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[Data structs] BST BBT DL : 0: 数据结构大型作业3.1输入一个数列L，生成一棵二叉排序树T；3.2对二叉排序树T作中序遍历，输出结果；3.3计算二叉排序树T的平均查找长度, 输出结果；3.4判断二叉排序树T是否为平衡二叉树，输出信息“OK！”/“NO！”；3.5再使用上述数列L，生成平衡的二叉排序树BT，每当插入新元素，发现当前的二叉排序树BT不是平衡的二叉排序树，则立即将它转换成新的平衡的二叉排序树BT；3.6计算平衡的二叉排序树BT的平均查找长度，输出结果。3.6分析对比未平衡化的二叉排序树和平衡的二叉排序树的查找效率(最好、最坏平均比较关键字数)-data structure large operations into a 3.1 L series, generating a binary tree Sort T; 3.2 pair of two fork-tree T for medium preorder, output results; 3.3 Ranking calculation Binary Tree Search T's average length of the output; 3. four judgment ordering two trees T fork whether balanced binary tree, the output message "OK!"/"NO!" ; again using the 3.5 series L, generate balanced binary tree sort BT, whenever insert a new element, found the current binary sort tree is not-BT Value of two binary sort tree, it will be immediately converted into the new balance of the two fork-tree BT; 3.6 Calculation balanced binary tree sort BT search length of the average output results. 3.6 Comparative Analysis of the outstanding balance of two fork-tree and balanced binary tree s
Date : 2026-01-03 Size : 4kb User : 洪玲叶
[Data structs] 树的问题（生成） DL : 0: ADT BinaryTree 的实现及验证程序采用的主要数据结构：二叉树、栈、队算法思想：1、先序建树、输出树、后序遍历用递归方法。性能分析：O( n )2、先序遍历、中序遍历：性能分析：O( n )(1) 若遇到新节点非空则先入栈，然后访问其左子树。(2) 若为空则将栈顶结点出栈，访问其右子树。(3) 循环1、2直到栈为空且无节点可入栈。先序与中序的区别是：先序在入栈时访问节点，中序在出栈时访问节点。3、层遍历：性能分析：O( n )(1) 根节点入队(2) 节点出队并访问(3) 若节点有左孩子，则左孩子入队；有右孩子，则右孩子入队。(4) 重复2、3直到队列为空。4、线索树：算法与先序遍历、中序遍历一样，只是将访问节点的Visit函数改为连接前驱与后继的操作。性能分析：O( -BinaryTree ADT Implementation and certification procedures used in the main data structure : binary tree, stack, algorithms team thinking : a first order contribution, the output tree, after preorder using recursive method. Performance Analysis : O (n) 2, preorder, the preorder : Performance Analysis : O (n) (1) If there is a new non-empty nodes were first pushed and then left to visit their son tree. (2) if the empty Zhanding node will stack up, visit their right subtrees. (3) 1,2 cycle until the stack is empty with no node can be pushed. First sequence with the sequence difference : Push the first sequence to visit nodes, which stack up in order to visit nodes. 3, the layer traverse : Performance Analysis : O (n) (1) nodes into Force (2) nodes and the team's visit (3) if the nodes ar
Date : 2026-01-03 Size : 2kb User : 徐欣
[Data structs] bptree DL : 0: 清华大学数据结构课上实现的B+树，设计一个4阶B+树，包括： (1) 叶子的每个记录应该包括4字节（long）关键码值和60字节的数据字段(存储文件名等，可以自定)，设每个叶子可以存储5条记录，而内部节点应该是关键码值/指针对。此外，每个节点还应该有指向同层下一个节点的指针、本节点存储的关键码数等； (2) 此4阶B+树应该支持插入、删除以及根据给定关键码值进行精确检索与关键码范围检索； (3) 显示（打印）此4阶B+树的生长(含删除节点)过程实例；-Tsinghua University class data structure to achieve the B-tree, the design of a B-tree four bands, including : (a) the leaves of each record should include 4-byte (long) key code value and 60 gigabytes of data fields (document storage, etc., can be set), set up each leaf store five records, and internal nodes is the key code value/means against. In addition, each node should have the same point under a layer of the target node, the node storage key code number; (2) The B-tree four bands should support the insertion, deletion and with the given key code value accurate retrieval and key codes scope retrieval; (3) Display (Print ) This four bands B-tree growth (including the deletion of nodes) process examples;
