Search - Compiler Design In c

Search - Compiler Design In c - List

[Other] ccfx DL : 0: 实验目的：用c语言对一个简单语言的子集编制一个一遍扫描的编译程序，以加深对编译原理的理解,掌握编译程序的实现方法和技术。 c.1词法分析 c.1.1实验目的设计、编制并调试一个词法分析程序，加深对词法分析原理的理解。 c.1.2实验要求 c.1.2.1待分析的简单语言的词法 (1) 关键字： begin if then while do end --------有实验报告+.cpp+分析-Experimental Objective: To use c language of a simple subset of language once again scan the preparation of a compiler in order to deepen understanding of the principles of the compiler, compiler grasp the realization of methods and techniques. c.1 lexical analysis the experiment was c.1.1 design, compilation and debugging a lexical analysis process, deepen the understanding of the principle of lexical analysis. c.1.2 experiment to be analyzed c.1.2.1 simple language lexical (1) keywords: begin if then while do end
Date : 2025-12-26 Size : 165kb User : zhangjuan
[Other] lexical_analysis_program DL : 0: 编译原理、词法分析程序。题目：词法分析程序的设计和实现实验内容：设计并实现C语言的词法分析程序，要求如下。 (1)可以识别出用Ｃ语言编写的源程序中的每个单词符号，并以记号的形式输出每个单词符号。 (2)可以识别并读取源程序中的注释。 (3)可以统计源程序中的语句行数、单词个数和字符个数，其中标点和空格不计算为单词，并输出统计结果。 (4)检查源程序存在的错误，并可以报告错误所在的行列位置。 (5)发现源程序中存在错误后，进行适当的恢复，使词法分析可以继续进行，通过一次词法分析处理，可以检查并报告源程序中存在的所有错误。实现要求：采用C/C++作为实现语言，手工编写词法分析程序。 -Compiler theory lexical analysis program. Title: lexical analysis program design and implementation of experimental content: the design and realization of C language lexical analyzer requirements are as follows. (1) can identify each word in the C language source code symbols, and outputs of each word to the mark in the form of symbols. (2) can identify and read the comments in the source code. (3) Statistical statement the number of rows in the source code, the number of words and the number of characters, including punctuation and spaces does not count as a word, and output of the statistical results. (4) Check the source error, and can report the error where the ranks of the position. (5) found that there is an error in the source program, proper recovery, lexical analysis can proceed through a lexical analysis processing, you can check and report all errors in the source. Requirements: adopt the C/C++ as the implementation language, hand-written lexical analyzer.
Date : 2025-12-26 Size : 5kb User : 王大可
[Other] main DL : 0: 问题描述　　中缀表达式就是我们通常所书写的数学表达式，后缀表达式也称为逆波兰表达式，在编译程序对我们书写的程序中的表达式进行语法检查时，往往就可以通过逆波兰表达式进行。我们所要设计并实现的程序就是将中缀表示的算术表达式转换成后缀表示，例如，将中缀表达式 (A 一 (B*C 十 D)*E) ／ (F 十 G ) 转换为后缀表示为： ABC*D十E*—FG十／注意：为了简化编程实现，假定变量名均为单个字母，运算符只有＋，－，＊，／和＾（指数运算），可以处理圆括号（），并假定输入的算术表达式正确。要求：使用栈数据结构实现，输入的中缀表达式以＃号结束输入整数N。表示下面有N个中缀表达式 N个由单个字母和运算符构成的表达式输出 N个后缀表达式。 -Problem Description infix expression is what we usually write mathematical expressions, the suffix expressions are also called Reverse Polish Notation in compiler writing program for our expression syntax checking, often it can be reverse Polish expression. We want to design and implement programs that will infix arithmetic expression into a suffix, for example, the infix expression (A a (B* C ten D)* E)/(F ten G) is converted to the suffix expressed as: ABC* D ten E*-FG ten/Note: To simplify programming, assuming the variable names are a single letter, operators only+,-,*, /, and ^ (exponentiation), can handle parentheses ( ), and assumes that the input of the arithmetic expression is correct. Requirements: Using the stack data structure, the input infix expression input integer ending with# N. Here there are N represents infix expression of N by a single letter and operators constitute an expression output N suffix expressions.
