Search - The ABC of C-language

Search - The ABC of C-language - List

[Other] abc DL : 0: C语言程序学生成绩管理系统源代码 txt版的可能有少于BUG-C Language Program student achievement management system txt version of the source code may be less than the BUG
Date : 2026-01-01 Size : 3kb User : lp
[Other] abc DL : 0: 投掷六个骰子能投掷出多少种排列组合呢？如1 2 3 4 5 6 和 6 5 4 3 2 1是同一种组合。问题可以转化为：n个相同小球放入r个相异盒子中，允许空盒。即求解不定方程 x1+x2+x3+ ... + xr = n 的非负整数解(x1, x2, x3, ..., xr)，0<= Xi <= n 令yi=xi+1,转化为 y1+y2+..+yr = n+r 此时 1<= yi <=n+1 相当于 n+r 个小球分成 r 堆，有多少种分法的问题即在这n+r-1个间隔中放置r-1个隔板，隔板之间的球的个数就相当于yi. 答案是 C(n+r-1,r-1) 本程序利用VC++语言解决本问题。-Throw six dice can throw out many permutations of it? As 123456 and 654321 is the same composition. Problem can be transformed into: n r identical balls into a different box, allowing the empty boxes. That solved indefinite equation x1+x2+x3+ ...+ xr = n of non-negative integer solutions (x1, x2, x3, ..., xr), 0 < = Xi < = n so yi = xi+1, into y1+y2+ ..+yr = n+r this case 1 < = yi < = n+1 equivalent n+r r balls into the heap, there are many kinds of issues of law that r-1 partition plates placed in this n+r-1 intervals, the ball separator between The number is equivalent to yi. answer is C (n+r-1, r-1) This procedure using VC++ solve the language problem.
Date : 2026-01-01 Size : 190kb User : 王涛
[Other] Arrange_Recursive DL : 0: c语言描述下的递归算法的无重复全排列，例：对字符串a[2]= abc 的全排列：abc acb bac bca cab cba-The recursive algorithm of the C language is arranged without duplication
Date : 2026-01-01 Size : 1kb User : 白佳豪