be less than those who were of no use, but used in very troublesome to find, therefore, Chuan-up and share the
Date : 2025-12-14 Size : 1.15mb User : myh0420
[source in ebook] 94-100 DL : 0: C语言精彩百例第93－100例第四篇综合应用篇实例94 用C语言实现遗传算法实例95 人工神经网络的C语言实现实例96 K_均值算法实例97 ISODATA算法实例98 快速傅立叶变换实例99 求解野人与传教士问题实例100 简单专家系统 -C language section 93-100 100 cases of patients with excellent fourth example of the comprehensive application of articles 94 with C language example of genetic algorithm to achieve 95 artificial neural networks to achieve the C-means algorithm 96 K_ examples examples examples 97 ISODATA algorithm Fast Fourier Transform 98 99 examples of problem solving examples of missionaries Savage 100 with a simple expert system
Date : 2025-12-14 Size : 128kb User : 杨志亮
[source in ebook] MS_files DL : 0: C++ primer中每个章节后的作业答案源码-C++ Primer in each section after the operation the answer source
Date : 2025-12-14 Size : 330kb User :
[source in ebook] ch3.16 DL : 0: Ch03 Ex16 [Ch03 Ex16] 假设如题3.1所述火车调度站的入口处有n节硬席或软席车厢（分别以H和S表示）等待调度，试编写算法，输出对这n节车厢进行调度的操作（即入栈或出栈操作）序列，以使用所有的软席车厢都被调整到硬席车厢之前。串。 -Ch03 Ex16 [Ch03 Ex16] assumptions, such as described in 3.1 title at the entrance to the train station scheduling has n hard seat section or Green compartment (H and S, respectively, to express) to wait for scheduling, preparation of test algorithm, the output of these n cars for scheduling operation (that is, a stack operation or
Date : 2025-12-14 Size : 1kb User : Sean
[source in ebook] xiti DL : 0: 在这部分中提供了由谭浩强编著的《C++程序设计》(清华大学出版社出版)一书中各章的全部习题的参考解答。为了帮助读者更好地理解程序，我们在有的程序中加了必要的注释。对有的题目，我们提供了几种不同的解法和程序，供读者比较分析。 -In this section provided by the authoring Hao Qiang
Date : 2025-12-14 Size : 85kb User : 风过柳影
[source in ebook] memory DL : 0: c++模板源码中的第一章节memory，方便你学习时参考，应该会对你有所帮助-c++ template source in the first section of memory, easy reference when you learn, it should be will help you
Date : 2025-12-14 Size : 2kb User : 西戈塔

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