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Search - josephus - List
[
Algorithm
]
Josephus
DL : 0
Josephus 问题描述 数据结构为链表的插入与查询-Josephus Problem Description
Date
: 2026-01-09
Size
: 4kb
User
:
程本飞
[
Algorithm
]
josephus
DL : 0
josephus问题,该问题非常经典,有助于初学者学习-josephus problem, the problem is very classic, will help beginners learn
Date
: 2026-01-09
Size
: 6kb
User
:
田威
[
Algorithm
]
Josephus
DL : 0
Josephus Problem implementation.
Date
: 2026-01-09
Size
: 1kb
User
:
gowdd
[
Algorithm
]
Josephus_problem
DL : 0
自己编写的Josephus问题的求解方法,用C语言采用数组方式实现,个人认为比教科书上提供的方法要精简的多,和大家一起分享-I have written Josephus problem solving method, using C language using an array of ways to achieve, personally think that way than the provision of textbooks to be streamlined and more to share with everyone
Date
: 2026-01-09
Size
: 867kb
User
:
weiw
[
Algorithm
]
Josephus
DL : 0
已知n个人(以编号1,2,3...n分别表示)围坐在一张圆桌周围。从编号为k的人开始报数,数到m的那个人出列;他的下一个人又从1开始报数,数到m的那个人又出列;依此规律重复下去,直到圆桌周围的人全部出列。 -Known n individuals (in numbers 1,2,3 ... n respectively) sitting around a round table around. From the number of people began to report the number of k, the number to the person out of the column m his newspaper the next person and from a starting number, count m, then a man out and so Law be repeated until the round table around were all out of the column.
Date
: 2026-01-09
Size
: 1kb
User
:
liuchenglong
[
Algorithm
]
Josephus
DL : 0
Josephus permutation algorithm
Date
: 2026-01-09
Size
: 709kb
User
:
Sergiu
[
Algorithm
]
sd2
DL : 0
约瑟夫环问题的程序清单-Josephus list of procedures-Josephus problem program list-Josephus list of procedures
Date
: 2026-01-09
Size
: 1kb
User
:
fghfghrtr
[
Algorithm
]
josephus
DL : 0
约瑟夫环问题,还包括很多很多其他的小程序-Josephus also includes a lot of other small programs
Date
: 2026-01-09
Size
: 3.14mb
User
:
陶程序员
[
Algorithm
]
Josephus--Problem
DL : 0
问题描述:n个人围成一个环,从第i个开始,由1到interval不断报数,凡报到interval的出列,直到环空为。出列的人按先后顺序构成一个新的序列。例如,n=8,i=2,interval=3.则输出序列为:4 7 2 6 3 1 5 8-Problem description: n individuals into a ring, from the beginning, I by 1 to interval number off, report any interval matri, till the annulus. Break the ranks of people according to the order in which they constitute a new sequence. For example, n = 8, I = 2, interval = 3. The output sequence is: 4 7 2 6 3 1 5 8
Date
: 2026-01-09
Size
: 17kb
User
:
zhongdecai
[
Algorithm
]
Josephus-(4)
DL : 0
Josephus alghoritm in C -Josephus alghoritm in C
Date
: 2026-01-09
Size
: 151kb
User
:
Barbos
[
Algorithm
]
yuesefuhuan
DL : 0
解决有关约瑟夫环的数学计算问题,约瑟夫环的相关定义可上网查询-solve the problem about Josephus by airthmetic
Date
: 2026-01-09
Size
: 1kb
User
:
fengpan
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