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private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
Date : 2008-10-13 Size : 399.57kb User : 欣欣

DL : 0
private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
Date : 2008-10-13 Size : 245.23kb User : 欣欣

DL : 0
private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {-private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI* 0.5f else return Math.PI* 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
Date : 2026-01-01 Size : 399kb User : 欣欣

DL : 0
private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {-private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI* 0.5f else return Math.PI* 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
Date : 2026-01-01 Size : 245kb User : 欣欣

Vigenere密码单表代换加密如明文为:wearediscoveredsaveyourself 密钥流为:ddeferfrfdwfefeggasdwfeffrg 密文流为:asfhjkhfkjerhfkjbjkfbdjkfgjk 即Ci=(Ki+Pi) 26 pi=(Ci-Ki) 26 要求实现加密和解密,C或C++描述源程序。 -Vigenere encrypted password alone, such as clear as the table Substitution: wearediscoveredsaveyourself key stream is: ddeferfrfdwfefeggasdwfeffrg ciphertext flow: asfhjkhfkjerhfkjbjkfbdjkfgjk that Ci = (Ki+ Pi) 26 pi = (Ci-Ki) 26 required to achieve encryption and decryption , C or C++ descriptions source.
Date : 2026-01-01 Size : 1kb User : 小杨

一个破解无线路由密码的工具pin码穷举,破解带wps无线路由-Brute-force tools to crack a wireless router password pin code, crack wireless router with wps
Date : 2026-01-01 Size : 644kb User :
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