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(1)首先调用Chessboard 类型的chessboard 属性中的initBoard()与printBoard()方法去初始 化与打印棋盘。  (2)从控制台获取用户的输入。  (3)再调用本类的isValid()方法去验证玩家输入的合法性,如果输入不合法,返回第2 步继续, 否则到第4 步。  (4)把玩家下的棋子位置赋值为 ● 。  (5)调用isWon( int posX , int posY , String chessman )判断玩家是否赢了。如果玩家赢了, 则调用isReply()方法输出的信息询问玩家是否重新游戏,如果玩家输入y,则返回第1 步重新 开始。  (6)调用computerDo()方法随机生成计算机的x,y 坐标,并把board[x][y] 赋值为 ○ 。如果 计算机赢了,则调用isReply()方法输出的信息询问玩家是否重新游戏,如果玩家输入y,则返 回第1 步重新开始,否则返回第2 步轮到用户输入。-(1) The first call Chessboard type chessboard properties initBoard () and printBoard () method to initialize and print the board.  (2) to obtain user input the console.  (3) and then call this class isValid () method to verify the legitimacy of player input, if the input is not valid, return to step 2 to continue, otherwise to step 4.  (4) under the pawn position players assigned to " ●" .  (5) calls isWon (int posX, int posY, String chessman) to determine whether the player wins. If the player wins, then call isReply () method outputs information to re-ask the players if the game, if a player enter y, then return to step 1 and start again.  (6) calling computerDo () method of a computer generated random x, y coordinates, and the board [x] [y] is assigned " ○" . If the computer wins, then call isReply () method outputs information to re-ask the players if the game, if a player enter y, then return to step 1 to start again, otherw
Date : 2026-01-01 Size : 12kb User : 冰山一角

1.写一个处理字符串的类,包含以下类方法:将字符串里大写字符变小写,小写字符变大写;在字符串中寻找子串的个数和分别出现的位置;将字符串转化为数字,并自动忽略非数字字符;找出两个字符串中相同字符的个数.-1. Write a string handling class that contains the following class method: a string in uppercase characters to lowercase, uppercase becomes lowercase characters to find the number and position of the substring, respectively, appear in the string convert a string digital and automatically ignore non-numeric characters to find the same number of characters in the two strings.
Date : 2026-01-01 Size : 1kb User : YWW
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