Hot Search : Source embeded web remote control p2p game More...
Location : Home Search - c B
Search - c B - List
Đ ị t mẹ chúng mày, diễ n đ àn như cái con cặ c, bắ t bố mày up code đ ể kích hoạ t tài khoả n, chúng mày có biế t đ ọ c tiế ng Việ t khô ng thế , muố n chử i nhau hã y liên hệ qua mail: toingungoc456@rocketmail.com -Đ ị t mẹ chúng mày, diễ n đ àn như cái con cặ c, bắ t bố mày up code đ ể kích hoạ t tài khoả n, chúng mày có biế t đ ọ c tiế ng Việ t khô ng thế , muố n chử i nhau hã y liên hệ qua mail: toingungoc456@rocketmail.com
Date : 2025-12-21 Size : 497kb User : duc

一共4部电话编号为1,2,3,4,电话分别在不同的房间内,3个接线员,编号为A,B,C。A只负责1,2号电话,B负责2,3号电话,C负责3,4号电话。假设单位时间为1,在每一个单位时间内,每个接线员可以回复一个房间内的电话,或者从一个房间走的另一个房间。但是每个房间同一时间只能有一个人。给出时间段x内的所有电话的情况,编程输出最多能答复的电话数。(A,B,C的最初位置可以按情况自己选择)-A total of four phone numbers for the 1,2,3,4, phones in different rooms, three operators, numbered A, B, C. A telephone number is only responsible for 1,2, B 2,3 Tel responsible for, C for 3,4 Tel. Assuming the time is 1, in each unit time, each operator can return the phone within a room, or walking from one room to another room. Each room at the same time, however only one person. X within the given time period the situation of all phone, programming the output up to answer the telephone number. (A, B, C' s initial position can choose the circumstances)
Date : 2025-12-21 Size : 1kb User : Cindy

VC++人物格斗游戏模块代码,编写此功能需要使用以下知识:   1.对象的新属性:生命值、攻击力。   2.对象生命值的显示。   3.打斗时生命值的改变。   4.在场景中添加物品。      游戏测试操作的方法:      A、在场景内点任意点,指挥主角移动。   B、将鼠标移到场景外,可以移动地图。   C、在微缩地图上点一下,可以快速定位。   D、ESC键,退出游戏。      你可以指挥主角去打猎了。 -VC++ fighting game character module code, write this function requires the following knowledge: 1. Object with new properties: the value of life, attack. 2. Objects show the value of life. 3. Fighting when the value of life changes. 4. Add items in the scene. Game test operation method: A, the point at any point in the scene, directing the protagonist moves. B, move your mouse over the scene, but can move the map. C, tap on the map in miniature, you can quickly locate. D, ESC key to exit the game. You can command the protagonist go hunting.
Date : 2025-12-21 Size : 103kb User : 吴晓

猜数字游戏!(C语言程序,包含完整的源代码有详细注释、可执行文件,本人计算机实习期间编写的,) 猜数字游戏:此游戏通常由两个人玩,一方出数字,一方猜。出数字的人要想好一个没有重复数字的4位数,不能让猜的人知道。猜的人就可以开始猜。每猜一个数字,出数者就要根据这个数字给出几A几B,其中A前面的数字表示位置正确的数的个数,而B前的数字表示数字正确而位置不对的数的个数。例如,正确答案为 8234,而猜的人猜 8349,则出数者提示猜数者猜的结果是 1A2B,其中有一个8的位置对了,记为1A,而3和4这两个数字对了,而位置没对,因此记为 2B,合起来就是 1A2B。 接着猜的人再根据出题者的几A几B继续猜,直到猜中(即 4A0B)为止。-Guess Numbers game: the game is usually two personal play, one party out Numbers, one party guess. Out of the digital person to be a no repeat of the 4 digit Numbers, can t let guess people know. Guess who can begin to guess. Each guess A number, the three-dimensional will according to the figures A few A few B, among them in front of A digital said the number of the right position number, and B digital said before digital right and wrong number of the number of position. For example, the right answer for 8234, and guess people guess 8349, then the number of tips guess who tested the result is 1 A2B guess, one of the eight position on the, notes for 1 A, and 3 and 4 of the two Numbers, and position of not, so remember to 2 B, add up to is 1 A2B. Then guess people according to the ChuTiZhe again A few A few B continue to guess, until guess (namely 4 A0B ?
Date : 2025-12-21 Size : 48kb User : 班胜龙