Date : 2026-01-03 Size : 3kb User : qqiang
[Data structs] 复件轮渡问题 DL : 0: 1．汽车轮渡口，过江渡船每次能载10辆车过江，过江车辆分为客车类和货车类，上渡船有如下规定：同类车先到先上船，客车先于货车上渡船，且每上4辆客车，才允许上一辆货车。若等待客车不足4辆，则从货车代替，若无货车等待允许客车上船。试写一个算法模拟渡口管理。算法设计: 1客车和货车均建立一个链式队列，初始均为空。以后来一辆车不是货车就是客车，因此可以说整个程序的事件驱动event就是这两个,客车表示1，货车表示0. 2轮船还没有到达时客车和货车均按次序排在各自队列中。 3轮船到达时，根据两个队列的情况，分别处理。处理如下： a 客车数不满4辆，则将排在前面的货车上船，但总数不能超过10，若没有货车等待，客车直接上船。 b 客车数满4，但不满8辆，客车先上，排在前面的只有一辆货车可以上船，若没有货车等待则货车不上。 c 客车满8辆但不满10，客车上船，排在前面的货车最多可以上2辆，但总数不能超过10。 d 客车满10，则全上客车,但总数不能超过10。 -1. I car ferry, crossing the river each ferry can carry 10 cars crossing the river, crossing the river into passenger vehicles and goods category, Ferry on the following provisions : first vehicle in a first embarkation, the first passenger ferry in the truck and four on each passenger will be permitted on a lorry. If waiting for the bus less than four, then replace the truck, without waiting for the lorry to allow passenger embarkation. Try to write a simulated crossing management. Algorithm design : a bus and the truck were established a chain cohort, the initial were empty. Later, a car is not a passenger vehicle is, it can be said of the entire process event-driven event is the two, said a passenger, said the lorry 0. Two ships have not yet arrived at the bus and the truck were ranked
Date : 2026-01-03 Size : 2kb User : 西们子
[Data structs] zuixiaoshengchengshu DL : 0: 最小生成树问题若要在n个城市之间建设通信网络，只需要架设n-1条线路即可。如何以最低的经济代价建设这个通信网，是一个网的最小生成树问题。（1）利用克鲁斯卡尔算法求网的最小生成树。（2）实现教科书6.5节中定义的抽象树类型 MFSet。以此表示构造生成树过程中的连通分量。（3）以文本形式输出生成树中各条边以及他们的权值。 -minimum spanning tree problem to the n-city building communications networks needed to put up only n-1 lines can be. How the lowest economic cost of building the communications network, the network is a minimum spanning tree problem. (1) using Kelushikaer network algorithm for the minimum spanning tree. (2) to achieve 6.5 textbook definition of the abstract tree types MFSet. Spanning Tree Construction said this process of connectivity components. (3) the form of text output spanning trees and the edge of their weights.
Date : 2026-01-03 Size : 1kb User : wangjian
[Data structs] sy3 DL : 0: 理解树结构的逻辑特性； 2 熟练掌握二叉树的逻辑结构特性及各种存储方法； 3 熟练掌握二插树的各种基本操作，尤其是三种遍历算法以及线索化算法。 4 进一步了解和掌握类的私有和公有成员函数的定义和使用以及类型的作用域 -Understanding of the logic tree structure characteristics 2 binary tree master logical structure of properties and a variety of storage methods 3 2 interpolation tree master basic operations, especially the three traversal algorithm, as well as clues algorithm. 4 to further understand and grasp the kind of private and public member function definition and use, as well as types of scope
Date : 2026-01-03 Size : 36kb User : vipzp
[Data structs] ha217 DL : 0: 哈夫曼树设计2进制前缀编码的方法如下. (1) 根据给定的n个字符以及相应的权值构造一棵最优二叉树 (2) 二叉树除了根结点以外,所有左边的分支标记 0 ,右边的分支标记为 1 (3) 对于每一种字符所对应的叶子结点找出到根结点的路径,则从根结点到此叶子结点路径上各分支字符组成的二进制数字串即为该字符的二进制前缀编码. -Huffman prefix tree design 2-band coding method is as follows. (1) According to the given n characters and the corresponding optimal weights of a binary tree structure (2) binary tree except root node, all branch of the left marker 0, the right side of the branch marked as 1 (3) for each character corresponding to the leaf node to the root node to find the path from the root node to this leaf node of the branch path characters composed of binary digit string is the character encoding of the binary prefix.
