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Search - INT 1 - List
[
assembly language
]
DirectInsertSort
DL : 0
实现直接插入排序 要求:封装成一个函数,形式如下: void DirectInsertSort(bool bOrder, bool bPrintEveryStep, int * array) 其中,参数bOrder是布尔类型变量,true表示升序,false表示降序 bPrintEveryStep表示是否把每一步的排序结果打印出来,true表示打印,false表示不打印 array是待排序的数组 -direct insertion sorting requirements : Packaging, as a function, the form is as follows : void DirectInsertSort (bool bOrder. bool bPrintEveryStep, int * array) which, bOrder parameter is a Boolean variable types, true ascending said. false descending bPrintEveryStep said whether they regard each step of the sort Print out the results, said Print true, not false print array is to sort the array
Date
: 2008-10-13
Size
: 898byte
User
:
失业
[
assembly language
]
int
DL : 0
编写函数int index返回字符t在字条串s中出现的最左边的位置,如果在s中没有与t匹配的子串,不返回-1-function int index prepared to return to the characters not string's note appeared in the leftmost position, If s and t is not matched substring, not to return -1
Date
: 2008-10-13
Size
: 7.59kb
User
:
luyou
[
assembly language
]
1-1
DL : 0
c++二、通过将其元素插入到双向链表中的方法对数组A进行排序。算法对链表的当前操作位置进行维护,当需要插入表项时,若新元素比当前位置值要大,则往前移动;若小则往后移动。编写函数DoubleSort实现上述排序算法。 template <class T> void DoubliSort( T a[], int n)
Date
: 2008-10-13
Size
: 943byte
User
:
zzlbly
[
assembly language
]
1-2
DL : 0
二、通过将其元素插入到双向链表中的方法对数组A进行排序。算法对链表的当前操作位置进行维护,当需要插入表项时,若新元素比当前位置值要大,则往前移动;若小则往后移动。编写函数DoubleSort实现上述排序算法。 template <class T> void DoubliSort( T a[], int n)
Date
: 2008-10-13
Size
: 6.54kb
User
:
zzlbly
[
assembly language
]
6-INT10
DL : 0
利用dos功能调用,显示字符和色彩图案-use function calls, showing character and color logo
Date
: 2026-01-07
Size
: 1kb
User
:
戚文明
[
assembly language
]
INT
DL : 0
控制中断的汇编代码-control interrupted code compilation
Date
: 2026-01-07
Size
: 2kb
User
:
潘仁海
[
assembly language
]
mcd
DL : 0
只要你想听CD,它在任何时候(DOS下,游戏下都可以)用鼠标激活,鼠标控制,为你播放.并提供了选曲和暂停功能,这为光驱上无直接播放建的朋友提供了莫大的方便.该程序思路巧妙,利用INT 33H的现有鼠标功能,巧妙扩展,达到任何条件下激活的能力!-CD if you want to hear it at any time (DOS, the next game can be) activated with the mouse, mouse control, for your players. And the selections and suspension of functions, for which there is no direct drive players construction of the great friends of convenience. The ingenious idea procedures, the use of INT 33H of the existing mouse functions, cleverly extended under any conditions to achieve the ability to activate!
Date
: 2026-01-07
Size
: 3kb
User
:
左文礼
[
assembly language
]
int1ctsr
DL : 0
汇编语言中断TSR时间程序(int 1ch)-assembly language TSR interruption time (int 1ch)
Date
: 2026-01-07
Size
: 1kb
User
:
王丹
[
assembly language
]
shizh
DL : 0
这个时钟程序是我在1993年编的一个小程序,现在贴出来给大家做参考,它执行后驻留内存,到整点时会报时,你可以用 Ctrl-Alt-U 把它从内存中下掉,可以用 Ctrl-Alt-C 变换颜色,用 Ctrl-Alt-O 把报时声音关掉(如果感到讨厌的话),在驻留内存时,用了直接改内存控制块的方法,所以用 MEM 或 MI 无法在内存中看到它,键盘控制用了直接截取 INT 9 的方法。 这个程序虽然很小,编译后才1K多一点点字节,但是麻雀虽小,五脏俱全,在这个程序中,你可以参考到以下编程方法:如何驻留内存;如何截取中断向量;如何在硬件层次上应答键盘;如何截取组合键。 要编译、连接成*.com文件-this my clock procedures in 1993 a series of small programs, is now posted out to you for reference. following the implementation of its presence memory, the whole point of the talks will be, you can use Ctrl-Alt-U from its memory under the swap. can use Ctrl-Alt-C transform color, using Ctrl-Alt-O put timekeeping voice switch off (if the annoyance), in the presence of memory, using a direct change memory control block in the way that they use MEM or MI in the memory not see it, keyboard control using a direct interception of the INT 9. This procedure Despite its small size, after compiling a little more than 1K byte, but Sparrow small, perfectly formed, in the process, you can refer to the following program : how the presence of memory; how interception interrupt vector; in response le
Date
: 2026-01-07
Size
: 3kb
User
:
黄文欢
[
assembly language
]
FONTNEW
DL : 0
dos下显示汉字,利用int 15 的87 号功能将字库装载到1m以上内存。-dos shown in Chinese characters, use int 15 87 functions will be loaded into character 1m more memory.
