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数 据 结 构 大型 作业3.1输入一个数列L,生成一棵二叉排序树T;3.2对二叉排序树T作中序遍历,输出结果;3.3计算二叉排序树T的平均查找长度, 输出结果;3.4判断二叉排序树T是否为平衡二叉树,输出信息“OK!”/“NO!”;3.5再使用上述数列L,生成平衡的二叉排序树BT,每当插入新元素,发现当前的二叉排序树BT不是平衡的二叉排序树,则立即将它转换成新的平衡的二叉排序树BT;3.6计算平衡的二叉排序树BT的平均查找长度,输出结果。3.6分析对比未平衡化的二叉排序树和平衡的二叉排序树的查找效率(最好、最坏平均比较关键字数)-data structure large operations into a 3.1 L series, generating a binary tree Sort T; 3.2 pair of two fork-tree T for medium preorder, output results; 3.3 Ranking calculation Binary Tree Search T's average length of the output; 3. four judgment ordering two trees T fork whether balanced binary tree, the output message "OK!"/"NO!" ; again using the 3.5 series L, generate balanced binary tree sort BT, whenever insert a new element, found the current binary sort tree is not-BT Value of two binary sort tree, it will be immediately converted into the new balance of the two fork-tree BT; 3.6 Calculation balanced binary tree sort BT search length of the average output results. 3.6 Comparative Analysis of the outstanding balance of two fork-tree and balanced binary tree s
Date : 2026-01-11 Size : 4kb User : 洪玲叶

huffman完整源代码C语言实现,有本人超级详细解释(看不懂你去跳楼吧) 算法设计: 1、对给定的n个权值{W1,W2,W3,...,Wi,...,Wn}构成n棵二叉树的初始集合F={T1,T2,T3,...,Ti,...,Tn},其中每棵二叉树Ti中只有一个权值为Wi的根结点,它的左右子树均为空。(为方便在计算机上实现算法,一般还要求以Ti的权值Wi的升序排列。) 2、在F中选取两棵根结点权值最小的树作为新构造的二叉树的左右子树,新二叉树的根结点的权值为其左右子树的根结点的权值之和。 3、从F中删除这两棵树,并把这棵新的二叉树同样以升序排列加入到集合F中。 4、重复二和三两步,直到集合F中只有一棵二叉树为止。 -Huffman complete C source code language, I have super-detailed explanation (you do not understand it jumped) algorithm design : one, the right to the right values n (W1, W2, W3 ,..., Wi ,..., Wn) n trees constitute the binary tree initial pool F = (T1, T2, T3, ... Ti ,..., Tn), which is indeed a binary tree Ti only a right to the value of Wi Root. it's about subtrees are empty. (For the convenience of the computer algorithm, the general also demanded the right to Ti Wi value of ascending.) 2. in 1984 two F Root weights smallest tree as a new structure of the binary tree around subtrees, new Binary Tree Root in the right value for their son around the tree Root and the right value. 3, F deleted from this two trees, and how the new binary tree in the same ascending into the pool F. 4, re
Date : 2026-01-11 Size : 11kb User : 乐乐

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二叉树的建立与遍历 可实现: (1)树的创建采用先序方式,用特殊符号0表示左、右子树为空 (2)每次输入一个节点的值,可以根据自己的需要设计不同的节点结构 (3)节点的值为非零数 (4)可以()形式输出创建的树 (5)用先序后序和中序遍历树 (6)销毁树 -Establishment and tree traversal can be achieved: (1) tree created using the first order approach, with special symbols 0 express the left and right subtree is empty (2) for each input the value of a node, you can according to their own needs Design of different node structure (3) non-zero value of the node number (4) can () to create the form of the output tree (5) after the first sequence and the sequence of traversal tree (6) the destruction of trees
Date : 2026-01-11 Size : 1kb User : 林渡

(一) 编写一个程序LAGO7-1.CPP,实现二叉树的各种运算,并在此基础上设计一个主程序完成如下功能。 (1) 输出二叉树B; (2) 输出二叉树B的深度; (3) 输出H结点的左、右孩子结点值; (4) 输出二叉树B的宽度; (5) 输出二叉树B的结点个数; 输出二叉树B的叶子结点个数 -(A) to prepare a program LAGO7-1.CPP, to achieve a variety of binary operations, and on this basis, design a main program performs the following functions. (1) output binary tree B (2) The output of a binary tree B of depth (3) The output of H nodes left and right child node value (4) outputs a binary tree B, width (5) output node B, the number of binary trees (6) outputs a binary tree B, the number of leaf nodes
Date : 2026-01-11 Size : 2kb User : xjj

