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插值的C语言的一段代码,开发环境为VC6.0,看看有没有人需要-Interpolation of the C language, a section of code, development environment for VC6.0, see if there is no need to
Date : 2025-12-14 Size : 29kb User : 王强

Handling preprocessor directives. Write a program that processes a preprocessor directive in the file containing the program in C. Should properly handle the directive # include, # define, # ifdef and ifndef. In the implementation of # define macro functions do not require treatment. In the implementation of # include nesting should be supported by any standard way. The standard way to headers can be specified by the environment variable INCLUDE or the command line. Program processing text files. All Programs in this section read data from the input text file, convert it in some way and write the result in the output file. For all programs in this section, the last two command-line option - input file name and output file name. If not specified the input file name, then the data is read from standard input. If not specified the output file name, then the result is printed to standard output.
Date : 2025-12-14 Size : 469kb User : anyman

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某超市为了促销,采用了购物打折的优惠方法,若顾客购物的金额f:1000≤f<2000,95折;2000≤f<3000,9折;3000≤f<5000,85折;f>5000,8折。编写程序,输入顾客的购物款计算出应付款-For a supermarket promotion, use discount shopping discount method, if the amount of customers shopping f: 1000 ≤ f < 2000,95 break 2000 ≤ f < 3000,9 break 3000 ≤ f < 5000,85 fold f> 5000 , 8 fold. Write a program, enter the shopping section to calculate the payable
Date : 2025-12-14 Size : 236kb User : 李世超

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用C#语言的编程,是控制台编程学习的其中一个章节,是初学者入门的很好的一个编程中的一个-Programming with C# language, is one of the console to learn programming section is a good beginner' s programming started in a
Date : 2025-12-14 Size : 3.44mb User : 谢晓

黄金分割法求最优化问题,Windows 7/vc6.0下编译通过。 运行结果正常。-The golden section method to seek the optimization problem
Date : 2025-12-14 Size : 42kb User : njut

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对一段文本中的字符串进行霍夫曼编码和解码,并显示各个字符对应的编码结果,并对编码后的内容进行解码并显示。-Huffman coding and decoding section of the text string and displays the coding results corresponding to each character, and encoded, decoded and displayed.
Date : 2025-12-14 Size : 1kb User : zhongpeng

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学习时候自己编的显示日历的一段代码,目前只能显示1900年以后任一年的1月份,其它的没时间去展开,仅供大家相互学习-Learn when their series display the calendar section of code currently only January in any year after 1900, the other do not have time to expand, we only learn from each other
Date : 2025-12-14 Size : 1kb User : zl

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简单的记录日志文件,包含临界段操作,支持在不同线程中的日志记录。-Simple log file that contains the critical section operation, support for logging in different threads.
Date : 2025-12-14 Size : 7kb User : yangjun

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输入两个不大于100000的正整数a和b,输出a/b的结果。当然,不是只输出整数部分,小数部分也是要算出来的,不过因为是整数, 如果结果是无限小数,结果一定是循环小数,必定存在循环节,比如1/3 = 0.33333....,或者1/7 = 0.142857142857..., 所以如果是循环小数,那么仅仅输出到第一个循环节结束就可以了,如果不是循环小数,则把精确结果输出(多余的末尾0不要输出)。 输入 仅一行输入,包含两个整数a和b,中间以空格分开-Not more than 100000 enter two positive integers a and b, with the output of a/b results. Of course, not only the output of the integer part, fractional part is to be counted out, but because it is an integer, if the result is an infinite decimal, the result will be a recurring decimal, surely there is a circular section, for example, 1/3 = 0.33333 ...., or 1/7 = 0.142857142857 ..., so if it is a recurring decimal, then the only output to the end of the first loop section can be, if not a recurring decimal, put the exact result output (0 Do not end the extra output). Enter only one line of input contains two integers a and b, separated by a space
Date : 2025-12-14 Size : 1kb User : 王涛

学生成绩核算系统的设计与实现 要求:(1)按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 (2)三个成绩对总评成绩的百分比被定义为常数,各占总成绩的30 、30 和40 。 (3)计算每位学生的总评成绩。 (4)计算该班级本课程的总平均成绩。 (5)计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优,89-80为良,79-70为中,69-60为及格,60分以下为不及格。 (6)按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。 -Student achievement accounting system design and implementation requirements: (a) by class according to the course from the document reads in the corresponding normal results, midterm exam and final exam. (2) three scores on the percentage of total grades are defined as constants, the total score of 30 , 30 and 40 . (3) calculate the total grades for each student. (4) to calculate the class of the course grade point average. (5) calculation is excellent, good, medium, passing, failing students and the percentage of the total number. Which is superior 100-90 ,89-80 ,79-70 is in good ,69-60 to pass 60 points or less failed. (6) according to the required output results in excellent, good, medium, pass, do not pass each section students learn, score.
Date : 2025-12-14 Size : 5kb User : Chengwei Xiao

VC编写的激光机程序,有板卡控制部分, 适合初学者-VC prepared by laser procedures, board control section for beginners
Date : 2025-12-14 Size : 5.2mb User : liqiang

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上海大学ACM在线判题系统部分源码,第4题到第201题,部分题目有缺失-Shanghai University ACM Online Judge System section Source
Date : 2025-12-14 Size : 36kb User : 张晨

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在做地铁隧道的断面变形分析时,会用到中轴线的提取-When the subway tunnel section deformation analysis, will be used to extract the axis of
Date : 2025-12-14 Size : 2.02mb User : zhangdong

做一个条形码识别工具。首先他完成了图像识别部分,得到了一系列条的宽度。他希望将这些宽度识别为一个01串。本来这是一个非常简单的任务,可是由于牟黑黑在识别的时候会有误差,使得问题变得没那么简单了。不过牟黑黑认为测量得到的结果最多比真实值大或小5 。请你帮忙完成这个识别程序。已知条形码中至少有一个是宽条,可能没有窄条。-Make a bar code recognition tool. First he completed the image recognition section, a series of the width. He hoped that those identified as a 01 string width. It would be a very simple task, but because Mu dark when there will be errors in identification, so the problem becomes not so simple. But Mu black think the results measured up to 5 larger or smaller than the true value. Please help complete this recognition program. Known barcode at least one wide strip, may not narrow.
Date : 2025-12-14 Size : 1kb User : yourunze
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