Date : 2025-12-26 Size : 1kb User : yyz
[Other] student DL : 0: C语言，学生成绩管理系统作业设计。VC++6.0编译通过, 利用结构体，结构体指针，单链表，文件操作，命令窗口下简单菜单设计，可从文件读入数据，自动保存数据，有错误自动判断修复，能添加，删除，查询，显示，排序记录，适合多数初学者期末C语言作业设计要求！如果要增加科目，只要修改源代码中的Class_N的值就可以了，科目的名称在程序第一次运行时输入，会自动保存到student.ini文件,程序运行时自动生成的student.ini文件为系统信息文件（二进制文件），student.db为数据存储文件（二进制文件），Student.txt为操作记录文件（文本文件），可以修改Student.txt的打开方式，那样就能保存以前的操作记录了。程序是本人自己设计，可以随便更改和传播！-C language, student achievement management system design work. VC++ 6.0 compiler, the use of the structure, a structure pointer, a single list, file operations, a simple menu design under the command window, you can read data a file, the data is automatically saved, there is an error automatically determine the repair, can add, delete, query, display, sort records, suitable for most beginners end of the C language design requirements of the job! If you want to increase the subjects, as long as the value of the modified source code Class_N on it, the name of the subjects in the program when you enter the first run, it will automatically save to student.ini file automatically generated runtime student.ini file system information file (binary), student.db for data storage files (binaries), Student.txt operating log file (text file), you can modify the way Student.txt open, so you can save the previous operating record . Procedure is my own design, you can easily change and spread!
Date : 2025-12-26 Size : 335kb User : namejiang
[Other] CompilerCminus DL : 0: 这个文件是编译原理课程设计的实验代码，这段代码中包括了词法分析以及语义树的生成，工程的话用vs2013打开，如果版本低的话，直接把里面的头文件与源文件拷出来在相关的c语言开发环境里建个新的工程就行了，里面有一个例子，直接跑就行了。-This file is experimental code compiler theory of curriculum design, this code is included in the lexical analysis and semantic tree generation, engineering, then use vs2013 open, if the version of the low, then directly to the inside of the header and source files copy them in the relevant c language development environment to build a new project on the line, there is an example, run directly on the line.
Date : 2025-12-26 Size : 1.19mb User :
[Other] Convert-infix DL : 0: 问题描述　　中缀表达式就是我们通常所书写的数学表达式，后缀表达式也称为逆波兰表达式，在编译程序对我们书写的程序中的表达式进行语法检查时，往往就可以通过逆波兰表达式进行。我们所要设计并实现的程序就是将中缀表示的算术表达式转换成后缀表示，例如，将中缀表达式 (A 一 (B*C 十 D)*E) ／ (F 十 G ) 转换为后缀表示为： ABC*D十E* FG十／注意：为了简化编程实现，假定变量名均为单个字母，运算符只有＋，－，＊，／和＾（指数运算），可以处理圆括号（），并假定输入的算术表达式正确。要求：使用栈数据结构实现，输入的中缀表达式以＃号结束输入整数N。表示下面有N个中缀表达式 N个由单个字母和运算符构成的表达式输出 N个后缀表达式。 -Problem description Is the infix expression we usually write mathematical expressions, postfix expression also known as anti Poland formula, the compiler checks the syntax of expressions we write in the program, often can be carried out by the anti Poland formula. We need to design and implement a program that will convert infix arithmetic expressions representing suffixes for example, infix expression (A 1 (B*C ten D) *E () / (F ten G) Convert to suffix: ABC*D ten E* FG ten Note: in order to simplify the programming, assume that the variables are single letters, only the operator +, -, *, / and ^ (exponentiation), can handle the parentheses (), and assume that the input arithmetic expression right. Requirements: to achieve the use of stack data structure, to the end of the input infix expression directly. input Integer N. Express the following N infix expression N expressions that consist of a single letter and operator output N suffix expression.
Date : 2025-12-26 Size : 1kb User : 王乐