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This programme is to show the words like a air balloon around the control button.It ia about interface programme.-This program is to show the words like a ai r balloon around the control ia about button.It interface program.
Date : 2008-10-13 Size : 48.16kb User : linrui

DL : 0
用AI方式实现10-20以内两个数的相加减,
Date : 2008-10-13 Size : 20.18kb User : cll

This programme is to show the words like a air balloon around the control button.It ia about interface programme.-This program is to show the words like a ai r balloon around the control ia about button.It interface program.
Date : 2026-01-10 Size : 2.75mb User :

DL : 0
用AI方式实现10-20以内两个数的相加减,-AI means 10-20 with less than two the number of addition and subtraction,
Date : 2026-01-10 Size : 20kb User : cll

chat nhieu nick, dung de chat trong yahoo, ai can lien he nick ya hoo thaiduongtrieuvu se gui cho, cai trang chet tiet nay rac roi qua
Date : 2026-01-10 Size : 4.55mb User : tdtv

坦克大战,样例,3个文件,main thank myAi,是AI入门-Battle City, sample, 3 files, main thank myAi, is AI Getting Started
Date : 2026-01-10 Size : 41kb User : mangoyoung

DL : 0
例:用筛选法求2~100之间的所有素数。 解:我们用下面的方法来解这题:先建立一个含有2~100之间所有自然数的数表,在数表中删去2的倍数(不包括2);然后找2后面第一个被保留的数p(是3),再删除p的倍数(不包括p);然后再找下一个被保留的数(是5),继续上述步骤:这样继续下去,直至P大于100为止。这样数表中剩下的数就是所要求的所有素数。这个求素数的方法称为爱拉托散(Eratosthenes)法。 -Example: Method 2 with the screening of all prime numbers between 100. Solution: We use the following method to solve this problem: first the establishment of a containing between 2 to 100 the number of all natural numbers table, delete table 2 in the number of multiples (not including 2) and then find the back of the first to be reserved 2 number p (a 3), then delete multiple of p (excluding p) and then find the next number to be reserved (was 5), continue the steps: continue to do so until the P is greater than 100 so far. So that the remaining number of tables is required for all prime numbers. This request is called Ai Latuo prime numbers scattered (Eratosthenes) method.
Date : 2026-01-10 Size : 1kb User : 00

五子棋Ai 用的是较为简单的方法,希望对大家有用-Backgammon Ai is a relatively simple approach, and hope to be useful
Date : 2026-01-10 Size : 61kb User : as

八皇后问题求解!用OPEN表和CLOSED表实现!人工智能实验!-Eight queens problem solving! OPEN and CLOSED table with table to achieve! AI experiment!
Date : 2026-01-10 Size : 479kb User : 张三

DL : 0
给定n个矩阵构成的一个链<A1,A2,...,An>,矩阵Ai的维数为pi-1 x pi,其中i=1,2,...,n 。 { 3x5,5x2,2x7,7x4,4x8 } 该矩阵链的乘积为: A1A2...An。 通过在乘积A1A2...An的不同位置加上括弧,以先计算其中几个的乘积,再合并计算,以减少总共的计算代价。 -Given n matrix consisting of a chain < A1, A2,..., An >, the dimensions of the matrix Ai for PI- 1 x PI, I = 1, 2,..., n. {3 x 5, 5 x2, 2 x7, 7 x4, 4 by 8} The product of matrix chain for: A1A2...The An. Through the product A1A2...An the different position of the bracket, by calculating the product of several of them first, then merge computation, in order to reduce the calculation of total price.
Date : 2026-01-10 Size : 819kb User : 李阳

人工智能的启发式查找八数码的解决问题,利用opne,close表去实现功能,最后输出最好路径-AI heuristics to find eight digital problem solving, use opne, close table to realize the function, the final output of the best path
Date : 2026-01-10 Size : 3kb User : 吴数点

//题目2: 益智游戏 //时间限制 : 20000ms //单点时限 : 1000ms //内存限制 : 256MB //描述 //幽香今天心情不错,正在和花田里的虫子玩一个益智游戏。 //这个游戏是这样的,对于一个数组A,幽香从A中选择一个数a,虫子从A中选择一个数b。a和b可以相同。她们的分数是a*b的因子的个数。 //幽香和虫子当然想要获得尽可能的高的分数,你能告诉她们应该选择哪两个数吗。 //由于幽香是个非常随意的人,数组A中的元素都是她随机选择的。 // //输入 //一行一个数n,表示A中整数的数量。 //接下来一行n个数,分别表示a1, a2, ..., an,为A中的元素。 // //n <= 100000, 1 <= ai <= 100000 //保证所有的ai都是随机生成的。 // //输出 //一行表示最大的分数。 // //样例输入 //2 //3 4 //样例输出 //6-hihocoder problem : my code for referances
Date : 2026-01-10 Size : 3kb User : 李中明

用AI语言prolog实现car的frame框架-the frame of car using prolog
Date : 2026-01-10 Size : 4kb User : zhuao76g284

DL : 0
五子棋极大极小搜索AI算法实现,方便移植,能够在VS2008上完美运行-Backgammon AI minimax search algorithm, easy to transplant, can be a perfect run in VS2008
Date : 2026-01-10 Size : 3.76mb User : 李志姚

调用百度AI开放平台动物识别API和百度百科API进行动物识别(Call Baidu AI open platform to identify API and Baidu Encyclopedia API for animal identification.)
Date : 2026-01-10 Size : 4kb User : sK2X73
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