Date : 2026-01-03 Size : 1kb User : 张
[Data structs] binary_tree_levelorder DL : 0: binary_tree_level_order(二叉树层排序): 输入:数组{1,2,3,4,5,6,7,8,9,10},建立二叉树,再进行层排序. 输出:输出排序结果.-binary_tree_level_order (tree layer order): Input: array (1,2,3,4,5,6,7,8,9,10), the establishment of binary tree and then sort layer. Output: Output to sort the results.
Date : 2026-01-03 Size : 1kb User : 陈扬坤
[Data structs] 1 DL : 0: 1. 建立二叉树方法1 2. 建立二叉树方法2" 3. 中序递归遍历二叉树 4. 计算树中结点个数 5. 结束程序运行") -1. The establishment of binary tree method 1 2. The establishment of tree methods 2 3. In order Recursive Binary Tree Traversal 4. Calculated the number of tree nodes 5. The end of run)
Date : 2026-01-03 Size : 1kb User : day
[Data structs] 3 DL : 0: 折半查找，输入单词，建立二叉树，然后据此二叉树查找单词-Half to find, enter the word, the establishment of binary tree, binary tree and then find words which
Date : 2026-01-03 Size : 2kb User : yanzu
[Data structs] 3 DL : 0: 定义一个二叉树的类，并递归与非递归中序遍历二叉树-Define a binary tree class, and recursive and non-recursive traversal of binary tree
Date : 2026-01-03 Size : 2kb User : kiki
[Data structs] Untitled1 DL : 0: 【问题描述】设计一个利用哈夫曼算法的编码和译码系统，重复地显示并处理以下项目，直到选择退出为止。【基本要求】 (1)初始化：键盘输入字符集大小n、n个字符和n个权值，建立哈夫曼树； (2)编码：利用建好的哈夫曼树生成哈夫曼编码； (3)输出编码； (4)设字符集及频度如下表：字符：A B C D E F 频度：4 9 23 2 17 15 字符：G H I J K 频度：1 2 3 3 4 -【Description】 design a question of the use of Huffman coding and decoding algorithm system, repeat the show and deal with the following items until the opt-out so far. The basic requirements 【】 (1) Initialization: keyboard input character set size of n, n and n characters of the right value, set up Huffman tree (2) Coding: Using the built Huffman Huffman tree generated coding (3) the output coding (4) based character set and the frequency of the following table: characters: ABCDEF frequency: 492,321,715 characters: GHIJK frequency: 12,334
Date : 2026-01-03 Size : 1kb User : Fiona
[Data structs] bMinusTree DL : 0: b-树的增加,因为我看到的资料里的最大关键字数目为m-1,我考虑了一下,2-3树的删除会比较麻烦,后来看了下算法导论,别人的数目是2t-1,所以相同情况下是2-3-4树,我考虑按照这个因子再写一个,增加删除部分,有问题可以联系我,联系方式在程序中已注明.-b-tree increases, because the information I have seen in the largest number of keywords for the m-1, I consider a bit ,2-3 tree removal would be more trouble, after reading An Introduction to the next algorithm, the number of people are 2t-1, so the same circumstances are 2-3-4 tree, I consider this factor in accordance with the write one, delete some of the increase, has problem can contact me, Contact us in the proceedings have been marked.