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1.接受原始数据:从终端读入字符集大小n,n个字符和n个权值,建立哈夫曼树。2.编码:利用已建立好的哈夫曼树,对文件中的正文进行编码。3.译码:利用已建立好的哈夫曼树将代码进行译码。4.打印编码规则:即字符与编码的一一对应关系。-1. Accept the raw data: From the terminal reads the character set size n, n characters, and n-weights, the establishment of Huffman trees. 2. Coding: Using the already established a good Huffman tree, the body of the document to be encoded. 3. Decoding: Using the already well-established Huffman tree to decode the code. 4. Print encoding rules: namely, one to one correspondence between characters and encoding.
Date : 2026-01-11 Size : 114kb User : 楚潇

二叉树也是递归定义的,其结点有左右子树之分,逻辑上二叉树有五种基本形态: (1)空二叉树——(a); (2)只有一个根结点的二叉树——(b); (3)右子树为空的二叉树——(c); (4)左子树为空的二叉树——(d); (5)完全二叉树——(e)注意:尽管二叉树与树有许多相似之处,但二叉树不是树的特殊情形。 -Binary tree is recursively defined, and its sub-tree nodes are so divided, there are five basic logical form of binary tree: (1) empty binary tree- (a) (2) there is only one root node Binary Tree- (b) (3) the right subtree of the binary tree is empty- (c) (4) the left subtree of the binary tree is empty- (d) (5) completely Binary Tree- (e) Note: Although the binary tree and the tree has many similarities, but the binary tree is not a special case.
Date : 2026-01-11 Size : 1kb User : zn

哈夫曼树的构造,假设有n个权值,则构造出的哈夫曼树有n个叶子结点。 n个权值分别设为 w1、w2、…、wn,则哈夫曼树的构造规则为:   (1) 将w1、w2、…,wn看成是有n 棵树的森林(每棵树仅有一个结点);   (2) 在森林中选出两个根结点的权值最小的树合并,作为一棵新树的左、右子树,且新树的根结点权值为其左、右子树根结点权值之和;   (3)从森林中删除选取的两棵树,并将新树加入森林;   (4)重复(2)、(3)步,直到森林中只剩一棵树为止,该树即为所求得的哈夫曼树。-Huffman tree construction, assuming there are n weights, Huffman tree is constructed with n leaf nodes. n-weights are set to w1, w2, ..., wn, the Huffman tree construction rules: (1) w1, w2, ..., wn as a forest of n trees (each tree only There is a node) (2) selected in the forest root weights two smallest trees combined, as a new tree to the left and right sub-tree, and the new root of the tree is the left-right and right sub-tree root and the right value (3) selected from the forest to remove two trees, and adding a new tree forest (4) repeat (2), (3) steps, until only the forest a tree until the tree is obtained by the Huffman tree.
Date : 2026-01-11 Size : 127kb User : huang

合肥工业大学数据结构试验五树和森林 包括完整的实验要求、实验预习报告、实验最终报告 实验要求: <1>将一棵树(或森林)转换为二叉树。 <2>求森林的高度。 <3>按层次方式遍历森林。 <4>输出一个森林中每个结点的值及其对应的层次数。 <5>输出一个森林的广义表形式-Hefei University of the data structure test five trees and forests, including the complete experimental requirements prelab report, the experiments final report experimental requirements: < 1> a tree (or forest) is converted to a binary tree. < 2> and forest height. < 3> hierarchical traversal forest. < 4> output value of each node in a forest and its corresponding number of levels. < 5> output generalized list in the form of a forest
Date : 2026-01-11 Size : 590kb User : 石帆

It s required to design an Abstract Data Type (ADT) Java implementation for the Heap Trees data structure that includes the following operations: 1. Constructor and display operations 2. Creating a Heap Tree a given array 3. Adding an element to the Heap Tree 4. Deleting an Element the Heap Tree 5. Sorting the array of elements using the Heap sort algorithm -It s required to design an Abstract Data Type (ADT) Java implementation for the Heap Trees data structure that includes the following operations: 1. Constructor and display operations 2. Creating a Heap Tree a given array 3. Adding an element to the Heap Tree 4. Deleting an Element the Heap Tree 5. Sorting the array of elements using the Heap sort algorithm
Date : 2026-01-11 Size : 8kb User : tamer
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