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[Crack Hack] vnx4 DL : 0: vnc本地口令破解C源代码默认情况下VNC服务端的密码是放在注册表中的，本工具只针对这种情况。首先用ASP读出注册表中的加密密码，然后用破解工具破解。我给出大家一个读取VNC密码的ASP脚本，默认情况下VNC密码存放在HKCU\Software\ORL\WinVNC3\Password Set WshShell = server.CreateObject("WScript.Shell") bkey=WSHShell.RegRead("HKCU\Software\ORL\WinVNC3\Password") for each str in bkey response.write hex(str) next 读取出来后结果类似 49 40 15 F9 A3 5E 8B 22这种十六进制，这是VNC加密的密码。我们可以用vncx4 破解它，vncx4使用很简单，只要在命令行下输入 c:\>vncx4 -W 然后顺序输入上面的每一个十六进制数据，每输完一个回车一次就行了。-vnc local crack password C source code default under VNC server password is placed on the registry. The tools only address this situation. First ASP registry read out the encryption password, and then use the tool to break the resolve. I have given you a password to read VNC ASP script, By default under the VNC password stored in HKCU \ Software \ ORL \ WinVNC3 \ P assword Set WshShell = server.CreateObject ( " WScript.Shell ") bkey = WSHShell.RegRead (" HK CU \ Software \ ORL \ WinVNC3 \ Password ") for eac h str in bkey response.write hex (str) next read out After similar results F9 49 40 15 22 A3 5E 8B this hexadecimal, it is encrypted VNC password. Vncx4 we can resolve it, vncx4 simple to use, as long as the command line input c : \
Date : 2025-12-29 Size : 4kb User : 小李
[Crack Hack] PGP800-S-W-Inner DL : 1: 可以实现对邮件的加密解密以及签名，采用多种加密算法，包括对称加密算法和公钥算法等-Can realize the encryption and decryption of messages and signatures, using a variety of encryption algorithms, including symmetric encryption algorithm and public key algorithm
Date : 2025-12-29 Size : 2.54mb User :
[Crack Hack] Citadel16FullSources DL : 0: Citadel v.1.6 Full Sources-Citadel s design-time Wizard in action In Delphi the forms visual designs are encoded as dfm files and directly included into the executables as resources. This implementation has two disadvantages: 1. They are fully exposed to the public. 2. The format is very suitable at design-time, but too bloated at runtime. We have designed a tool that fixes both problems and it will only take you 1 minute to implement. All you have to do is: • add one component • add one line of code to your project • launch the Citadel Wizard Compression: The benefits from getting a smaller executable are obvious. There are some products that compress executables. They get a very good compression ratio but need more memory to work, as the full executable must be loaded at startup and code memory is not shared between instances. Citadel just compresses the dfm resources and they are loaded on demand as usual, so it doesn t suffer these problems. Encryption: Why would you w
Date : 2025-12-29 Size : 1.38mb User : 瘦马
[Crack Hack] NetBoxDex DL : 0: NetBoxDex v0.1 (NetBox 解包工具源码) NetBox 是一个全新概念的开发平台，它提供了业界最快速的用于开发 Internet 商业应用的开发和编译工具。NetBox 支持包括 JavaScript、VBScript、Perl 等目前应用最为广泛的脚本语言来构建功能强大和性能稳定的应用服务器、网络服务器以及 HTML-Based 网络多媒体桌面应用。NetBox 支持目前最为流行的 XML 和 Web Service 工业标准和 ASP、COM、.NET 等流行标准，NetBox 对第三方数据库的完美支持使您新构建的商务应用可以容易的将已有的应用系统整合进来，从而充分利用现有的 IT 资源，大大的节约投资。NetBox 提供的 SSL、TLS 安全协议、RSA、DES 等加密算法和独立于应用程序的虚拟机技术使您的数据得到最大限度的保护。NetBox 提供将应用部署到无线设备的能力。NetBox 提供将您的应用编译成独立可执行文件的能力，极大的加快运行速度和代码安全性。使用 NetBox 开发，大大提高了应用系统的可扩展性、稳定性和安全性。NetBox 的出现也首次让应用软件开发商能够如此快速和容易的构建完整的基于 Internet 强大应用。-NetBoxDex v0.1 (NetBox unpack tool source) NetBox is a new concept of development platform, which provides the industry s most rapid development of Internet business applications for the development and build tools. NetBox support including JavaScript, VBScript, Perl, etc. Currently the most widely used scripting language to build powerful and stable performance of application servers, Web servers and HTML-Based Network Multimedia desktop application. NetBox support the current most popular industry-standard XML and Web Service and ASP, COM,. NET and other popular standards, NetBox the perfect support for third-party database to build your new business applications can easily integrate to existing applications in, to make full use of existing IT resources, dramatically reduce investment. NetBox provided by SSL, TLS security protocols, RSA, DES and other encryption algorithms and application-independent virtual machine technology enables you to get maximum protection of data. NetBox w
Date : 2025-12-29 Size : 301kb User : 程光
[Crack Hack] 1008 DL : 0: Julius Caesar曾经使用过一种很简单的密码。对于明文中的每个字符，将它用它字母表中后5位对应的字符来代替，这样就得到了密文。比如字符A用F来代替。如下是密文和明文中字符的对应关系。密文 A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 明文 V W X Y Z A B C D E F G H I J K L M N O P Q R S T U 你的任务是对给定的密文进行解密得到明文。你需要注意的是，密文中出现的字母都是大写字母。密文中也包括非字母的字符，对这些字符不用进行解码。 -Julius Caesar had used a very simple passwords. To express each of the characters in its alphabet with its corresponding character after the 5 to replace, so get the ciphertext. A character such as using F instead. Here are the characters in the ciphertext and plaintext correspondence. Ciphertext ABCDEFGHIJKLMNOPQRSTU VWXYZ expressly VWXYZABCDEFGHIJKLMNOP QRSTU Your task is given to decrypt the ciphertext be clear. You need to note that the ciphertext letter appears in all capital letters. Ciphertext also includes non-alphabetic characters, these characters without decoding.