Date : 2026-01-03 Size : 2kb User : 杨毅
[Data structs] jiafen DL : 0: 求一棵加分值最高的二叉树，其中序遍历序列为给出的节点编号顺序，如1，2，3，4，5...n，求出的树加分值最高-The highest score for an increase in the binary tree, which traversal sequence for the given node number sequence, such as 1,2,3,4,5 ... n, obtained the highest score of the tree increases
Date : 2026-01-03 Size : 4kb User : yyx
[Data structs] HuffmanCode DL : 0: 数据结构课程Huffman编码实验课程作业，具有完整控制台界面，实现功能1.由字符串生成huffman码2.打印huffman树3.由huffman码还原为字符串-Data structure course experiment coursework Huffman coding, with a complete control panel interface, the realization of function 1. Huffman code generated by the string 2. Huffman tree print 3. Huffman code to restore from a string
Date : 2026-01-03 Size : 3kb User : che
[Data structs] tree DL : 0: 本程序可以用三种方法建立二叉树，并实现相应功能。1、通过输入树的嵌套括号表示序列建立二叉树；2、根据前序遍历序列和中序遍历序列建立二叉树；3、建立哈夫曼树-This program can use three ways to establish a binary tree, and to achieve that function. 1, by entering the tree to establish a sequence of nested parentheses binary tree 2, according to preorder traversal sequences and the establishment of a binary tree in order traversal sequences 3, the establishment of Huffman tree
Date : 2026-01-03 Size : 55kb User : moon walker
[Data structs] xiansuo DL : 0: 1 理解树结构的逻辑特性； 2 熟练掌握二叉树的逻辑结构特性及各种存储方法； 3 熟练掌握二插树的各种基本操作，尤其是三种遍历算法以及线索化算法。 4 进一步了解和掌握类的私有和公有成员函数的定义和使用以及类型的作用域 -A tree structure to understand the logic of identity two master binary logic of structural characteristics and various storage methods 3 master 2 plug tree of basic operations, in particular, three kinds of traversal algorithms, as well as clues algorithm. 4 to further understand and master classes in private and public member function definition and use of types of scope
Date : 2026-01-03 Size : 7kb User : zhangge
[Data structs] 2 DL : 0: 二叉排序树的创建与使用 (时间限制为：1000毫秒) 描述：二叉排序树的定义是：或者是一棵空树，或者是具有下列性质的二叉树：（1）若它的左子树不空，则左子树上所有的结点值均小于它的根结点的值；（2）若它的右子树不空，则右子树上所有结点的值均大于或等于它的根结点的值；（3）它的左右子树也分别为二叉排序树。现要求根据输入的元素值，构造一棵二叉排序树，并输出其先序遍历、中序遍历和后序遍历结果。输入：输入第一行为测试用例个数n，接下来为n个测试用例，每个测试用例占两行，其中第一行为元素个数m，第二行为m个需要构造成二叉排序树的元素值。输出：每个测试用例用三行输出，其中第一行输出先序遍历结果，第二行输出中序遍历结果，第三行输出后序遍历结果。各元素之间用一个空格隔开。样例输入： 1 5 8 4 2 6 4 样例输出： 8 4 2 6 4 2 4 4 6 8 2 4 6 4 8 -Binary Sort Tree creation and use of (Time limit: 1000 ms) Description: Binary sort tree is defined as: either an empty tree, or the nature of the binary tree with the following: (1) if its left subtree is not empty, then the left sub-tree of all nodes were less than the value of its root node (2) if it s the right subtree is not empty, then the right sub-tree of all nodes are greater than or equal to the value of its root node (3) around its sub- tree were binary sort tree. Are required elements of the input value, a binary sort tree structure, and the output of its first order traversal, inorder traversal and postorder traversal results. Input: Enter the number of the first acts of the test case n, then for the n test cases, accounting for two lines of each test case, where the first acts of the number of elements m, m a need to construct the second act into a binary sort tree of element values . Output: With three lines of output for each test case, wh
Date : 2026-01-03 Size : 1kb User : zhoupenghua
[Data structs] 3 DL : 0: 二叉树的建立、打印、遍历，二叉树的建立、打印、遍历-The establishment of a binary tree, print, traversing, the establishment of a binary tree, print, traverse
Date : 2026-01-03 Size : 1kb User : 杨仕凯
[Data structs] 2-3-tree DL : 0: 2—3树是这样一种树： A．每个非叶子结点都有2个或3个儿子； B．每条众树根到树叶的路径长度相等； C．只有一个根结点的树也是2—3树。本题目要求从键盘输入以整数序列，建立一棵2-3树。所以我的建树构思为以2-3树的插入操作来进行建树。-2-3 tree is such a tree: A. Each non-leaf node has two or three sons B. Each congregation tree roots to leaves is equal to the length of the path C. 2-3 tree is only one root node of the tree. The subject of the request to establish a 2-3 tree from keyboard input to a sequence of integers. So I conceived the achievements of the achievements of 2-3 tree insertion operation.
Date : 2026-01-03 Size : 2kb User : 冯读庆

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