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[Data structs] Untitled1 DL : 0: 【问题描述】设计一个利用哈夫曼算法的编码和译码系统，重复地显示并处理以下项目，直到选择退出为止。【基本要求】 (1)初始化：键盘输入字符集大小n、n个字符和n个权值，建立哈夫曼树； (2)编码：利用建好的哈夫曼树生成哈夫曼编码； (3)输出编码； (4)设字符集及频度如下表：字符：A B C D E F 频度：4 9 23 2 17 15 字符：G H I J K 频度：1 2 3 3 4 -【Description】 design a question of the use of Huffman coding and decoding algorithm system, repeat the show and deal with the following items until the opt-out so far. The basic requirements 【】 (1) Initialization: keyboard input character set size of n, n and n characters of the right value, set up Huffman tree (2) Coding: Using the built Huffman Huffman tree generated coding (3) the output coding (4) based character set and the frequency of the following table: characters: ABCDEF frequency: 492,321,715 characters: GHIJK frequency: 12,334
Date : 2026-01-15 Size : 1kb User : Fiona
[Data structs] Haffmancode DL : 0: 课程设计： 1.求出在一个n×n的棋盘上，放置n个不能互相捕捉的国际象棋“皇后”的所有布局。 2.设计一个利用哈夫曼算法的编码和译码系统，重复地显示并处理以下项目，直到选择退出为止。【基本要求】 1) 将权值数据存放在数据文件(文件名为data.txt，位于执行程序的当前目录中) 2) 分别采用动态和静态存储结构 3) 初始化：键盘输入字符集大小n、n个字符和n个权值，建立哈夫曼树； 4) 编码：利用建好的哈夫曼树生成哈夫曼编码； 5) 输出编码； 6) 设字符集及频度如下表：字符空格 A B C D E F G H I J K L M 频度 186 64 13 22 32 103 21 15 47 57 1 5 32 20 字符 N O P Q R S T U V W X Y Z 频度 57 63 15 1 48 51 80 23 8 18 1 16 1 -Curriculum design: 1. Obtained in an n × n chessboard, the place to catch each other should not n个chess "Queen" of all the layout. 2. The design of a use of Huffman coding and decoding algorithms systems, and deal with duplicate to show the following items until the exit date selection. The basic requirements 【】 1) will be the right value data stored in data files (file named data.txt, located in the implementation of procedures in the current directory) 2), respectively, dynamic and static storage structure 3) Initialization: keyboard input character set size of n, n and n characters of the right value, set up Huffman tree 4) Coding: Using the built Huffman tree generated Huffman coding 5) output coding 6) The character set and the frequency of the following table: Space characters A B C D E F G H I J K L M Frequency of 186 64 13 22 32 103 21 15 47 57 1 5 32 20 Character N O P Q R S T U V W X Y Z Frequency 57 63 15 1 48 51 80 23 8 18 1 16 1
Date : 2026-01-15 Size : 538kb User : 赵刚
[Data structs] grapher DL : 0: 深度优先，广度优先，最短路径，最小生成树的图形演示以及源代码-Depth-first, breadth-first, shortest path, minimum spanning tree, as well as graphical presentation source
Date : 2026-01-15 Size : 83kb User : 沈扬
[Data structs] rootdp DL : 0: 题意：a->b c :攻克b城堡前要先攻克a城堡攻克b城堡将获得c 共有n个城堡（编号为-n）最多攻克m个城堡能获得的最大收益把作为树的根把节点连成一棵树 p[root][i]表示在以root为根的子树中选取i个点能获得的最大收益 p[root][i]=max(p[root][i],p[root][i-j]+p[v[e]][j]) 当root!=0时每棵子树根必选所以p[root][i]=p[root][i-1]+val[root] 结果为p[0][m] -Meaning of the questions: a-> bc: overcome b Castle before the first capture of a castle overcome b Castle will get c The total n Castle (number-n) up to overcome the m castles can get maximum benefit The root of the tree as a node connected into a tree p [root] [i] i points to get selected in the sub-tree root-root maximum benefit p [root] [i] = max (p [root] [i], p [root] [ij]+ p [v [e]] [j]) When the root! = 0 Meike subtree root Required so p [root] [i] = p [root] [i-1]+ val [root] The result is p [0] [m]
Date : 2026-01-15 Size : 4kb User :
[Data structs] hufferman DL : 0: 用下表给出的字符集和频度的实际统计数据建立哈夫曼树，并实现以下报文的编码和译码：“THIS PROGRAM IS MY FAVORITE”字符 A B C D E F G H I J K L M 频度 64 13 22 32 103 21 15 47 57 1 5 32 20 字符 N O P Q R S T U V W X Y Z 频度 57 63 15 1 48 51 80 23 8 18 1 16 1-The actual statistics of the character set and the frequency established by the following table shows the Huffman tree, and to achieve the following message encoding and decoding: " THIS PROGRAM IS MY FAVORITE" character ABCDEFGHIJKLM frequency 641,322,321,032,115 4757153220 characters NOPQRSTUVWXYZ frequency ° 57 ' 6,315,148,518,023,818,116 1
Date : 2026-01-15 Size : 3kb User : 梁耀燊
[Data structs] hdu5102 DL : 0: hdu5102的ac源码。算法：队列、数据结构、图论、模拟。题意：输入一棵树，输出前k小的点对最短距离dis（i，j）的和。-AC source of hdu 5102. Algorithm: queues, data structures, graph theory, simulation. Meaning of the title: Enter a tree, output the sum of the first k smallest shortest distance of dis (i, j).
Date : 2026-01-15 Size : 1kb User : 郑泽彬
[Data structs] BinaryTree DL : 0: 编程实现二叉树的存储结构与基本算法，主要包括以下功能：  创建二叉树B的二叉链二叉树B：A(B(D,E(H(J,K(L,M(,N))))),C(F,G(,I)))  通过对二叉树B的操作，输出二叉树B的广义表（字符串）表达式  通过对二叉树B的操作，输出H结点的左孩子与右孩子  通过对二叉树B的操作，出二叉树B的深度  通过对二叉树B的操作，计算出二叉树B的结点个数  通过对二叉树B的操作，计算出二叉树B的叶子结点个数  通过对二叉树B的操作，输出二叉树B的先序遍历序列  通过对二叉树B的操作，输出二叉树B的中序遍历序列  通过对二叉树B的操作，输出二叉树B的后序遍历序列  释放二叉树B-Programming storage structure and basic algorithms binary tree, including the following features:  create binary chain binary B binary B' s: A (B (D, E (H (J, K (L, M (, N)))) ), C (F, G (, I)))  B through binary operation generalized table output binary tree B (strings) by binary expression  B operation, the output of H nodes left child and right children  B through binary operation, the depth of a binary tree B B  through binary operation to calculate the number of nodes of a binary tree B B  through binary operation to calculate the number of leaf nodes of the binary tree B  by binary tree B operation, first order output binary tree B traversal sequence  through the binary tree B operation, the output of a binary tree B of traversal sequence  through the binary tree B operation, after the sequence output binary tree B traversal sequence  release binary Tree B
Date : 2026-01-15 Size : 57kb User : 郭培鑫