Search - josephus

Search - josephus - List

[Console] yosegh DL : 0: 该程序是数据结构中的链表应用,即约瑟夫环的小游戏.-the program is the data structure Application List, Josephus small game.
Date : 2008-10-13 Size : 842byte User : liujie
[Console] yosegh DL : 0: 该程序是数据结构中的链表应用,即约瑟夫环的小游戏.-the program is the data structure Application List, Josephus small game.
Date : 2026-01-09 Size : 1kb User : liujie
[Console] josephus_b DL : 0: Josephus alqoritm made using microsoft studio 2008 The implementation is oki.
Date : 2026-01-09 Size : 218kb User : Ruben
[Console] Josephus DL : 0: 解决约瑟夫问题的一个较为简单的例子的源代码。-Joseph problems to solve a relatively simple example of the source code.
Date : 2026-01-09 Size : 1kb User : luolizi
[Console] main DL : 0: 计算约瑟夫环，本程序是一个控制台程序，能够计算出约瑟夫环。-compute the Josephus
Date : 2026-01-09 Size : 1kb User : 郭军
[Console] Josephus DL : 0: 实现约瑟夫环，输入总个数和开始报数序号以及间隔，输出一个出队队列-Josephus, enter the total number and start reporting the number of serial interval, the output of a team queue
Date : 2026-01-09 Size : 245kb User : meng
[Console] Joseph_ring20120813 DL : 0: 约瑟夫环问题的c++解决方法，包括双向链表和单向链表两种解决方法。-Josephus problem c++ solutions, including the doubly linked list, singly linked list are two workarounds.
Date : 2026-01-09 Size : 5.01mb User : 沈宙
[Console] Josephus DL : 0: 简单的约瑟夫环和复杂的约瑟夫环问题的代码。-Simple Joseph ring and complex Joseph ring problem code
Date : 2026-01-09 Size : 171kb User : zhangyi
[Console] JoseQuestion DL : 0: 约瑟夫环问题求解　　　约瑟夫环问题的具体描述是：设有编号为1，2，……，n的n(n>0)个人围成一个圈，从第1个人开始报数，报到m时停止报数，报m的人出圈，再从他的下一个人起重新报数，报到m时停止报数，报m的出圈，……，如此下去，直到所有人全部出圈为止。当任意给定n和m后，设计算法求n个人出圈的次序。-Josephus Josephus problem solving specific description is: has numbered 1, 2, ...... n n (n> 0) individuals in a circle, from the start of the first personal number off, stop newspaper report m The number of reported m, a circle, and then re-reported number from the next person from his report m stop the reported number reported m circle out ...... and they continue to do so until all the circle until everyone. When any given n and m, design algorithms to find the order of n individuals a circle.
Date : 2026-01-09 Size : 1kb User : 冯读庆
[Console] JosephusProblem DL : 0: 用C程序解决约瑟夫斯问题，是一个出现在计算机科学和数学中的问题。在计算机编程的算法中，类似问题又称为约瑟夫环。-In computer science and mathematics, the Josephus Problem (or Josephus permutation) is a theoretical problem related to a certain counting-out game.
Date : 2026-01-09 Size : 97kb User : 王旺
[Console] ysfhcPP DL : 0: 约瑟夫环，大学的c++算法实验，做一个约瑟夫环的源码-Josephus, the University of c++ algorithm experiment, make a source of Josephus
Date : 2026-01-09 Size : 1.47mb User : wl
[Console] Josephus DL : 0: 约瑟夫环的实现，算法是自己写的，简单小程序-Josephus realization algorithm is to write a simple little program
Date : 2026-01-09 Size : 427kb User : 蓝色
[Console] Josephus DL : 0: 约瑟夫（Josephus）环问题：编号为1,2,3,…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数的上限值m，从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一人开始重新从1报数，如此下去，直到所有人全部出列为止。建立n个人的单循环链表存储结构，运行结束后，输出依次出队的人的序号。（必须用链表）-Joseph (Josephus) Central question: numbered 1,2,3, ..., n n individuals clockwise direction around a circle, each holding a password (positive integer). An optional start a positive integer as the upper limit of the number m, from the first person to start a clockwise direction from the beginning of the order number, report m stop. M out of newspaper columns, his password as the new value of m, starting from the next person on his re-clockwise direction from one number off, and so on, until all the columns so far. N round robin to establish a personal list storage structure, after the end of the run, the output sequence number of people out of the team. (Must list)
Date : 2026-01-09 Size : 98kb User : syw
[Console] josephus DL : 0: 约瑟夫环运作如下：1、一群人围在一起坐成环状（如：N）2、从某个编号开始报数（如：K）3、数到某个数（如：M）的时候，此人出列，下一个人重新报数4、一直循环，直到所有人出列，约瑟夫环结束-Josephus is the application of a mathematical problem: Given n individuals (with numbers 1,2,3 ... n, respectively) sitting around a round table. From the number of people reported a few k, m is the number of out of that person his next and from one individual to start off, count to m that another person out so the law of repeated until the round table were all out of the column.
Date : 2026-01-09 Size : 165kb User : 吴艳如
[Console] josephusGame DL : 0: 约瑟夫游戏，基于boost库，实现了完全符合开闭原则的工厂模式，学习工厂模式可以作为参考。-josephus games
Date : 2026-01-09 Size : 16kb User :
[Console] josephus DL : 0: Josephus问题的解决,N个人的队列，从第M个开始数到K就出列，最后的人胜出-the solve of Josephus problem
Date : 2026-01-09 Size : 1kb User : andychen
[Console] JosephuCircle DL : 0: 约瑟夫环问题，N个人围成一圈，从任意一个人开始报数，报到M的人从船上跳到水里，直到船上剩下指定的人数，求出最后剩下的人的编号-Josephus problem, N personal circle, began to count off any person, to report M man jumped into the water the boat until the specified number of people remaining on board, find the number of the last remaining person
Date : 2026-01-09 Size : 1kb User : JustForYou