Date
: 2026-01-07
Size
: 1kb
User
:
ronson
[
assembly language
]
int
DL : 1
编写函数int index返回字符t在字条串s中出现的最左边的位置,如果在s中没有与t匹配的子串,不返回-1-function int index prepared to return to the characters not string's note appeared in the leftmost position, If s and t is not matched substring, not to return-1
Date
: 2026-01-07
Size
: 7kb
User
:
luyou
[
assembly language
]
1-2
DL : 0
二、通过将其元素插入到双向链表中的方法对数组A进行排序。算法对链表的当前操作位置进行维护,当需要插入表项时,若新元素比当前位置值要大,则往前移动;若小则往后移动。编写函数DoubleSort实现上述排序算法。 template <class T> void DoubliSort( T a[], int n) -Second, through its elements inserted into the two-way linked list of methods to sort array A. Algorithm to list the current operating position for maintenance, when the need to insert a table entry, if the new element to the location than the current value to big, then move forward if small is the next move. Prepared to achieve the above function DoubleSort sorting algorithm. template
Date
: 2026-01-07
Size
: 831kb
User
:
zzlbly
[
assembly language
]
C8051_int_asm
DL : 0
C8051 int 的汇编驱动程序,如果能看懂会给你带来很大的好处,学习的好资料.-The driver of C8051 int, it will bring you very big benfit if you will read it, it is very nice.
Date
: 2026-01-07
Size
: 2kb
User
:
华伟大
[
assembly language
]
1
DL : 0
编写一个程序,输出基本数据类型char, short, int, long, float, double和指针类型void *, char *, short *, int *, long *, float *, double *的数据类型的长度。-The preparation of a program, the output of basic data types char, short, int, long, float, double and pointer type void*, char*, short*, int*, long*, float*, double* length of data types.
Date
: 2026-01-07
Size
: 870kb
User
:
bettwe
[
assembly language
]
int13h
DL : 0
BIOS int 13h功能描述,DOS下编程很值得收藏。-description of the interrupt 13H.
Date
: 2026-01-07
Size
: 8kb
User
:
彬彬2009
[
assembly language
]
int-10-varios-caracteres-tarea-2
DL : 0
this program displays on screen a string of characters until the enter key is pressed using int 10
Date
: 2026-01-07
Size
: 1kb
User
:
jam89
[
assembly language
]
break-delay-int
DL : 0
中断-delay-int-清屏 等一些汇编中断指令 接口 汇编可用-int 10-21 break
Date
: 2026-01-07
Size
: 2kb
User
:
lee
[
assembly language
]
shiyan2
DL : 1
求一元n次多项式的值 一个n次多项式如: 其中 被称为系数。在本题中使用LinkedList类,其数据记录项Term中包含每一项的系数 及x的幂次。 struct Term { double coeff int power } 在程序中以(系数、幂次)对的序列输入一个多项式。在输入的幂次为0时终止程序,将每对系数/幂次存储到按幂次排序的链表中。 (a)按以下形式输出结果多项式中的每一项 ai*x^i (b)输入x的3个值并调用函数 double poly(LinkedList<Term>&f, double x) 求出多项式的值并输出结果。 -Seeking an n times n times the value of the polynomial polynomial such as: which is called the coefficient. In this problem, use the LinkedList class contains a coefficient and a power of x times in its data entry Term. struct Term {double coeff int power } Enter a polynomial (coefficient, power) sequence in the program. The input power of 0 to terminate the program, each pair of coefficients/power storage to power sorted linked list. (A) the following form output to each one of the polynomial AI* X ^ i (b) the input x 3 value and call the function of double poly (LinkedList <Term> & F, double x) obtained polynomial values and output results.
Date
: 2026-01-07
Size
: 5.08mb
User
:
梁小强
[
assembly language
]
gtest_demo1
DL : 0
程序如下: #include <iostream> //包含头文件iostream using namespace std //使用命名空间std int main( ) { cout<<″This is a C++ program.″ return 0 } 在运行时会在屏幕上输出以下一行信息: This is a C++ program.-At run time on the screen output the following information: This is a c++ progAt run time on the screen output the following information: This is a c++ program.ram.
Date
: 2026-01-07
Size
: 1.56mb
User
:
天空
[
assembly language
]
int
DL : 0
windows int IRQ3中断是使用-windows int IRQ3 interrupt is using
Date
: 2026-01-07
Size
: 1kb
User
:
edward
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