Search - josephus

Search - josephus - List

[Compress-Decompress algrithms] 2 DL : 0: 2．用循环链表解Josephus问题。设有n个人围坐在一个圆桌周围，现从第1个人开始报数，数到第m的人出列，然后从出列的下一个人重新开始报数，数到第m的人又出列，…，如此反复直到所有的人全部出列为止。Josephus问题是：对于任意给定的n和m，求出按出列次序得到的n个人员的序列-2. Josephus solution of the problem with the circulation list. With n individuals sitting around a round table is started by a report from the first number, the number of people out to the first m columns, and then from the next person out of the column began to count off again, several to the first m out of those people who have column, ..., and so forth until all of the columns were all out of date. Josephus The question is: For any given n and m, find out the columns according to the order received sequence of n-persons
Date : 2026-01-09 Size : 1kb User : sprite
[Compress-Decompress algrithms] Huffman DL : 0: 哈夫曼树，用哈夫曼树解决约瑟夫环问题代码具有良好封装性-Huffman tree Huffman tree the Josephus problem code with good package
Date : 2026-01-09 Size : 2kb User : 朱春明
[Compress-Decompress algrithms] Josephus DL : 0: 约瑟夫环单链表的，循环单链表求解约瑟夫环。包含4个程序-Josephus single linked list, circular single list solving Josephus. Program contains four
Date : 2026-01-09 Size : 11kb User : 林琳