Search - Radius point

Search - Radius point - List

[Algorithm] ahpzaizhengdixitong DL : 0: 对于阵地的生存概率计算, 可以使用文献1 中的解析公式作粗略估算, 具体方法为, 把整个阵地看作一个点目标, 即以阵地的中心作为攻击点。求解出某型弹对阵地的破坏半径, 代入解析式即可。但在实际情况下, 相对于来袭武器的破坏半径, 把阵地看作点目标必然引起很大的误差。所以, 本文拟用层次分析法对阵地这个系统进行可能受到攻击的目标分类, 按各分项指标的重要性得出系统的生存概率-Probability of survival for the position calculation, you can use the literature in a rough estimate for analytical formula, the specific method, the whole position as a point target, that is, to position the center point of the attack. Solving for the position of a certain type of bomb damage radius, can be incorporated into the analytical. However, in practice, as opposed to the destruction of the radius of incoming weapons, and position as a point target is bound to lead to significant error. Therefore, this article intended to be position-level analysis of this system may be targeted by the classification of the sub-indicators in accordance with the importance of the survival probability derived system
Date : 2025-12-31 Size : 291kb User : jingyuhai
[Algorithm] BallFit DL : 0: 用有限的数据点采用最小二乘的方法拟合一个球，算出了球心坐标和半径。数据点来源与Solidworks软件中绘制的一个球上的点集-With limited data points using least squares method of fitting a ball, calculate the coordinates and radius of the core. Solidworks data sources and mapping software on a ball point set
Date : 2025-12-31 Size : 2.7mb User : GongChun
[Algorithm] ExpandingRods DL : 0: 题意:已知一个圆的弦长l0及这条弦所在的弧长l1,求弦的中心点到弧的中心点的距离思想:这是一个列方程然后利用二分法解方程的题目,令该疑弧所对的圆心角为anlg, 半径为r,根据题意有两个方程:l1=anlg*r l0=2*r*sin(anlg/2) 两个方程两个未知数, 通过化简有:2*l1*sin(anlg/2)-anlg*l0=0 因为角度的值是从0到2*pi,题目中讲到过弧的长度不可能大于弦的两倍,所以角度不可能取到2*pi,但是有可能为0,把零特殊考虑, 再从0到2*pi间二分找解就不会出错了!但是要注意精度问题,取七位小数才能得出正确解.-Italian title: Known l0 chord of a circle and arc length of this string where l1, seeking the center of the arc chord distance of the center of thought: This is a solution out equations and then use the dichotomy of the title equation, so that The arc of the doubt on the central angle for the anlg, radius r, according to the meaning of problems with two equations: l1 = anlg* r l0 = 2* r* sin (anlg/2) two equations two unknowns, by simplification are: 2* l1* sin (anlg/2)-anlg* l0 = 0 because the value of the angle is from 0 to 2* pi, the title referred to had not greater than the arc length of the string twice, So can not get to the point of 2* pi, but there may be 0, to zero special consideration, and then from 0 to 2* pi to find solution between the two points will not be wrong! but to pay attention to accuracy problems, were taken to seven decimal the correct solution.
Date : 2025-12-31 Size : 1kb User : yangxiuyi
[Algorithm] sphereFit DL : 0: 该程序通过读取的文本中的三维坐标点信息，通过最小二乘和神经网络来进行拟合，得到球的圆心和半径。-The program information through the text to be read in the three-dimensional coordinate point, by the least squares and neural networks to be fitted to obtain the ball center and the radius.
Date : 2025-12-31 Size : 2.41mb User : wangqingfeng