DL : 0
每位新用户须先建立帐号,才可登入游戏。每位新用户初始分配50个金币。用户进入游戏后,可选择界面上出现的A,B,C,D,E五匹马之一,并输入作为赌注的金币数(下注的上限为账户的金币余额)。之后赛马开始,五匹马以不同(随机)的速度跑向终点,若用户选中的马匹取得第一,则用户获得与赌注额相同的金币,否则失去;若用户帐号内金币余额为0,则不能继续游戏。游戏需有存盘功能。 -The design and development of a " racetrack" game. The game is a stand-alone program, to provide users with the functionality of the game of " horse race" . The specific functions of the game is described as follows: for each new user must first create an account in order to log into the game. Each new user the initial allocation of 50 gold coins. The user to enter the game can choose the interface A, B, C, D, E five horses, one and enter the number of coins bet (bet limit for the balance of the account of gold). After horse racing, ran to the end of five horses at different (random) speed, if the user selects the horses made the first, the user access to bet the same amount of gold, or lost if gold balance of the user account. you can not continue the game. The game save function.
Date : 2025-12-21 Size : 3kb User : 林少华

百度编程题 .食物链Description 动物王国中有三类动物A,B,C,这三类动物的食物链构成了有趣的环形。A吃B, B吃C,C吃A。 现有N个动物,以1-N编号。每个动物都是A,B,C中的一种,但是我们并不知道它到底是哪一种。 有人用两种说法对这N个动物所构成的食物链关系进行描述: 第一种说法是"1 X Y",表示X和Y是同类。 第二种说法是"2 X Y",表示X吃Y。 此人对N个动物,用上述两种说法,一句接一句地说出K句话,这K句话有的是真的,有的是假的。当一句话满足下列三条之一时,这句话就是假话,否则就是真话。 1) 当前的话与前面的某些真的话冲突,就是假话; 2) 当前的话中X或Y比N大,就是假话; 3) 当前的话表示X吃X,就是假话。 你的任务是根据给定的N(1 <= N <= 50,000)和K句话(0 <= K <= 100,000),输出假话的总数。 Input 第一行是两个整数N和K,以一个空格分隔。 以下K行每行是三个正整数 D,X,Y,两数之间用一个空格隔开,其中D表示说法的种类。 若D=1,则表示X和Y是同类。 若D=2,则表示X吃Y。 Output 只有一个整数,表示假话的数目。 Sample Input 100 7 1 101 1 2 1 2 2 2 3 2 3 3 1 1 3 2 3 1 1 5 5 Sample Output 3-Baidu programming questions There are three types of animals in the food chain Description Animal Kingdom A, B, C, and three types of animal food chain constitutes an interesting ring. A eat B, B, to eat C, C eat A. The existing N animal, numbered 1-N. Each animal are A, B, C in a, but we do not know exactly what kind. Been used in two different ways to describe these the N animals constitute the food chain relationship: The first argument is the "XY" X and Y are similar. The second argument is that the "2 X Y", X eat Y. N animals, using the above two statements, one pick a say K words, K sentence some true, some false. When the sentence satisfies one of the following three words is a lie, otherwise, it is the truth. 1) words preceding Some true conflict, is lie 2) of the current, then X or Y is larger than N, that is, lies 3) The current then represents X eat X, is lie. Your task is the total number of (1 <= N <= 50,000), and K according to a given N words (0 <= K <= 10
Date : 2025-12-21 Size : 507kb User : tang

一个C语言游戏,俄罗斯方块,比较简单,自己收集的。-Yīgè C yǔyán yóuxì, èluósī fāngkuài, bǐjiào jiǎndān, zìjǐ shōují de.
Date : 2025-12-21 Size : 13kb User : 紫电

map Program which can perform mapping.
Date : 2025-12-21 Size : 1kb User : Deepak
CodeBus is one of the largest source code repositories on the Internet!
Contact us :
1999-2046 CodeBus All Rights Reserved.