Date : 2025-12-29 Size : 1kb User : dvd
[Crack Hack] aes DL : 0: AES算法，实现对文件加密。包含密码学课程报告 class CRijndael { private: int Nk,Nr,round long Total_Round,Cur_Round char *SourceFileName,*TargetFileName CString source,*target,save CFile Source,Target byte (* State)[4],*w[4],*key[4] public: CString ErrorMessage CRijndael() virtual ~CRijndael() bool EncrypFile() bool DecrypFile() CString DecrypStr() CString EncrypStr() bool SetFileName(CString SFileName,CString TFileName) bool SetString(CString sour,CString &targ) bool SetVariable(int k,int r,CString skey) int GetCurPos() private: void SubBytes() void ShiftRows() void MixColumns() byte Multi(byte a,byte b) void AddRoundKey() void KeyExpansion() void InvShiftRows() void InvSubBytes() void InvMixColumns() void Encryption() void Decryption() } -AES algorithm to realize the files are encrypted. Course report contains the password 。 class CRijndael {private: int Nk, Nr, round long Total_Round, Cur_Round char* SourceFileName,* TargetFileName CString source,* target, save CFile Source, Target byte (* State) [4] ,* w [4],* key [4] public: CString ErrorMessage CRijndael () virtual ~ CRijndael () bool EncrypFile () bool DecrypFile () CString DecrypStr () CString EncrypStr () bool SetFileName (CString SFileName, CString TFileName) bool SetString (CString sour, CString & targ) bool SetVariable (int k, int r, CString skey) int GetCurPos () private: void SubBytes () void ShiftRows () void MixColumns () byte Multi (byte a, byte b) void AddRoundKey () void KeyExpansion () void InvShiftRows () void InvSubBytes () void InvMixColumns () void Encryption () void Decryption () }
Date : 2025-12-29 Size : 280kb User : fff
[Crack Hack] aes_key_expand_128 DL : 0: The key expansion function takes the user supplied 16 bytes long key and utilizes the previously created round constant matrix rcon and the substitution table s_box to generate a 176 byte long key schedule w, which will be used during the en- and decryption processes. The blue arrowed closed loop indicates that the functions rot_word and sub_bytes are called iteratively by the key expansion function.-The key expansion function takes the user supplied 16 bytes long key and utilizes the previously created round constant matrix rcon and the substitution table s_box to generate a 176 byte long key schedule w, which will be used during the en- and decryption processes. The blue arrowed closed loop indicates that the functions rot_word and sub_bytes are called iteratively by the key expansion function.
Date : 2025-12-29 Size : 1kb User : darshan
[Crack Hack] aes_cipher_top DL : 0: the first task of the ”main” program aes_demo is a call to aes_init in Line 1. This initialization routine supplies 1 the actual en- and decryption functions (cipher and inv_cipher) with the expanded key schedule w, the substitution tables s_box and inv_s_box, and the polynomial matrices poly_mat and inv_poly_mat. These quantities have to be generated only once and can be used by any subsequent en- or decipher call.
Date : 2025-12-29 Size : 2kb User : darshan
[Crack Hack] RSA DL : 0: 利用C\C++实现RSA算法的加、解密运算。具体包括： 1）利用扩展的Euclid计算 a mod n 的乘法逆元； 2）Miller-Rabin素性测试算法对一个给定的大数进行测试； 3）实现的运算，并计算； 4）利用Euler定理手工计算，并与3）计算的结果对比； 5）实现RSA算法。并对 I LOVE NANJING UNIVERSITY OF AERONAUTICS AND ASTRONAUTICS 加解密。说明：为了方便实现，分组可以小一点，比如两个字母一组。字母及其数字编码字母及其数字编码空格 00 N 14 A 01 O 15 B 02 P 16 C 03 Q 17 D 04 R 18 E 05 S 19 F 06 T 20 G 07 U 21 H 08 V 22 I 09 W 23 J 10 X 24 K 11 Y 25 L 12 Z 26 M 13 -Use of C \ C++ implements the RSA algorithm encryption and decryption operations. These include: 1) using the extended Euclid calculate a mod n multiplicative inverse 2) Miller-Rabin primality testing algorithm for a given test large numbers 3) to achieve the operation, and the calculation 4) the use of Euler Theorem manual calculation, and compared with the results of the calculation 3) 5) implement the RSA algorithm. And I LOVE NANJING UNIVERSITY OF AERONAUTICS AND ASTRONAUTICS encryption and decryption. Description: In order to facilitate the achievement of the packet may be smaller, for example, a group of two letters. Alphabet letters and their digital encoding and digital encoding Spaces 00 N 14 A 01 O 15 B 02 P 16 C 03 Q 17 D 04 R 18 E 05 S 19 F 06 T 20 G 07 U 21 H 08 V 22 I 09 W 23 J 10 X 24 K 11 Y 25
Date : 2025-12-29 Size : 1kb User : 刘洋