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Search - elliptic curve - List
[
Algorithm
]
ecc
DL : 0
椭圆曲线密码系统教程和相关源代码,是非常难得的学术资料-Elliptic Curve Cryptography Tutorial and related source code, it is very rare academic information
Date
: 2025-12-22
Size
: 514kb
User
:
王袍
[
Algorithm
]
ECDLPsolver
DL : 0
椭圆曲线对数问题解决算法:采用Pohlig-Hellman 算法化简问题-Elliptic curve logarithm problem-solving algorithm: The Pohlig-Hellman algorithm simplification problem
Date
: 2025-12-22
Size
: 3kb
User
:
陈洁
[
Algorithm
]
Ellipticcurvepublickeysystem
DL : 0
计算机安全学中椭圆曲线公钥系统的c源码 输入与输出: 请输入椭圆曲线方程y^2=x^3+cx+d(mod p)中c,d,p的值:8,10,23 椭圆曲线方程为y^2=x^3+8x+10(mod23) 请输入所取明文x的x1,x2:19,13 请输入选择的椭圆曲线上的点a0的x,y:7,8 请输入私钥a=17 选取t=3 加密的结果是(y0,y1,y2) = ((22,22),20,18) 实施解密: (c1,c2)=(18,12) x1=19 x2=13 -Computer Security Studies in the elliptic curve public key system, c-source input and output: Please enter the elliptic curve equation y ^ 2 = x ^ 3+ cx+ d (mod p) in the c, d, p values: 8,10,23 elliptic curve equation y ^ 2 = x ^ 3+8 x+10 (mod23) Please enter the plaintext x by taking the x1, x2: 19,13 Please enter a choice of elliptic curve point a0 of the x, y: 7,8 Please enter a private key a = 17 select t = 3 encrypted result is (y0, y1, y2) = ((22,22), 20,18) implementation of the decryption: (c1, c2) = (18,12) x1 = 19 x2 = 13
Date
: 2025-12-22
Size
: 12kb
User
:
ttt
[
Algorithm
]
ecc
DL : 0
椭圆曲线加密系统的介绍,以及各种加密算法的实现。-Introduction to elliptic curve encryption system, and various encryption algorithm.
Date
: 2025-12-22
Size
: 2.38mb
User
:
周发旺
[
Algorithm
]
EECCl
DL : 0
椭圆曲线密码体制中的ECC校验验算法分析和程序实现可直接使用。 -The inspection algorithm analysis and procedures of the elliptic curve cryptosystem ECC can be used directly.
Date
: 2025-12-22
Size
: 255kb
User
:
面积
[
Algorithm
]
EECCCsourceccl
DL : 0
椭圆曲线加密算法源代码,用Vissual C++开发,非常好的东西 -Elliptic curve encryption algorithm source code, of use Vissual C++ development, a very good thing
Date
: 2025-12-22
Size
: 100kb
User
:
[
Algorithm
]
ecc
DL : 0
椭圆曲线加密算法,参数内置,需要手动修改。-Elliptic curve encryption algorithm
Date
: 2025-12-22
Size
: 533kb
User
:
慕骋
[
Algorithm
]
project1
DL : 0
使用多个akka actor分布式计算完美平方数-An interesting problem in arithmetic with deep implications to elliptic curve theory is the problem of nding perfect squares that are sums of consecutive squares. use Scala and the actor model to build a good solution to this problem that runs well on multi-core machine
Date
: 2025-12-22
Size
: 1kb
User
:
应平
[
Algorithm
]
cut-cell-area-1
DL : 0
椭圆曲线与矩形网格相交围城的且个网格的各部分面积的程序-The area of elliptic curve and the cell.
Date
: 2025-12-22
Size
: 21kb
User
:
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