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[Other] Navicat-For-MySQL-Enterprise-Edition-V8.2.19 DL : 0: Navicat For MySQL Enterprise Edition V8.2.19简体中文绿色版 Navicat是一个强大的MySQL数据库管理和开发工具。Navicat为专业开发者提供了一套强大的足够尖端的工具，但它对于新用户仍然是易于学习。Navicat,使用了极好的图形用户界面（GUI），可以让你用一种安全和更为容易的方式快速和容易地创建、组织、存取和共享信息。用户可完全控制 MySQL 数据库和显示不同的管理资料，包括一个多功能的图形化管理用户和访问权限的管理工具，方便将数据从一个数据库移转到另一个数据库中（Local to Remote、Remote to Remote、Remote to Local），进行档案备份。 Navicat 支援 Unicode，以及本地或遥距 MySQL 伺服器多连线，用户可浏览数据库、建立和删除数据库、编辑数据、建立或执行 SQL queries、管理用户权限（安全设定）、将数据库备份/复原、汇入/汇出数据（支援 CSV, TXT, DBF 和 XML 档案种类）等。新版与任何 MySQL 5.0.x 伺服器版本兼容，支援 Triggers，以及 BINARY VARBINARY/BIT 数据种类等的风范。绿化说明: 1.双击绿化+注册.exe程序.就可以使用了. 2.该版本已去除注册机程序。（貌似杀软误报这个文件，所以去除了！） 3.该版中加入绿化卸载程序！ -Navicat For MySQL Enterprise Edition V8.2.19 green simplified Chinese version Navicat is a powerful MySQL database management and development tools. Navicat for professional developers with a powerful set of tools for sophisticated enough, but it is still easy for new users to learn. Navicat, the use of an excellent graphical user interface (GUI), allows you to use a safe and easier way to quickly and easily create, organize, access and share information. Users can completely control the MySQL database and display different management information, including a multi-purpose graphical management of users and access rights management tools to facilitate the transfer of data from one database to another database (Local to Remote, Remote to Remote , Remote to Local), for file backup. Navicat supports Unicode, as well as local or remote MySQL server, multi-connection, the user can browse the database, creating and deleting a database, edit data, creating or perform SQL queries, manage us
Date : 2025-12-26 Size : 5.86mb User : 陈海龙
[Other] Catch_That_Cow DL : 0: 上帝王牌 Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer John has two modes of transportation: walking and teleporting. * Walking: FJ can move from any point X to the points X - 1 or X + 1 in a single minute * Teleporting: FJ can move from any point X to the point 2 × X in a single minute. If the cow, unaware of its pursuit, does not move at all, how long does it take for Farmer John to retrieve it? Input Line 1: Two space-separated integers: N and K Output Line 1: The least amount of time, in minutes, it takes for Farmer John to catch the fugitive cow. Sample Input 5 17 Sample Output 4 Hint The fastest way for Farmer John to reach the fugitive cow is to move along the following path: 5-10-9-18-17, which takes 4 minutes.-shangdiwangpai Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,000) on the same number line. Farmer John has two modes of transportation: walking and teleporting. * Walking: FJ can move from any point X to the points X- 1 or X+ 1 in a single minute * Teleporting: FJ can move from any point X to the point 2 × X in a single minute. If the cow, unaware of its pursuit, does not move at all, how long does it take for Farmer John to retrieve it? Input Line 1: Two space-separated integers: N and K Output Line 1: The least amount of time, in minutes, it takes for Farmer John to catch the fugitive cow. Sample Input 5 17 Sample Output 4 Hint The fastest way for Farmer John to reach the fugitive cow is to move along the following path: 5-10-9-18-17, which takes 4 minutes.
Date : 2025-12-26 Size : 176kb User : 上帝王牌
[Other] overfencing DL : 0: USACooverfencing 题解，描述农夫John在外面的田野上搭建了一个巨大的用栅栏围成的迷宫。幸运的是，他在迷宫的边界上留出了两段栅栏作为迷宫的出口。更幸运的是，他所建造的迷宫是一个“完美的”迷宫：即你能从迷宫中的任意一点找到一条走出迷宫的路。给定迷宫的宽度W(1<=W<=38)及高度H(1<=H<=100)。 2*H+1行，每行2*W+1的字符以下面给出的格式表示一个迷宫。然后计算从迷宫中最“糟糕”的那一个点走出迷宫所需的步数(就是从最“糟糕”的一点，走出迷宫的最少步数）。（即使从这一点以最优的方式走向最靠近的出口，它仍然需要最多的步数）当然了，牛们只会水平或垂直地在X或Y轴上移动，他们从来不走对角线。每移动到一个新的方格算作一步（包括移出迷宫的那一步）这是一个W=5,H=3的迷宫：-USACooverfencing Solution description in the fields outside, Farmer John, built a huge fenced maze. Fortunately, he set aside in the maze of border export of two fence maze. Fortunately, that he had built the labyrinth is a " perfect" maze: from any point in the maze to find a way out of the maze. To the maze-set the width of the W (1 < = W < = 38) and height H (1 < = H < = 100).* H+1 line, the character of each line* W+1 a maze in the format given below. And then calculate the most from the maze of " bad" a point out of the maze required number of steps (from " bad" , the minimum number of steps out of the labyrinth). (From this point the best way to the nearest export, it still needs the most number of steps) Of course, cattle are only level or vertically in the X or Y axis move, they do not have to go diagonal . Squares counted every move to a new step (including that step out of the maze) This is a W = 5, H = 3 of the maze:
Date : 2025-12-26 Size : 1kb User : 李明